Float Variable Constantly Evaluating to 0 [duplicate] - variables

Question

This question already has answers here:
Why does division result in zero instead of a decimal?
(5 answers)
Closed 7 months ago.
I am in a C++ class and for my final I am developing a program that asks a user whether they want to convert Fahrenheit temps to Celsius or Kelvin (there is a third menu option, but it is irrelevant to the issue). One of the tasks is to write a void function to convert to Celsius and to convert to Kelvin. I am also supposed to store the Celsius conversion, the Kelvin conversion, and the Fahrenheit number in an array. I am running into an issue where my floating-point Celsius variable (cel in the program) is always 0. This results in Kelvin always being 273.15. I have checked and "f" is storing the number that I input. Below is my function:
// Celcius function
void showCelcius(float f)
{
float cel, kel;
cel = (5/9) * (f - 32);
cout << cel << endl; // Test to check cel value after equation
kel = cel + 273.15;
cout << fixed << showpoint << setprecision(1);
cout << f << " Fahrenheit = "
<< cel << " Celcius\n";
temps[totalCount][0] = f;
temps[totalCount][1] = cel;
temps[totalCount][2] = kel;
}
Here is the ouput:
I have also tried putting the whole equation in parentheses. How can I get the variable "cel" to evaluate to the result of the equation?

Answer 1

I figured it out. It appears that since '5' and '9' were of type int it was not evaluating the equation at all. I added static_cast() to each number and it works.
// Celcius function
void showCelcius(float f)
{
float cel, kel;
cel = (static_cast<float>(5)/static_cast<float>(9))*(f - static_cast<float>(32));
cout << cel << endl;
kel = cel + 273.15;
cout << fixed << showpoint << setprecision(1);
cout << f << " Fahrenheit = "
<< cel << " Celcius\n";
temps[totalCount][0] = f;
temps[totalCount][1] = cel;
temps[totalCount][2] = kel;
}