Related
i want to show the salaries less than the largest number in the table
create table instructor(
ID number not null ,
name varchar(20) ,
dept_name varchar(25),
salary number,
primary key (ID)
);
insert into instructor values('10101', 'sirinvasan' , 'comp csi' , '65000');
insert into instructor values('12121', 'wu' , 'finance' , '90000');
insert into instructor values('15151', 'mozart' , 'music' , '40000');
insert into instructor values('22222', 'einstein' , 'physics' , '95000');
insert into instructor values('32343', 'el said' , 'history' , '60000');
i tried using
select distinct T.salary
from instructor as T , instructor as S
where T.salary < S.salary
but it gives me this error ORA-00933: SQL command not properly ended
You can do it in a single table scan using analytic functions:
SELECT salary
FROM (
SELECT DISTINCT
salary,
DENSE_RANK() OVER (ORDER BY salary DESC) AS rnk
FROM instructor
)
WHERE rnk > 1
Or, if you want to use a sub-query:
SELECT DISTINCT
salary
FROM instructor
WHERE salary NOT IN (SELECT MAX(salary) FROM instructor);
db<>fiddle here
Try this
Select salary from table where salary < (Select
max(salary) from table)
There are many ways to do this. Here is another one.
with a as (
select salary
, max(salary) over () as maxsalary
from instructor
)
select distinct salary
from a
where salary < maxsalary
In the name of completeness, here is another viable answer:
SELECT DISTINCT i.salary
FROM instructor i
ORDER BY i.salary DESC
OFFSET 1 ROW;
I actually like the simplicity of this one. It is just ordering the query and skipping the first row. No analytic functions necessary.
DBFiddle Here: (LINK)
I have a requirement to find emplid having data difference in same table. Table consist of 50-60 columns.. I need to check if any column has change in data from previous row, emplidshould get pick up as well as if any new employee get add that also needs to pick up..
I have created a basic query and it is working but need some way to achieve same purpose as I do not want to write every column name.
My query:
select
emplid
from
ps_custom_tbl t, ps_custom_tbl prev_t
where
prev_t.emplid = t.emplid
and t.effdt = (select max effdt from ps_custom_tbl t2
where t2.emplid = t.emplid)
and prev_t.effdt = (select max(effdt) from ps_custom_tbl prev_t2
where emplid = prev_t.emplid and effdt < t.effdt)
and (t.first_name prev_t.first_name Or t.last_name prev_t.last_name …. 50 columns);
Can you please suggest another way to achieve same thing?
You can use MINUS.
if no_data then both are the same, if there are some records - mean that there is a difference between
create table emp as select * from hr.employees;
insert into emp select employee_id+1000, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id,
decode(department_id ,30,70, department_id)
from hr.employees;
select first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id
from emp where employee_id <= 1000
minus
select first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id
from emp where employee_id > 1000;
But you have to list all columns, because if you have eg different dates or ids - they will be compared too. But it's easier to list columns in SELECT clause then write for everyone WHERE condition.
Maybe it will help.
-- or if different tables and want to compare all cols simply do
drop table emp;
create table emp as select * from hr.employees;
create table emp2 as
select employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id,
decode(department_id ,30,70, department_id) department_id
from hr.employees;
select * from emp
minus
select * from emp2;
---- ADD DATE CRITERIA
-- yes, you can add date criteria and using analytical functions check which
-- is newer and which is
older and then compare one to another. like below:
drop table emp;
create table emp as select * from hr.employees;
insert into emp
select
employee_id,
first_name,
last_name,
email,
phone_number,
hire_date+1,
job_id,
salary,
commission_pct,
manager_id,
decode(department_id ,30,70, department_id)
from hr.employees;
with data as --- thanks to WITH you retrieve data only once
(select employee_id, first_name, last_name, email, phone_number,
hire_date,
row_number() over(partition by employee_id order by hire_date desc) rn -- distinguish newer and older record,
job_id, salary, commission_pct, manager_id, department_id
from emp)
select employee_id, first_name, last_name, email, phone_number, department_id from data where rn = 1
MIUNUS--- find the differences
select employee_id, first_name, last_name, email, phone_number, department_id from data where rn = 2;
You will have to write all columns in some sense no matter what you do.
