SQL Query check result with other rows in same table - sql

I want build SQL query to select row based on date range and also want additional columns
Following is my sample table
+----+--------------+--------------+--------------+--------------+
| id | CustomerID | AccountID | DateFrom | DateTo |
+----+--------------+--------------+--------------+--------------+
| 1 | C0001 | A0001 | 21/01/2016 | 28/01/2016 |
| 2 | C0001 | A0001 | 01/02/2016 | 08/02/2016 |
| 3 | C0002 | A0002 | 09/02/2016 | 16/02/2016 |
| 4 | C0002 | A0002 | 14/01/2016 | 21/01/2016 |
| 5 | C0003 | A0003 | 07/01/2016 | 14/01/2016 |
| 6 | C0003 | A0003 | 09/02/2016 | 16/02/2016 |
| 7 | C0004 | A0004 | 01/01/2016 | 07/01/2016 |
| 8 | C0004 | A0004 | 09/03/2016 | 16/03/2016 |
+----+--------------+--------------+--------------+--------------+
If if pass Date Range is from 01/02/2016 to 28/02/2016 then I need result as follows
+----+-------------+------------+--------------+--------------+-------------+
| id | CustomerID | AccountID | DateFrom | DateTo | isPrevious |
+----+-------------+------------+--------------+--------------+-------------+
| 1 | C0001 | A0001 | 01/02/2016 | 08/02/2016 | Yes |
| 2 | C0002 | A0002 | 09/02/2016 | 16/02/2016 | Yes |
| 3 | C0003 | A0003 | 09/02/2016 | 16/02/2016 | Yes |
+----+-------------+------------+--------------+--------------+-------------+


This asume you want the data be full contain and no just overlaps with the target range. Also assume none of your row ranges overlap each other.
SELECT t1.*,
CASE WHEN (SELECT 1
FROM yourTable t2
WHERE t2.DateFrom < t1.DateFrom
and t2.CustomerID = t1.CustomerID
and t2.AccountID = t1.AccountID ) IS NULL
THEN 'No'
ELSE 'Yes'
END as isPrevious
FROM yourTable t1
WHERE DateFrom <= '2016-02-28' and
DateTo >= '2016-02-01';


If I understand correctly, this is a simple select:
select t.*
from t
where DateFrom <= '2016-02-28' and
DateTo >= '2016-02-01';
At least, this would give the results as you describe them.

Related

Finding MAX date aggregated by order - Oracle SQL

I have a data orders that looks like this:
| Order | Step | Step Complete Date |
|:-----:|:----:|:------------------:|
| A | 1 | 11/1/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/3/2019 |
| | 5 | 11/3/2019 |
| | 6 | 11/5/2019 |
| | 7 | 11/5/2019 |
| B | 1 | 12/1/2019 |
| | 2 | 12/2/2019 |
| | 3 | |
| C | 1 | 10/21/2019 |
| | 2 | 10/23/2019 |
| | 3 | 10/25/2019 |
| | 4 | 10/25/2019 |
| | 5 | 10/25/2019 |
| | 6 | |
| | 7 | 10/27/2019 |
| | 8 | 10/28/2019 |
| | 9 | 10/29/2019 |
| | 10 | 10/30/2019 |
| D | 1 | 10/30/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/2/2019 |
| | 5 | 11/2/2019 |
What I need to accomplish is the following:
For each order, assign the 'Order_Completion_Date' field as the most recent 'Step_Complete_Date'. If ANY 'Step_Complete_Date' is NULL, then the value for 'Order_Completion_Date' should be NULL.
I set up a SQL FIDDLE with this data and my attempt, below:
SELECT
OrderNum,
MAX(Step_Complete_Date)
FROM
OrderNums
WHERE
Step_Complete_Date IS NOT NULL
GROUP BY
OrderNum
This is yielding:
ORDERNUM MAX(STEP_COMPLETE_DATE)
D 11/2/2019
A 11/5/2019
B 12/2/2019
C 10/30/2019
How can I achieve:
| OrderNum | Order_Completed_Date |
|:--------:|:--------------------:|
| A | 11/5/2019 |
| B | NULL |
| C | NULL |
| D | 11/2/2019 |

