How to insert and display Chinese character in oracle database? - sql

i have inserted Chinese character into oracle database. but the value is not suitable with the character, the value such as ¿¿ :¿¿¿!. the data type is varchar2. same problem when i want to display the data. How to store and display Chinese character into oracle 10g database ?

To support unicode character use driver Properties as shown :-
Class.forName("oracle.jdbc.driver.OracleDriver");
String url = "jdbc:oracle:thin:#10.52.45.36:1521:ORCL";
Properties connectionProps = new Properties();
connectionProps.put("useUnicode","true"); //Property 1
connectionProps.put("characterEncoding","UTF-8" ); //Property 2
connectionProps.put("user", "SYSTEM");
connectionProps.put("password", "Root-123");
Connection conn = DriverManager.getConnection(url,connectionProps);
Statement stmt = conn.createStatement();
And ensure that the datatype in the oracle table is NVARCHAR/NCHAR. Also, while inserting use function such as TO_NCHAR('-some-unicode-value-') or N'-some-unicode-value-'
This should be it!

Related

POSTGRES JSON: Updating array value in column

I am using POSTGRES SQL JSON.
In json column the value is stored as array which I want to update using SQL query
{"roles": ["Admin"]}
The output in table column should be
{"roles": ["SYSTEM_ADMINISTRATOR"]}
I tried different queries but it is not working.
UPDATE public.bo_user
SET json = jsonb_set(json, '{roles}', to_jsonb('SYSTEM_ADMINISTRATOR')::jsonb, true);
UPDATE public.bo_user
SET json = jsonb_set(json, '{roles}', to_jsonb('["SYSTEM_ADMINISTRATOR"]')::jsonb, true);
ERROR: could not determine polymorphic type because input has type unknown
SQL state: 42804
Kindly help me with the query
but at the moment it is to update the value at 0 index
That can be done using an index based "path" for jsonb_set()
update bo_user
set "json" = jsonb_set("json", '{roles,0}'::text[], '"SYSTEM_ADMINISTRATOR"')
where "json" #>> '{roles,0}' = 'Admin'
The "path" '{roles,0}' references the first element in the array and that is replaced with the constant "SYSTEM_ADMINISTRATOR"' Note the double quotes inside the SQL string literal which are required for a valid JSON string
The WHERE clause ensures that you don't accidentally change the wrong value.
So this worked.
UPDATE public.bo_user
SET json = jsonb_set(json, '{roles}', ('["SYSTEM_ADMINISTRATOR"]')::jsonb, true)
where id = '??';

Invalid number string (7498) JDBC Request

I'm converting this progress statement into SQL.
for each usr_mstr where usr_userid matches "PRF52" exclusive-lock:
assign usr_force_change = no.
end.
This is what I currently have.
UPDATE PUB.usr_mstr SET usr_force_change = 'false' WHERE usr_userid = 'PRF52'
The error that I am receiving is '[DataDirect][OpenEdge JDBC Driver][OpenEdge] Invalid number string (7498)'.
A select statement for this field is working and returns the following.
SELECT usr_force_change FROM PUB.usr_mstr WHERE usr_userid = 'PRF52'
usr_force_change
false
The column data type was of type 'LOGICAL'. This translates to type 'BIT' in SQL. I updated the statement to the following at it worked.
UPDATE PUB.usr_mstr SET usr_force_change = '0' WHERE usr_userid = 'PRF51'
You need to choose Query type as Update Statement when submit update
Update Statement - use this for Inserts and Deletes as well

Database Table Column is taken as String Value in Oracle Function in JSP

Select decrypt(PRODUCT_NUMBER,'123456789') as PRODUCT_NUMBER FROM Test
PRODUCT_NUMBER is a column in Test Table and contains Encrypted data Decrypt() is a function created and working fine.
When i run this Sql on Oracle SQL Developer it gives correct Result but when i run the same on JSP it gives me error on Function.
In JSP i call this by:
String sql = "Select decrypt(PRODUCT_NUMBER,'123456789') as PRODUCT_NUMBER FROM Test";
rs = conn.executeQuery(sql);
I think it takes PRODUCT_NUMBER as String ('PRODUCT_NUMBER') and Not as Column Name so it gives error.
java.sql.SQLException: ORA-01465: invalid hex number
This is the Decrypt Function
create or replace FUNCTION decrypt(p_raw IN RAW, p_key IN VARCHAR2) RETURN VARCHAR2 IS
v_retval RAW(255);
p_key2 RAW(255);
BEGIN
p_key2 := utl_raw.cast_to_raw(p_key);
dbms_obfuscation_toolkit.DES3Decrypt
(
input => p_raw,
key => p_key2,
which => 1,
decrypted_data => v_retval
);
RETURN RTRIM(utl_raw.cast_to_varchar2(v_retval), CHR(0));
END decrypt;
Solved!!
Query and Function both work perfect.
Actually My Co Developer had pointed the Connection to another replica instance of the DB that contained -1 in some columns so that's why it was giving error.
I reverted that and query worked like a charm.
Thanks for your time Everyone:)

