how to substitute from a string to multiple patterns using awk/sed? - awk

Question

I have a patternfile.txt.
1 FPAT = "pata"
2 FPAT = "patb"
3 FPAT = "patc"
and a awkfile.txt.
BEGIN { FPAT }
{
for(i=1; i<=NF; i++){
print("%s\n", $i)}
}
I want to make multiple files after substitute a string 'FPAT' to each patterns pata, patb, patc one by one like these.
awkfile1.txt :
BEGIN { FPAT = "pata" }
{
for(i=1; i<=NF; i++){
print("%s\n", $i)}
}
awkfile2.txt :
BEGIN { FPAT = "patb" }
{
for(i=1; i<=NF; i++){
print("%s\n", $i)}
}
awkfile3.txt :
BEGIN { FPAT = "patc" }
{
for(i=1; i<=NF; i++){
print("%s\n", $i)}
}
Please help me.

Answer 1

I've got a feeling that this is a bit of an XY problem but I think you can get the output you're looking for in one invocation of awk:
awk '{ print "BEGIN { " substr($0, index($0, $2)) " }" > ("awkfile" $1 ".txt") }' patternfile.txt
This simply reads each line of the input file and produces the writes the part you're interested in (from the second field to the end of the line) to the output file. It uses the first field of the input to determine the output file name.