Select all rows that matches any from other table - sql

Question

Get all Users from first table that have any word matching in another table;
I have Users table that contain, among others, column with FullName, that column is Full Text Search Indexed. Sometimes first "word" is name, sometimes first "word" is surname from the FullName column;
Like John Smith or Smith John.
And another table that have just local firstname.
I want to get all Users that have matching local name.
Users Table:
John Smith
Rebecca Mark
Maria Anna
Lance Maria
Emilia Clark
Snow John
Natalie Butler
Name Table:
Maria
Smith
Result of Query:
John Smith
Maria Anna
Lance Maria
Snow John
I can do only single Name with Contains function.
SELECT * FROM Users WHERE CONTAINS(FullName, 'John');
But I need it for each row in Name Table.
Every row from FullName contains any of Name Table... But in SQL Query.

Answer 1

To avoid a case where you are search for 'Maria' and the matching name is 'Marianne', check for 2 conditions: (1) the name is at the start or (2) at the end of FullName:
(1):
SELECT u.*
FROM Users u INNER JOIN Name n
ON
u.FullName LIKE concat(n.name, ' %')
OR
u.FullName LIKE concat('% ', n.name)
or (2):
SELECT u.*
FROM Users u INNER JOIN Name n
ON
concat(' ', u.FullName, ' ') LIKE concat('% ', n.name, ' %')

Answer 2

use join and like for matching
select u.* from table_users u join table_name b on
u.users like concat('%',b.name,'%')

Answer 3

You can use exists for this:
select u.*
from users u
where exists (select 1
from nametable n
where u.fullname like '%' + n.name + '%'
);
If you want to avoid partial matches on names, then take the delimiters into account:
where exists (select 1
from nametable n
where ' ' + u.fullname + ' ' like '% ' + n.name + ' %'
);