I have a table variable defined thus
DECLARE #DatesTable TABLE
(
Id uniqueidentifier,
FooId uniqueidentifier,
Date date,
Value decimal (26, 10)
)
Id is always unique but FooId is duplicated throughout the table. What I would like to do is to select * from this table for each unique FooId having the max(date). So, if there are 20 rows with 4 unique FooIds then I'd like 4 rows, picking the row for each FooId where the date is the largest.
I've tried using group by but I kept getting errors about various fields not being in the select clause etc.
Use a common table expression with row_number():
;WITH cte AS
(
SELECT Id, FooId, Date, Value,
ROW_NUMBER() OVER(PARTITION BY FooId ORDER BY Date DESC) As rn
FROM #DatesTable
)
SELECT Id, FooId, Date, Value
FROM cte
WHERE rn = 1
Often the most efficient method is a correlated subquery:
select dt.*
from #DatesTable dt
where dt.date = (select max(dt2.date) from #DatesTable dt2 where dt2.fooid = dt.fooid);
However, for this to be efficient, you need an index on (fooid, date). In more recent versions of SQL Server, you can have indexes on table variables. In earlier versions, you can do this using a primary key.
Related
I want to get the last record from the duplicate records and want the non-duplicate records also.
As depicted in the below image I want to get row number 4, 5, 7 and 9 in my output.
Here, In the below image the ** Main table** was shown. From which I have to concat first two columns and then from that new column I need the last row of duplicate records and the non-duplicate rows also.
I have tried with the given below SQL code.
DECLARE #dense_rank_demo AS TABLE (
Bid INT,
cid INT,
BCode NVARCHAR(10)
);
INSERT INTO #dense_rank_demo(Bid,cid,BCode)
VALUES(2393,1,'LAX'),(2394,54,'BRK'),(2395,57,'ONT'),(2393,1,'SAN'),(2393,1,'LAX'),(2393,1,'BRK'),(2394,54,'ONT'),(2395,57,'SAN'),(2394,1,'ONT');
SELECT * FROM #dense_rank_demo;
SELECT
CONCAT([Bid],'_',[cid]) as [Key],BCode,DENSE_RANK() over( order by CONCAT([Bid],'_',[cid]))
from #dense_rank_demo
From the SQL code I found that there is no column on which we can apply order by for getting the expected Result.
So that, I have add one column name Id and done some other changes for getting expected output.
Here I am Sharing the code in which I have done some changes.
DECLARE #dense_rank_demo AS TABLE (
ID INT IDENTITY(1,1),
Bid INT,
cid INT,
BCode NVARCHAR(10));
DECLARE #tableGroupKey TABLE
(
dr bigint,
[Key] VARCHAR(50)
)
INSERT INTO #dense_rank_demo(Bid,cid,BCode)
VALUES(2393,1,'LAX'),
(2394,54,'BRK'),
(2395,57,'ONT'),
(2393,1,'SAN'),
(2393,1,'LAX'),
(2393,1,'BRK'),
(2394,54,'ONT'),
(2395,57,'SAN'),
(2394,1,'ONT');
with [drd] as
(
select
concat([Bid],'_',[cid]) as [Key],
BCode,
dense_rank() over(partition by concat([Bid],'_',[cid]) order by ID) as
[dr]
from #dense_rank_demo
)
INSERT INTO #tableGroupKey(dr,[Key])
select MAX(dr) dr,[Key]
from [drd]
GROUP BY [Key]
SELECT *,CONCAT(Bid,'_',cid) AS [Key] FROM #dense_rank_demo [drd]
select Result.* FROM
(
SELECT *,CONCAT(Bid,'_',cid) AS [Key] ,
dense_rank() over(partition by concat([Bid],'_',[cid]) order by ID) as
[dr]
FROM #dense_rank_demo [drd]
) as [Result]
INNER JOIN #tableGroupKey [gk] ON
[Result].[Key] = [gk].[Key] AND [gk].dr = [Result].dr
ORDER BY [Result].ID
The Expected output is as below:
[Output]
The issue here is the ordering of the values within the result set. If you had a specific order to use, this would be fairly straightforward - however, you are relying on dense_rank() to consistently and reliably returning the same values for those in the table. If we could use, for example, the alpha sort on the BCode column then it would be simple to use a CTE and get the last/first one:
with [drd] as
(
select
concat([Bid],'_',[cid]) as [Key],
BCode,
dense_rank() over(partition by concat([Bid],'_',[cid]) order by Bcode desc) as [dr]
from #dense_rank_demo
)
select *
from [drd]
where dr = 1
As the order of dense_rank() is not guaranteed in your code, I'm not sure that this is feasible in a scalable way.
