I have a string like this:
+COPS:0,0,"XL",2 or +CSQ: "15",99
How can I get "XL" or "15" from the string.
On the second one, I've tried using replace and remove +CSQ: and ,99 but I can't do this on the first one.
For the first string use String.Split to split on commas then String.Trim to remove the quotes:
Dim line = "+COPS:0,0,""XL"",2"
' Split fields on comma
Dim fields = line.Split(",")
' Quote literal
Dim quote = """"c
' Use trim to remove quotes
Dim value = fields(2).Trim(quote)
Same spirit as #Phillip Trelford but avoiding one step splitting on quotes :
Dim line = "+COPS:0,0,""XL"",2"
' Split fields on quotes
Dim fields = line.Split(""""c)
Dim value = fields(1)
One liner function :
Public Function getValue(ByVal from As String) As String
Return from.Split(""""c)(1)
End Function
You could use Regular expressions for that task.
For example :
Dim stringtoscan = yourstringhere
Dim expression As New Text.RegularExpressions.Regex(Chr(34) + "(.*?)" + Chr(34))
Dim stringMatches = expression .Matches(stringtoscan)
Related
I have a file name like below:
sub_fa__hotchkis_type1a__180310__PUO4x4__180813
I want to separate it with double underscores "__" and using this code:
Dim MdlNameArr() As String = Path.GetFileNameWithoutExtension(strProjMdlName).Split(New Char() {"__"}, StringSplitOptions.RemoveEmptyEntries)
myTool.Label9.Text = MdlNameArr(1).ToString
I expect the result will be "hotchkis_type1a" but it returns "fa".
It doesnt recognize single underscore "_".
Is there any method to use it properly?
You need to split on a string rather than just a character, so if we look at the available overloads for String.Split, we find the nearest one to that is String.Split(string(), options) which takes an array of strings as the separators and requires the inclusion of StringSplitOptions like this:
Dim s = "sub_fa__hotchkis_type1a__180310__PUO4x4__180813"
Dim separators() As String = {"__"}
Dim parts = s.Split(separators, StringSplitOptions.None)
If parts.Length >= 2 Then
Console.WriteLine(parts(1))
Else
Console.WriteLine("Not enough parts found.")
End If
Outputs:
hotchkis_type1a
I want to filter out other characters from a string as well as split the remaining numbers with periods.
This is my string: major.number=9minor.number=10revision.number=0build.number=804
and this is the expected output: 9.10.0.804
Any suggestions?
As to my comment, if your text is going to be constant you can use String.Split to remove the text and String.Join to add your deliminators. Quick example using your string.
Sub Main()
Dim value As String = "major.number=9minor.number=10revision.number=0build.number=804"
Dim seperator() As String = {"major.number=", "minor.number=", "revision.number=", "build.number="}
Console.WriteLine(String.Join(".", value.Split(seperator, StringSplitOptions.RemoveEmptyEntries)))
Console.ReadLine()
End Sub
If your string does not always follow a specific pattern, you could use Regex.Replace:
Sub Main()
Dim value as String = "major.number=9minor.number=10revision.number=0build.number=804"
Dim version as String = Regex.Replace(value, "\D*(\d+)\D*", "$1.") ' Run the regex
version = version.Substring(0, version.Length - 1) ' Trim the last dot
End
Note you should Imports System.Text.RegularExpressions.
net 2.0 and need to split the last / mark of the string. Currently I have a code that says Dim test As String = "Software\Microsoft\Windows\Welcome" and need a code that will split that Software\Microsoft\Windows\Welcome into two separate section at the end
So I'll have Software\Microsoft\Windows and Welcome as new strings.
I can only find things that will split the beginning from the rest like
Dim whole As String = "Software/Microsoft/Windows/Run"
Dim firstpart As String = whole.Substring(0, whole.IndexOf("/"))
Dim lastpart As String = whole.Substring(whole.IndexOf("/") + 1)`
Use String.LastIndexOf()
Dim whole As String = "Software/Microsoft/Windows/Run"
Dim firstpart As String = whole.Substring(0, whole.LastIndexOf("/"))
Dim lastpart As String = whole.Substring(whole.LastIndexOf("/") + 1)
Try splitting with '\' As your delimeter and store it as a string array. Then just grab the last element and it should be "Welcome".
I have this string:
Dim stringToCleanUp As String = "bon;jour"
Dim characterToRemove As String = ";"
I want a function who removes the ';' character like this:
Function RemoveCharacter(ByVal stringToCleanUp, ByVal characterToRemove)
...
End Function
What would be the function ?
ANSWER:
Dim cleanString As String = Replace(stringToCleanUp, characterToRemove, "")
Great, Thanks!
The String class has a Replace method that will do that.
Dim clean as String
clean = myString.Replace(",", "")
Function RemoveCharacter(ByVal stringToCleanUp, ByVal characterToRemove)
' replace the target with nothing
' Replace() returns a new String and does not modify the current one
Return stringToCleanUp.Replace(characterToRemove, "")
End Function
Here's more information about VB's Replace function
The string class's Replace method can also be used to remove multiple characters from a string:
Dim newstring As String
newstring = oldstring.Replace(",", "").Replace(";", "")
You can use the string.replace method
string.replace("character to be removed", "character to be replaced with")
Dim strName As String
strName.Replace("[", "")
These are valid characters:
a-z
A-Z
0-9
-
/
How do I remove all other characters from my string?
Dim cleanString As String = Regex.Replace(yourString, "[^A-Za-z0-9\-/]", "")
Use either regex or Char class functions like IsControl(), IsDigit() etc. Get a list of these functions here: http://msdn.microsoft.com/en-us/library/system.char_members.aspx
Here's a sample regex example:
(Import this before using RegEx)
Imports System.Text.RegularExpressions
In your function, write this
Regex.Replace(strIn, "[^\w\\-]", "")
This statement will replace any character that is not a word, \ or -. For e.g. aa-b#c will become aa-bc.
Dim txt As String
txt = Regex.Replace(txt, "[^a-zA-Z 0-9-/-]", "")
Function RemoveCharacter(ByVal stringToCleanUp)
Dim characterToRemove As String = ""
characterToRemove = Chr(34) + "#$%&'()*+,-./\~"
Dim firstThree As Char() = characterToRemove.Take(16).ToArray()
For index = 1 To firstThree.Length - 1
stringToCleanUp = stringToCleanUp.ToString.Replace(firstThree(index), "")
Next
Return stringToCleanUp
End Function
I've used the first solution from LukeH, but then realized that this code replaces the dot for extension, therefore I've just upgraded the code slightly:
Dim fileNameNoExtension As String = Path.GetFileNameWithoutExtension(fileNameWithExtension)
Dim cleanFileName As String = Regex.Replace(fileNameNoExtension, "[^A-Za-z0-9\-/]", "") & Path.GetExtension(fileNameWithExtension)
cleanFileName will the file name with no special characters with extension.