Aggregate function with KEEP can handle this
select ordernum,
max(step_complete_date)
keep (DENSE_RANK FIRST ORDER BY step_complete_date desc nulls first) res
FROM
OrderNums
GROUP BY
OrderNum

You can use a CASE expression to first count if there are any NULL values and if not then find the maximum value:
Query 1:
SELECT OrderNum,
CASE
WHEN COUNT( CASE WHEN Step_Complete_Date IS NULL THEN 1 END ) > 0
THEN NULL
ELSE MAX(Step_Complete_Date)
END AS Order_Completion_Date
FROM OrderNums
GROUP BY OrderNum
Results:
| ORDERNUM | ORDER_COMPLETION_DATE |
|----------|-----------------------|
| D | 11/2/2019 |
| A | 11/5/2019 |
| B | (null) |
| C | (null) |

First, you are representing dates as varchars in mm/dd/yyyy format (at least in fiddle). With max function it can produce incorrect result, try for example order with dates '11/10/2019' and '11/2/2019'.
Second, the most simple solution is IMHO to use fallback date for nulls and get null back when fallback date wins:
SELECT
OrderNum,
NULLIF(MAX(NVL(Step_Complete_Date,'~')),'~')
FROM
OrderNums
GROUP BY
OrderNum
(Example is still for varchars since tilde is greater than any digit. For dates, you could use 9999-12-31, for instance.)

hive/sql:count each user_id gets how many uid

There is a table like:
+-----------+---------+------------+
| uid | user_id | month |
+-----------+---------+------------+
| d23fsdfsa | 101 | 2017-01-02 |
| 43gdasc | 102 | 2017-05-06 |
| b65hrfd | 101 | 2017-08-11 |
| 1wseda | 103 | 2017-09-13 |
| vdfhryd | 101 | 2017-08-06 |
| b6thd3d | 105 | 2017-05-03 |
| ve32h65 | 102 | 2017-01-02 |
| 43gdasc | 102 | 2017-09-06 |
+-----------+---------+------------+
How can one count each user_id where if the user_id appears in the same month, then only count one?
The final table should look like below: (because '101' has two uid in the same month so it only counts one for it)
+---------+-----------+
| user_id | count_num |
+---------+-----------+
| 101 | 2 |
| 102 | 3 |
| 103 | 1 |
| 105 | 1 |
+---------+-----------+

If I understand correctly, you want the number of distinct months for each user. If so:
select user_id, count(distinct trunc(month, 'MONTH')) as count_num
from t
group by user_id;

How to check dates condition from one table to another in SQL

Which way we can use to check and compare the dates from one table to another.
Table : inc
+--------+---------+-----------+-----------+-------------+
| inc_id | cust_id | item_id | serv_time | inc_date |
+--------+---------+-----------+-----------+-------------+
| 1 | john | HP | 40 | 17-Apr-2015 |
| 2 | John | HP | 60 | 10-Jan-2016 |
| 3 | Nick | Cisco | 120 | 11-Jan-2016 |
| 4 | samanta | EMC | 180 | 12-Jan-2016 |
| 5 | Kerlee | Oracle | 40 | 13-Jan-2016 |
| 6 | Amir | Microsoft | 300 | 14-Jan-2016 |
| 7 | John | HP | 120 | 15-Jan-2016 |
| 8 | samanta | EMC | 20 | 16-Jan-2016 |
| 9 | Kerlee | Oracle | 10 | 2-Feb-2017 |
+--------+---------+-----------+-----------+-------------+
Table: Contract:
+-----------+---------+----------+------------+
| item_id | con_id | Start | End |
+-----------+---------+----------+------------+
| Dell | DE2015 | 1/1/2015 | 12/31/2015 |
| HP | HP2015 | 1/1/2015 | 12/31/2015 |
| Cisco | CIS2016 | 1/1/2016 | 12/31/2016 |
| EMC | EMC2016 | 1/1/2016 | 12/31/2016 |
| HP | HP2016 | 1/1/2016 | 12/31/2016 |
| Oracle | OR2016 | 1/1/2016 | 12/31/2016 |
| Microsoft | MS2016 | 1/1/2016 | 12/31/2016 |
| Microsoft | MS2017 | 1/1/2017 | 12/31/2017 |
+-----------+---------+----------+------------+
Result:
+-------+---------+---------+--------------+
| Calls | Cust_id | Con_id | Tot_Ser_Time |
+-------+---------+---------+--------------+
| 2 | John | HP2016 | 180 |
| 2 | samanta | EMC2016 | 200 |
| 1 | Nick | CIS2016 | 120 |
| 1 | Amir | MS2016 | 300 |
| 1 | Oracle | OR2016 | 40 |
+-------+---------+---------+--------------+
MY Query:
select count(inc_id) as Calls, inc.cust_id, contract.con_id,
sum(inc.serv_time) as tot_serv_time
from inc inner join contract on inc.item_id = contract.item_id
where inc.inc_date between '2016-01-01' and '2016-12-31'
group by inc.cust_id, contract.con_id
The result from inc table with filter between 1-jan-2016 to 31-Dec-2016 with
count of inc_id based on the items and its contract start and end dates .

