I have date in database in this format 04-03-12 23:00:00. How I can convert it to this format 16.02.2012 and still user order by ? Because when I used to_char then order by doesnt work correctly
Dates are not stored with any for at - at least if you are using a DATE or TIMESTAMP format, which you really should be. You can just use the raw column in the order by, something like:
select to_char(date_field, 'DD.MM.YYYY')
from my_table
order by date_field;
If you have it stored as a VARCHAR, which I can't stress enough would be a bad thing, you'd have to convert to a date for the order by and to a DATE and back to a VARCHAR, something like:
select to_char(to_date(varchar_field, 'DD-MM-RR HH24:MI:SS'), 'DD.MM.YYYY')
from my_table
order by to_date(varchar_field, 'DD-MM-RR HH24:MI:SS')
Related
Been trying to figure out why the sorting is being done by the DD of the value which is in the format of DD-MON-YY and not on the YY.
SELECT MY_DATE
FROM MY_DB
ORDER BY MY_DATE DESC;
Originally I had some TO_CHAR and TO_DATE functions in this but now it is as basic as it can be and yet it is still not sorting as I would expect it to.
quick question on Oracle To_timestamp.
I have a two fields in a table that are both varchars
1 field contains the YYYYMMDD formatted value
the 2nd field contains the hh24mmss formatted value
Im trying to convert these two fields into a timestamp field,
expected output is DD/MM/YYYY HH24:mm:ss
like '7/23/2015 12:53:04'
however, it gaves me weird result...
like '7/15/0023 12:53:04'
seems year becomes day and day becomes year..
---------- heres my sql ----------------
select
to_date(to_char(to_date('20150723','yyyymmdd'),'yyyymmdd'),'yyyymmdd') dt,
to_char(to_date(SUBSTR('005304000',1,6), 'hh24miss'), 'hh24:mi:ss') tm,
TO_TIMESTAMP(
to_date(to_char(to_date('20150723','yyyymmdd'),'yyyymmdd'),'yyyymmdd') ||
to_char(to_date(SUBSTR('005304000',1,6), 'hh24miss'), 'hh24:mi:ss'), 'yyyy/mm/dd HH24:MI:SS' ) dttm
from dual
You have one layer to much in your conversion chain. And it will be much easier if you concatenate the two columns before converting them:
to_date(date_column||time_column, 'YYYYMMDDHH24MISS')
will return a date and a time (an Oracle DATE includes a time part).
Now that you have a proper date value, you can then format that as you want:
to_char(to_date(date_column||time_column, 'YYYYMMDDHH24MISS'), 'yyyy/mm/dd HH24:MI:SS')
As your "time" column doesn't contain milliseconds there is no real benefit in using to_timestamp.
But you should really fix your table, and store that information in a single DATE (or TIMESTAMP) column. Storing dates in varchar columns is always a very bad choice.
I have REPORTDATE column in database (DATETIME) type.
I want to extract only DATE value from the DATETIME, then to do COUNT for each day and to put WHERE clause to restrict only dates later than some specific date.
So I have this clause:
SELECT to_char(REPORTDATE, 'DD.MM.YYYY') AS MY, COUNT(*) from INCIDENT
where to_char(REPORTDATE, 'DD.MM.YYYY')>'09.11.2013'
GROUP BY to_char(REPORTDATE, 'DD.MM.YYYY')
It returns me results but but I can notice wrong result such as : 30.10.2013 which is wrong result.
How to solve this?
WHERE to_char(REPORTDATE, 'DD.MM.YYYY')>'09.11.2013'
You are comparing two STRINGS. You need to compare the DATEs. As I already said in the other answer here, you need to leave the date as it is for DATE calculations. TO_CHAR is for display, and TO_DATE is to convert a string literal into DATE.
SELECT TO_CHAR(REPORTDATE, 'DD.MM.YYYY'),
COUNT(*)
FROM TABLE
WHERE REPORTDATE > TO_DATE('09.11.2013', 'DD.MM.YYYY')
GROUP BY TO_CHAR(REPORTDATE, 'DD.MM.YYYY')
Also, REPORTDATE is a DATE column, hence it will have datetime element. So, if you want to exclude the time element while comparing, you need to use TRUNC
WHERE TRUNC(REPORTDATE) > TO_DATE('09.11.2013', 'DD.MM.YYYY')
However, applying TRUNC on the date column would suppress any regular index on that column. From performance point of view, better use a Date range condition.
For example,
WHERE REPORTDATE
BETWEEN
TO_DATE('09.11.2013', 'DD.MM.YYYY')
AND
TO_DATE('09.11.2013', 'DD.MM.YYYY') +1
The condition to_char(REPORTDATE, 'DD.MM.YYYY')>'09.11.2013' compare to strings, so 30.10.2013 is after 09.11.2013.
You need to compare the dates, not the string values, so you have to change your query to the following.
