I would like to send the date format from the database as Month/Day only. I've already stored the date in a table, now I want to send it like this format. The SQL I have is:
CONVERT(VARCHAR(15),date,102) AS date
Which sends MM/DD/YYYY. My question is what is the code to send MM/DD only?
Try this:
SELECT convert(varchar,DATEPART(mm,date_column)) + '/' +
convert(varchar,DATEPART(dd,date_column)) from your_table
SQL Fiddle Link
Related
I need help in figuring out the date conversion logic in Snowflake. The documentation isn't clear enough on this.
In SQL Server, I would try
SELECT CONVERT(DATE, '20200730', 101)
and it gives me '07/30/2020'.
If I try the following in Snowflake,
to_varchar('20200730'::date, 'mm/dd/yyyy')
it gives me '08/22/1970'. Why would it give an entire different date? Need help in getting the logic with the correct date.
The issue with what you are doing is that you are assuming that Snowflake is converting your string of '20200730'::DATE to 2020-07-03. It's not. You need to specify your input format of a date. So, 2 options based on your question being a bit vague:
If you have a string in a table and you wish to transform that into a date and then present it back as a formatted string:
SELECT TO_VARCHAR(TO_DATE('20200730','YYYYMMDD'),'MM/DD/YYYY');
--07/30/2020
If the field in the table is already a date, then you just need to apply the TO_VARCHAR() piece directly against that field.
Unlike SQL Server, Snowflake stores date fields in the same format regardless of what you provide it. You need to use the TO_VARCHAR in order to format that date in a different way...or ALTER SESSION SET DATE_OUTPUT_FORMAT will also work.
Try select to_varchar(TO_DATE( '20200730', 'YYYYMMDD' ), 'MM/DD/YYYY'); which produces 2020-07-30
You may need to refer to https://docs.snowflake.com/en/user-guide/date-time-input-output.html#timestamp-formats
I am trying to extract the date from a sentence like the below in SQL Server:
CC - Date of Pay - 7/26/2019;
Ideally, I would like to extract the date into its own column called DateofPay
Please try this code bellow :
SELECT SUBSTRING(RIGHT(`sentence`,10),1,9) as NewDate
For some reason (I have no control over this) dates are stored as Integers in an iSeries AS400 DB2 system that I need to query. E.g. today will be stored as:
20,171,221
Being in the UK I need it to be like the below in Date format:
21/12/2017
This is from my query: (OAORDT = date field)
Select
Date(SUBSTR( CHAR( OAORDT ),7,2) ||'/' || SUBSTR(CHAR ( OAORDT ),5,2) || '/' || SUBSTR(CHAR (OAORDT ),1,4)) AS "Order Date"
from some.table
However, all I get is Nulls. If I remove the Date function, then it does work but its now a string, which I don't want:
Select
SUBSTR( CHAR( OAORDT ),7,2) ||'/' || SUBSTR(CHAR ( OAORDT ),5,2) || '/' || SUBSTR(CHAR (OAORDT ),1,4) AS "Order Date"
from some.table
How do I convert the OAORDT field to Date?
Just to update - I will be querying this from MS SQL Server using an OpenQuery
Thanks.
1) How do I convert the OAORDT field to Date?
Simplest is to use TIMESTAMP_FORMAT :
SELECT DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD'))
2) Being in the UK I need it to be [...] in Date format 21/12/2017 :
SELECT VARCHAR_FORMAT(DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD')),'DD/MM/YYYY')
Note, you didn't specify where you are doing this, but since you tagged as ibm-midrange, I am answering for embedded SQL. If you want JDBC, or ODBC, or interactive SQL, the concept is similar, just the means of achieving it is different.
Make sure SQL is using dates in the correct format, it defaults to *ISO. For you it should be *EUR. In RPG, you can do it this way:
exec sql set option *datfmt = *EUR;
Make sure that set option is the first SQL statement in your program, I generally put it immediately between D and C specs.
