I want to have the following result:
| # | Country | Percent | Nb bookings |
| 1 | France | 20% | 10 bookings |
| 2 | Canada | 80% | 8 bookings |
My actual db are like that:
Table 1: ___Kardex
KDX_Id (exemple 9)
...
KDX_PostalAddress_Country (example: FR)
Table 2: ___Bookings
BOO_Id
BOO_ClientId (link with table 1, = 9)
Table 3: ___CountryList
CTY_Code (link with table 1, = FR)
CTY_en (should show France)
My SQL query in PDO is the following:
SELECT KDX_PostalAddress_Country,
COUNT(KDX_Id) * 100 /
(SELECT COUNT(KDX_Id)
FROM ___Kardex) AS KDX_CountryPercentage,
COUNT(KDX_Id) AS KDX_CountryCount
FROM ___Kardex
WHERE KDX_HotelId=:hotel_id
GROUP BY KDX_PostalAddress_Country
ORDER BY KDX_CountryPercentage DESC
But I can't get the country name (CTY_en), just it code (KDX_PostalAddress_Country).
I have try to insert an INNER JOIN without success.
INNER JOIN ___CountryList
ON ___Kardex.KDX_PostalAddress_Country=___CountryList.CTY_Code
Could you please help me to solve this problem ?
Thanks a lot.
Have you tried this?
SELECT CTY_en,
COUNT(KDX_Id) * 100 /
(SELECT COUNT(KDX_Id)
FROM ___Kardex) AS KDX_CountryPercentage,
COUNT(KDX_Id) AS KDX_CountryCount
FROM ___Kardex
INNER JOIN ___CountryList
ON ___Kardex.KDX_PostalAddress_Country=___CountryList.CTY_Code
WHERE KDX_HotelId=:hotel_id
GROUP BY KDX_PostalAddress_Country
ORDER BY KDX_CountryPercentage DESC
Related
I'm trying to get the sum of two columns, but it seems to be adding incorrectly. I have a table Tbl_Booths and another table called Tbl_Extras.
In the Tbl_Booths:
BoothId | ExhId | BoothPrice
1 | 1 | 400
2 | 1 | 500
3 | 2 | 400
4 | 3 | 600
So totalBoothPrice for ExhId = 1 is 900
Tbl_Extras:
ExtraId | ExhId | Item | ItemCost
1 | 1 | PowerSupply | 400
2 | 2 | PowerSupply | 400
3 | 1 | Lights | 600
4 | 3 | PowerSupply | 400
5 | 4 | Lights | 400
So totalItemCost for ExhId = 1 is 1000
I need to find a way to get the sum of totalBoothPrice + totalItemCost
The value should of course be 900 + 1000 = 1900
I'm a total beginner to SQL so please have patience :-)
Thank you in advance for any input you can give me, since I'm going made here !
It is used in a Caspio database system.
You can use union all to combine the two tables and then aggregate:
select exhid, sum(price)
from ((select exhid, boothprice as price
from tbl_booths
) union all
(select exhid, itemcost as price
from tbl_extras
)
) e
group by exhid;
This returns the sum for all exhid values. If you want to filter them, then you can use a where clause in either the outer query or both subqueries.
Here is a db<>fiddle.
Booth totals:
select exhid, sum(boothprice) as total_booth_price
from tbl_booths
group by exhid;
Extra totals:
select exhid, sum(itemcost) as total_item_cost
from tbl_extras
group by exhid;
Joined:
select
exhid,
b.total_booth_price,
e.total_item_cost,
b.total_booth_price + e.total_item_cost as total
from
(
select exhid, sum(boothprice) as total_booth_price
from tbl_booths
group by exhid
) b
join
(
select exhid, sum(itemcost) as total_item_cost
from tbl_extras
group by exhid
) e using (exhid)
order by exhid;
This only shows exhids that have both booth and extras, though. If one can be missing use a left outer join. If one or the other can be missing, you'd want a full outer join, which MySQL doesn't support.
I still tried select all customers which is in two group. Duplicate from customers is normal because select is from invoice but I need to know the customers who had a group in the first half year and jumped to another in the second half year.
