how to sum count sql - sql

How to total count?
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP
RESULT:
NEW Accepted
1 5
But I need a total count
result: 6

I'd do something like this;
SELECT
COUNT(CASE WHEN id = 1 THEN 1 END) as New,
COUNT(CASE WHEN id = 2 THEN 5 END) as Accepted,
COUNT(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
This is exactly what the CASE statement should be used for, the logic is very simple. This will avoid having to perform multiple calculations on the same fields.
As a note, the value in your THEN statement isn't used in this instance at all, it's just doing a COUNT of the number rather than performing a SUM. I've also removed the ELSE NULL because this is what the CASE will do by default anyway.
If your intention was to SUM the values then do this;
SELECT
SUM(CASE WHEN id = 1 THEN 1 END) as New,
SUM(CASE WHEN id = 2 THEN 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
Example
Assuming you have only two values in your database, 1 and 2, we can create test data like this;
CREATE TABLE #SHP (id int)
INSERT INTO #SHP (id)
VALUES (1),(2)
And use this query;
SELECT
SUM(CASE WHEN id = 1 then 1 END) as New,
SUM(CASE WHEN id = 2 then 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM #SHP
Gives this result;
New Accepted Total
1 5 6

Try this:
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) +
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Total"
from SHP

You could wrap your query into a subquery and do something like this:
SELECT SUM(New) as New, Sum(Accepted) as Accepted, Sum(New + Accepted) as Total FROM
(SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP) as SubQuery
That's if you don't want to duplicate doing the counts and just adding the two together.

try this
with s1 as(
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE 0 END) as "New"
from SHP
),s2 as
(
SELECT
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE 0 END) as "Accepted"
from SHP
)
select sum("New"+ "Accepted") from s1,s2

Related

Adding a dummy identifier to data that varies by position and value

I am working on a project in SQL Server with diagnosis codes and a patient can have up to 4 codes but not necessarily more than 1 and a patient cannot repeat a code more than once. However, codes can occur in any order. My goal is to be able to count how many times a Diagnosis code appears in total, as well as how often it appears in a set position.
My data currently resembles the following:
PtKey
Order #
Order Date
Diagnosis1
Diagnosis2
Diagnosis3
Diagnosis 4
345
1527
7/12/20
J44.9
R26.2
NULL
NULL
367
1679
7/12/20
R26.2
H27.2
G47.34
NULL
325
1700
7/12/20
G47.34
NULL
NULL
NULL
327
1710
7/12/20
I26.2
J44.9
G47.34
NULL
I would think the best approach would be to create a dummy column here that would match up the diagnosis by position. For example, Diagnosis 1 with A, and Diagnosis 2 with B, etc.
My current plan is to rollup the diagnosis using an unpivot:
UNPIVOT ( Diag for ColumnALL IN (Diagnosis1, Diagnosis2, Diagnosis3, Diagnosis4)) as unpvt
However, this still doesn’t provide a way to count the diagnoses by position on a sales order.
I want it to look like this:
Diagnosis
Total Count
Diag1 Count
Diag2 Count
Diag3 Count
Diag4 Count
J44.9
2
1
1
0
0
R26.2
1
1
0
0
0
H27.2
1
0
1
0
0
I26.2
1
1
0
0
0
G47.34
3
1
0
2
0
You can unpivot using apply and aggregate:
select v.diagnosis, count(*) as cnt,
sum(case when pos = 1 then 1 else 0 end) as pos_1,
sum(case when pos = 2 then 1 else 0 end) as pos_2,
sum(case when pos = 3 then 1 else 0 end) as pos_3,
sum(case when pos = 4 then 1 else 0 end) as pos_4
from data d cross apply
(values (diagnosis1, 1),
(diagnosis2, 2),
(diagnosis3, 3),
(diagnosis4, 4)
) v(diagnosis, pos)
where diagnosis is not null;
Another way is to use UNPIVOT to transform the columns into groupable entities:
SELECT Diagnosis, [Total Count] = COUNT(*),
[Diag1 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis1' THEN 1 ELSE 0 END),
[Diag2 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis2' THEN 1 ELSE 0 END),
[Diag3 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis3' THEN 1 ELSE 0 END),
[Diag4 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis4' THEN 1 ELSE 0 END)
FROM
(
SELECT * FROM #x UNPIVOT (Diagnosis FOR DiagGroup IN
([Diagnosis1],[Diagnosis2],[Diagnosis3],[Diagnosis4])) up
) AS x GROUP BY Diagnosis;
Example db<>fiddle
You can also manually unpivot via UNION before doing the conditional aggregation:
SELECT Diagnosis, COUNT(*) As Total Count
, SUM(CASE WHEN Position = 1 THEN 1 ELSE 0 END) As [Diag1 Count]
, SUM(CASE WHEN Position = 2 THEN 1 ELSE 0 END) As [Diag2 Count]
, SUM(CASE WHEN Position = 3 THEN 1 ELSE 0 END) As [Diag3 Count]
, SUM(CASE WHEN Position = 4 THEN 1 ELSE 0 END) As [Diag4 Count]
FROM
(
SELECT PtKey, Diagnosis1 As Diagnosis, 1 As Position
FROM [MyTable]
UNION ALL
SELECT PtKey, Diagnosis2 As Diagnosis, 2 As Position
FROM [MyTable]
WHERE Diagnosis2 IS NOT NULL
UNION ALL
SELECT PtKey, Diagnosis3 As Diagnosis, 3 As Position
FROM [MyTable]
WHERE Diagnosis3 IS NOT NULL
UNION ALL
SELECT PtKey, Diagnosis4 As Diagnosis, 4 As Position
FROM [MyTable]
WHERE Diagnosis4 IS NOT NULL
) d
GROUP BY Diagnosis
Borrowing Aaron's fiddle, to avoid needing to rebuild the schema from scratch, and we get this:
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=d1f7f525e175f0f066dd1749c49cc46d

