How to remove modifiers in a SQL Server stored procedure - sql

Question

I have a variable #modifier which returns (::22::) now I want to remove the : after the value 22 i.e it should return (::22). If modifier has a value of (:10:::), it should return (:10).
Is this possible in a SQL Server stored procedure?

Answer 1

You could use of reverse() function
select #modifier [modifier],
REVERSE(SUBSTRING(REVERSE(#modifier ), patindex('%[^:]%', REVERSE(#modifier )), len(#modifier))) [modifiedstring]
EDIT :
SELECT #modifier [modifier],
CASE
WHEN PATINDEX('%[0-9]%', #modifier) > 0
THEN REVERSE(SUBSTRING(REVERSE(#modifier), PATINDEX('%[^:]%', REVERSE(#modifier)), LEN(#modifier)))
ELSE ''
END [modifiedstring];
Note : In above first you check the strings have some numeric values present or not by using patindex() function
Result :
modifier modifiedstring
::22:: ::22
:10::: :10
::::

Answer 2

Try This
DECLARE #V VARCHAR(20) = ':10::'
SELECT
MyString = #V,
Result = REVERSE(
SUBSTRING(REVERSE(#V),
PATINDEX('%[0-9]%',REVERSE(#v)),
LEN(#V)))
Result
MyString Result
-------------------- --------------------
:10:: :10

Answer 3

Please try this. We can do this without reverse also.
CREATE TABLE strs1
(
modifier VARCHAR(100)
)
Go
INSERT INTO strs1 VALUES
('::22::'),
(':10:::')
GO
SELECT modifier,
LEFT(modifier,PATINDEX('%[0-9]%',modifier)+ PATINDEX('%[^0-9]%',SUBSTRING(modifier,PATINDEX('%[0-9]%',modifier),LEN(modifier)))-2)
Modifiedstring
FROM strs1
OUTPUT
/*------------------------
SELECT modifier,
LEFT(modifier,PATINDEX('%[0-9]%',modifier)+ PATINDEX('%[^0-9]%',SUBSTRING(modifier,PATINDEX('%[0-9]%',modifier),LEN(modifier)))-2)
Modifiedstring
FROM strs1
------------------------*/
modifier Modifiedstring
----------------------------- -----------------
::22:: ::22
:10::: :10
(2 row(s) affected)