Oracle: not a valid month - sql

I have a table with the following fields:
Reports (table name)
Rep_Date (date)
Rep_Time (date)
The Rep_Time field has values like '01/01/1753 07:30:00' i.e. the time part is relevant. I have written the following query:
select Reports.pid, MaxDate from Reports
INNER JOIN (
select pid, max(TO_DATE(TO_CHAR(REP_DATE, 'DD/MM/YYYY')
|| TO_CHAR(REP_TIME, 'HH24:MI:SS'), 'DD/MM/YYYY HH24:MI:SS')) As MaxDate
from reports
group by pid
) ReportMaxDate
on Reports.PID = ReportMaxDate.PID
AND To_Date(To_Char(MaxDate, 'DD/MM/YYYY')) = REP_DATE
WHERE REPORTS.PID=61
The derived table part of the query runs, but when I run the entire query I get an error: "not a valid month". Why is this?
In order to help debug this; if I run the following query:
select rep_date, rep_time from reports where pid=61 and rownum=1
I get:
Rep_Date = 01/04/2009
Rep_Time = 01/01/1753 13:00:00
UPDATE 15:58
I am now able to execute the following query:
select Reports.pid, MaxDate from Reports
INNER JOIN (
select pid, max(TO_DATE(TO_CHAR(REP_DATE, 'DD/MM/YYYY')
|| TO_CHAR(REP_TIME, 'HH24:MI:SS'), 'DD/MM/YYYY HH24:MI:SS')) As MaxDate
from reports group by pid
) ReportMaxDate
on Reports.PID = ReportMaxDate.PID
AND to_date(to_char(maxdate,'MM/DD/YYYY'),'MM/DD/YYYY') = REP_DATE
WHERE REPORTS.PID=61
However, I need to add one more statement to the WHERE clause comparing the time part of MaxDate to rep_time: to_date(to_char(maxdate,'MM/DD/YYYY'),'MM/DD/YYYY') = REP_DATE does not work.

1.
To_Date(To_Char(MaxDate, 'DD/MM/YYYY')) = REP_DATE
is causing the issue. when you use to_date without the time format, oracle will use the current sessions NLS format to convert, which in your case might not be "DD/MM/YYYY". Check this...
SQL> select sysdate from dual;
SYSDATE
---------
26-SEP-12
Which means my session's setting is DD-Mon-YY
SQL> select to_char(sysdate,'MM/DD/YYYY') from dual;
TO_CHAR(SY
----------
09/26/2012
SQL> select to_date(to_char(sysdate,'MM/DD/YYYY')) from dual;
select to_date(to_char(sysdate,'MM/DD/YYYY')) from dual
*
ERROR at line 1:
ORA-01843: not a valid month
SQL> select to_date(to_char(sysdate,'MM/DD/YYYY'),'MM/DD/YYYY') from dual;
TO_DATE(T
---------
26-SEP-12
2.
More importantly, Why are you converting to char and then to date, instead of directly comparing
MaxDate = REP_DATE
If you want to ignore the time component in MaxDate before comparision, you should use..
trunc(MaxDate ) = rep_date
instead.
==Update : based on updated question.
Rep_Date = 01/04/2009 Rep_Time = 01/01/1753 13:00:00
I think the problem is more complex. if rep_time is intended to be only time, then you cannot store it in the database as a date. It would have to be a string or date to time interval or numerically as seconds (thanks to Alex, see this) . If possible, I would suggest using one column rep_date that has both the date and time and compare it to the max date column directly.
If it is a running system and you have no control over repdate, you could try this.
trunc(rep_date) = trunc(maxdate) and
to_char(rep_date,'HH24:MI:SS') = to_char(maxdate,'HH24:MI:SS')
Either way, the time is being stored incorrectly (as you can tell from the year 1753) and there could be other issues going forward.

To know the actual date format, insert a record by using sysdate. That way you can find the actual date format. for example
insert into emp values(7936, 'Mac', 'clerk', 7782, sysdate, 1300, 300, 10);
now, select the inserted record.
select ename, hiredate from emp where ename='Mac';
the result is
ENAME HIREDATE
Mac 06-JAN-13
voila, now your actual date format is found.

