I'm trying to create a new column (y) from another column (x) - my aim is to extract the numeric value after the 1st space of the string from the right-hand side, and if there is no numeric value after the space, then NULL.
I used the following SQL query below; however, the query extracted both numeric and non-numeric after the space into the new column (y) - please see the first image below. I have also attempted to use case statement but have yet to achieve the required output.
SELECT x, SUBSTR(x, INSTR(x,' ', -1) + 1) AS y
FROM <table_name>;
I would like the table to return:-
Thanks for your help in advance!
You could try regular expression function REGEXP_SUBSTR
SELECT x, REGEXP_SUBSTR (x, '(\s)(\d+)$') AS y
FROM <table_name>
Please check demo here: http://sqlfiddle.com/#!4/7bc0ee/4866
If you want to keep your SUBSTRING idea, you can use VALIDATE_CONVERSION to check whether your substring is numeric or not.
Then a CASE will select this substring or NULL if not numeric:
SELECT x,
CASE WHEN VALIDATE_CONVERSION(SUBSTR(x, INSTR(x,' ', -1) + 1) AS NUMBER) = 1
THEN SUBSTR(x, INSTR(x,' ', -1) + 1)
ELSE NULL END AS y
FROM yourtable;
Try out db<>fiddle
Here the documentation of VALIDATE_CONVERSION
Related
I have a Column which is a Varchar like a:b:c:d or h:i:j
Here I want resultant column as b:c:d or i:j respectively
I tried SPLIT_PART('a:b:c:d',':',2) function but this returns only 'b'
Although you could do this with array methods, it might be simple enough to do:
select substr(str, position(':' in str) + 1)
I'm trying to get the max value from a text field. All but two of the values are numbers with a single decimal. However, two of the values have something like 8.2.10. How can I pull back just the integer value? The values can go higher than 9.n, so I need to convert this field into a number so that I can get the largest value returned. So all I want to get back is the 8 from the 8.2.1.
Select cast(VERSION as int) is bombing out because of those two values with a second . in them.
You may derive by using regexp_substr with \d pattern :
with tab as
(
select regexp_substr('8.2.1', '\d', 1, 1) from dual
union all
select regexp_substr('9.0.1', '\d', 1, 1) from dual
)
select * from tab;
For Oracle you must attend the value as string for retire only the part before the dot. Ex:
SELECT NVL( SUBSTR('8.2.1',0, INSTR('8.2.1','.')-1),'8.2.1') AS SR FROM DUAL;
Check than the value is repeated 3 times in the sentence, and if the value is zero or the value didn't have decimal part then it will return the value as was set.
I had to use T-SQL rather PL/SQL, but the idea is the same:
DECLARE #s VARCHAR(10);
SELECT #s='8.2.1';
SELECT CAST(LEFT(#s, CHARINDEX('.', #s) - 1) AS INT);
returns the integer 8 - note that it won't work if there are no dots because it takes the part of the string to the left of the first dot.
If my quick look at equivalent functions was correct, then in Oracle that would end up as:
SELECT CAST(SUBSTR(VERSION, 1, INSTR(VERSION, '.') - 1) AS INT)
I have a column with data zeros after 6th column
i want to remove the leading zero after the 6th pipe in the data.
Please let me know if there is any way to do it. I tried to use substr with Trim but its not working.
Let's say your column is called COL something like the following should work:
CONCAT(SUBSTR(1,INSTR(COL,'|', 1,5)), LTRIM(SUBSTR(INSTR(COL,'|', 1,5)+1)),'0'))
Assuming from your current data that you need to only replace every occurrence of |00 with |, You can achieve thing using REPLACE function.
SELECT 'TMB|MLE020828585|74384911WA3S|="''07300058"|74384911|0013' AS Current_String,
replace('TMB|MLE020828585|74384911WA3S|="''07300058"|74384911|0013', '|00', '|') AS result_String
You can replace hard-coded value in above with your column name.
The above query generate result as below.
Current_String | result_String
------------------------------------------------------------------------------------------------------------------------
TMB|MLE020828585|74384911WA3S|="'07300058"|74384911|0013 | TMB|MLE020828585|74384911WA3S|="'07300058"|74384911|13
Hope this will help.
Oleg was correct in utilizing INSTR(), that is how I would do it. He was missing some arguments, though. Also, I wasn't able to get ltrim to work, so I cast it to an int instead. I tested and updated my table with your data using:
UPDATE mytable
SET mycolumn = Substr(mycolumn , 1, Instr(mycolumn , '|', 1, 5))
|| CAST(Substr(mycolumn , Instr(mycolumn , '|', 1, 5) + 1) AS INT)
I want to insert a value into an sql server 2008 table.
The value are like 20.00- , 10.00-
The minus sign is at the end of the value.
How can I achieve this?
How about using something like this?
SELECT REPLACE(CAST(-456.00 AS VARCHAR(10)),'-','') + '-'
Where 456.00 is your value
You could insert raw data into a staging table first. Then you could either convert the values in the staging table and insert them afterwards into the actual table, or insert and convert at the same time.
Here's how you could go about the conversion.
For every input value, you would need to check if it has a minus. If it does, then one character should be deleted at the last position and one character should be inserted at the first position. Otherwise nothing should be deleted or inserted.
So, essentially you can have an indication in the form of 1 or 0 and use that number to determine how many characters to insert or delete.
There are various methods of obtaining that 1/0 result.
For instance, you could take the input value's last character as a substring and use CHARINDEX to search for - within that substring:
CHARINDEX('-', LEFT(InputValue, LEN(InputValue)))
If the last character of InputValue is '-', the CHARINDEX will return 1, otherwise it will return 0.
