Regular expression Oracle - sql
I am learning to use regular expressions and I'm using them to limit the results of a search query by using the REGEXP_LIKE in Oracle 11. Placing an example of the data available, I have the following:
Plan navegación 200 MB
Plan navegación 1 GB
Plan navegación 1 GB
Plan de navegacion 3G
Plan de navegacion 4G
Plan de navegacion 3G Empresarial
Plan de navegacion 4G Empresarial
Plan de servicios 3G
Plan de servicios 4G
Plan navegación Datos
I want this result is limited to the following (Only 3G, 4G):
Plan de navegacion 3G
Plan de navegacion 4G
Plan de navegacion 3G Empresarial
Plan de navegacion 4G Empresarial
I am using the following search pattern but I did not properly filtered results:
Upper(PLAN_GSM),'(NAVEGA){1}|(3G|4G|5G)'
Upper(PLAN_GSM),'((NAVEGA)+)(3G|4G)+'
I have done several tests and do not find the solution. Someone could give me hints?
You could simply use LIKE, as below:
select *
from mytable
where PLAN_GSM LIKE 'Plan de navegacion _G%';
or use REGEXP_LIKE, as below:
select *
from mytable
where REGEXP_LIKE(PLAN_GSM, '^Plan de navegacion (3|4|5)G(*)');
SQL Fiddle demo
Reference:
Oracle/PLSQL: REGEXP_LIKE Condition on Tech on the Net
You can use this:
SELECT * FROM mytable
WHERE REGEXP_LIKE(mycolumn, '\APlan de navegacion \dG.*\z', 'c');
\d represents a digit
\A is the beginning of the string
.* greedily matches any characters
\z is the end of the string
select *
from all_tab_columns
where COLUMN_NAME like '%MAIN%ACCOUNT%LINK%CODE%N%' and TABLE_NAME like 'CB%' and not regexp_like(table_name,'[0-9]')
The above query will fetch the only object without number of content.
select *
from all_tab_columns
where COLUMN_NAME like '%MAIN%ACCOUNT%LINK%CODE%N%' and TABLE_NAME like 'CB%' and not regexp_like(table_name,'[0-9]')
The above query will fetch only object with numbers content.
Related
How to get Sql Text for every username [duplicate]
I need to see the queries that are being sent to Oracle to execute them. Can someone give me specific detailed instructions on how to do this ?
If you want to see the queries from a specific user, you can use this (assuming you have privileges to query v$session and v$sqlarea (usually through SELECT_CATALOG_ROLE) SELECT sess.sid, sess.username, sqla.optimizer_mode, sqla.hash_value, sqla.address, sqla.cpu_time, sqla.elapsed_time, sqla.sql_text FROM v$sqlarea sqla, v$session sess WHERE sess.sql_hash_value = sqla.hash_value AND sess.sql_address = sqla.address AND sess.username = 'SCOTT' Replace SCOTT with the appropriate username in your system Output: 544 SCOTT ALL_ROWS 2004330732 07000001064088E8 89391 131836 SELECT sess.sid, sess.username, sqla.optimizer_mode, sqla.h ash_value, sqla.address, s qla.cpu_time, sqla.elapsed_time, sqla.sql_text FROM v$sqlarea sq la, v$session sess WHERE sess.sql_hash_ value = sqla.hash_value AND sess.sql_ address = sqla.address AND sess.usern ame = 'SCOTT'
This query will show queries that are currently running: select sql_text from v$sqlarea where users_executing > 0; See documentation of V$SQLAREA
You can check and get the data if you have access to these two oracle tables/views (v$sqlarea & v$sqltext), Also accoridng to your need you can also modify the query and add A.cpu_time, A.elapsed_time if required. Query - SELECT A.SQL_ID, A.FIRST_LOAD_TIME, A.SQL_TEXT, A.SQL_FULLTEXT FROM v$sqlarea A, v$sqltext B WHERE A.PARSING_SCHEMA_NAME = 'TESTUSER' --YOUR USERNAME AND A.SQL_ID = B.SQL_ID AND A.HASH_VALUE = B.HASH_VALUE ORDER BY A.FIRST_LOAD_TIME DESC Output -
sql substr variable url extraction process
Context: till now i uses to use regexp in sql to extract variable urls. I find it very slow and want to optimize it using substr and instr commands. That's important for me cause as i'm new in sql it serves me to be more familiar with such commands. database: my db is made by posts extracted from social platforms. text are called "titre". It contains variables url in different formats: www, http, https. I want to create a table or table view (i m not fixed) containing those url and the related id_post. My work: I have noticed that url always ends with a blank space, sthg like: "toto want to share with you this www.example.com in his post" here stands what i ve done so far: ---longueur de la chaîne de caractère depuis https select LENGTH(substr(titre, INSTR(titre,'https:'))) from post_categorised_pages where id_post = '280853248721200_697941320345722'; ---longueur de la chaîne de caractère depuis le blanc select LENGTH(substr(titre, INSTR(titre,' ', 171))) from post_categorised_pages where id_post = '280853248721200_697941320345722'; --- différence pour obtenir la longueur de chaîne de caractères de l'url select LENGTH(substr(titre, INSTR(titre,'https:'))) - LENGTH(substr(titre, INSTR(titre,' ', 171))) as longueur_url from post_categorised_pages where id_post = '280853248721200_697941320345722'; ---url select substr(titre, 171, 54)from post_categorised_pages where id_post = '280853248721200_697941320345722'; Question: How can i automotasize that over the whole table "post_categorised_page"? Can i introduce case when statements to take into account https or http of www. and how can i do that? Thanks a lot!!!!