Note that this is not an optimal solution for a program. Best practice is to set the RPG and SQL date formats both to *ISO. I like to do that explicitly. RPG date format is set by
ctl-opt DatFmt(*ISO);
SQL date format is set by
exec sql set option *datfmt = *ISO;
Now all internal dates are processed in *ISO format, and have no year range limitation (year can be 0001 - 9999). And you can display or print in any format you please. Likewise, you can receive input in any format you please.
Edit Dates are a unique beast. Not every language, nor OS knows how to handle them. If you are looking for a Date value, the only format you need to specify is the format of the string you are converting to a Date. You don't need to (can't) specify the internal format of the Date field, and the external format of a Date field can be mostly anything you want, and different each time you use it. So when you use TIMESTAMP_FORMAT() as #Stavr00 mentioned:
DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD'))
The format provided is not the format of the Date field, but the format of the data being converted to a Timestamp. Then the Date() function converts the Timestamp value into a Date value. At this point format doesn't matter because regardless of which external format you have specified by *DATFMT, the timestamp is in the internal timestamp format, and the date value is in the internal date format. The next time the format matters is when you present the Date value to a user as a string or number. At that point the format can be set to *ISO, *EUR, *USA, *JIS, *YMD, *MDY, *DMY, or *JUL, and in some cases *LONGJUL and the *Cxxx formats are available.
Since none of variants suited my needs I've came out with my own.
It is as simple as:
select * from yourschema.yourtable where yourdate = int(CURRENT DATE - 1 days) - 19000000;
This days thing is leap year-aware and suits most needs fine.
Same way days can be turned to months or years.
No need for heavy artillery like VARCHAR_FORMAT/TIMESTAMP_FORMAT.
Below worked for me:
select date(substring(trim(DateCharCol), 1, 2)||'/'||substring(trim(DateCharCol), 3, 2)||'/'||'20'||substring(trim(DateCharCol), 5, 2)) from yourTable where TableCol =?;
I have a Oracle table where there is one date-time field.
On select query i am able to get all the field values but not timefield value in my .net application.
select abc.Id, abc.Name, abc.When from details abc where abc.Id='"+1234+"'
Could anyone suggest me.
The format of the returned DATE field from Oracle depends upon your default NLS settings in the database.
Oracle stores dates (and times) in an internal representation and when you select the date values you can then format them as you need. An official Oracle explaination is here.
To force the format you can explicitly convert the date to a string representation using:
select abc.Id,
abc.Name,
TO_CHAR(abc.When, 'DD-MON-YYYY HH24:MI:SS') AS when
from details abc
where abc.Id='"+1234+"'
If you are ONLY wanting the time portion of the WHEN column then:
select abc.Id,
abc.Name,
TO_CHAR(abc.When, 'HH24:MI:SS') AS when
from details abc
where abc.Id='"+1234+"'
This will then return it as a string rather than a date and time which may or may not be OK for you depending upon what you then want to do with it.
The format you choose for the date and time could be any of the Oracle date and time formats, see here.
Hope it helps...
I have two columns. ColA and ColB contains char(10) with data "20090520" and "20090521".
I want to select and get the date difference in days. I have tried using Format() and CDate()
but MS Access always display as #ERROR.
Access prefers its dates in this format:
#2009-12-01#
You can convert your date to something Access understands with:
CDate(Format([ColA], "0000-00-00"))
Or alternatively:
DateSerial(Left([ColA],4),Mid([ColA],5,2),Right([ColA],2))
And to display the result in your preferred format:
Format(<date here>, "dd-mm-yyyy")
Try using DateSerial() to convert the dates:
DateSerial(Left([FieldName],4),Mid([FieldName],5,2),Right([FieldName],2))
If at all possible, change the datatype to a date datatype. You should not store dates as character data.
I am connecting to another database which I have no control on. That is why this problem occurred. Thanks for the feedback.