Hello! is that anyway to write similar query without using union?

is that anyway to write similar query without using union?
select sum(decode(p.sumsend,0,1,0)) recvcnt,
sum(decode(p.sumsend,0,1,0)*p.sumserv) recvsum
from some_table p
where p.polefilter = 5
union
select sum(decode(p.sumsend,0,1,0)) recvcnt,
sum(decode(p.sumsend,0,1,0)*p.sumserv) recvsum
from some_table p
where p.polefilter != 5
If you are OK with having all 4 columns on one row, then one option is conditional aggregation:
select
sum(case when polefilter = 5 and sumsend = 0 then 1 else 0 end) recvcnt1,
sum(case when polefilter = 5 and sumsend = 0 then 1 else 0 end * sumserv) recvsum1,
sum(case when polefilter <> 5 and sumsend = 0 then 1 else 0 end) recvcnt2,
sum(case when polefilter <> 5 and sumsend = 0 then 1 else 0 end * sumserv) recvsum2
from some_table p
where polefilter is not null
On the other hand, if you want two rows in the resultset, then you can use aggregation and a case expression to define the groups:
select
case when polefilter = 5 then 1 else 0 end as polefilter_is_5
sum(case when sumsend = 0 then 1 else 0 end) recvcnt,
sum(case when sumsend = 0 then 1 else 0 end * sumserv) recvsum1
from some_table p
where p.polefilter is not null
group by case when polefilter = 5 then 1 else 0 end
Note that I changed the decode() functions to case expressions; both do the same thing, but the latest is standard SQL (and is somehow more flexible).
A query like the one below should work. Please provide sample data and expected output when asking a question next time.
SELECT SUM (CASE WHEN p.sumsend = 0 THEN 1 ELSE 0 END) recvcnt,
SUM (CASE WHEN p.sumsend = 0 THEN 1 ELSE 0 END * p.sumserv) recvsum
FROM some_table p
GROUP BY CASE p.polefilter WHEN 5 THEN 1 ELSE 0 END;