SELECT to_char(REPORTDATE, 'DD.MM.YYYY') AS MY, COUNT(1)
from INCIDENT
where trunc(REPORTDATE)> to_date('09.11.2013', 'DD.MM.YYYY')
GROUP BY to_char(REPORTDATE, 'DD.MM.YYYY')
Note: I added a little modification from count(*) to count(1) for optimize the query having the same results.
I have a date column in a table stored as MM/DD/YYYY format. I have to select and store the same date in another table in YYYY-MM-DD format i.e. XSD Date Format. But I am not able to do it. I am using this query:
select to_date(date_column,'YYYY-MM-DD') from table;
But still I am not able to do it. Giving me error
ORA-01843 : not a valid month
use
select to_char(date_column,'YYYY-MM-DD') from table;
It sounds like you've got it the wrong way round. If your existing data is in MM/DD/YYYY format, then you want:
select to_date(date_column,'MM/DD/YYYY') from table;
to convert the existing data to DATE values. (I do wonder why they're not stored as dates, to be honest...)
If you want to perform the conversion in one step, you might want:
select to_char(to_date(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD') from table;
In other words, for each row, parse it in MM/DD/YYYY format, then reformat it to YYYY-MM-DD format.
(I'd still suggest trying to keep data in its "natural" type though, rather than storing it as text in the first place.)
I assume that you can use the Oracle SQL Developer, which you can download from here.
You can define the date format which you want to work with:
ALTER SESSION SET nls_date_format='yyyy-mm-dd';
With this, now you can perform a query like this:
SELECT * FROM emp_company WHERE JDate = '2014-02-25'
If you want to be more specific you can define the date format like this:
ALTER SESSION SET nls_date_format='yyyy-mm-dd hh24:mi:ss';
To convert a DATE column to another format, just use TO_CHAR() with the desired format, then convert it back to a DATE type:
SELECT TO_DATE(TO_CHAR(date_column, 'DD-MM-YYYY'), 'DD-MM-YYYY') from my_table
select to_date(to_char(ORDER_DATE,'YYYY/MM/DD'))
from ORDERS;
This might help but, at the end you will get a string not the date. Apparently,
your format problem will get solved for sure .
For military time formatting,
select TO_CHAR(SYSDATE, 'yyyy-mm-dd hh24:mm:ss') from DUAL
--2018-07-10 15:07:15
If you want your date to round DOWN to Month, Day, Hour, Minute, you can try
SELECT TO_CHAR( SYSDATE, 'yyyy-mm-dd hh24:mi:ss') "full-date" --2018-07-11 10:40:26
, TO_CHAR( TRUNC(SYSDATE, 'year'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-year"-- 2018-01-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'month'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-month" -- 2018-07-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'day'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-Sunday" -- 2018-07-08 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'dd'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-day" -- 2018-07-11 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'hh'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-hour" -- 2018-07-11 10:00:00
, TO_CHAR( TRUNC(SYSDATE, 'mi'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-minute" -- 2018-07-11 10:40:00
from DUAL
For formats literals, you can find help in
https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions242.htm#SQLRF52037
You can do this simply by :
select to_char(to_date(date_column, 'MM/DD/YYYY'), 'YYYY-MM-DD') from table
According to the comments, the data-type in the datatable is DATE.
So you should simply use:
"select date_column from table;"
Now if you execute the select you will get back a date data-type, which should be what you need for the .xsd.
Culture-dependent formating of the date should be done in the GUI (most languages have convenient ways to do so), not in the select-statement.
Basically , Data in a Date column in Oracle can be stored in any user defined format or kept as default.
It all depends on NLS parameter.
Current format can be seen by : SELECT SYSDATE FROM DUAL;
If you try to insert a record and insert statement is NOT in THIS format then it will give :
ORA-01843 : not a valid month error.
So first change the database date format before insert statements ( I am assuming you have bulk load of insert statements) and then execute insert script.
Format can be changed by :
ALTER SESSION SET nls_date_format = 'mm/dd/yyyy hh24:mi:ss';
Also You can Change NLS settings from SQL Developer GUI , (Tools > preference> database > NLS)
Ref: http://oracle.ittoolbox.com/groups/technical-functional/oracle-sql-l/how-to-view-current-date-format-1992815
This worked for me! You can convert to datatype you want be it a date or string
to_char(TO_DATE(TO_CHAR(end_date),'MM-DD-YYYY'),'YYYY-MM-DD') AS end_date
Late reply but for.databse-date-type the following line works.
SELECT to_date(t.given_date,'DD/MM/RRRR') response_date FROM Table T
given_date's column type is Date
Just to piggy back off of Yahia, if you have a timestamp you can use this function to cast exclusively as date, removing the timestamps.
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYY-MM-DD') AS TrackerKey__C
Or in my case I need the below format
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYYMMDD') AS TrackerKey__C
SELECT TO_DATE(TO_CHAR(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD')
FROM table;
if you need to change your column output date format just use to_char this well get you a string, not a date.
use
SELECT STR_TO_DATE(date_column,'%Y-%m-%d') from table;
also gothrough
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html
I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy