Objective-C NSArray remove object duplicates based on function - objective-c

Question

It is clear from this question that there are many ways to remove duplicates from an NSArray when the array's elements are primitive types, or when the elements are perfect duplicates. But, is there a way to remove duplicates based on a transformation applied to each element, as is permitted in Underscore.js's uniq function, rather than by simply comparing the whole elements? And if a manual implementation would be difficult to optimize, is there an efficient system-provided method (or 3rd party library algorithm) for accomplishing this that I am missing?

Answer 1

A simple approach:
NSMutableArray* someArray = something;
for (int i = someArray.count - 1; i > 0; i--) {
MyObject* myObject = someArray[i];
for (int j = 0; j < i; j++) {
MyObject* myOtherObject = someArray[j];
if ([myObject isSortaEqual:myOtherObject]) {
[someArray removeObjectAtIndex:i];
break;
}
}
}
Yes, it's N-squared, but that's not a biggie unless the array is fairly large.

Answer 2

If you want to redefine what equality means for your objects, then consider overriding -hash and -isEqual:. Then you can create an NSSet from your array if order is irrelevant, or an NSOrderedSet if it is relevant. Here's an example of a Person class where I want the name of the person to determine object equality.
#interface Person
#property (nonatomic, copy) NSString *name;
#end
#implementation Person
- (BOOL)isEqual:(id)object
{
Person *otherPerson = (Person *)object;
return [self.name isEqualToString:otherPerson.name];
}
- (NSUInteger)hash
{
return [self.name hash];
}
#end
Uniquing them now is rather easy:
NSArray *people = ...;
// If ordered is irrelevant, use an NSSet
NSSet *uniquePeople = [NSSet setWithArray:people];
// Otherwise use an NSOrderedSet
NSOrderedSet *uniquePeople = [NSOrderedSet orderedSetWithArray:people];

Answer 3

Absolutely. You are looking for a way to pass your own method for testing for uniqueness (at least, that's what the uniq function you refer to does).
indexesOfObjectsPassingTest: will allow you to pass your own block to determine uniqueness. The result will be an NSIndexSet of all the objects in the array that matched your test. With that you can derive a new array. The block you are passing is roughly equivalent to the Underscore iterator passed to uniq.
The sister method, indexesOfObjectsWithOptions:passingTest: also allows you to specify enumeration options (i.e. concurrent, reverse order, etc.).
As you mention in your question, there are lots of ways to accomplish this. NSExpressions with blocks, Key-value coding collections operators, etc. could be used for this as well. indexesOfObjectsPassingTest: is probably the closest to what you seem to be looking for, though you can do much the same thing (with a lot more typing) using expressions.

Answer 4

I just came up against this problem, so I wrote a category on NSArray:
#interface NSArray (RemovingDuplicates)
- (NSArray *)arrayByRemovingDuplicatesAccordingToKey:(id (^)(id obj))keyBlock;
#end
#implementation NSArray (RemovingDuplicates)
- (NSArray *)arrayByRemovingDuplicatesAccordingToKey:(id (^)(id obj))keyBlock
{
NSMutableDictionary *temp = [NSMutableDictionary dictionaryWithCapacity:[self count]];
for (NSString *item in self) {
temp[keyBlock(item)] = item;
}
return [temp allValues];
}
#end
You can use it like this (this example removes duplicate words, ignoring case):
NSArray *someArray = #[ #"dave", #"Dave", #"Bob", #"shona", #"bob", #"dave", #"jim" ];
NSLog(#"result: %#", [someArray arrayByRemovingDuplicatesAccordingToKey:^(id obj){
return [obj lowercaseString];
}]);
Output:
2015-02-17 17:44:10.268 Untitled[4043:7711273] result: (
dave,
shona,
jim,
bob
)
The 'key' is a block that returns an identifier used to compare the objects. So if you wanted to remove Person objects according to their name, you'd pass ^(id obj){ return [obj name]; }.
This solution is O(n), so is suitable to large arrays, but doesn't preserve order.