Another migration question. I have a chunk of VB6 code that seems to need some workaround for .NET. For a shortened version, this is all it is doing:
Printer.Line (lftx * stepx * fx, k * stepy * fy)-(rgtx * stepx * fx, k * stepy * fy), RGB(77, 66, 71)
Keep giving me Error ID: BC30205, End of statement expected, on minus sign.
I have added a parenthesis that encloses the contents of the command, aware that it does not completely solve the problem.
Doing so a different error appears, Error ID: BC30452, Operator '-' is not defined for types '(Single, Single)' and '(Single, Single)'.
I guess it can't subtract because of the commas inside the brackets...
As you may have noticed, I never written in VB6 and im not a programmer. How do I implement the same thing in .NET? Thank you for all the help
An equivalent instruction for printer.line is e.Graphics.DrawLine(). Here is a sample code that you may find here and to which I have added e.Graphics.DrawLine in the following code:
Imports System.Drawing
Imports System.Drawing.Drawing2D
Imports System.Drawing.Printing
Private Sub btnPrint_Click(sender As Object, e As EventArgs) Handles btnPrint.Click
' ...
' These two lines initiate printing. Place this code in an
' appropriate place in the application.
Dim pd As New HelloPrintDocument()
pd.Print()
End Sub
' ...
' This class manages the printing process.
Public Class HelloPrintDocument
Inherits PrintDocument
Protected Overrides Sub OnPrintPage(ByVal e As PrintPageEventArgs)
MyBase.OnPrintPage(e)
' Draw text to the printer graphics device.
Dim fnt As New Font("Arial", 10, FontStyle.Regular,
GraphicsUnit.Point)
e.Graphics.DrawString("Hello, Printer!", fnt, Brushes.Black, 0, 0)
Dim x0 As Int32 = 0
Dim y0 As Int32 = 0
Dim x1 As Int32 = 0
Dim y1 As Int32 = 50
e.Graphics.DrawLine(Pens.Black, New Point(x0, y0), New Point(x1, y1))
Dim w As Int32 = 200 ' rectangle width
Dim h As Int32 = 50 ' rectangle height
y0 += 12
e.Graphics.DrawRectangle(Pens.Red, New Rectangle(New Point(x0, y0), New Size(w, h)))
y0 = e.PageBounds.Height - h * 2
e.Graphics.FillRectangle(Brushes.Green, New Rectangle(New Point(x0, y0), New Size(w, h)))
fnt.Dispose()
' Indicate that there are no more pages.
e.HasMorePages = False
End Sub
End Class
Related
I'm rewriting a VB6 application in VB.net. Instead of using the VB6 printer namespace, I'm trying make the code natively VB.net compatible.
The VB6 application has a bunch of printer.print statements as well as a bunch of printer.line statements. (I believe the lines use TWIPs.) Here is an example of some of the lines.
Printer.DrawWidth = 1.5
Printer.Line (200, 12940)-(11275, 12940)
Printer.Line (200, 13680)-(6660, 13680)
Printer.Line (6712, 13680)-(11275, 13680)
Printer.FillStyle = vbFSTransparent
Printer.DrawWidth = 1
Printer.DrawStyle = vbDashDot
Printer.Circle (5700, 6000), draw_scale * BC_Diam / 2
media.FontItalic = True
Printer.Print "some text"
media.FontItalic = False
Printer.Print "additional, non italic text"
The only way I've been able to find how to do any of this in VB.net is by using the PrintDocument's PrintPage event. A problem with doing it this way is you have to pass all of the text to this subroutine all at once and deal with a "printArea" for word wrap. Another problem is it makes it very difficult to switch between italic and non italic text. In the same way for text, I think I would have to pass in all of the line/circle coordinates as well, then draw them from the event subroutine.