SQL sum of two conditional aggregation

So yesterday I learned about conditional aggregation. I'm fairly new to SQL.
Here is my query:
select
Year_CW,
sum(case when col = 0 then 1 else 0 end) as "Total_sampled(Checked)",
sum(case when col = 1 then 1 else 0 end) as "Total_unsampled(Not_Checked)",
sum(case when col = 0 AND col2 = 'accepted' then 1 else 0 end) as "Accepted",
sum(case when col = 0 AND col2 = 'accepted with comments' then 1 else 0 end) as "Accepted with comments",
sum(case when col = 0 AND col2 = 'request for rework' then 1 else 0 end) as "Request for rework",
sum(case when col = 0 AND col2 = 'rejected' then 1 else 0 end) as "Rejected",
sum(case when col = 0 Or col = 1 then 1 else 0 end) as "Total_DS"
from
(select
Year_CW, SAMPLED as col, APPROVAL as col2
from
View_TEST tv) tv
group by
Year_CW
order by
Year_CW desc
I'm basically just calculating some KPIs grouped by week.
Look at the row for "Total_DS". It is essentially the sum of the first two sums, "Total_sampled(Checked)" and "Total_unsampled(Not_Checked)".
Is there a way that I can add the two columns from the first two sums to get the third one instead of trying to get the data all over again? I feel performance wise this would be terrible practice. It doesn't matter for this database but I don't want to learn bad code practice from the start.
Thanks for helping.
You probably won't see a significant performance hit from what you're doing now as you already have all the data available, you're just repeating the case evaluation.
But you can't refer to the column aliases for the first two columns within the same level of query.
If you can't do a simple count as #Zeki suggested because you aren't sure if there might be values other than zero and one (though this looks rather like a binary true/false equivalent, so there may well be a check constraint limiting you to those values), or if you're just more interested in a more general case, you can use an inline view as #jarhl suggested:
select Year_CW,
"Total_sampled(Checked)",
"Total_unsampled(Not_Checked)",
"Accepted",
"Accepted with comments",
"Request for rework",
"Rejected",
"Total_sampled(Checked)" + "Total_unsampled(Not_Checked)" as "Total_DS"
from (
select Year_CW,
sum(case when col = 0 then 1 else 0 end) as "Total_sampled(Checked)",
sum(case when col = 1 then 1 else 0 end) as "Total_unsampled(Not_Checked)",
sum(case when col = 0 AND col2 = 'accepted' then 1 else 0 end) as "Accepted",
sum(case when col = 0 AND col2 = 'accepted with comments' then 1 else 0 end)
as "Accepted with comments",
sum(case when col = 0 AND col2 = 'request for rework' then 1 else 0 end)
as "Request for rework",
sum(case when col = 0 AND col2 = 'rejected' then 1 else 0 end) as "Rejected"
from (
select Year_CW, SAMPLED as col, APPROVAL as col2
from View_TEST tv
) tv
group by Year_CW
)
order by Year_CW desc;
The inner query gets the data and calculates the conditional aggregate values. The outer query just gets those values from the inner query, and also adds the Total_DS column to the result set by adding together the rwo values from the inner query.
You should generally avoid quoted identifiers, and if you really need them in your result set you should apply them at the last possible moment - so use unquoted identifiers in the inner query, and give them qupted aliases in the outer query. And personally if the point of a query is to count things, I prefer to use a conditional count over a conditional sum. I'm also not sure why you already have a subquery against your view, which just changes the column names and makes the main query slightly more obscure. So I might do this as:
select year_cw,
total_sampled_checked as "Total_sampled(Checked)",
total_unsampled_not_checked as "Total_unsampled(Not_Checked)",
accepted as "Accepted",
accepted_with_comments as "Accepted with comments",
request_for_rework as "Request for rework",
rejected as "Rejected",
total_sampled_checked + total_unsampled_not_checked as "Total_DS"
from (
select year_cw,
count(case when sampled = 0 then 1 end) as total_sampled_checked,
count(case when sampled = 1 then 1 end) as total_unsampled_not_checked,
count(case when sampled = 0 and approval = 'accepted' then 1 end) as accepted,
count(case when sampled = 0 and approval = 'accepted with comments' then 1 end)
as accepted_with_comments,
count(case when sampled = 0 and approval = 'request for rework' then 1 end)
as request_for_rework,
count(case when sampled = 0 and approval = 'rejected' then 1 end) as rejected
from view_test
group by year_cw
)
order by year_cw desc;
Note that in the case expression, then 1 can be then <anything that isn't null>, so you could do then sampled or whatever. I've left out the implicit else null. As count() ignores nulls, all the case expression has to do is evaluate to any not-null value for the rows you want to include in the count.
You can try below
select Year_CW,
sum(case when col = 0 then 1 else 0 end) as "Total_sampled(Checked)",
sum(case when col = 1 then 1 else 0 end) as "Total_unsampled(Not_Checked)",
sum(case when col = 0 AND col2 = 'accepted' then 1 else 0 end) as "Accepted",
sum(case when col = 0 AND col2 = 'accepted with comments' then 1 else 0 end) as "Accepted with comments",
sum(case when col = 0 AND col2 = 'request for rework' then 1 else 0 end) as "Request for rework",
sum(case when col = 0 AND col2 = 'rejected' then 1 else 0 end) as "Rejected",
sum(sum(case when col = 0 then 1 else 0 end) = 0 Or sum(case when col = 1 then 1 else 0 end) = 1 then 1 else 0 end) as "Total_DS"
from (select Year_CW, SAMPLED as col, APPROVAL as col2
from View_TEST tv
) tv
group by Year_CW
order by Year_CW desc

