I have recieved a particular date in the particular format
2015-06-13T21:49:13.395-07:00 which is inserted as varchar in database.
I want to convert this date into DATE format but am not getting the right formatter for the same
Use to_timestamp_tz() function to convert your string to a value of timestamp with timezone data type:
select to_timestamp_tz('2015-06-13T21:49:13.395-07:00'
, 'yyyy-mm-dd"T"hh24:mi:ss.ffTZH:TZM') as res
from dual
Result:
RES
----------------------------------
13.06.15 21:49:13,395000000 -07:00
SELECT CAST(LEFT(REPLACE('2015-06-13T21:49:13.395-07:00','T',' '),23) AS DATETIME)
Related
Based on the example mentioned here in the Snowflake documentation, why are the date and timestamp values returning different values just by changing the ORDER BY clause? Also, I am trying to convert a string to a date format which is not returning correct results in Snowflake while this works fine in other SQL based Engines. Need help from experts on this.
This query
SELECT '20200710', TO_DATE('20200710');
is returning the following output
20200710 | 1970-08-22
Also tried:
SELECT TO_DATE('20200710', 'YYYY-MM-DD');
and got the error:
Can't parse '20200710' as date with format 'YYYY-MM-DD'
To convert to a date data type, you would use:
SELECT TO_DATE('20200710', 'YYYYMMDD')
I would recommend just keeping the date data type. But if you want a string in the format YYYY-MM-DD:
SELECT TO_CHAR(TO_DATE('20200710', 'YYYYMMDD'), 'YYYY-MM-DD')
I have a string that is a date and it is in this format 'dd-mon-yy' ie:
27-Jan-18
28-Jan-18
How do I convert it into date with this format 'dd/mm/yyyy' using Standard SQL in BigQuery?
If you want to convert dates from the string format to a particular date format, you will first have to convert the string to a date using the PARSE_DATE function in BigQuery and then use the FORMAT_DATE function to convert the date into the desired format. Here is a snippet of code that converts the string of type "DD-Mon-YY" to a date value of the format dd/mm/yyyy:
SELECT FORMAT_DATE("%d/%m/%E4Y", PARSE_DATE("%d-%b-%y", "name_of_column_with_string_dates")) as formatted_dates FROM `projectId.dataset.table`
In my DB, there is a date field in the format yyyymmdd.
I have to get all the dates in the format dd-mm-yyyy for that particlar date.
ex:
Date
20170130
20170228
20170325
for the above dates, I need the output in the below format with the dates and day of the particular dates
date day
30-01-2017 tuesday
28-02-2017 tuesday
25-03-2017 saturday
If the column is a string, then it can hold invalid date values such as February 31, one way to avoid this is by a small function such as this:
create or replace
function my_to_date( p_str in varchar2 ) return date
is
begin
return to_date( p_str );
exception
when others then
return null;
end;
\\
select to_char(my_to_date('20170231'),'DD-MM-YYYY Day')
from dual
\\
Demo
Try below:
Select to_char(yrdate, 'dd-mm-yyyy'), to_char(yrdate, 'D') from yrtable
It sounds like your dates aren't actually DATE fields but some kind of CHAR field? The best option would be to convert to DATE and then convert back to CHAR:
SELECT TO_CHAR(TO_DATE(mydate, 'YYYYMMDD'), 'DD-MM-YYYY Day')
FROM mytable;
This uses the YYYYMMDD mask to convert your string into a date, then uses the mask DD-MM-YYYY Day to convert it back into a string. Use day if you want the day name in lowercase (as in your OP).
#user2778168 answer will give you the results you want. But why?
Your database does not have dates stored in yyyymmdd format or any other date format for at mater, unless it's defined with a character type definition. Oracle stores all dates in a single internal structure, and with only slight variations timestamps are the same. The format used only tells Oracle how to display the value or to convert a string to a date. Unless a specific format is specified Oracle uses the NLS_DATE_FORMAT for this determination. See here and scan down to "Datetime Format Models" for format specifications.