See this for more information about reliably sorted results: how does SELECT TOP works when no order by is specified?
you need one row per BID i.e the latest one, But you have not specified the logic of the last row. Usually, last row is the most recent added one and so there is usually a timestamp that can be used to pick the latest row where there are duplicates.
The code below uses the Bcode as a part of the order by calause, that means it will automatically pick the row that has the lowest alphabet order, which not be the row that you expect unless thats how you define the most recent row. You would in general need to play with the order by clause based on your needs but the timestamp makes most sense
row_number() generates the values 1-n based on the partition by, incase there is a tie, and you need both rows, then you need to use the dense_rank instead. Based on your needs you can adjust that
with main as (
select
concat(Bid, cid) as key,
row_number() over(partition by concat(Bid, cid) order by Bcode) as rank_
from <table_name>
)
select * from main where rank_ = 1
I have a Table Valued Function qlikview_verlauf. I want to return a table with id, Date and Path.
Identity(seed, increment)
The ID is an autoincrement value. I want to start this autoincrement (seed) from the max(id)+1 from another table named Testfortschritt.
I have tried the following, but it doesn't work. The Error Message is incorrect Syntax.
Create FUNCTION [dbo].[qlikview_verlauf](#param INT)
RETURNS #qlikview_verlauf table (
ID INT IDENTITY((Select max(id) from Testfortschritt),1)
,[Date] date NOT NULL
,[Path] varchar(600) NOT NULL
)
I would set aside the IDENTITY of your ID column and rather use ROW_NUMBER to generate the ID in your SELECT statement.
For example:
SELECT
(SELECT MAX(id) FROM Testfortschritt) +
ROW_NUMBER OVER(ORDER BY (SELECT 1)) AS ID,
[Date],
[Path]
FROM <YourTable>
Since I don't know how your exact statement looks like, I used ORDER BY (SELECT 1) which lets SQL Server decide in which order records are numbered. If you have a specific order just replace (SELECT 1) with your order columns.
Since the ID should be uniqe I also omitted the PARTITION BY clause which isn't needed in your scenario.
More about ROW_NUMBER can be found here
I need to get the latest price of an item (as part of a larger select statement) and I can't quite figure it out.
Table:
ITEMID DATE SALEPRICE
1 1/1/2014 10
1 2/2/2014 20
2 3/3/2014 15
2 4/4/2014 13
I need the output of the select to be '20' when looking for item 1 and '13' when looking for item 2 as per the above example.
I am using Oracle SQL
The most readable/understandable SQL (in my opinion) would be this:
select salesprice from `table` t
where t.date =
(
select max(date) from `table` t2 where t2.itemid = t.itemid
)
and t.itemid = 1 -- change item id here;
assuming your table's name is table and you only have one price per day and item (else the where condition would match more than one row per item). Alternatively, the subselect could be written as a self-join (should not make a difference in performance).
I'm not sure about the OVER/PARTITION used by the other answers. Maybe they could be optimized to better performance depending on the DBMS.
Maybe something like this:
Test data
DECLARE #tbl TABLE(ITEMID int,DATE DATETIME,SALEPRICE INT)
INSERT INTO #tbl
VALUES
(1,'1/1/2014',10),
(1,'2/2/2014',20),
(2,'3/3/2014',15),
(2,'4/4/2014',13)
Query
;WITH CTE
AS
(
SELECT
ROW_NUMBER() OVER(PARTITION BY ITEMID ORDER BY [DATE] DESC) AS rowNbr,
tbl.*
FROM
#tbl AS tbl
)
SELECT
*
FROM
CTE
WHERE CTE.rowNbr=1
Try this!
