List the most recently hired employee in each department [closed] - sql

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I'am a trainee in sql, any help for this query,would be great.TIA.
select distinct jobtitle,max([HireDate]),LoginID from [HumanResources].[Employee] as e
where loginid in (select distinct LoginID from HumanResources.Employee
where JobTitle in (select distinct JobTitle from [HumanResources].[Employee]) )
group by JobTitle,LoginID;

If you are talking about a command line program this will work.
puts "Hello World"
or if you want an object oriented version
class HelloWorld
def initialize(name)
#name = name.capitalize
end
def sayHi
puts "Hello #{#name}!"
end
end
hello = HelloWorld.new("World")
hello.sayHi
If you are looking for a ruby on rails version of Hello World. Check the Getting Started Guide for Rails.

Related

Set SQL WHERE value using an element from a list [closed]

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I have a variable with a list on it and I need to use its value for my find option. I get an error when I set my id_user to id_u.
Here is the list
id_u = user_key[0]
This is my SELECT and WHERE
find = ("SELECT * FROM hashtags WHERE id_user=id_u")
You have to concatenate SELECT string with variable value.
Try like this:
id_u = user_key[0]
find = ("SELECT * FROM hashtags WHERE id_user=" + id_u)

Server SQL how to clean column using STUFF? [closed]

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608A
608 A
17113 R
16524 DC1
ASM-1780
234604A - Low L2 Cu
19658B-->
234605 - High L2 Cu
17015 Rev A 405734UD0A
43224A (W
23809 REVB
Is there an SQL server query that cleans the column above and removes the excess content on the right such that the data is converted to below:
608
608
17113
16524
ASM-1780
234604
19658
234605
17015
43224
23809
I have tried using STUFF, but it doesn't clean well.
You seem to want everything up to and including the first digit followed by a non-digit.
Well, this returns what you are asking for:
select str, left(str, patindex('%[0-9][^0-9]%', str + ' '))
Here is a db<>fiddle.

How to create a data frame from a text file [closed]

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I am having trouble creating a data frame with the following data:
Force (N) microstrain1 microstrain2 microstrain3 microstrain4 microstrain5
24.838 9.689 -20.299 19.785 15.601 -7.681
49.691 22.610 -40.797 41.304 32.200 -15.332
75.309 33.357 -61.678 62.512 48.726 -22.422
97.227 41.944 -80.524 81.011 62.266 -30.228
121.641 52.692 -100.775 100.703 77.248 -36.884
Every time I try to use a delimiter I get the following message:
/Users/macbookpro/PycharmProjects/Projects/Lab_3/Bending.py:5: ParserWarning: Falling back to the 'python' engine because the 'c' engine does not support regex separators (separators > 1 char and different from '\s+' are interpreted as regex); you can avoid this warning by specifying engine='python'.
df1 = pd.read_csv('MEE322-thurs_1040_group1_9.5cm.txt',delimiter=' ')
Did you try the python engine instead of the c engine?:
df1 = pd.read_csv('MEE322-thurs_1040_group1_9.5cm.txt', delimiter=' ', engine='python')

Restrict data to logged in user asp.net [closed]

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I am creating a medication ordering website as part on an assignment. I have a link table that contains the users id and medication id.
When a user is logged in I want them to see their medication only
SELECT [MedicineId] FROM [Prescription] WHERE ([PatientId] = #PatientId)
I have not created a log in yet because I dont want to log in every time im testing.
[![tables][2]][2]
You can use Session for a sample patient.
Session["PatientId"] = 1453;
var SqlQuery = "SELECT [MedicineId] FROM [Prescription] WHERE [PatientId] =" + Session["PatientId"].ToString();
With SQL Parameters
var SqlQuery = "SELECT [MedicineId] FROM [Prescription] WHERE [PatientId] = #PatientId";
var connection = new SqlConnection(/* your DB connection */);
var command = new SqlCommand(SqlQuery, connection);
command.Parameters.AddWithValue(
"PatientId", Session["PatientId"].ToString());

Julia list all functions provided by a module [closed]

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I'm looking for a Julia function which, when applied to a module name, lists the functions available through the module.
Basically, I don't want to scour through source code and I've noticed that the documentation for many modules usually doesn't have everything.
names works, mostly:
module MyMod
test() = 3
foo() = 4
end
names(MyMod, true)
gives me
4-element Array{Symbol,1}:
:eval
:test
:foo
:MyMod
Just need to strip out the module name and eval
Expanding on the previous answer slightly, the following seems to work:
function module_functions(modname)
list = Symbol[]
for nm in names(modname)
typeof(eval(nm)) == Function && push!(list,nm)
end
return list
end
Example:
using PyPlot
module_functions(PyPlot)
produces the following output in the REPL:
165-element Array{Symbol,1}:
:contourf
:over
:xticks
:ion
:flag
:summer
:stackplot
:tricontourf
:minorticks_on
:gray
:savefig
:errorbar
:box
:figure
:vlines
:subplot_tool
:jet
⋮
:locator_params
:imshow
:pie
:sci
:axhline
:streamplot
:hist2d
:copper
:text3D
:Axes3D
:loglog
:zticks
:hexbin
:pcolor
:semilogy
:thetagrids