In terms of comparing current and previous, you might find this easier
select
col1,
col2,
...
lag(col1) over ( partition by empid order by effdt ) as prev_col1,
lag(col2) over ( partition by empid order by effdt ) as prev_col2
...
and then you comparison will be along the lines of
select *
from ( <query above >
where
decode(col1,prev_col1,0,1) = 1 or
decode(col2,prev_col2,0,1) = 1 or
...
The use of DECODE in this way handles the issues of nulls.
My requirement is to send out data to managers, they change any/all/none of the data in the columns, and send back to me. I then have to identify each column that has a difference from what I sent, and mark those columns as changed for a central office reviewer to visually scan and approve/deny the changes for integration back into the central data set.
This solution may not fit your needs of course, but a template structure is offered here that you can augment to meet your needs no matter the number of columns. In the case of your question, 50-60 columns will make this SQL query huge, but I've written heinously long queries in the past with great success. Add columns a few at a time rather than all wholesale according to this template and see if they work along the way.
You could easily write pl/sql to write this query for you for the tables in question.
This would get very cumbersome if you had to compare columns from 3 or more tables or bi-directional changes. I only care about single direction changes. Did the person change my original row columns or not. If so, what columns did they change, and what was my before value and what is their after value, and show me nothing else please.
In other words, only show me rows with columns that have changes with their before values and nothing else.
create table thing1 (id number, firstname varchar2(10), lastname varchar2(10));
create table thing2 (id number, firstname varchar2(10), lastname varchar2(10));
insert into thing1 values (1,'Buddy', 'Slacker');
insert into thing2 values (1,'Buddy', 'Slacker');
insert into thing1 values (2,'Mary', 'Slacker');
insert into thing2 values (2,'Mary', 'Slacke');
insert into thing1 values (3,'Timmy', 'Slacker');
insert into thing2 values (3,'Timm', 'Slacker');
insert into thing1 values (4,'Missy', 'Slacker');
insert into thing2 values (4,'Missy', 'Slacker');
commit;
Un-comment commented select * queries one at a time after each data set to understand what is in each data set at each stage of the refinement process.
with rowdifferences as
(
select
id
,firstname
,lastname
from thing2
minus
select
id
,firstname
,lastname
from thing1
)
--select * from rowdifferences
,thing1matches as
(
select
t1.id
,t1.firstname
,t1.lastname
from thing1 t1
join rowdifferences rd on t1.id = rd.id
)
--select * from thing1matches
, col1differences as
(
select
id
,firstname
from rowdifferences
minus
select
id
,firstname
from thing1matches
)
--select * from col1differences
, col2differences as
(
select
id
,lastname
from rowdifferences
minus
select
id
,lastname
from thing1matches
)
--select * from col2differences
,truedifferences as
(
select
case when c1.id is not null then c1.id
when c2.id is not null then c2.id
end id
,c1.firstname
,c2.lastname
from col1differences c1
full join col2differences c2 on c1.id = c2.id
)
--select * from truedifferences
select
t1m.id
,case when td.firstname is not null then t1m.firstname end beforefirstname
,td.firstname afterfirstname
,case when td.lastname is not null then t1m.lastname end beforelastname
,td.lastname afterlastname
from thing1matches t1m
join truedifferences td on t1m.id = td.id
;
The following is the prompt I need to answer:
List the number of customers for each employee. Include employee's name and number of
customers labeled appropriately, listing the employee with the most customers first.