You can also change the value of this database parameter for your session by using the ALTER SESSION command and use it as you wanted
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MM-YYYY';
SELECT TO_DATE('05-12-2015') FROM dual;
05/12/2015

You can customize as you wish the format inside the ''
SELECT TO_CHAR(column_name, 'MONTH-DAY-yy') FROM table_name;

Related

My TO_DATE seeming not to function properly

So I am trying to get the section id and the amount of students in that section who enrolled on 02/10/2007. The query returns no results when it should return 6 rows.
The date format its in already is DD-MON-YY.
This is what I have so far:
I took the TO_DATE from another query I did and it worked properly on. The query works without it so im sure its somthing to do with the TO_DATE
SELECT section_id, COUNT(student_id) "ENROLLED"
FROM enrollment
WHERE enroll_date = TO_DATE('2/10/2007', 'MM/DD/YYYY')
GROUP BY section_id
ORDER BY ENROLLED;
Most probably the issue is that there is a fractional date component that you are not taking into account. You can ignore that fractional date component by truncating the column in your query:
SELECT section_id, COUNT(student_id) "ENROLLED"
FROM enrollment
WHERE TRUNC(enroll_date) = TO_DATE('2/10/2007', 'MM/DD/YYYY')
GROUP BY section_id
ORDER BY ENROLLED;
I am assuming that the column enroll_date is of the data type DATE.
Some explanation: Oracle stores dates as described here, it does NOT store a date as you state "The date format its in already is DD-MON-YY.". That is only the format you see the date in, which is determined by the parameter NLS_DATE_FORMAT for your session.
Lets do a quick test with a test table. Create table and check the NLS_DATE_FORMAT form my session.
create table DATE_TST
( id NUMBER GENERATED BY DEFAULT ON NULL AS IDENTITY,
test_date DATE
);
INSERT INTO date_tst (test_date) VALUES (SYSDATE);
SELECT value
FROM nls_session_parameters
WHERE parameter = 'NLS_DATE_FORMAT';
DD-MON-YYYY
This is how I will see my dates.
SELECT * FROM date_tst;
04-OCT-2020
So I have todays date. Cool. Now lets see if I can query using that date:
SELECT * FROM date_tst WHERE test_date = TO_DATE('04-OCT-2020','DD-MON-YYYY');
no rows.
No rows are shown because the date format I get my date in does not have a time component. DATE has Year, month, day, hour, minute and seconds. The format only has year, month and day. Lets query the data to check if there is a time component.
SELECT TO_CHAR(test_date,'DD-MON-YYYY HH24:MI:SS') FROM date_tst;
4-OCT-2020 21:12:39
Ah there it is... SYSDATE is the current time up to the second. Now lets try that query again with a more precise date format:
SELECT * FROM date_tst WHERE test_date = TO_DATE('04-OCT-2020 21:12:39','DD-MON-YYYY HH24:MI:SS');
04-OCT-2020
And there is our row. The TRUNC command will cut off the time component:
SELECT TO_CHAR(TRUNC(test_date),'DD-MON-YYYY HH24:MI:SS') FROM date_tst;
04-OCT-2020 00:00:00
So you can simplify your query:
SELECT * FROM date_tst WHERE TRUNC(test_date) = TO_DATE('04-OCT-2020','DD-MON-YYYY');
04-OCT-2020
TO_DATE('2/10/2007', 'MM/DD/YYYY') gives you a date at midnight; however,this will only match values at that instant. What you need to do is either:
TRUNCate the dates in your column back to midnight so that your value matches (however, this will prevent you using an index on the column and you would need to use a function-based index); or
A better solution is to use a date range starting at midnight of the day you want to match and going up-to, but not including, midnight of the next day.
You can do this using TO_DATE or using a date literal:
SELECT section_id,
COUNT(student_id) "ENROLLED"
FROM enrollment
WHERE enroll_date >= DATE '2007-02-10'
AND enroll_date < DATE '2007-02-11'
GROUP BY section_id
ORDER BY ENROLLED;
As an aside:
The date format its in already is DD-MON-YY.
Assuming that the enroll_date column has a DATE data type then this has no format; it is a binary data type consisting of 7 bytes (for century, year-of-century, month, day, hour, minute and second).
What you are seeing is the default date format the user interface applies when it displays the binary date value to the user and you can change it using:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD"T"HH24:MI:SS';
(or to whatever format you want.)
This does not change the binary data stored in the column.