Example:
SELECT
f.eankod as kod, --(groups)
ad.kod as firma, --(markComp)
f.nazfirmy as nazev, --(nameComp)
COUNT(ad.kod),
sum(f.sumZklZakl + f.sumZklSniz + f.sumOsv) as cena_bez_dph --(Price)
FROM
ddoklfak as f
LEFT OUTER JOIN aadresar ad ON ad.idfirmy = f.idfirmy
WHERE
f.datvyst >= '2017-01-01'
and f.datvyst <= '2017-12-31'
and f.modul like 'FAV'
GROUP BY
f.eankod,
ad.kod,
f.nazfirmy
HAVING COUNT (ad.kod) > 1
order by
ad.kod
Result:
GROUP markcomp nameComp price
| D002 | B5846 | Cosmopolis | price ... |
| D003 | B6987 | Tismotis | price ... |
| D009 | B8974 | Teramis | price ... |
| D006 | B8876 | Kesmethis | price ... | I need this, same company but diferent group, because this
| D008 | B8876 | Kesmethis | price ... | company jumped. I need know only jumped company. (last two rows from examples)
Thx for help.
You can use a CTE to find out which nameComp show up multiple times, and keep those ones only. For example:
with
x as (
-- your query
)
select * from x where nameComp in (
select nameComp from x group by nameComp having count(*) > 1
)
I've got these two tables:
___Subscriptions
|--------|--------------------|--------------|
| SUB_Id | SUB_HotelId | SUB_PlanName |
|--------|--------------------|--------------|
| 1 | cus_AjGG401e9a840D | Free |
|--------|--------------------|--------------|
___Rooms
|--------|-------------------|
| ROO_Id | ROO_HotelId |
|--------|-------------------|
| 1 |cus_AjGG401e9a840D |
| 2 |cus_AjGG401e9a840D |
| 3 |cus_AjGG401e9a840D |
| 4 |cus_AjGG401e9a840D |
|--------|-------------------|
I'd like to select the SUB_PlanName and count the rooms with the same HotelId.
So I tried:
SELECT COUNT(*) as 'ROO_Count', SUB_PlanName
FROM ___Rooms
JOIN ___Subscriptions
ON ___Subscriptions.SUB_HotelId = ___Rooms.ROO_HotelId
WHERE ROO_HotelId = 'cus_AjGG401e9a840D'
and
SELECT
SUB_PlanName,
(
SELECT Count(ROO_Id)
FROM ___Rooms
Where ___Rooms.ROO_HotelId = ___Subscriptions.SUB_HotelId
) as ROO_Count
FROM ___Subscriptions
WHERE SUB_HotelId = 'cus_AjGG401e9a840D'
But I get empty datas.
Could you please help ?
Thanks.
You need to use GROUP BY whenever you do some aggregation(here COUNT()). Below query will give you the number of ROO_ID only for the SUB_HotelId = 'cus_AjGG401e9a840D' because you have this condition in WHERE. If you want the COUNTs for all Hotel_IDs then you can simply remove the WHERE filter from this query.
SELECT s.SUB_PlanName, COUNT(*) as 'ROO_Count'
FROM ___Rooms r
JOIN ___Subscriptions s
ON s.SUB_HotelId = r.ROO_HotelId
WHERE r.ROO_HotelId = 'cus_AjGG401e9a840D'
GROUP BY s.SUB_PlanName;
To be safe, you can also use COUNT(DISTINCT r.ROO_Id) if you don't want to double count a repeating ROO_Id. But your table structures seem to have unique(non-repeating) ROO_Ids so using a COUNT(*) should work as well.
I'm stucking for a solution at the problem of finding daily profits from db (ms access) table. The difference wrt other tips I found online is that I don't have in the table a field "Price" and one "Cost", but a field "Type" which distinguish if it is a revenue "S" or a cost "C"
this is the table "Record"
| Date | Price | Quantity | Type |
-----------------------------------
|01/02 | 20 | 2 | C |
|01/02 | 10 | 1 | S |
|01/02 | 3 | 10 | S |
|01/02 | 5 | 2 | C |
|03/04 | 12 | 3 | C |
|03/03 | 200 | 1 | S |
|03/03 | 120 | 2 | C |
So far I tried different solutions like:
SELECT
(SELECT SUM (RS.Price* RS.Quantity)
FROM Record RS WHERE RS.Type='S' GROUP BY RS.Data
) as totalSales,
(SELECT SUM (RC.Price*RC.Quantity)
FROM Record RC WHERE RC.Type='C' GROUP BY RC.Date
) as totalLosses,
ROUND(totalSales-totaleLosses,2) as NetTotal,
R.Date
FROM RECORD R";
in my mind it could work but obviously it doesn't
and
SELECT RC.Data, ROUND(SUM (RC.Price*RC.QuantitY),2) as DailyLoss
INTO #DailyLosses
FROM Record RC
WHERE RC.Type='C' GROUP BY RC.Date
SELECT RS.Date, ROUND(SUM (RS.Price*RS.Quantity),2) as DailyRevenue
INTO #DailyRevenues
FROM Record RS
WHERE RS.Type='S'GROUP BY RS.Date
SELECT Date, DailyRevenue - DailyLoss as DailyProfit
FROM #DailyLosses dlos, #DailyRevenues drev
WHERE dlos.Date = drev.Date";
My problem beyond the correct syntax is the approach to this kind of problem
You can use grouping and conditional summing. Try this:
SELECT data.Date, data.Income - data.Cost as Profit
FROM (
SELECT Record.Date as Date,
SUM(IIF(Record.Type = 'S', Record.Price * Record.Quantity, 0)) as Income,
SUM(IIF(Record.Type = 'C', Record.Price * Record.Quantity, 0)) as Cost,
FROM Record
GROUP BY Record.Date
) data
In this case you first create a sub-query to get separate fields for Income and Cost, and then your outer query uses subtraction to get actual profit.
For a project I want to generate a price list.
I want to get only the latest prices from each supplier for each article.
There are just those two tables.
Table articles
ARTNR | TXT | ACTIVE | SUPPLIER
------------------------------------------
10 | APPLE | Y | 10
20 | ORANGE | Y | 10
30 | KEYBOARD | N | 20
40 | ORANGE | Y | 20
50 | BANANA | Y | 10
60 | CHERRY | Y | 10
Table prices
ARTNR | PRCGRP | PRCDAT | PRICE
--------------------------------------
10 | 10 | 01-Aug-10 | 2.1
10 | 10 | 05-Aug-11 | 2.2
10 | 10 | 21-Aug-12 | 2.5
20 | 0 | 01-Aug-10 | 2.1
20 | 10 | 09-Aug-12 | 2.3
10 | 10 | 14-Aug-13 | 2.7
This is what I have so far:
SELECT
ARTICLES.[ARTNR], ARTICLES.[TXT], ARTICLES.[ACTIVE], ARTICLES.[SUPPLIER], PRICES.PRCGRP, PRICES.PRCDAT, PRICES.PRICE
FROM
ARTICLES INNER JOIN PRICES ON ARTICLES.ARTNR = PRICES.ARTNR
WHERE
(
(ARTICLES.[ACTIVE]="Y") AND
(ARTICLES.[SUPPLIER]=10) AND
(PRICES.PRCGRP=0) AND
(PRICES.PRCDAT=(SELECT MAX(PRCDAT) FROM PRICES as art WHERE art.ARTNR = PRICES.artnr) )
)
ORDER BY ARTICLES.ARTNR
;
It is okay to choose just one supplier each time, but I want the max price.
The problem is:
Lots of articles do not show up with the query above,
but I cannot figure out what is wrong.
I can see that they should be in the resultset when I leave out the subselect on max prcdat.
What is wrong?
Your subquery to get the latest price does not take the other conditions into account, that is when you're getting the latest price, you may get a price in another price group or that is not active. When you join that against the filtered list that has no inactive prices and only prices in a single price group, you get no hits that exist in both.
Either you need to duplicate or - better - move your conditions inside the subquery to get the best price under the conditions. I can't test against access, but something like this should be possible if the SQL is not too limited;
SELECT a.artnr, a.txt, a.active, a.supplier, p.prcgrp, p.prcdat, p.price
FROM articles a INNER JOIN prices p ON a.ARTNR = p.ARTNR
JOIN (
SELECT a.artnr, MAX(p.prcdat) prcdat
FROM articles a JOIN prices p ON a.artnr = p.artnr
WHERE a.active='Y' AND a.supplier=10 AND p.prcgrp=10
GROUP BY a.artnr) z
ON a.artnr = z.artnr AND p.prcdat = z.prcdat
ORDER BY a.ARTNR
If the SQL support in access won't allow a join with a subquery, you can just move the conditions inside your existing subquery, something like;
SELECT a.artnr, a.txt, a.active, a.supplier, p.prcgrp, p.prcdat, p.price
FROM articles a INNER JOIN prices p ON a.ARTNR = p.ARTNR
WHERE p.prcdat = (
SELECT MAX(p2.prcdat)
FROM articles a2 JOIN prices p2 ON a2.artnr = p2.artnr
WHERE a.artnr = a2.artnr AND a2.active='Y' AND a2.supplier=10 AND p2.prcgrp=10
)
ORDER BY a.ARTNR;
Note that due to limitations in identifying a unique price (no primary key in prices), the queries may give duplicates if several prices for the same article have the same prcdat. If that's a problem, you'll probably need to duplicate your conditions outside the subquery too.