The following is my EMPLOYEES table:
create table EMPLOYEES
(EmpID char(4) unique Not null,
Ename varchar(10),
Job varchar(9),
MGR char(4),
Hiredate date,
Salary decimal(7,2),
Comm decimal(7,2),
DeptNo char(2) not null,
Primary key(EmpID),
Foreign key(DeptNo) REFERENCES DEPARTMENTS(DeptNo));
insert into EMPLOYEES values (7839,'King','President',null,'17-Nov-11',5000,null,10);
insert into EMPLOYEES values (7698,'Blake','Manager',7839,'01-May-11',2850,null,30);
insert into EMPLOYEES values (7782,'Clark','Manager',7839,'02-Jun-11',2450,null,10);
insert into EMPLOYEES values (7566,'Jones','Manager',7839,'02-Apr-11',2975,null,20);
insert into EMPLOYEES values (7654,'Martin','Salesman',7698,'28-Feb-12',1250,1400,30);
insert into EMPLOYEES values (7499,'Allen','Salesman',7698,'20-Feb-11',1600,300,30);
insert into EMPLOYEES values (7844,'Turner','Salesman',7698,'08-Sep-11',1500,0,30);
insert into EMPLOYEES values (7900,'James','Clerk',7698,'22-Feb-12',950,null,30);
insert into EMPLOYEES values (7521,'Ward','Salesman',7698,'22-Feb-12',1250,500,30);
insert into EMPLOYEES values (7902,'Ford','Analyst',7566,'03-Dec-11',3000,null,20);
insert into EMPLOYEES values (7369,'Smith','Clerk',7902,'17-Dec-10',800,null,20);
insert into EMPLOYEES values (7788,'Scott','Analyst',7566,'09-Dec-12',3000,null,20);
insert into EMPLOYEES values (7876,'Adams','Clerk',7788,'12-Jan-10',1100,null,20);
insert into EMPLOYEES values (7934,'Miller','Clerk',7782,'23-Jan-12',1300,null,10);
The following is my CUSTOMERS table:
create table CUSTOMERS
(CustID char(6) unique Not null,
Name varchar(45),
Address varchar(40),
City varchar(30),
State varchar(2),
Zip varchar(9),
AreaCode char(3),
Phone varchar (9),
RepID char(4) not null,
CreditLimit decimal(9,2),
Primary key(CustID),
Foreign key(RepID) References EMPLOYEES(EmpID));
insert into CUSTOMERS values (100,'Jocksports','345 Viewridge','Belmont','CA','96711',415,'598-6609',7844,5000);
insert into CUSTOMERS values (101,'TKB Sport Shop','490 Boli Rd.','Redwood City','CA','94061',415,'368-1223',7521,10000);
insert into CUSTOMERS values (102,'Vollyrite','9722 Hamilton','Burlingame','CA','95133',415,'644-3341',7654,7000);
insert into CUSTOMERS values (103,'Just Tennis','Hillview Mall','Burlingame','CA','97544',415,'677-9312',7521,3000);
insert into CUSTOMERS values (104,'Every Mountain','574 Surry Rd.','Cupertino','CA','93301',408,'996-2323',7499,10000);
insert into CUSTOMERS values (105,'K + T Sports','3476 El Paseo','Santa Clara','CA','91003',408,'376-9966',7844,5000);
insert into CUSTOMERS values (106,'Shape Up','908 Sequoia','Palo Alto','CA','94301',415,'364-9777',7521,6000);
insert into CUSTOMERS values (107,'Womens Sports','Valco Village','Sunnyvale','CA','93301',408,'967-4398',7499,10000);
insert into CUSTOMERS values (108,'North Woods Fitness Supply Center','98 Lone Pine Way','Hibbing','MN','55649',612,'566-9123',7844,8000);
The following is my query:
select ename, empId
from EMPLOYEES
where EmpID in
(select count(repid) as NumberOfCustomers
from CUSTOMERS
group by RepID);
Why is my query not working?
I know I want to match the empid from EMPLOYEES to the repID in CUSTOMERS and then COUNT how many times the rep ID shows up in CUSTOMERS. The only reason I need the EMPLOYEES table is to out put Ename. Im confused about the syntaxt I need to use because I need to output the count of RepID in the CUSTOMERS table
You can also use Common Table Expression if you are using SQL Server 2005 and above.