To see this run the following:
select value
from nls_session_parameters
where parameter = 'NLS_DATE_FORMAT';
Select yrdate default_format
, to_char(yrdate, 'dd-mm-yyyy') specified_format
, dump(yrdate) unformated
from yrtable;
alter session set nls_date_format = 'Month dd,yyyy';
Rerun the above queries.
It seems you hold date column(date1) in character format. Suppose you have a table named days:
SQL> desc days
date1 varchar2(10)
then,
we should convert it into date, and then into char format, with aliases in quotation marks to provide lowercase aliases as you wanted.
perhaps your database's date language is non-english like mine(turkish), then you need to convert it to english.
lastly, it'a appropriate to order the results according to converted date, seen from your output. So we can use the following SQL :
select to_char(to_date(date1,'yyyymmdd'),'dd-mm-yyyy') "date",
to_char(to_date(date1,'yyyymmdd'),'day','nls_date_language=english') "day"
from days
order by to_date(date1,'yyyymmdd');
D e m o
This i got to convert a single binary date to Gregorian date ,
Select to_char(to_date(sum(2415020+42744),'J'),'MMDDYYYY') Last_arrear_date from dual;
But I'm not able to convert a binary date column date into Gregorean in xyz table
For Example
Suppose i have a table borm,That has account_open_date column that stores data in binary format , I want to convert that account_open_date column data into Gregorian date format. Please let me know how to convert that
While you have to change the entire column, Don't use the sum function.
Try the below SQL command it will work.
select acct_no, to_char(to_date((account_open_date + 2415020), 'J'),'DD-MON-YYYY')
from borm;
To Change Binary to Gregorian
select column1 ,...columnN, to_char(to_date((Column_name + 2415020), 'J'),'DD-MON-YYYY')
from Table_Name
WHERE Condition;
To change Gregorian to Binary:
select column1,columnN, to_char(to_date(Column_Name,'YYYYMMDD'),'J')-2415020
from Table_Name
where condition ;
I need to convert 2014-11-18T14:08:43+00:00 which is in varchar in my sql developer to date format in order to filter a few entries.
I tried
to_date(LAST_UPDATE_DATE,'YYYY-MM-DD')
but it gives an error
ORA-01830: date format picture ends before converting entire input
string.
Kindly help..
Just in case you didn't mean to put up sql server but instead you need to use oracle (seeing as you are using to_date and you are getting an ora exception)
I added a quick datetime conversion for date and timestamp (no milliseconds) for your date format:
SELECT to_Date(concat
(substr
(myvar,0,10),
concat(' ',
substr(myvar,12,8)
)
),'YYYY-MM-DD HH24:mi:ss') AS mydate
FROM mytable
Fiddle
declare #varDate as nvarchar(50) = '2014-11-18T14:08:43+00:00'
select CAST(substring(#varDate,0,CHARINDEX('T',#varDate)) as date)
Either you can use it like this
declare #Date as nvarchar(100) = '2014-11-18T14:08:43+00:00'
SELECT CONVERT(DATE,#Date) AS Date
OR go for this answer which is accepted in this question
ORA-01830: date format picture ends before converting entire input string / Select sum where date query
ORA-01830: date format picture ends before converting entire input string.
to_date(LAST_UPDATE_DATE,'YYYY-MM-DD')
2014-11-18T14:08:43+00:00 is TIMESTAMP and not DATE.
First of all, you should never ever store DATE/TIMSTAMP as string. It is a database design flaw.
Anyway, you could convert it to TIMESTAMP WITH TIMEZONE.
For example,
SQL> SELECT to_timestamp_tz('2014-11-18T14:08:43+00:00',
2 'YYYY-MM-DD"T"HH24:MI:SS.FFTZH:TZM')
3 AS tm_stamp
4 FROM dual;
TM_STAMP
----------------------------------------------------------------
18-NOV-14 02.08.43.000000000 PM +00:00
SQL>
You could try this;
Select CAST ('2014-11-18T14:08:43+00:00' as date)
The assumption is you are in SQL Server 2012