I have a scenario as below
Exchange is of type "topic" and i have two queues(queue1 and queue2) binded to it with routing key #.
Each queue is having 1 consumer. Now, when i send a message from publisher both queues are getting my message since its binded to routing key # .
Is there any way, we can send messages to only one queue on round robin basis ?
Since, each message is getting into both queues , i am getting duplication of messages.
If you are looking for round robin consuming you shoud see this pattern:
https://www.rabbitmq.com/tutorials/tutorial-two-java.html
So basically you publish to one queue and then you add consumers to the same queue.
through the QoS = 1 you have the round-robin. In this way you can add more consumers without create new queues
Related
Using RabbitMQ 3.7.16, with spring-amqp 2.2.3.RELEASE.
Multiple clients publish messages to the DataExchange topic exchange in our RabbitMQ server, using a unique routing key. In the absence of any bindings, the exchange will route all the messaged to the data.queue.generic through the AE.
When a certain client (client ID 1 and 2 in the diagram) publishes lots of messages, in order to scale the consumption of their messages independently from other clients, we are starting consumers and assign them to only handle a their client ID. To achieve this, each client-consumer is defining a new queue, and it binds it to the topic exchange with the routing key events.<clientID>.
So scaling up is covered and works well.
Now when the messages rate for this client goes down, we would like to also scale down its consumers, up to the point of removing all of them. The intention is to then have all those messages being routed to the GenericExchange, where there's a pool of generic consumers taking care of them.
The problem is that if I delete data.queue.2 (in order to remove its binding which will lead to new messages being routed to the GenericExchange) all its pending messages will be lost.
Here's a simplified architecture view:
It would be an acceptable solution to let the messages expire with a TTL in the client queue, and then dead letter them to the generic exchange, but then I also need to stop the topic exchange from routing new messages to this "dying" queue.
So what options do I have to stop the topic exchange from routing messages to the client queue where now there's no consumer connected to it?
Or to explore another path - how to dead letter messages in a deleted/expired queue?
If the client queue is the only one with a matching binding as your explanation seems to suggest, you can just remove the binding between the exchange and the queue.
From then on, all new messages for the client will go through the alternate exchange, your "generic exchange", to be processed by your generic consumers.
As for the messages left over in the client queue, you could use a shovel to send them back to the topic exchange, for them to be routed to the generic exchange.
This based on the assumption the alternate exchange is internal. If it's not internal, you can target it directly with the shovel.
As discussed with Bogdan, another option to resolve this while ensuring no message loss is occuring is to perform multiple steps:
remove the binding between the specific queue and the exchange
have some logic to have the remaining messages be either consumed or rerouted to the generic queue
if the binding removal occurs prior to the consumer(s) disconnect, have the last consumer disconnect only once the queue is empty
if the binding removal occurs after the last consumer disconnect, then have a TTL on messages with alternate exchange as the generic exchange
depending on the options selected before, have some cleanup mecanism to remove the lingering empty queues
A producer sends the message with routing key (x) to the exchange once in 5 secs. Based on the routing key, it is send to 2 queues A and B. The consumer which consumes from A wants it once in 5 secs , but the consumer that consumes from B needs the message only once in one min..
One way is to consume the messages from Queue B and discard the messages that we don't need(only considering once in one min) .
Is there any other better way for this to do in rabbitmq ?
A consumer can keep state about the last time he consumed a message. When a new message arrives, can check if the the desired time has passed since the last message was consumed. If it wasn't, he can just ignore the message.
This is logic that must be handled by the consumer, not the RabbitMQ broker.
The deduplication exchange of the RMQ deduplication plugin has been designed to fit this purpose.
You can specify the time in which you don't want to see a similar message more than once and the exchange will drop any further copy of the given message. Messages are identified via the x-deduplication-header.
The amount of time a message is guaranteed to be unique can be controlled via the x-cache-ttl exchange argument or message header.
My scenario is such that I want to have one queue for the producer where the published messages will be stored. The messages will be associated with some routing key such that abcd.1234(some id).
Now from the consumer part I want that every consumer will connect to this queue and pop the messages based on the routing key pattern. Such as say consumer for abcd.123 will pop the messages with routing key abcd.123 and so on.
I tried to use topic exchange but I don't think its directly fitting into this use case as topic exchange generates one queue for each subscriber(consumer)
So, in there any way to consume (pop) message from queue based on the routing key of that queue.
Similar to queue.pop(:routing_key:xyz)
kindly help on this how to proceed?