Private Sub document_PrintPage(ByVal sender As Object, ByVal e As System.Drawing.Printing.PrintPageEventArgs) Handles document.PrintPage
Dim printFont As Font = New Font("Courier New", 8.5, FontStyle.Regular)
' Set print area size and margins
With document.DefaultPageSettings
Dim leftMargin As Integer = .Margins.Left 'X
Dim topMargin As Integer = .Margins.Top 'Y
Dim printHeight As Integer = .PaperSize.Height - topMargin * 2
Dim printWidth As Integer = .PaperSize.Width - leftMargin * 2
End With
' Check if the user selected to print in Landscape mode
' if they did then we need to swap height/width parameters
If document.DefaultPageSettings.Landscape Then
Dim tmp As Integer
tmp = printHeight
printHeight = printWidth
printWidth = tmp
End If
Dim lines As Int32
Dim chars As Int32
'Now we need to determine the total number of lines
'we're going to be printing
Dim numLines As Int32 = CInt(printHeight / printFont.Height)
' Create a rectangle printing are for our document
Dim printArea As New RectangleF(leftMargin, topMargin, printWidth, printHeight)
' Set format of string.
Dim format As New StringFormat(StringFormatFlags.LineLimit)
e.Graphics.MeasureString(txtText.Text.Substring(curChar), printFont, New SizeF(printWidth, printHeight), format, chars, lines)
e.Graphics.DrawString(txtText.Text.Substring(curChar), printFont, Brushes.Black, printArea, format)
'Increase current char count
curChar += chars
'Detemine if there is more text to print, if
'there is the tell the printer there is more coming
Debug.Print("curChar < txtText.Text.Length:" & (curChar < txtText.Text.Length))
If curChar < txtText.Text.Length Then
e.HasMorePages = True
Else
e.HasMorePages = False
curChar = 0
End If
End Sub
There has to be a better way to do this, right? How I can call Graphics.DrawLine, Graphics.DrawEllipse, Graphics.DrawString, etc. for the PrintDocument from outside of the PrintPage event in VB.net like you could in VB6?
a strange phenomenon occurs.
With my edge detection program, I can transfer the inside of the GraphicsPath to a new image.
It always works great – except when I scale the original image with GIMP and Word (aspect ratio remains, only the dimensions are changed). Then the area is shifted. To the left and up. See attachement. In line 68, I looked what is in rectCutout. Everything OK.
Does this have anything to do with GIMP? The dots per inch are the same (72). The compression quality of the JPEG also (100%).
I just realized: if I scale an image larger, the result is completely black.
The strange thing is: I'm not saying: the picture that is drawn on is larger than the picture that is saved. Then it would be logical that the path is not in the same position. It's about the fact that the loaded image is just smaller.
I would be happy if someone could tell me why. 😄
this is the scaled image which is loaded
Here you see the GUI, ready to save
cropped image, area has x and y offset
#Disable Warning CA1707 ' Bezeichner dürfen keine Unterstriche enthalten
Imports System.Drawing.Drawing2D
Imports Microsoft.WindowsAPICodePack.Dialogs
Public NotInheritable Class AllesGrafische
Public Shared Sub Paint_the_Rectangle(ByVal g As Graphics, ByVal recta As Rectangle)
If g IsNot Nothing Then
g.SmoothingMode = SmoothingMode.AntiAlias
g.CompositingQuality = CompositingQuality.HighQuality
g.PixelOffsetMode = PixelOffsetMode.HighQuality
g.InterpolationMode = InterpolationMode.HighQualityBilinear
Using Pen_Hellblau As Pen = New Pen(Color.FromArgb(0, 200, 255), 1.0F)
g.DrawRectangle(Pen_Hellblau, recta)
End Using
End If
End Sub
Public Shared Sub Draw_Curve(ByVal g As Graphics, ByVal theList As List(Of Point))
If theList IsNot Nothing AndAlso theList.Count > 0 AndAlso g IsNot Nothing Then
g.SmoothingMode = SmoothingMode.AntiAlias
g.CompositingQuality = CompositingQuality.HighQuality
g.PixelOffsetMode = PixelOffsetMode.HighQuality
g.InterpolationMode = InterpolationMode.HighQualityBilinear
Dim theList_neu As New List(Of Point)
Using gp As New GraphicsPath
For i As Integer = 1 To theList.Count - 1 Step 1
Dim a As Integer = theList(i).X
Dim b As Integer = theList(i).Y
Dim c As Integer = theList(i - 1).X
Dim d As Integer = theList(i - 1).Y
Dim Entfernungsbetrag As Double = Math.Sqrt(Math.Pow(a, 2) + Math.Pow(b, 2) + Math.Pow(c, 2) + Math.Pow(d, 2) - 2 * a * c - 2 * b * d)
If Entfernungsbetrag < Form1.erlaubte_Entfernung Then
theList_neu.Add(theList(i))
End If
Next
If theList_neu.Count = 0 Then Return
gp.AddLines(theList_neu.ToArray())
Using Pen_hellrosa As Pen = New Pen(Color.FromArgb(255, 64, 239), 1.0F)
g.DrawPath(Pen_hellrosa, gp)
End Using
If Form1.ClosePath Then
gp.CloseFigure()
End If
If Form1.CheckBox1.Checked Then
Dim Speicherpfad As String
Using SFD1 As New CommonSaveFileDialog
SFD1.Title = "Wo soll das Bild gespeichert werden?"