Maybe, instead of the "HTTP", HTTPS" or "WWW" string you would need to have the name of a column. In this case, probably, it would be helpful to have a definition table where to define all possible sources. This tabel to have 2 columns (ID and source_name). Then, in your post_categorised_pages table, to insert also the source of the message (the ID value). Then, into the query, to join with this definition table by ID and, instead of select substr(titre, INSTR(titre,'https:'), (LENGTH(substr(titre, INSTR(titre,'https:'))) - LENGTH(substr(titre, INSTR(titre,' ', (INSTR(titre,'https:')))))))from post_categorised_pages where id_post = '280853248721200_697941320345722'; to have select substr(titre, INSTR(titre,"definition table".source_name), (LENGTH(substr(titre, INSTR(titre,"definition table".source_name))) - LENGTH(substr(titre, INSTR(titre,' ', (INSTR(titre,"definition table".source_name)))))))from post_categorised_pages where id_post = '280853248721200_697941320345722';
Ok guys, here is the solution i have found (there is stil one mistake, see at end of post). I use two views to finally extract my strings. First view is create by a connect by request: --- create intermediate table view with targeted pattern position create or replace view Start_Position_Index as with "post" as (select id, text from "your_table" where id= 'xyz') select id, instr(text,'#', 1, level) as position, text from post connect by level <= regexp_count(titre, '#'); then --- create working table view with full references and blank position for each pattern match and string_lenght for each one create or replace view _#_index as select id, position as hashtag_pos, INSTR(text,' ', position) as blank_position, INSTR(text,' ', position) - position as string_length, text from Start_Position_Index; At the end you will be able to retrieve the hashtags (in that case) you were looking for in your string. Ok so the mistakes: - if the pattern you are looking for is at the end of your string it will retrieve a null value cause there will be no blank space (as it is at end of the string). - it is not well optimized cause here i am working with views and not tables. I think using tables will be faster. But i m pretty sure there is lots of things to do in order to optimize this code... any idea? The challenge were how to extract specific pattern recursively among strings whithout using costy regex and without using pl/sql stuff. What do you think of that?
How about using Oracle Full Text search? This will index all the words from the column and will provide the hashtags or web addresses, as both are written in one word, without space in between.
FullText Contains "AND DO"
I found a weird issue with a query that uses FullText index. The following query #1 SELECT * FROM tbparticipant where contains([FullTextQuery],'ALINE AND NASCIMENTO') returns ALINE DO NASCIMENTO ALINE QUEIROZ DO NASCIMENTO ALINE NASCIMENTO DE SOUZA ALINE CORREIA DO NASCIMENTO But this query #2 SELECT * FROM tbparticipant where contains([FullTextQuery],'ALINE AND DO') returns nothing. I thought it would be a problem with "DO" being too short, but this query #3 SELECT * FROM tbparticipant where contains([FullTextQuery],'ALINE AND DE') returns ALINE NASCIMENTO DE SOUZA So, what's wrong with the query #2?