Filtering a dataset by date and time Oracle SQL through Power BI

I'm having trouble with filtering a date and time for anything two hours before and sooner. I tried this:
SELECT *
FROM
table
where
date >= sysdate - 1
AND
TO_DATE( Time, 'HH24:MI:SS' ) >= TO_DATE( sysdate, 'HH24:MI:SS' ) - 2
But I'm getting an inconsistent type error which is what I thought I was handling with the TO_DATE() function but I guess not.
sysdate is already a date (and time), so TO_DATE( sysdate, 'HH24:MI:SS' ) doesn't make any sense.
You didn't provide your data types for your date and time columns in table, so I'm going to assume they're both varchar2(10) with formats MM/DD/YYYY and HH24:MI:SS respectively.
I'm also going to go ahead and change your example table and column names, since they're invalid names to use in a real query.
-- example data
with my_table as (select '06/13/2019' as date_column, '09:40:34' as time_column from dual)
-- your query
SELECT *
FROM
my_table
where
to_date(date_column || ' ' || time_column, 'MM/DD/YYYY HH24:MI:SS') >= sysdate - 2/24
What I'm doing here is to combine your date and time strings into one date-time string, then converting it to an Oracle date type (actually date+time). Then we compare it to sysdate - 2/24, which says to take the current time and subtract 2/24ths of a day, which is 2 hours.
For this example, you might need to change the example data date_column and time_column values to something from the past 2 hours, depending on when you run this and what time zone you're in.

YYYYMMDD to YYYYMM in oracle

I have a column with DATE datatype in a table.
I am trying to retrieve the column values in YYYYMM format. My select query looks like below
select *
from tablename
where date column = to_char(to_date('12/31/4000','MM/DD/YYYY'),'YYYYMM');
I am getting below exception.
ORA-01847: day of month must be between 1 and last day of month
Appreciate any input on this.
I think the simplest method is:
where to_char(datecolumn, 'YYYYMM') = '400012'
Or, if you prefer:
where to_char(datecolumn, 'YYYYMM') = to_char(to_date('12/31/4000', 'MM/DD/YYYY'), 'YYYYMM');
Syntax-wise, the right hand date (to the right of the equals) is OK. But you are doing a character comparison, not a date comparison.
This works for me in multiple databases:
select to_char (to_date('12/31/4000','MM/DD/YYYY'),'YYYYMM')
from dual;
Even though your column is named DATE_COLUMN, you are comparing based on characters in the query.
So, try this instead - this compares based on dates (NOT a character comparison) and truncates off the hour, minute, ETC. so you are only comparing the DAY:
select * from DATE_TAB
where TRUNC(DATE1, 'DDD') = TRUNC(to_date('12/31/4000','MM/DD/YYYY'),'DDD');
NOTE: The DATE1 field above is a DATE field. If you're DATE_COLUMN is not a DATE field, you must
convert it to a DATE datatype first (using TO_DATE, ETC.)
Assuming that "date_column" is actually a date, and that you have an index on date_column, you can do something like this to return the data quickly (without truncating dates in all rows to do a comparison):
with dat as (
select level as id, sysdate - (level*10) as date_column
from dual
connect by level <= 100
)
select id, date_column
from dat
where date_column between to_date('11/1/2013', 'MM/DD/YYYY') and last_day(to_date('11/2013 23:59:59', 'MM/YYYY HH24:MI:SS'))
Here I just dummy up some data with dates going back a few years. This example picks all rows that have a date in the month of November 2013.
If your date_column's data-type is DATE, then use
select *
from tablename
where TO_CHAR(date_column,'YYYYMM') = to_char (to_date('12/31/4000','MM/DD/YYYY'),'YYYYMM');
If your date_column's data-type is VARCHAR, then use:
select *
from tablename
where date_column = to_char (to_date('12/31/4000','MM/DD/YYYY'),'YYYYMM');
I somehow feel your error is because you have a space between date and column as
"date column". If the field name in the table is "COLUMN", then just removing the word "DATE" from your original query would suffice, as:
select *
from tablename
where column = to_char(to_date('12/31/4000','MM/DD/YYYY'),'YYYYMM');
If your column (YYYYMMDD) is in number format, the simplest way to get YYYYMM would be
select floor(DATE/100)
from tablename;

