Separate XML node values into separate rows in SQL - sql

Question

I have a SQL table with a XML column. The value of the column looks like this:
<StudentGroup xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<StudentIds>
<int>3000</int>
<int>3001</int>
<int>3002</int>
<int>8</int>
<int>9</int>
</StudentIds>
</StudentGroup>
I want to get the each StudentIDs in a separate row instead of it in one row. Here is what I have done:
select
xmlColumn.value('(/StudentGroup/StudentIds)[1]','varchar(max)') as IDs
from myTable
This select statement returns the IDs in one row. Like this:
30003001300289
What is want is
3000
3001
3002
8
9
Please help! Thanks in advance.

Answer 1

When you have the XML in a variable:
DECLARE #x XML = '
<StudentGroup xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<StudentIds>
<int>3000</int>
<int>3001</int>
<int>3002</int>
<int>8</int>
<int>9</int>
</StudentIds>
</StudentGroup>';
SELECT
n.v.value('.','INT') AS ID
FROM
#x.nodes('/StudentGroup/StudentIds/int') AS n(v);
When you have the XML in a table:
DECLARE #x XML = '
<StudentGroup xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<StudentIds>
<int>3000</int>
<int>3001</int>
<int>3002</int>
<int>8</int>
<int>9</int>
</StudentIds>
</StudentGroup>';
DECLARE #t TABLE(
x XML
);
INSERT INTO #t(x)VALUES(#x);
SELECT
n.v.value('.','INT') AS ID
FROM
#t
CROSS APPLY x.nodes('/StudentGroup/StudentIds/int') AS n(v);