If I understand correctly your problem, this query will return the desidered result:
select
count(*) as Calls,
inc.cust_id,
contract.con_id,
sum(inc.serv_time) as tot_serv_time
from
inc inner join contract
on inc.item_id = contract.item_id
and inc.inc_date between contract.start and contract.end
where
inc.inc_date between '2016-01-01' and '2016-12-31'
group by
inc.cust_id,
contract.con_id
the question is a little vague so you might need some adjustments to this query.

select
Calls = count(*)
, Cust = i.Cust_id
, Contract = c.con_id
, Serv_Time = sum(Serv_Time)
from inc as i
inner join contract as c
on i.item_id = c.item_id
and i.inc_date >= c.[start]
and i.inc_date <= c.[end]
where c.[start]>='20160101'
group by i.Cust_id, c.con_id
order by i.Cust_Id, c.con_id
returns:
+-------+---------+----------+-----------+
| Calls | Cust | Contract | Serv_Time |
+-------+---------+----------+-----------+
| 1 | Amir | MS2016 | 300 |
| 2 | John | HP2016 | 180 |
| 1 | Kerlee | OR2016 | 40 |
| 1 | Nick | CIS2016 | 120 |
| 2 | samanta | EMC2016 | 200 |
+-------+---------+----------+-----------+
test setup: http://rextester.com/WSYDL43321
create table inc(
inc_id int
, cust_id varchar(16)
, item_id varchar(16)
, serv_time int
, inc_date date
);
insert into inc values
(1,'john','HP', 40 ,'17-Apr-2015')
,(2,'John','HP', 60 ,'10-Jan-2016')
,(3,'Nick','Cisco', 120 ,'11-Jan-2016')
,(4,'samanta','EMC', 180 ,'12-Jan-2016')
,(5,'Kerlee','Oracle', 40 ,'13-Jan-2016')
,(6,'Amir','Microsoft', 300 ,'14-Jan-2016')
,(7,'John','HP', 120 ,'15-Jan-2016')
,(8,'samanta','EMC', 20 ,'16-Jan-2016')
,(9,'Kerlee','Oracle', 10 ,'02-Feb-2017');
create table contract (
item_id varchar(16)
, con_id varchar(16)
, [Start] date
, [End] date
);
insert into contract values
('Dell','DE2015','20150101','20151231')
,('HP','HP2015','20150101','20151231')
,('Cisco','CIS2016','20160101','20161231')
,('EMC','EMC2016','20160101','20161231')
,('HP','HP2016','20160101','20161231')
,('Oracle','OR2016','20160101','20161231')
,('Microsoft','MS2016','20160101','20161231')
,('Microsoft','MS2017','20170101','20171231');

SQL - Count of instances between two dates for mutliple criteria

I have a table of account numbers with a date range. I must use another table of data to determine how many times we interacted with that account between the date range. I'm at a loss where to even start.
Table1
+------+------------+------------+
| Acct | EndDate | StartDate |
+------+------------+------------+
| 1 | 2017-02-14 | 2016-12-16 |
| 2 | 2017-02-14 | 2016-12-16 |
| 3 | 2017-02-13 | 2016-12-15 |
+------+------------+------------+
Table2
+------+--------------+
| acct | calllog_date |
+------+--------------+
| 1 | 2016-06-16 |
| 1 | 2016-08-15 |
| 1 | 2015-11-10 |
| 2 | 2015-11-10 |
| 2 | 2015-11-13 |
| 2 | 2015-11-16 |
| 2 | 2015-11-19 |
| 3 | 2015-11-19 |
| 3 | 2015-11-23 |
| 4 | 2015-11-30 |
+------+--------------+