Another method, also using CHARINDEX, would be to go like this:
CAST(CHARINDEX('-', InputValue) AS bit)
If InputValue has a minus, CHARINDEX will return a positive result and CAST will convert it to 1. If there is no minus, CHARINDEX will give you a 0, which will stay 0 after the cast.
Now you can use the expression's result to determine:
whether to delete the last character or not:
STUFF(InputValue, LEN(InputValue), CAST(CHARINDEX('-', InputValue) AS bit), '')
and
whether to prefix the value with a '-':
REPLICATE('-', CAST(CHARINDEX('-', InputValue) AS bit))
That is, the complete expression is this:
REPLICATE('-', CAST(CHARINDEX('-', InputValue) AS bit)) +
STUFF(InputValue, LEN(InputValue), CAST(CHARINDEX('-', InputValue) AS bit), '')
In the final statement you could also use CROSS APPLY to avoid repetition of the emphasised sub-expression, something aloong the lines of this (assuming you will choose to do insertion + processing):
INSERT INTO dbo.TargetTable (columns)
SELECT
...
REPLICATE('-', x.HasMinus) + STUFF(InputValue, LEN(InputValue), x.HasMinus, ''),
...
FROM dbo.StagingTable
CROSS APPLY (SELECT CAST(CHARINDEX('-', InputValue) AS bit)) AS x (HasMinus)
;
It is long but :
select IIF(ISNUMERIC(IIF(RIGHT(RTRIM('20.55-'), 1) = '-', '-' + REPLACE('20.55-', '-',''), '20.55-')) = 1, CONVERT(decimal(7,3), IIF(RIGHT(RTRIM('20.55-'), 1) = '-', '-' + REPLACE('20.55-', '-',''), '20.55-')), NULL)
Simply :
Select CASE WHEN LEFT(InputValue,1) = '-' THEN '-' ELSE '' END + REPLACE(InputValue,'-','')
You may need to Cast it as money (or numeric or decimal)
Given data in a column which look like this:
00001 00
00026 00
I need to use SQL to remove anything after the space and all leading zeros from the values so that the final output will be:
1
26
How can I best do this?
Btw I'm using DB2
This was tested on DB2 for Linux/Unix/Windows and z/OS.
You can use the LOCATE() function in DB2 to find the character position of the first space in a string, and then send that to SUBSTR() as the end location (minus one) to get only the first number of the string. Casting to INT will get rid of the leading zeros, but if you need it in string form, you can CAST again to CHAR.
SELECT CAST(SUBSTR(col, 1, LOCATE(' ', col) - 1) AS INT)
FROM tab
In DB2 (Express-C 9.7.5) you can use the SQL standard TRIM() function:
db2 => CREATE TABLE tbl (vc VARCHAR(64))
DB20000I The SQL command completed successfully.
db2 => INSERT INTO tbl (vc) VALUES ('00001 00'), ('00026 00')
DB20000I The SQL command completed successfully.
db2 => SELECT TRIM(TRIM('0' FROM vc)) AS trimmed FROM tbl
TRIMMED
----------------------------------------------------------------
1
26
2 record(s) selected.
The inner TRIM() removes leading and trailing zero characters, while the outer trim removes spaces.
This worked for me on the AS400 DB2.
The "L" stands for Leading.
You can also use "T" for Trailing.
I am assuming the field type is currently VARCHAR, do you need to store things other than INTs?
If the field type was INT, they would be removed automatically.
Alternatively, to select the values:
SELECT (CAST(CAST Col1 AS int) AS varchar) AS Col1
I found this thread for some reason and find it odd that no one actually answered the question. It seems that the goal is to return a left adjusted field:
SELECT
TRIM(L '0' FROM SUBSTR(trim(col) || ' ',1,LOCATE(' ',trim(col) || ' ') - 1))
FROM tab
One option is implicit casting: SELECT SUBSTR(column, 1, 5) + 0 AS column_as_number ...
That assumes that the structure is nnnnn nn, ie exactly 5 characters, a space and two more characters.
Explicit casting, ie SUBSTR(column,1,5)::INT is also a possibility, but exact syntax depends on the RDBMS in question.
Use the following to achieve this when the space location is variable, or even when it's fixed and you want to make a more robust query (in case it moves later):
SELECT CAST(SUBSTR(LTRIM('00123 45'), 1, CASE WHEN LOCATE(' ', LTRIM('00123 45')) <= 1 THEN LEN('00123 45') ELSE LOCATE(' ', LTRIM('00123 45')) - 1 END) AS BIGINT)
If you know the column will always contain a blank space after the start:
SELECT CAST(LOCATE(LTRIM('00123 45'), 1, LOCATE(' ', LTRIM('00123 45')) - 1) AS BIGINT)
both of these result in:
123
so your query would
SELECT CAST(SUBSTR(LTRIM(myCol1), 1, CASE WHEN LOCATE(' ', LTRIM(myCol1)) <= 1 THEN LEN(myCol1) ELSE LOCATE(' ', LTRIM(myCol1)) - 1 END) AS BIGINT)
FROM myTable1
This removes any content after the first space character (ignoring leading spaces), and then converts the remainder to a 64bit integer which will then remove all leading zeroes.
If you want to keep all the numbers and just remove the leading zeroes and any spaces you can use:
SELECT CAST(REPLACE('00123 45', ' ', '') AS BIGINT)
While my answer might seem quite verbose compared to simply SELECT CAST(SUBSTR(myCol1, 1, 5) AS BIGINT) FROM myTable1 but it allows for the space character to not always be there, situations where the myCol1 value is not of the form nnnnn nn if the string is nn nn then the convert to int will fail.
Remember to be careful if you use the TRIM function to remove the leading zeroes, and actually in all situations you will need to test your code with data like 00120 00 and see if it returns 12 instead of the correct value of 120.