Setting a Clob value in a native query

Oracle DB.
Spring JPA using Hibernate.
I am having difficulty inserting a Clob value into a native sql query.
The code calling the query is as follows:
#SuppressWarnings("unchecked")
public List<Object[]> findQueryColumnsByNativeQuery(String queryString, Map<String, Object> namedParameters)
{
List<Object[]> result = null;
final Query query = em.createNativeQuery(queryString);
if (namedParameters != null)
{
Set<String> keys = namedParameters.keySet();
for (String key : keys)
{
final Object value = namedParameters.get(key);
query.setParameter(key, value);
}
}
query.setHint(QueryHints.HINT_READONLY, Boolean.TRUE);
result = query.getResultList();
return result;
}
The query string is of the format
SELECT COUNT ( DISTINCT ( <column> ) ) FROM <Table> c where (exact ( <column> , (:clobValue), null ) = 1 )
where "(exact ( , (:clobValue), null ) = 1 )" is a function and "clobValue" is a Clob.
I can adjust the query to work as follows:
SELECT COUNT ( DISTINCT ( <column> ) ) FROM <Table> c where (exact ( <column> , to_clob((:stringValue)), null ) = 1 )
where "stringValue" is a String but obviously this only works up to the max sql string size (4000) and I need to pass in much more than that.
I have tried to pass the Clob value as a java.sql.Clob using the method
final Clob clobValue = org.hibernate.engine.jdbc.ClobProxy.generateProxy(stringValue);
This results in a java.io.NotSerializableException: org.hibernate.engine.jdbc.ClobProxy
I have tried to Serialize the Clob using
final Clob clob = org.hibernate.engine.jdbc.ClobProxy.generateProxy(stringValue);
final Clob clobValue = SerializableClobProxy.generateProxy(clob);
But this appears to provide the wrong type of argument to the "exact" function resulting in (org.hibernate.engine.jdbc.spi.SqlExceptionHelper:144) - SQL Error: 29900, SQLState: 99999
(org.hibernate.engine.jdbc.spi.SqlExceptionHelper:146) - ORA-29900: operator binding does not exist
ORA-06553: PLS-306: wrong number or types of arguments in call to 'EXACT'
After reading some post about using Clobs with entities I have tried passing in a byte[] but this also provides the wrong argument type (org.hibernate.engine.jdbc.spi.SqlExceptionHelper:144) - SQL Error: 29900, SQLState: 99999
(org.hibernate.engine.jdbc.spi.SqlExceptionHelper:146) - ORA-29900: operator binding does not exist
ORA-06553: PLS-306: wrong number or types of arguments in call to 'EXACT'
I can also just pass in the value as a String as long as it doesn't break the max string value
I have seen a post (Using function in where clause with clob parameter) which seems to suggest that the only way is to use "plain old JDBC". This is not an option.
I am up against a hard deadline so any help is very welcome.
I'm afraid your assumptions about CLOBs in Oracle are wrong. In Oracle CLOB locator is something like a file handle. And such handle can be created by the database only. So you can not simply pass CLOB as bind variable. CLOB must be somehow related to database storage, because this it can occupy up to 176TB and something like that can not be held in Java Heap.
So the usual approach is to call either DB functions empty_clob() or dbms_lob.create_temporary (in some form). Then you get a clob from database even if you think it is "IN" parameter. Then you can write as many data as you want into that locator (handle, CLOB) and then you can use this CLOB as a parameter for a query.
If you do not follow this pattern, your code will not work. It does not matter whether you use JPA, SpringBatch or plan JDBC. This constrain is given by the database.
It seems that it's required to set type of parameter explicitly for Hibernate in such cases. The following code worked for me:
Clob clob = entityManager
.unwrap(Session.class)
.getLobHelper()
.createClob(reader, length);
int inserted = entityManager
.unwrap(org.hibernate.Session.class)
.createSQLQuery("INSERT INTO EXAMPLE ( UUID, TYPE, DATA) VALUES (:uuid, :type, :data)")
.setParameter("uuid", java.util.Uuid.randomUUID(), org.hibernate.type.UUIDBinaryType.INSTANCE)
.setParameter("type", java.util.Uuid.randomUUID(), org.hibernate.type.StringType.INSTANCE)
.setParameter("data", clob, org.hibernate.type.ClobType.INSTANCE)
.executeUpdate();
Similar workaround is available for Blob.
THE ANSWER: Thank you both for your answers. I should have updated this when i solved the issue some time ago. In the end I used JDBC and the problem disappeared in a puff of smoke!

multiple parameter "IN" prepared statement

I was trying to figure out how can I set multiple parameters for the IN clause in my SQL query using PreparedStatement.
For example in this SQL statement, I'll be having indefinite number of ?.
select * from ifs_db where img_hub = ? and country IN (multiple ?)
I've read about this in
PreparedStatement IN clause alternatives?
However I can't figure it out how to apply it to my SQL statement above.
There's not a standard way to handle this.
In SQL Server, you can use a table-valued parameter in a stored procedure and pass the countries in a table and use it in a join.
I've also seen cases where a comma-separated list is passed in and then parsed into a table by a function and then used in a join.
If your countries are standard ISO codes in a delimited list like '#US#UK#DE#NL#', you can use a rather simplistic construct like:
select * from ifs_db where img_hub = ? and ? LIKE '%#' + country + '#%'
Sormula will work for any data type (even custom types). This example uses int's for simplicity.
ArrayList<Integer> partNumbers = new ArrayList<Integer>();
partNumbers.add(999);
partNumbers.add(777);
partNumbers.add(1234);
// set up
Database database = new Database(getConnection());
Table<Inventory> inventoryTable = database.getTable(Inventory.class);
ArrayListSelectOperation<Inventory> operation =
new ArrayListSelectOperation<Inventory>(inventoryTable, "partNumberIn");
// show results
for (Inventory inventory: operation.selectAll(partNumbers))
System.out.println(inventory.getPartNumber());
You could use setArray method as mentioned in the javadoc below:
http://docs.oracle.com/javase/6/docs/api/java/sql/PreparedStatement.html#setArray(int, java.sql.Array)
Code:
PreparedStatement statement = connection.prepareStatement("Select * from test where field in (?)");
Array array = statement.getConnection().createArrayOf("VARCHAR", new Object[]{"AA1", "BB2","CC3"});
statement.setArray(1, array);
ResultSet rs = statement.executeQuery();