How to select from SQL table WHERE a TIMESTAMP is a specific Date

Im trying to do a query where a TIMESTAMP field is = to a specific date but my query is not working:
The field is type TIMESTAMP(6) which I have only ever worked with DATE / DATETIME fields before. Here is example of a value stored here: 04-OCT-13 12.29.53.000000000 PM
Here is my SELECT statement:
SELECT * FROM SomeTable WHERE timestampField = TO_DATE('2013-10-04','yyyy-mm-dd')
I am retrieving no results and I am assuming it has to do with the fact that its not matching the TIME portion of the timestamp
If you want every record that occurs on a given day then this should work:
SELECT * FROM SomeTable
WHERE timestampField >= TO_TIMESTAMP( '2013-03-04', 'yyyy-mm-dd' )
AND timestampField < TO_TIMESTAMP( '2013-03-05', 'yyyy-mm-dd')
That will be likely to take advantage of an index on timestampField if it exists. Another way would be:
SELECT * FROM SomeTable
WHERE TRUNC(timestampField) = TO_DATE( '2013-03-04', 'yyyy-mm-dd' )
in which case you may want a function-based index on TRUNC(timestampField).
(Note that TRUNC applied to a TIMESTAMP returns a DATE.)

Select from table by knowing only date without time (ORACLE)

I'm trying to retrieve records from table by knowing the date in column contains date and time.
Suppose I have table called t1 which contains only two column name and date respectively.
The data stored in column date like this 8/3/2010 12:34:20 PM.
I want to retrieve this record by this query for example (note I don't put the time):
Select * From t1 Where date="8/3/2010"
This query give me nothing !
How can I retrieve date by knowing only date without the time?
DATE is a reserved keyword in Oracle, so I'm using column-name your_date instead.
If you have an index on your_date, I would use
WHERE your_date >= TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND your_date < TO_DATE('2010-08-04', 'YYYY-MM-DD')
or BETWEEN:
WHERE your_date BETWEEN TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND TO_DATE('2010-08-03 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
If there is no index or if there are not too many records
WHERE TRUNC(your_date) = TO_DATE('2010-08-03', 'YYYY-MM-DD')
should be sufficient. TRUNC without parameter removes hours, minutes and seconds from a DATE.
If performance really matters, consider putting a Function Based Index on that column:
CREATE INDEX trunc_date_idx ON t1(TRUNC(your_date));
Personally, I usually go with:
select *
from t1
where date between trunc( :somedate ) -- 00:00:00
and trunc( :somedate ) + .99999 -- 23:59:59
Convert your date column to the correct format and compare:
SELECT * From my_table WHERE to_char(my_table.my_date_col,'MM/dd/yyyy') = '8/3/2010'
This part
to_char(my_table.my_date_col,'MM/dd/yyyy')
Will result in string '8/3/2010'
You could use the between function to get all records between 2010-08-03 00:00:00:000 AND 2010-08-03 23:59:59:000
trunc(my_date,'DD') will give you just the date and not the time in Oracle.
Simply use this one:
select * from t1 where to_date(date_column)='8/3/2010'
Try the following way.
Select * from t1 where date(col_name)="8/3/2010"