"Do" is on stopword list - stopwords are words considered to common or to short to have any significant meaning for full text queries. You can list your stopwords for english language like this: select * from sys.fulltext_system_stopwords where language_id = 1033 Reference: http://msdn.microsoft.com/en-us/library/ms142551.aspx
Why is this query not working for number 1?
this query returns 5 results as expected select * from [SalesLogix].[sysdba].[LEAD] where USERFIELD1 like '0' but this query returns nothing select * from [SalesLogix].[sysdba].[LEAD] where USERFIELD1 like '1' the USERFIELD1 is a varchar 80 field Here is all the data that is in the DB and as you can see there are two records with USERFIELD1 = '1' but there seems to be a line break after them...maybe that is causing the issue...is there anyway to grab those two records LEADID,CREATEUSER,CREATEDATE,MODIFYUSER,MODIFYDATE,ACCOUNTMANAGERID,ASSIGNDATE,BUSINESSDESCRIPTION,COMPANY,COMPANY_UC,CREDITRATING,DATAQUALITY,DESCRIPTION,DIVISION,DONOTSOLICIT,EMAIL,EMPLOYEES,FAX,FIRSTNAME,HOMEPHONE,IMPORTID,IMPORTSOURCE,INDUSTRY,INTERESTS,ISPRIMARY,LASTCALLDATE,LASTNAME,LASTNAME_UC,LEADSOURCEID,MIDDLENAME,MOBILE,NEXTCALLDATE,NOTES,PREFERRED_CONTACT,PREFIX,PRIORITY,QUALIFICATION_CATEGORYID,REVENUE,SECCODEID,SICCODE,STATUS,SUFFIX,TICKER,TITLE,TOLLFREE,TYPE,USERFIELD1,USERFIELD2,USERFIELD3,USERFIELD4,USERFIELD5,USERFIELD6,USERFIELD7,USERFIELD8,USERFIELD9,USERFIELD10,WEBADDRESS,WORKPHONE,LEAD_ADDRESSID,DONOTEMAIL,DONOTFAX,DONOTMAIL,DONOTPHONE Q134915558 ,U6UJ9A00000S,2011-09-20 17:36:10.053,U6UJ9A00000S,2011-09-20 17:36:10.053,NULL,2011-09-20 17:36:10.053,NULL,Johndoe,JOHNDOE,NULL,NULL,NULL,NULL,0,test#gmail.com,NULL,NULL,Harry,NULL,NULL,NULL,NULL,Restaurant Pro Express demo download,T,NULL,Scott,SCOTT, ,NULL,NULL,NULL,this is from the site,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,1 ,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4075559999,QQ134915558 ,NULL,NULL,NULL,NULL Q39769667 ,U6UJ9A00000S,2011-09-20 17:46:18.103,U6UJ9A00000S,2011-09-20 17:46:18.103,NULL,2011-09-20 17:46:18.103,NULL,scaoo,SCAOO,NULL,NULL,NULL,NULL,0,harry333#harry.com,NULL,NULL,upper2,NULL,NULL,NULL,NULL,Aldelo for Restaurants demo download,T,NULL,Scott,SCOTT,L6UJ9A000004,NULL,NULL,NULL,this is a download,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,0,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4074615519,QQ39769667 ,NULL,NULL,NULL,NULL Q488888476 ,U6UJ9A00000S,2011-09-20 17:49:28.963,U6UJ9A00000S,2011-09-20 17:49:28.963,NULL,2011-09-20 17:49:28.963,NULL,Johndoe,JOHNDOE,NULL,NULL,NULL,NULL,0,markus#gmail.com,NULL,NULL,upper,NULL,NULL,NULL,sales,posnation.com online demo request,T,NULL,Scott,SCOTT,L6UJ9A000004,NULL,NULL,NULL,this is from upper,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,0,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4074615519,QQ488888476 ,NULL,NULL,NULL,NULL Q504845720 ,U6UJ9A00000S,2011-09-20 17:06:10.053,U6UJ9A00000S,2011-09-20 17:06:10.053,U6UJ9A00000G,2011-09-20 17:06:10.053,NULL,Rafner ext.,RAFNER EXT.,NULL,NULL,NULL,NULL,0,raf#raf.com,NULL,NULL,James,4075615519,NULL,NULL,sales,NULL,NULL,NULL,Rafner,RAFNER, ,NULL,NULL,NULL,Raf associates is asking a question,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,QQ504845720 ,NULL,NULL,NULL,NULL Q539171226 ,U6UJ9A00000S,2011-09-20 17:49:28.963,U6UJ9A00000S,2011-09-20 17:49:28.963,NULL,2011-09-20 17:49:28.963,NULL,scaoo,SCAOO,NULL,NULL,NULL,NULL,0,harry333#harry.com,NULL,NULL,upper3,NULL,NULL,NULL,NULL,Aldelo for Restaurants demo download,T,NULL,Scott,SCOTT,L6UJ9A000004,NULL,NULL,NULL,this is a download,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,0,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4074615519,QQ539171226 ,NULL,NULL,NULL,NULL Q547088411 ,U6UJ9A00000S,2011-09-20 