In sql-server may also work in Oracle sql
select * from
(
select *,rn=row_number()over(partition by ITEMID order by DATE desc) from table
)x
where x.rn=1
You need Row_number() to allocate a number to all records which is partition by ITEMID so each group will get a RN,then as you are ordering by date desc to get Latest record
SEE DEMO
I have been trying to find some info on how to select a non-aggregate column that is not contained in the Group By statement in SQL, but nothing I've found so far seems to answer my question. I have a table with three columns that I want from it. One is a create date, one is a ID that groups the records by a particular Claim ID, and the final is the PK. I want to find the record that has the max creation date in each group of claim IDs. I am selecting the MAX(creation date), and Claim ID (cpe.fmgcms_cpeclaimid), and grouping by the Claim ID. But I need the PK from these records (cpe.fmgcms_claimid), and if I try to add it to my select clause, I get an error. And I can't add it to my group by clause because then it will throw off my intended grouping. Does anyone know any workarounds for this? Here is a sample of my code:
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
This is the result I'd like to get:
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid, cpe.fmgcms_claimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
The columns in the result set of a select query with group by clause must be:
an expression used as one of the group by criteria , or ...
an aggregate function , or ...
a literal value
So, you can't do what you want to do in a single, simple query. The first thing to do is state your problem statement in a clear way, something like:
I want to find the individual claim row bearing the most recent
creation date within each group in my claims table
Given
create table dbo.some_claims_table
(
claim_id int not null ,
group_id int not null ,
date_created datetime not null ,
constraint some_table_PK primary key ( claim_id ) ,
constraint some_table_AK01 unique ( group_id , claim_id ) ,
constraint some_Table_AK02 unique ( group_id , date_created ) ,
)
The first thing to do is identify the most recent creation date for each group:
select group_id ,
date_created = max( date_created )
from dbo.claims_table
group by group_id
That gives you the selection criteria you need (1 row per group, with 2 columns: group_id and the highwater created date) to fullfill the 1st part of the requirement (selecting the individual row from each group. That needs to be a virtual table in your final select query:
select *
from dbo.claims_table t
join ( select group_id ,
date_created = max( date_created )
from dbo.claims_table
group by group_id
) x on x.group_id = t.group_id
and x.date_created = t.date_created
If the table is not unique by date_created within group_id (AK02), you you can get duplicate rows for a given group.
You can do this with PARTITION and RANK:
select * from
(
select MyPK, fmgcms_cpeclaimid, createdon,
Rank() over (Partition BY fmgcms_cpeclaimid order by createdon DESC) as Rank
from Filteredfmgcms_claimpaymentestimate
where createdon < 'reportstartdate'
) tmp
where Rank = 1
The direct answer is that you can't. You must select either an aggregate or something that you are grouping by.
So, you need an alternative approach.
1). Take you current query and join the base data back on it
SELECT
cpe.*
FROM
Filteredfmgcms_claimpaymentestimate cpe
INNER JOIN
(yourQuery) AS lookup
ON lookup.MaxData = cpe.createdOn
AND lookup.fmgcms_cpeclaimid = cpe.fmgcms_cpeclaimid
2). Use a CTE to do it all in one go...
WITH
sequenced_data AS
(
SELECT
*,
ROW_NUMBER() OVER (PARITION BY fmgcms_cpeclaimid ORDER BY CreatedOn DESC) AS sequence_id
FROM
Filteredfmgcms_claimpaymentestimate
WHERE
createdon < 'reportstartdate'
)
SELECT
*
FROM
sequenced_data
WHERE
sequence_id = 1
NOTE: Using ROW_NUMBER() will ensure just one record per fmgcms_cpeclaimid. Even if multiple records are tied with the exact same createdon value. If you can have ties, and want all records with the same createdon value, use RANK() instead.