SFD1.Filters.Add(New CommonFileDialogFilter("PNG", ".png"))
If System.IO.Directory.Exists("C:\Users\...\source\repos\VB.NET\Get mouse position and draw rectangle on screen") Then
SFD1.InitialDirectory = "C:\Users\...\source\repos\VB.NET\Get mouse position and draw rectangle on screen"
Else
SFD1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Desktop)
End If
If SFD1.ShowDialog = CommonFileDialogResult.Ok Then
Speicherpfad = SFD1.FileName & ".png"
Else
Return
End If
End Using
Using bmpSource As Bitmap = New Bitmap(Form1.Pfad_Bild)
Dim rectCutout As RectangleF = gp.GetBounds()
Using m As Matrix = New Matrix()
m.Translate(-rectCutout.Left, -rectCutout.Top)
gp.Transform(m)
End Using
Using bmpCutout As Bitmap = New Bitmap(CInt(Math.Round(rectCutout.Width, 0)), CInt(Math.Round(rectCutout.Height, 0)))
Using graphicsCutout As Graphics = Graphics.FromImage(bmpCutout)
graphicsCutout.Clip = New Region(gp)
graphicsCutout.DrawImage(bmpSource, CInt(-rectCutout.Left), CInt(-rectCutout.Top))
bmpCutout.Save(Speicherpfad, Imaging.ImageFormat.Png)
Form1.CheckBox1.Checked = False
End Using
End Using
End Using
End If
End Using
End If
End Sub
End Class
#Enable Warning CA1707 ' Bezeichner dürfen keine Unterstriche enthalten
The solution is to use .SetResolution()
Using Original As Bitmap = New Bitmap(Form1.Pfad_Bild)
Dim rectCutout As RectangleF = gp.GetBounds()
Using m As System.Drawing.Drawing2D.Matrix = New System.Drawing.Drawing2D.Matrix()
m.Translate(-rectCutout.Left, -rectCutout.Top)
gp.Transform(m)
End Using
Using bmpCutout As Bitmap = New Bitmap(CInt(Math.Round(rectCutout.Width, 0)), CInt(Math.Round(rectCutout.Height, 0)))
bmpCutout.SetResolution(Original.HorizontalResolution, Original.VerticalResolution)
.
.
.
.
.
I'm adding a control to a picturebox. This control is a component, precisely it's a toggle switch posted here. I'd like this control to be vertical and not horizontal .
So, since objects can't be rotated or flipped, I found a way to flip the picturebox image with:
PictureBox1.Image.RotateFlip(RotateFlipType.Rotate180FlipNone)
PictureBox1.Refresh()
The error I'm getting at RunTime is:
System.Windows.Forms.PictureBox.Image.get returned Nothing
Endeed the control is not an image so is there a way to flip the control inside of the picturebox by 180 degrees?
Also, You think there is a way to know when the value of the toggle switch is on or off?
Thanks
As already mentioned above, extend the control to have it drawn either horizontally or vertically.