;WITH CTE
AS
(
SELECT RepID, COUNT(*) AS CNT
FROM CUSTOMERS
GROUP BY REPID
)
SELECT E.Ename, E.EmpID, ISNULL(C.CNT, 0)
FROM EMPLOYEES E
LEFT OUTER JOIN CTE C ON C.RepID = E.EmpID
DEMO
SELECT *
FROM employees e
CROSS APPLY
(
SELECT COUNT(*)
FROM customers c
WHERE c.repId = e.empId
) cc (cnt)
ORDER BY
cnt DESC
See this on SQLFiddle
The same with a subquery:
SELECT *,
(
SELECT COUNT(*)
FROM customers c
WHERE c.repId = e.empId
) cnt
FROM employees e
ORDER BY
cnt DESC
Your inner query only has a count(repid), which is a count, not the actual EmployeeID that your outer query requires in where EmpID in (xxx). Not sure why're you want a count in your inner query, because you'll lose it in the final result, but this should work:
select ename, empId
from EMPLOYEES
where EmpID in (
select repID
from CUSTOMERS);
What about this? or did i misunderstand
SELECT ename, count(*) as NumCustomers
FROM Customers INNER JOIN
Employees ON customers.repid = employees.empid GROUP BY repid,ename
ORDER BY numCustomers DESC
There are two tables that would be relevant in this. Workon and Employee. The contents of these two tables are EMPID NAME SALARY DID (department ID) for employee and PID EMPID HOURS from work on. The SQL I have written is
select e.name, w.pid
from employee e, workon w
where e.empid = w.empid
group by e.name, w.pid, w.empid
having count (e.name) > 1
order by w.pid
I have been trying to figure out why this code will not give me employees that work on more than one project. Please help me figure out what I am doing wrong.
your group by was returning one row per employee per project, by definition this could never have more than 1 row
below sql should work
WARNING: i am not sure how this will affect performance of server use at your own risk
following will return 1 row per employee per workon but be limited to employees with more than 1 workon record (so if employee has 5 workon records, you will get 5 rows with same e.name and then 5 different w.pid values)
select e.name, w.pid
from employee e, workon w
where e.empid = w.empid
and e.empid in (
select w.empid
from workon w -- there was a typo here originally
group by 1
having count (*) > 1
)
order by e.name, w.pid
SELECT E.NAME, W.PID
from employee e inner join workon w on e.empid = w.empid
where e.empid in (select EMPID from workon GROUP BY EMPID HAVING COUNT(EMPID) > 1)
The subquery is counting all records with that empid associated to it with more than 1 project, and the main Query is checking to see if the empid from empid table is in the subquery's results.
You can try this below query.
Here in a variable all distinct count department has been taken from department master table. After that only those employee has been selected where count match with distinct linked department count in relation table.
CREATE TABLE employees
(
employee_id int NOT NULL CONSTRAINT pk_employees PRIMARY KEY,
employee_name nvarchar(128) NOT NULL CONSTRAINT uk_employees_employee_name UNIQUE
);
CREATE TABLE departments
(
department_id int NOT NULL PRIMARY KEY,
department_name nvarchar(128) NOT NULL CONSTRAINT uk_departments_department_name UNIQUE
);
CREATE TABLE department_employees
(
department_id int NOT NULL CONSTRAINT fk_department_employees_departments REFERENCES departments(department_id),
employee_id int NOT NULL CONSTRAINT fk_departement_employees_employees REFERENCES employees(employee_id),
CONSTRAINT pk_deparment_employees PRIMARY KEY (department_id, employee_id)
)
INSERT INTO employees
VALUES (1, 'John Doe'), (2, 'Jane Doe'), (3, 'William Doe'), (4, 'Margaret Doe')
INSERT INTO departments
VALUES (1, 'Accounting'), (2, 'Humman Resources'), (3, 'Marketing')
INSERT INTO department_employees
VALUES
(1, 1), (2, 1), (3, 1),
(2, 2), (2, 3),
(3, 3), (3, 4)
declare #distinctDeptCount int
SET #DistinctDeptCount = (SELECT Count(Distinct department_id) FROM departments)
--SELECT #DistinctDeptCount
SELECT Distinct employees.employee_id, employee_name
from employees
where employees.employee_id in (
select employee_id from department_employees GROUP BY employee_id HAVING COUNT(department_id) >= #distinctDeptCount
)
Here is the live demo Emp. with all Department
The output is as shown below
employee_id employee_name
1 John Doe
I have a table EmpDetails:
DeptID EmpName Salary
Engg Sam 1000
Engg Smith 2000
HR Denis 1500
HR Danny 3000
IT David 2000
IT John 3000
I need to make a query that find the highest salary for each department.
SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID
The above query is the accepted answer but it will not work for the following scenario. Let's say we have to find the employees with the highest salary in each department for the below table.
DeptID
EmpName
Salary
Engg
Sam
1000
Engg
Smith
2000
Engg
Tom
2000
HR
Denis
1500
HR
Danny
3000
IT
David
2000
IT
John
3000
Notice that Smith and Tom belong to the Engg department and both have the same salary, which is the highest in the Engg department. Hence the query "SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID" will not work since MAX() returns a single value. The below query will work.
SELECT DeptID, EmpName, Salary FROM EmpDetails
WHERE (DeptID,Salary) IN (SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID)
Output will be
DeptID
EmpName
Salary
Engg
Smith
2000
Engg
Tom
2000
HR
Danny
3000
IT
John
3000
Assuming SQL Server 2005+
WITH cteRowNum AS (
SELECT DeptID, EmpName, Salary,
DENSE_RANK() OVER(PARTITION BY DeptID ORDER BY Salary DESC) AS RowNum
FROM EmpDetails
)
SELECT DeptID, EmpName, Salary
FROM cteRowNum
WHERE RowNum = 1;
If you want to show other parameters too along with DeptId and Salary like EmpName, EmpId
SELECT
EmpID
, Name,
, Salary
, DeptId
FROM Employee
where
(DeptId,Salary)
in
(select DeptId, max(salary) from Employee group by DeptId)
SELECT empName,empDept,EmpSalary
FROM Employee
WHERE empSalary IN
(SELECT max(empSalary) AS salary
From Employee
GROUP BY EmpDept)
Select empname,empid,Sal,DeptName from
(Select e.empname,e.empid,Max(S.Salary) Sal,D.DeptName, ROW_NUMBER() Over(partition by D.DeptName order by s.salary desc) Rownum
from emp e inner join Sal S
on e.empid=s.empid
inner join Dept d on e.Deptid=d.Deptid
group by e.empname,e.empid,D.DeptName,s.Salary
) x where Rownum = 1
This will work if the department, salary and employee name are in the same table.
select ed.emp_name, ed.salary, ed.dept from
(select max(salary) maxSal, dept from emp_dept group by dept) maxsaldept
inner join emp_dept ed
on ed.dept = maxsaldept.dept and ed.salary = maxsaldept.maxSal
Is there any better solution than this?
ermn, something like:
select
d.DeptID,
max(e.Salary)
from
department d
inner join employees e on d.DeptID = e.DeptID
group by
d.DeptID
WITH cteRowNum AS (
SELECT DeptID, EmpName, Salary,
ROW_NUMBER() OVER(PARTITION BY DeptID ORDER BY Salary DESC) AS RowNum
FROM EmpDetails
)
SELECT DeptID, EmpName, Salary,Rownum
FROM cteRowNum
WHERE RowNum in(1,2);
SELECT Employee_ID
, First_name
, last_name
, department_id
, Salary
FROM (SELECT Employee_ID
, First_name
, last_name
, department_id
, Salary
, MAX(salary) OVER (PARTITION BY department_id) dept_max_sal
FROM EMPLOYEES) AS Emp
WHERE salary = dept_max_sal;
Use following command;
SELECT A.*
FROM #EmpDetails A
INNER JOIN ( SELECT DeptID ,
MAX(salary) AS salary
FROM #EmpDetails
GROUP BY DeptID
) B ON A.DeptID = B.DeptID
AND A.salary = B.salary
ORDER BY A.DeptID
SELECT DeptID, MAX(Salary)
FROM EmpDetails
GROUP BY DeptID
This query will work fine, but the moment if you want to fetch some others details related to the employee having the highest salary will contradict.
You can use :
SELECT DepatID, a , b, c
FROM EmpDetails
WHERE Salary IN (
SELECT max(Salary)
FROM EmpDetails
GROUP BY DeptID
);
if you will use the previous query it will only reflects the records of the min val except the salary as you have used the max function.