Running Counts on Multiple Columns with One SQL Query

I'm looking to run a count SQL query on multiple columns at once. 83 of them. For each, I'd simply like to figure out how many instances there are in which the value = 1.
ex.
select count(*) from [filename.filename]
where [Column001] = 1
select count(*) from [filename.filename]
where [Column002] = 1
All data in each column is marked with wither a 0 or a 1.
Instead of writing 83 small queries, is there a way for me to write it all in one query and have them all display as a table with the results?
This seems to be what you want:
SELECT SUM(CASE WHEN Column_1 = 1 THEN 1 ELSE 0 END) N_1,
SUM(CASE WHEN Column_2 = 1 THEN 1 ELSE 0 END) N_2,
SUM(CASE WHEN Column_3 = 1 THEN 1 ELSE 0 END) N_3,
.....
SUM(CASE WHEN Column_83 = 1 THEN 1 ELSE 0 END) N_83
FROM YourTable;

SQL Transform of raw data into summary table?

I have a table full of survey data which I need to transform into a nice summary table. The survey question was (for example) "Rank your restaurant preferences in order". The raw data looks like:
CUST_ID WENDYS_RANK MCDONALDS_RANK BURGERKING_RANK
1 First Third Second
2 Second First Third
3 None First Second
4 Second Third First
(repeat for 100,000+ records)
I need to turn this into a nice table that looks like:
NAME NUM_FIRST NUM_SECOND NUM_THIRD
Wendys 1 2 0
McDonalds 2 0 2
BK 1 2 1
But it's been so darn long since I did a transformation like this I not only forgot how to write the SQL, I forgot what this transformation is called, which makes it hard to google. Can anyone help me?
Thanks...
Here is one method:
select 'Wendys',
sum(case when Wendys_Rank = 'First' then 1 else 0 end) as Rank1,
sum(case when Wendys_Rank = 'Second' then 1 else 0 end) as Rank2,
sum(case when Wendys_Rank = 'Third' then 1 else 0 end) as Rank3
from surveydata
union all
select 'McDonalds',
sum(case when McDonalds_Rank = 'First' then 1 else 0 end) as Rank1,
sum(case when McDonalds_Rank = 'Second' then 1 else 0 end) as Rank2,
sum(case when McDonalds_Rank = 'Third' then 1 else 0 end) as Rank3
from surveydata
union all
select 'BK',
sum(case when BK_Rank = 'First' then 1 else 0 end) as Rank1,
sum(case when BK_Rank = 'Second' then 1 else 0 end) as Rank2,
sum(case when BK_Rank = 'Third' then 1 else 0 end) as Rank3
from surveydata;