Imports System.Drawing
Imports System.Drawing.Drawing2D
Imports System.Windows.Forms
Public Class ToggleSwitch
Inherits CheckBox
Public Sub New()
MyBase.New
SetStyle(ControlStyles.AllPaintingInWmPaint Or
ControlStyles.UserPaint, True)
UpdateStyles()
Padding = New Padding(6)
End Sub
Private _orientation As Orientation = Orientation.Horizontal
Public Property Orientation As Orientation
Get
Return _orientation
End Get
Set(value As Orientation)
_orientation = value
Dim max = Math.Max(Width, Height)
Dim min = Math.Min(Width, Height)
If value = Orientation.Vertical Then
Size = New Size(min, max)
Else
Size = New Size(max, min)
End If
End Set
End Property
'Fix by: #41686d6564
<Browsable(False),
Bindable(False),
DesignerSerializationVisibility(DesignerSerializationVisibility.Hidden),
EditorBrowsable(EditorBrowsableState.Never)>
Public Overrides Property AutoSize As Boolean
Get
Return False
End Get
Set(value As Boolean)
End Set
End Property
Protected Overrides Sub OnPaint(e As PaintEventArgs)
Dim g = e.Graphics
g.Clear(BackColor)
g.SmoothingMode = SmoothingMode.AntiAlias
g.PixelOffsetMode = PixelOffsetMode.Half
Dim p = Padding.All
Dim r = 0
Dim rec As Rectangle
Using gp = New GraphicsPath
If _orientation = Orientation.Vertical Then
r = Width - 2 * p
gp.AddArc(p, p, r, r, -180, 180)
gp.AddArc(p, Height - r - p, r, r, 0, 180)
r = Width - 1
rec = New Rectangle(0, If(Checked, Height - r - 1, 0), r, r)
'Or
'rec = New Rectangle(0, If(Checked, 0, Height - r - 1), r, r)
'To get the ON on top.
Else
r = Height - 2 * p
gp.AddArc(p, p, r, r, 90, 180)
gp.AddArc(Width - r - p, p, r, r, -90, 180)
r = Height - 1
rec = New Rectangle(If(Checked, Width - r - 1, 0), 0, r, r)
End If
gp.CloseFigure()
g.FillPath(If(Checked, Brushes.DarkGray, Brushes.LightGray), gp)
g.FillEllipse(If(Checked, Brushes.Green, Brushes.WhiteSmoke), rec)
End Using
End Sub
End Class
As for the second part of your question, please read CheckBox.Checked property and CheckBox.CheckedChanged event.
Impelemntation example:
Private Sub ToggleSwitch1_CheckedChanged(sender As Object, e As EventArgs) Handles ToggleSwitch1.CheckedChanged
If ToggleSwitch1.Checked Then
'ToDo with ON state...
Else
'ToDo with OFF state..
End If
End Sub
I am developing a website where i'm pulling some data from a query and then needing to print this data to a brady pr300 plus label printer. I would like for the printing to happen automatically from the web server to the printer without having the print dialog box pop up on the client computer.
What is the best way to go about this? javascript, vb behind code?
I've been playing around with this without much luck. I created a printingclass with onbeginprint method and onprintpage method. When i call the print, it goes to the onbeginprint method, but for some reason it doesnt go to onprintpagemethod when i step through the code. The error i get is System.Drwaing.Printing.invalidprinterexception: no printers are installed.
I'm kind of stuck at the moment.
