sql combining 2 queries with different order by group by - sql

Question

I have a query where I am counting the most frequent response in a database and ranking them by highest amount so using group by and order by.
The following shows how to do it for one:
select health, count(health) as count
from [Health].[Questionaire]
group by Health
order by count(Health) desc
which outputs the following:
Health Count
----------- -----
Very Good 6
Good 5
Poor 4
I would like to do with another column on the same table another query similar to the following so two queries using one sql statement like the following:
Health Count Diet Count
----------- ----- ----- -----
Very Good 6 Very Good 6
Good 5 Good 4
Poor 4 Poor 3
UPDATE!!
Hello this is how the table looks like at the moment
ID Diet Health
----------- ----- -------
101 Very Good Very Good
102 Poor Good
103 Poor Poor
I would like to do with another column on the same table another query similar to the following so two queries using one sql statement like the following:
Health Count Diet Count
----------- ----- ----- -----
Very Good 2 Very Good 1
Poor 1 Good 1
Good 0 Poor 1
Can anyone please help me out with this one?
Can provide further clarification if needed!

Answer 1

Here are 2 different ways of doing it, notice i removed the redundant column:
Test data:
DECLARE #t table(Health varchar(20), Diet varchar(20))
INSERT #t values
('Very good', 'Very good'),
('Poor', 'Good'),
('Poor', 'Poor')
Query 1:
;WITH CTE1 as
(
SELECT Health, count(*) CountHealth
FROM #t --[Health].[Questionaire]
GROUP BY health
), CTE2 as
(
SELECT Diet, count(*) CountDiet
FROM #t --[Health].[Questionaire]
GROUP BY Diet
)
SELECT
coalesce(Health, Diet) Grade,
coalesce(CountHealth, 0) CountHealth,
coalesce(CountDiet, 0) CountDiet
FROM CTE1
FULL JOIN
CTE2
ON CTE1.Health = CTE2.Diet
ORDER BY CountHealth DESC
Result 1:
Grade CountHealth CountDiet
Poor 2 1
Very good 1 1
Good 0 1
Mixing the results like that is really not good practice, so here is a different solution
Query 2:
SELECT Health, count(*) Count, 'Health' Grade
FROM #t --[Health].[Questionaire]
GROUP BY health
UNION ALL
SELECT Diet, count(*) CountDiet, 'Diet'
FROM #t --[Health].[Questionaire]
GROUP BY Diet
ORDER BY Grade, Count DESC
Result 2:
Health Count Grade
Good 1 Diet
Poor 1 Diet
Very good 1 Diet
Poor 2 Health
Very good 1 Health

Answer 2

You need to join the table to itself, but (as your sample data shows) to deal with gaps in actual data for specific values.
If you have a table that has the range of health/diet values:
select
v.value Status,
count(a.id) healthCount,
count(b.id) DietCount
from health_diet_values v
left join Questionaire a on a.health = v.value
left join Questionaire b on b.diet = v.value
group by v.value
or if you don't have such a table, you need to generate the list of values manually and join from that:
select
v.value Status,
count(a.id) healthCount,
count(b.id) DietCount
from (select 'Very Good' value union all
select 'Good' union all
select 'Poor') v
left join Questionaire a on a.health = v.value
left join Questionaire b on b.diet = v.value
group by v.value
Both of these queries produce zeroes if there is no matching data for the value.
Note that in your desired output you have a redundant column - you repeat the value column. The above queries produce output that looks like:
Status HealthCount DietCount
-------------------------------
Very Good 2 1
Good 1 1
Poor 0 1