17:46:18.103,U6UJ9A00000S,2011-09-20 17:46:18.103,NULL,2011-09-20 17:46:18.103,NULL,Johndoe,JOHNDOE,NULL,NULL,NULL,NULL,0,markus#gmail.com,NULL,NULL,upper,NULL,NULL,NULL,sales,posnation.com online demo request,T,NULL,Scott,SCOTT,L6UJ9A000004,NULL,NULL,NULL,this is from upper,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,0,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4074615519,QQ547088411 ,NULL,NULL,NULL,NULL Q913526837 ,U6UJ9A00000S,2011-09-20 17:36:10.053,U6UJ9A00000S,2011-09-20 17:36:10.053,NULL,2011-09-20 17:36:10.053,NULL,Johndoe,JOHNDOE,NULL,NULL,NULL,NULL,0,test#gmail.com,NULL,NULL,Parry,NULL,NULL,NULL,NULL,Restaurant Pro Express demo download,T,NULL,Scott,SCOTT, ,NULL,NULL,NULL,this is from the site agan,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,1 ,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,4075559999,QQ913526837 ,NULL,NULL,NULL,NULL Q925684753 ,U6UJ9A00000S,2011-09-21 09:36:10.420,U6UJ9A00000S,2011-09-21 09:36:10.420,NULL,2011-09-21 09:36:10.420,NULL,POSfasion,POSFASION,NULL,NULL,NULL,NULL,0,sdfa#ss.com,NULL,NULL,Maria,NULL,NULL,NULL,NULL,Aldelo for Restaurants demo download,T,NULL,becker4,BECKER4,L6UJ9A000004,NULL,NULL,NULL,this is another lead from the live site,NULL,NULL,NULL,NULL,NULL,SYST00000001,NULL,New,NULL,NULL,NULL,NULL,NULL,0,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,7778889999,QQ925684753 ,NULL,NULL,NULL,NULL
If there are characters after the 1 in the userField1 then try using a wildcard, as shown below. select * from [SalesLogix].[sysdba].[LEAD] where USERFIELD1 like '1%' Also the statement you wrote select * from [SalesLogix].[sysdba].[LEAD] where USERFIELD1 like '1' Is essentially equivalent to select * from [SalesLogix].[sysdba].[LEAD] where USERFIELD1 = '1' You may want to read up on using the LIKE clause http://msdn.microsoft.com/en-us/library/ms179859.aspx
Use where USERFIELD1 = '1 ' You don't need LIKE as you aren't using any wild cards.
You're using LIKE wrong. Put a wildcard or a pattern in there or use an = operator. Your data seems malformed.
Try a like with the value surrounded by a wildcard ie USERFIELD1 like '1%' Should sort out whatever problem you're having if it is related to the line break field
SQL Server 2008 full-text search doesn't find word in words?
In the database I have a field with a .mht file. I want to use FTS to search in this document. I got this working, but I'm not satisfied with the result. For example (sorry it's in dutch, but I think you get my point) I will use 2 words: zieken and ziekenhuis. As you can see, the phrase 'zieken' is in the word 'ziekenhuis'. When I search on 'ziekenhuis' I get about 20 results. When I search on 'zieken' I get 7 results. How is this possible? I mean, why doesn't the FTS resturn the minimal results which I get from 'ziekenhuis'? Here's the query I use: SELECT DISTINCT d.DocID 'Id', d.Titel, (SELECT afbeeldinglokatie FROM tbl_Afbeelding WHERE soort = 'beleid') as Pic, 'belDoc' as DocType FROM docs d JOIN kpl_Document_Lokatie dl ON d.DocID = dl.DocID JOIN HandboekLokaties hb ON dl.LokatieID = hb.LokatieID WHERE hb.InstellingID = #instellingId AND ( FREETEXT(d.Doel, #searchstring) OR FREETEXT(d.Toepassingsgebied, #searchstring) OR FREETEXT(d.HtmlDocument, #searchstring) OR FREETEXT (d.extraTabblad, #searchstring) ) AND d.StatusID NOT IN( 1, 5)
I would suggest that you look at using the CONTAINS predicate, as opposed to FREETEXT Usage scenarios, including what you wish to achieve, can be found in the examples section of the documentation. From your description, I believe that you are attempting to perform a "Prefix" search. For example: USE AdventureWorks; GO SELECT Name FROM Production.Product WHERE CONTAINS(Name, ' "SearchTerm*" '); GO This will provide you a result set containing all words that "contain" the prefix search term.