Public Sub PrintDocument()
Dim tprinter As New PCPrint
tprinter.PrinterFont = New Font("Verdana", 10)
tprinter.TextToPrint = "HELLO WORLD"
tprinter.PrintName = "testbrady"
tprinter.Print()
End Sub
Protected Overrides Sub OnBeginPrint(ByVal e As Printing.PrintEventArgs)
' Run base code
MyBase.OnBeginPrint(e)
'Check to see if the user provided a font
'if they didnt then we default to Times New Roman
If _font Is Nothing Then
'Create the font we need
_font = New Font("Times New Roman", 10)
End If
End Sub
Protected Overrides Sub OnPrintPage(ByVal e As Printing.PrintPageEventArgs)
' Run base code
MyBase.OnPrintPage(e)
'Declare local variables needed
Static curChar As Integer
Dim printHeight As Integer
Dim printWidth As Integer
Dim leftMargin As Integer
Dim rightMargin As Integer
Dim lines As Int32
Dim chars As Int32
'Set print area size and margins
With MyBase.DefaultPageSettings
printHeight = .PaperSize.Height - .Margins.Top - .Margins.Bottom
printWidth = .PaperSize.Width - .Margins.Left - .Margins.Right
leftMargin = .Margins.Left 'X
rightMargin = .Margins.Top 'Y
End With
MyBase.DefaultPageSettings.PrinterSettings.PrinterName = PrintName
'Check if the user selected to print in Landscape mode
'if they did then we need to swap height/width parameters
If MyBase.DefaultPageSettings.Landscape Then
Dim tmp As Integer
tmp = printHeight
printHeight = printWidth
printWidth = tmp
End If
'Now we need to determine the total number of lines
'we're going to be printing
Dim numLines As Int32 = CInt(printHeight / PrinterFont.Height)
'Create a rectangle printing are for our document
Dim printArea As New RectangleF(leftMargin, rightMargin, printWidth, printHeight)
'Use the StringFormat class for the text layout of our document
Dim format As New StringFormat(StringFormatFlags.LineLimit)
'Fit as many characters as we can into the print area
e.Graphics.MeasureString(_text.Substring(RemoveZeros(curChar)), PrinterFont, New SizeF(printWidth, printHeight), format, chars, lines)
'Print the page
e.Graphics.DrawString(_text.Substring(RemoveZeros(curChar)), PrinterFont, Brushes.Black, printArea, format)
'Increase current char count
curChar += chars
'Detemine if there is more text to print, if
'there is the tell the printer there is more coming
If curChar < _text.Length Then
e.HasMorePages = True
Else
e.HasMorePages = False
curChar = 0
End If
End Sub
Hello StackOverflow Members,
This is what i ended up doing to get the label printer to work.
Imports System.Drawing
Imports System.Drawing.Printing
Public Sub prt(variables)
Dim prn As New Printing.PrintDocument
Dim psz As New Printing.PaperSize With {
.RawKind = Printing.PaperKind.Custom,
.Width = 400,
.Height = 150
}
Using (prn)
prn.PrinterSettings.PrinterName = printer
prn.DefaultPageSettings.PaperSize = psz
prn.DefaultPageSettings.Margins.Left = 5
prn.DefaultPageSettings.Margins.Right = 5
prn.DefaultPageSettings.Margins.Top = 5
prn.DefaultPageSettings.Margins.Bottom = 5
AddHandler prn.PrintPage,
AddressOf Me.PrintPageHandler
prn.Print()
RemoveHandler prn.PrintPage,
AddressOf Me.PrintPageHandler
End Using
End Sub
Private Sub PrintPageHandler(ByVal sender As Object,
ByVal args As Printing.PrintPageEventArgs)
Dim shopnameX As Integer = 10, shopnameY As Integer = 10
Dim sfont As New Font("Arial Black", 14)
Dim strfomart As New StringFormat()
Dim StrRight As New StringFormat()
Dim StrLeft As New StringFormat()
strfomart.Alignment = StringAlignment.Center
StrRight.Alignment = StringAlignment.Far
StrLeft.Alignment = StringAlignment.Near
Dim dashValues As Single() = {5, 2, 5, 2}
Dim blackPen As New Pen(Color.Black, 1)
' blackPen.DashPattern = dashValues
Dim i As Integer, j As Integer
args.Graphics.DrawString(part.ToString, sfont, Brushes.Black, New
PointF(shopnameX, shopnameY))
End Sub
I have to generate the following figure according to user fed values. How do I go about drawing the arcs (B-C-F as in figure, circular in nature) given their start point & end point (B & F respectively) & the height from the segment BF? I can do some geometric calculations & get the radius & all, but how do I draw the arc?
I have tried using the Graphics.DrawCurve() method, but it doesn't work as expected. How can I make this method work for circular arcs? Any other workaround is also welcome.
From my comment:
If you have computed the necessary radius to generate the curve, then
simply draw the entire circle with Graphics.DrawEllipse(), but use
Graphics.SetClip() and pass a rectangle using the points B and F as a
side and computing the other two points using the height C. This will
clip the entire circle to just the part visible within that rectangle.
Then call Graphics.ResetClip() and draw the rest of the lines. Repeat
the SetClip() trick to draw the curve at the bottom as well.
Here's a proof of concept for the top curve thru B, C, and F.
I used the formulas provided by Donna Roberts at Investigative Circle Activity Using Three Points.
Here's a screenshot:
...and the code that produced it:
Public Class Form1
Private B As New Point(50, 100)
Private F As New Point(250, 100)
Private DistanceFromBF As Integer = 50
Private Sub Form1_Paint(sender As System.Object, e As System.Windows.Forms.PaintEventArgs) Handles MyBase.Paint
If B.Y = F.Y Then
Dim C As New Point(B.X + (F.X - B.X) / 2, B.Y - DistanceFromBF)
Dim ctr As Point
Dim rad As Double
CircleFromPointsOnCircumference(B, C, F, ctr, rad)
Dim rc As New Rectangle(ctr, New Size(1, 1))
rc.Inflate(rad, rad)
e.Graphics.DrawRectangle(Pens.Black, rc)
Dim clip As New Rectangle(New Point(B.X, B.Y - DistanceFromBF), New Size(F.X - B.X, DistanceFromBF))
e.Graphics.SetClip(clip)
e.Graphics.DrawEllipse(Pens.Green, rc)
e.Graphics.ResetClip()
DrawPoint(B, e.Graphics, Color.Red)
DrawPoint(C, e.Graphics, Color.Red)
DrawPoint(F, e.Graphics, Color.Red)
DrawPoint(ctr, e.Graphics, Color.Green)
End If
End Sub
Private Sub DrawPoint(ByVal pt As Point, ByVal G As Graphics, ByVal clr As Color)
Dim rc As New Rectangle(pt, New Size(1, 1))
rc.Inflate(3, 3)
Using brsh As New SolidBrush(clr)
G.FillEllipse(brsh, rc)
End Using
End Sub
Private Sub CircleFromPointsOnCircumference(ByVal ptA As Point, ByVal ptB As Point, ByVal ptC As Point, ByRef Center As Point, ByRef Radius As Double)
Dim mR As Double = CDbl(ptA.Y - ptB.Y) / CDbl(ptA.X - ptB.X)
Dim mT As Double = CDbl(ptC.Y - ptB.Y) / CDbl(ptC.X - ptB.X)
Dim X As Double = (mR * mT * (ptC.Y - ptA.Y) + mR * (ptB.X + ptC.X) - mT * (ptA.X + ptB.X)) / CDbl(2) * (mR - mT)
Dim Y As Double = CDbl(-1) / mR * (X - CDbl(ptA.X + ptB.X) / CDbl(2)) + (CDbl(ptA.Y + ptB.Y) / CDbl(2))
Center = New Point(X, Y)
Radius = Math.Sqrt(Math.Pow(ptA.X - Center.X, 2) + Math.Pow(ptA.Y - Center.Y, 2))
End Sub
End Class
Got it! Thanks #Mitch & #Idle_Mind
Using the builtin DrawArc method of Graphics
Friend Function draw_tank() As Boolean
' Create pen.
Dim blackPen As New Pen(Color.Black, 3)
' Create rectangle to bound ellipse.
Dim rect As New Rectangle(100, 100, 200, 200)
' Keeping the width & length same (200) we get a circle
' Create start and sweep angles on ellipse.
Dim startAngle As Single = 225.0F
Dim sweepAngle As Single = 90.0F
' Draw arc to screen.
Dim myarc As Graphics = Me.CreateGraphics
myarc.DrawArc(blackPen, rect, startAngle, sweepAngle)
Return True
End Function
Suggestions/Improvements welcome.
Note - This isn't the actual function from my code.