I have implemented the example from the RabbitMQ website:
RabbitMQ Example
I have expanded it to have an application with a button to send a message.
Now I started two consumer on two different computers.
When I send the message the first message is sent to computer1, then the second message is sent to computer2, the thrid to computer1 and so on.
Why is this, and how can I change the behavior to send each message to each consumer?
Why is this
As noted by Yazan, messages are consumed from a single queue in a round-robin manner. The behavior your are seeing is by design, making it easy to scale up the number of consumers for a given queue.
how can I change the behavior to send each message to each consumer?
To have each consumer receive the same message, you need to create a queue for each consumer and deliver the same message to each queue.
The easiest way to do this is to use a fanout exchange. This will send every message to every queue that is bound to the exchange, completely ignoring the routing key.
If you need more control over the routing, you can use a topic or direct exchange and manage the routing keys.
Whatever type of exchange you choose, though, you will need to have a queue per consumer and have each message routed to each queue.
you can't it's controlled by the server check Round-robin dispatching section
It decides which consumer turn is. i'm not sure if there is a set of algorithms you can pick from, but at the end server will control this (i think round robin algorithm is default)
unless you want to use routing keys and exchanges
I would see this more as a design question. Ideally, producers should create the exchanges and the consumers create the queues and each consumer can create its own queue and hook it up to an exchange. This makes sure every consumer gets its message with its private queue.
What youre doing is essentially 'worker queues' model which is used to distribute tasks among worker nodes. Since each task needs to be performed only once, the message is sent to only one node. If you want to send a message to all the nodes, you need a different model called 'pub-sub' where each message is broadcasted to all the subscribers. The following link shows a simple pub-sub tutorial
https://www.rabbitmq.com/tutorials/tutorial-three-python.html
I've defined one topic exchange (alarms) and multiple queues, each with its own routing key:
allAlarms, with routing key alarms.#: I want this to be used for receiving all alarms in a monitoring application
alarms_[deviceID], with routing key alarms.[deviceID], where the number of devices can vary at any given time
When sending an alarm from the device, I publish it using the routing key alarms.[deviceID]. The monitoring app, however, only consumes from the allAlarms queue. This leads to the following problem:
The messages in the allAlarms queue have been consumed, while the messages in the remaining queues are ready. Is there a better way of handling messages from multiple consumers? Ideally, I'd like to be able to also send commands back to the devices using the same queues where the devices publish their alarms.
It looks like you have consumers bound to the allAlarms queue but not to any of the alarms_[deviceID] queues.
In AMQP, a single consumer is bound to a single queue by name (and each queue can have multiple consumers bound to it). Messages are delivered to the consumers of a queue in round robin such that for a given message in a queue there is exactly one consumer that will receive the message. That is, consumers cannot listen to multiple queues.
Since you're using a topic exchange, you're correctly routing a single message to multiple queues via the routing key and queue bindings. This means that you can have a consumer for each queue and when a message is delivered to the exchange, each queue will get a copy of the message and each queue will deliver the message to exactly one consumer on each queue.
Thus, if allAlarms is consuming messages, it's because it has a consumer attached to the queue. If any of the alarms_[deviceID] are not consuming messages then they must not have consumers bound to those individual queues. You have to start up consumers for each alarms_[deviceID] by name. That will allow you to also have different consumer logic for different queues.
One last thing:
Ideally, I'd like to be able to also send commands back to the devices using the same queues where the devices publish their alarms.
You don't want to do this using the same queue because there's nothing that will stop the non-device consumers on the queue from picking up those messages.
I believe you're describing RPC over RabbitMQ. For that you will want to publish the messages to the alarms queues with a reply-to header which is the name of a temporary queue. This temp queue is a single-use queue that the consumer will publish to when it's done to communicate back to the device. The device will publish to the alarms exchange and then immediately start listening to the temp queue for a response from the consumer.
For more info on RPC over RabbitMQ check out this tutorial.
I don't think you need any of the queues for the devices - the alarm_[deviceid] queues.
You don't have any consumer code set up on these queues, and the messages are backed up and waiting for you to consume them.
You also haven't mentioned a need to consume messages from these queues. Instead, you are only consuming messages form the alarmAll queue.
Therefore, I would drop all of the alarm_[deviceid] queues and only have the alarmAll queue.
Just publish the alarms through your exchange and route them all to the alarmAll queue and be done with it. No need for any other routing or queues.