Try using a JOIN based on a match between the date values:
SELECT t1.Acct, COUNT(*) AS cnt
FROM Table1 AS t1
JOIN Table2 AS t2
ON t1.Acct = t2.Acct AND t2.calllog_date BETWEEN t1.StartDate AND t1.EndDate
GROUP BY t1.Acct

Considering values from one table as column header in another

I have a base table where I need to calculate the difference between two dates based on the type of the entry.
tblA
+----------+------------+---------------+--------------+
| TypeCode | Log_Date | Complete_Date | Pending_Date |
+----------+------------+---------------+--------------+
| 1 | 18/04/2016 | 19/04/2016 | |
| 2 | 10/04/2016 | 18/04/2016 | 15/04/2016 |
| 3 | 12/04/2016 | 19/04/2016 | |
| 4 | 15/04/2016 | 17/04/2016 | 16/04/2016 |
| 5 | 16/04/2016 | 21/04/2016 | |
| 1 | 19/04/2016 | 20/04/2016 | |
| 2 | 20/03/2016 | 31/03/2015 | |
| 3 | 25/03/2016 | 28/03/2016 | |
| 4 | 26/03/2016 | 27/03/2016 | |
| 5 | 27/03/2016 | 30/03/2016 | |
+----------+------------+---------------+--------------+
I have another look up table which has the column names to be considered based on the TypeCode.
tblB
+----------+----------+---------------+
| TypeCode | DateCol1 | DateCol2 |
+----------+----------+---------------+
| 1 | Log_Date | Complete_Date |
| 2 | Log_Date | Pending_Date |
| 3 | Log_Date | Complete_Date |
| 4 | Log_Date | Pending_Date |
| 5 | Log_Date | Complete_Date |
+----------+----------+---------------+
I am doing a simple DATEDIFF between two dates for my calculation. However I want to lookup which columns to consider for this calculation from tblB and apply it on tblA based on the TypeCode.
Resulting table:
For example: When the TypeCode is 2 or 4 then the calculation should be DATEDIFF(d, Log_Date, Pending_Date), otherwise DATEDIFF(d, Log_Date, Complete_Date)
+----------+------------+---------------+--------------+----------+
| TypeCode | Log_Date | Complete_Date | Pending_Date | Cal_Days |
+----------+------------+---------------+--------------+----------+
| 1 | 18/04/2016 | 19/04/2016 | | 1 |
| 2 | 10/04/2016 | 18/04/2016 | 15/04/2016 | 5 |
| 3 | 12/04/2016 | 19/04/2016 | | 7 |
| 4 | 15/04/2016 | 17/04/2016 | 16/04/2016 | 1 |
| 5 | 16/04/2016 | 21/04/2016 | | 5 |
| 1 | 19/04/2016 | 20/04/2016 | | 1 |
| 2 | 20/03/2016 | 31/03/2015 | | |
| 3 | 25/03/2016 | 28/03/2016 | | 3 |
| 4 | 26/03/2016 | 27/03/2016 | | |
| 5 | 27/03/2016 | 30/03/2016 | | 3 |
+----------+------------+---------------+--------------+----------+
Any help would be appreciated. Thanks.

Use JOIN with CASE expression:
SELECT
a.*,
Cal_Days =
DATEDIFF(
DAY,
CASE
WHEN b.DateCol1 = 'Log_Date' THEN a.Log_Date
WHEN b.DateCol1 = 'Complete_Date' THEN a.Complete_Date
ELSE a.Pending_Date
END,
CASE
WHEN b.DateCol2 = 'Log_Date' THEN a.Log_Date
WHEN b.DateCol2 = 'Complete_Date' THEN a.Complete_Date
ELSE a.Pending_Date
END
)
FROM TblA a
INNER JOIN TblB b
ON b.TypeCode = a.TypeCode