SELECT
DeptID,
Salary
FROM
EmpDetails
GROUP BY
DeptID
ORDER BY
Salary desc
***
> /*highest salary by each dept*/
***
select d.Dept_Name,max(e.salary)
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
group by d.Dept_Name
select distinct e.d_id,d.Dept_Name
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
select e.salary,d.Dept_Name,d.Dept_Id
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
/////simplest query for max salary dept_wise////
Use the below quesry:
select employee_name,salary,department_id from emp where salary in(select max(salary) from emp group by department_id);
select empno
from EMP e
where salary=(select max(sal)
from EMP w
where groupby w.deptno having e.deptno=w.deptno)
I hope it will work...
Use correlated subquery:
SELECT DeptID, EmpName, Salary
FROM EmpDetails a
WHERE Salary = (SELECT MAX(Salary)
FROM EmpDetails b
WHERE a.DeptID = b.DeptID)
This is the best possible solution for ORACLE:
Select * from (select customerid, city, freight,
row_number() over (partition by customerid order by freight desc) Row_Number from
(select orders.orderId, customers.CUSTOMERID, customers.city, orders.FREIGHT from orders inner join customers on orders.customerid = customers.customerid where customers.country='Germany' order by customers.customerid, orders.freight desc)
order by customerid, freight desc) where Row_Number<=2;
Notice here I have used partition by clause for marking row number, this is majorly because we need to partition the records grouping them according to customer id. I have used two inner queries here. The inner most query is to give a view which is sorted according to customer ID and decreasing order of cost. Now from that we need to obtain always top two records so firstly we need to name them and then we need to filter them according to rownum. Second level query is to mark rownum according to customer ID. And final query will filter the result according to rownum. For every partition.
select deptid, empname, salary from
(Select deptid, empname,salary,
rank() Over(Partition by deptid order by salary desc)as rank from
EmpDetails) emp
where emp.rank = 1
First ranks each employee by salary in descending order having highest
rank 1 and then selects only deptid, empname, salary. You can do this for
all Nth member of the group.
SELECT empname
FROM empdetails
WHERE salary IN(SELECT deptid max(salary) AS salary
FROM empdetails
group by deptid)
select a.*
from EmpDetails a
inner join
(
select DeptID,max(Salary) as Salary
from EmpDetails group by DeptID
)b
on a.DeptID = b.DeptID and a.Salary = b.Salary
Here is a way to get maximum values and names on any version of SQL.
Test Data:
CREATE TABLE EmpDetails(DeptID VARCHAR(10), EmpName VARCHAR(10), Salary DECIMAL(8,2))
INSERT INTO EmpDetails VALUES('Engg','Sam',1000)
INSERT INTO EmpDetails VALUES('Engg','Smith',2000)
INSERT INTO EmpDetails VALUES('HR','Denis',1500)
INSERT INTO EmpDetails VALUES('HR','Danny',3000)
INSERT INTO EmpDetails VALUES('IT','David',2000)
INSERT INTO EmpDetails VALUES('IT','John',3000)
Example:
SELECT ed.DeptID
,ed.EmpName
,ed.Salary
FROM (SELECT DeptID, MAX(Salary) MaxSal
FROM EmpDetails
GROUP BY DeptID)AS empmaxsal
INNER JOIN EmpDetails ed
ON empmaxsal.DeptID = ed.DeptID
AND empmaxsal.MaxSal = ed.Salary
Not the most elegant, but it works.
SELECT D.DeptID, E.EmpName, E.Salary
FROM Employee E
INNER JOIN Department D ON D.DeptId = E.DeptId
WHERE E.Salary IN (SELECT MAX(Salary) FROM Employee);
select * from (
select a.* from EmpDetails a
right join (select DeptID,max(salary) as Salary from EmpDetails group by DeptID) b
on b.DeptID=a.DeptID and b.salary=a.salary ) as c group by c.DeptID;
The below query will display employee name with their respective department name in which that particular employee name is having highest salary.
with T as
(select empname, employee.deptno, salary
from employee
where salary in (select max(salary)
from employee
group by deptno))
select empname, deptname, salary
from T, department
where T.deptno=department.deptno;
I executed the above query successfully on Oracle database.
