I am trying to change the format of a timestamp in AWS Athena but I am not able to get it correct, would someone please help?
The value (Data format: string (Partitioned)) of the column I am trying to change is
20220826T073200Z
and I would like the output to be
2022-08-26 07:32:00
You need to parse date first, for example with date_parse:
select date_parse('20220826T073200Z', '%Y%m%dT%H%i%sZ');
Output:
_col0
2022-08-26 07:32:00.000
If this is not good enough you can format it with date_format:
select date_format(date_parse('20220826T073200Z', '%Y%m%dT%H%i%sZ'), '%Y-%m-%d %H:%i:%s');
_col0
2022-08-26 07:32:00
Related
Edited: Want to convert the format.
I am kinda new in BigQuery, recently I was working on a project. I want to convert above type of format into yyyy/mm/dd format. How will I do that?
You can combine PARSE_DATE with FORMAT_DATE to get the desired output:
SELECT FORMAT_DATE("%Y/%m/%d",PARSE_DATE("%B %d, %Y","June 10, 2014")) AS date_str
PARSE_DATE will parse the provided string into a DATE type value in BQ format (YYYY-MM-DD) and then FORMAT_DATE will format this DATE to a string with the desired output.
In case someone is wondering how to convert the whole column;
FORMAT_DATE("%Y/%m/%d",PARSE_DATE("%B %d, %Y",ColumnName)) as DesiredColumnName
In PrestoSQL, I'm trying to use parse_datetime to convert a field to timestamp.
The field is in the format of "2014-01-01 00:00:00+07", I tried using the following but its throwing an error, and I could not find any doc on this format:
parse_datetime(row.created_at,'YYYY-MM-dd HH:mm:ss.SSSSSS+ZZ')
Error I'm seeing is
Invalid format: "2014-01-01 00:00:00+00" is malformed at "+00"
What would be the correct way to parse this format of datetime?
You can try YYYY-MM-dd HH:mm:ssZ format:
trino> select parse_datetime('2014-01-01 00:00:00+00','YYYY-MM-dd HH:mm:ssZ');
_col0
-----------------------------
2014-01-01 00:00:00.000 UTC
I am writing a sql query in AWS Athena, where I have a timestamp field and I had to extract the dates of June 2021 (only dates, without time).
I am able to convert timestamp to date but then having trouble with converting to varchar.
Can anybody help please. Thanks in advance.
select substr(CAST(server_time AS VARCHAR)) from matomo_log_link_visit_action where server_time like "2021-06-%" ;
You can use the format_datetime function. For example:
select format_datetime(my_timestamp, 'yyyy-MM-dd')
see the docs: https://prestodb.io/docs/current/functions/datetime.html
I have a date value in this format 'dd-mmm-yyyy'(Example31-Mar-2020) in a glue table. I need to transform this to 'yyyy-mm-dd' (output:2020-03-31) format using sparkSql.
I have tried. "date_format(reference_line_attribute3, 'yyyy-mm-dd')" but this just gives null as output.
Please help.
Thank you
This should do the trick
df.withColumn("newDate",
date_format(
to_date($"reference_line_attribute3", "dd-MMM-yyyy"),
"yyyy-MM-dd"))
Output
+-------------------------+----------+
|reference_line_attribute3| newDate|
+-------------------------+----------+
| 31-Mar-2020|2020-03-31|
+-------------------------+----------+
I have this date format in hive: 20180618151752
Make the following query to leave it in the following way:
select
concat(substr(xdr.time_stop,1,8),' ',
substr(xdr.time_stop,9,2),':',
substr(xdr.time_stop,10,2),':',
substr(xdr.time_stop,11,2)) as date
from padl.fraude_vozm_xdr;
20180618 18:17:52
Now, I need to convert that string field to date, how could I do it?.
Thank you
Use from_unixtime and unix_timestamp.
from_unixtime(unix_timestamp('20180618151752','yyyyMMddHHmmss'),'yyyyMMdd HH:mm:ss')