You can join the table on itself to get the PK:
Select cpe1.PK, cpe2.MaxDate, cpe1.fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate cpe1
INNER JOIN
(
select MAX(createdon) As MaxDate, fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate
group by fmgcms_cpeclaimid
) cpe2
on cpe1.fmgcms_cpeclaimid = cpe2.fmgcms_cpeclaimid
and cpe1.createdon = cpe2.MaxDate
where cpe1.createdon < 'reportstartdate'
Thing I like to do is to wrap addition columns in aggregate function, like max().
It works very good when you don't expect duplicate values.
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid, MAX(cpe.fmgcms_claimid) As fmgcms_claimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
What you are asking, Sir, is as the answer of RedFilter.
This answer as well helps in understanding why group by is somehow a simpler version or partition over:
SQL Server: Difference between PARTITION BY and GROUP BY
since it changes the way the returned value is calculated and therefore you could (somehow) return columns group by can not return.
You can use as below,
Select X.a, X.b, Y.c from (
Select X.a as a, sum (b) as sum_b from name_table X
group by X.a)X
left join from name_table Y on Y.a = X.a
Example;
CREATE TABLE #products (
product_name VARCHAR(MAX),
code varchar(3),
list_price [numeric](8, 2) NOT NULL
);
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
INSERT INTO #products VALUES ('Dinding', 'ADE', 2000)
INSERT INTO #products VALUES ('Kaca', 'AKB', 2000)
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
--SELECT * FROM #products
SELECT distinct x.code, x.SUM_PRICE, product_name FROM (SELECT code, SUM(list_price) as SUM_PRICE From #products
group by code)x
left join #products y on y.code=x.code
DROP TABLE #products
I have a Sql Server 2005 table with following data:
idHearing is the primary key (identity), idCase is a foreign key that may duplicate. StartDate and StartTime specify the date and time of the event - both fields are of DateTime type (for whatever reason these are separate fields). All StartDate data has a time of 12:00:00. All StartTime data has a date of 1/1/1900. IsScheduled and IsOnCalendar are bit fields.
My challenge is to select the latest (in terms of Date/Time) hearing for each idCase. If the StartDate/StartTime are identical (as is in the rows 1 and 2), preference should be given to a row which has IsScheduled and/or IsCalendar on. If those are columns are same as well, then it does not matter which row gets returned.
To make this more complicated, I must do it all in single SELECT statement (because it must be in a view) and I have to return all the columns that you see below.
I've tried several ways, but my SQL-FU isn't strong. Any ideas?
Use:
CREATE VIEW vw_summary AS
WITH example AS (
SELECT t.idcase,
t.startdate,
t.startime,
t.isscheduled,
t.isoncalendar,
ROW_NUMBER() OVER (PARTITION BY t.idcase ORDER BY t.startdate DESC,
t.starttime DESC,
t.isscheduled DESC,
t.isoncalendar DESC) AS rank
FROM TABLE t)
SELECT e.*
FROM example e
WHERE e.rank = 1
Check & see - might tweak the ORDER BY on the ROW_NUMBER...
Pretty much the same as omg ponies answer. Row_number is your friend. I'm not entirely sure the bit fields are treated as you want, but you get the idea. As ever, it's always best to be explicit with the fields you are selecting, but I'm lazy.
create table #table
(
idHearing int,
idCase int,
startDate datetime,
starttime datetime,
isscheduled bit,
isoncalendar bit
);
insert into #table values(1,1,'8/2/2010','3:30:00 PM',1,1)
insert into #table values(2,1,'8/2/2010','3:30:00 PM',1,0)
insert into #table values(3,2,'8/3/2010','5:30:00 PM',1,1)
insert into #table values(4,2,'8/4/2010','9:30:00 PM',1,1)
insert into #table values(5,3,'8/2/2010','3:00:00 PM',1,1)
select * from
(
select
row_number()
over
(partition by idcase order by
startdate desc,
starttime desc,
isscheduled desc,
isoncalendar desc
) idCasePosition,
*
from #table
) x
where idCasePosition=1
drop table #table