If you just want to get the highest salary from that table, by department:
SELECT MAX(Salary) FROM TableName GROUP BY DeptID
IF you want Department and highest salary, use
SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID
if you want more columns in employee and department, use
select Department.Name , emp.Name, emp.Salary from Employee emp
inner join (select DeptID, max(salary) [salary] from employee group by DeptID) b
on emp.DeptID = b.DeptID and b.salary = emp.Salary
inner join Department on emp.DeptID = Department.id
order by Department.Name
if use salary in (select max(salary...)) like this, one person have same salary in another department then it will fail.
The below listed query will list highest salary in each department.
select deptname, max(salary) from department, employee where
department.deptno=employee.deptno group by deptname;
I executed this query successfully on Oracle database.
with ctesal as (
select DepartmentId , Name , Salary, ROW_Number() OVER (partition by DepartmentId
order by Salary desc) as RowNum
from dbo.Employee
)
select DepartmentId , Name , Salary , RowNum from ctesal where RowNum =2;
This is applicable to SQL server.
ROW_Number is a inbuilt function in SQL server .It gives count starting from 1 based on partition by and order by clause. At the end, We can write where condition based on our requirements.
I have like 2 approaches using one with Rank and the other with ROW_NUMBER
This is my sample data
Age Name Gender Salary
----------- -------------------------------------------------- ---------- -----------
1 Mark Male 5000
2 John Male 4500
3 Pavan Male 5000
4 Pam Female 5500
5 Sara Female 4000
6 Aradhya Female 3500
7 Tom Male 5500
8 Mary Female 5000
9 Ben Male 6500
10 Jodi Female 7000
11 Tom Male 5500
12 Ron Male 5000
13 Ramani Female 7000
So here is my first query to find max salary and the person with that max salary for each Gender
with CTE as(
select RANK() over(partition by Gender Order by Salary desc) as [Rank],* from employees)
select * from CTE where [Rank]=1
Rank Age Name Gender Salary
-------------------- ----------- -------------------------------------------------- ---------- -----------
1 10 Jodi Female 7000
1 13 Ramani Female 7000
1 9 Ben Male 6500
So in this case, we can see there is a tie between these 2 female employees "Jodi" and "Ramani". In that case, As a tie-breaker I want to make use of Age as a deciding factor and person with more age is supposed to be displayed
with CTE as(
select RANK() over(partition by Gender Order by Salary desc,age desc) as [Rank],* from employees)
select * from CTE where [Rank]=1
Rank Age Name Gender Salary
-------------------- ----------- -------------------------------------------------- ---------- -----------
1 13 Ramani Female 7000
1 9 Ben Male 6500
Usually, in this case for finding the highest salary, it doesn't make much difference even if
Rank, Dense_Rank, or Row_Number() are used. But they have some impact in other cases.
Thank you #JoeStefanelli for his answer (https://stackoverflow.com/a/8477083/4691279). He provided SQL Server 2005+ version and I used the same to create the Oracle version:
WITH cteRowNum(dep_id, emp_id, Salary, RowNums) AS (
SELECT dep_id, emp_id, Salary,
DENSE_RANK() OVER(PARTITION BY dep_id ORDER BY Salary DESC) AS RowNums
FROM employee
)
SELECT cteRowNum.dep_id, cteRowNum.emp_id, cteRowNum.Salary
FROM cteRowNum
WHERE cteRowNum.RowNums = 1;
You can test this using livesql.oracle.com, below are my DDLs and DMLs you can use:
create table employee (
emp_id varchar2(50) NOT NULL,
dep_id varchar2(50) NOT NULL,
salary number not null
);
create table department (
dep_id varchar2(50) NOT NULL,
dep_name varchar2(50) NOT NULL
);
insert into employee values (100, 5000, 1000000);
insert into employee values (200, 5000, 2000000);
insert into employee values (300, 5000, 3000000);
insert into employee values (400, 6000, 1500000);
insert into employee values (500, 6000, 1500000);
insert into employee values (600, 7000, 1000000);
insert into employee values (700, 7000, 1000000);
insert into employee values (800, 7000, 2000000);
insert into department values (5000, 'dep 1');
insert into department values (6000, 'dep 2');
insert into department values (7000, 'dep 3');
And below is the success screenshot of the query: