In this table, column FeeComponent contains three types of value suppose a, b, c and regarding Amt having price.
A 40
A 20
B 30
B 20
B 40
c 60
Now I want Result in the form of a table like
A,B,C
Amount by FeeComponent-wise.
It's a single Table.
I tried Something like:
Select
(Select Amt from Trn_Clear where Amt='A') As 'A1',
(Select Amt From Trn_Clear where Amt='B') As 'B1'
From Trn_Clear
I think that what you wanna do is to pivot your table; in that case, if you are using SQL Server 2005, you should try something like this:
SELECT *
FROM (SELECT FeeComponent, Amt FROM Trn_Clear) AS S
PIVOT(SUM(Amt) FOR FeeComponent IN ([A],[B],[C])) AS PT
In this case, I use SUM as your aggregation function, but you could use the one you need (AVG,MIN,MAX). Hope this helps.
Related
Currently I have a table as my database, and I want to create a Bar Chart to of out the Reasons Column. This is an example of my table:
Table Name: Survey
id
reasons
1
a,b,c
2
a,d,e
3
b,c,d
How to count total amount of each reasons like this table below?
reasons
total
a
2
b
2
c
2
d
1
e
1
You would use string_split():
select s.value as reason, count(*)
from t cross apply
string_split(reasons, ',') s
group by s.value
order by s.value;
That said, you should fix your data model. You should have a separate table with one row per reason.
Sample data
CREATE TEMP TABLE a AS
SELECT id, adate::date, name
FROM ( VALUES
(1,'1/1/1900','test'),
(1,'3/1/1900','testing'),
(1,'4/1/1900','testinganother'),
(1,'6/1/1900','superbtest'),
(2,'1/1/1900','thebesttest'),
(2,'3/1/1900','suchtest'),
(2,'4/1/1900','test2'),
(2,'6/1/1900','test3'),
(2,'7/1/1900','test4')
) AS t(id,adate,name);
CREATE TEMP TABLE b AS
SELECT id, bdate::date, score
FROM ( VALUES
(1,'12/31/1899', 7 ),
(1,'4/1/1900' , 45),
(2,'12/31/1899', 19),
(2,'5/1/1900' , 29),
(2,'8/1/1900' , 14)
) AS t(id,bdate,score);
What I want
What I need to do is aggregate column text from table a where the id matches table b and the date from table a is between the two closest dates from table b. Desired output:
id date score textagg
1 12/31/1899 7 test, testing
1 4/1/1900 45 testinganother, superbtest
2 12/31/1899 19 thebesttest, suchtest, test2
2 5/1/1900 29 test3, test4
2 8/1/1900 14
My thoughts are to do something like this:
create table date_join
select a.id, string_agg(a.text, ','), b.*
from tablea a
left join tableb b
on a.id = b.id
*having a.date between b.date and b.date*;
but I am really struggling with the last line, figuring out how to aggregate only where the date in table b is between the closest two dates in table b. Any guidance is much appreciated.
I can't promise it's the best way to do it, but this is a way to do it.
with b_values as (
select
id, date as from_date, score,
lead (date, 1, '3000-01-01')
over (partition by id order by date) - 1 as thru_date
from b
)
select
bv.id, bv.from_date, bv.score,
string_agg (a.text, ',')
from
b_values as bv
left join a on
a.id = bv.id and
a.date between bv.from_date and bv.thru_date
group by
bv.id, bv.from_date, bv.score
order by
bv.id, bv.from_date
I'm presupposing you will never have a date in your table greater than 12/31/2999, so if you're still running this query after that date, please accept my apologies.
Here is the output I got when I ran this:
id from_date score string_agg
1 0 7 test,testing
1 92 45 testinganother,superbtest
2 0 19 thebesttest,suchtest,test2
2 122 29 test3,test4
2 214 14
I might also note that between in a join is a performance killer. IF you have large data volumes, there might be better ideas on how to approach this, but that depends largely on what your actual data looks like.
Fair warning: I'm new to using SQL. I do so on an Oracle server either via AQT or with SQL Developer.
As I haven't been able to think or search my way to an answer, I put myself in your able hands...
I'd like to combine data from table A (high quality data) with data from table B (fresh data) such that the entries from B are only included when the date stamp are later than those available from table A.
Both tables include entries from multiple entities, and the latest date stamp varies with those entities.
On the 4th of january, the tables may look something like:
A____________________________ B_____________________________
entity date type value entity date type value
X 1.jan 1 1 X 1.jan 1 2
X 1.jan 0 1 X 1.jan 0 2
X 2.jan 1 1 X 2.jan 1 2
Y 1.jan 1 1 (new entry)X 3.jan 1 1
Y 3.jan 1 1 Y 1.jan 1 2
Y 3.jan 1 2
(new entry)Y 4.jan 1 1
I have made an attempt at some code that I hope clarify my need:
WITH
AA AS
(SELECT entity, date, SUM(value)
FROM table_A
GROUP BY
entity,
date),
BB AS
(SELECT entity, date, SUM(value)
FROM table_B
WHERE date > ALL (SELECT date FROM AA)
GROUP BY
entity,
date
)
SELECT * FROM (SELECT * FROM AA UNION ALL SELECT * FROM BB)
Now, if the WHERE date > ALL (SELECT date FROM AA)would work seperately for each entity, I think have what I need.
That is, for each entity I want all entries from A, and only newer entries from B.
As the data in table A often differ from that of B (values are often corrected) I dont think I can use something like: table A UNION ALL (table B MINUS table A)?
Thanks
Essentially you are looking for entries in BB which do not exist in AA. When you are doing date > ALL (SELECT date FROM AA) this will not take into consideration the entity in question and you will not get the correct records.
Alternative is to use the JOIN and filter out all matching entries with AA.
Something like below.
WITH
AA AS
(SELECT entity, date, SUM(value)
FROM table_A
GROUP BY
entity,
date),
BB AS
(SELECT entity, date, SUM(value)
FROM table_B
LEFT OUTER JOIN AA
ON AA.entity = BB.entity
AND AA.DATE = BB.date
WHERE AA.date == null
GROUP BY
entity,
date
)
SELECT * FROM (SELECT * FROM AA UNION ALL SELECT * FROM BB)
I find your question confusing, because I don't know where the aggregation is coming from.
The basic idea on getting newer rows from table_b uses conditions in the where clause, something like this:
select . . .
from table_a a
union all
select . . .
from table_b b
where b.date > (select max(a.date) from a where a.entity = b.entity);
You can, of course, run this on your CTEs, if those are what you really want to combine.
Use UNION instead of UNION ALL , it will remove the duplicate records
SELECT * FROM (
SELECT *
FROM AA
UNION
SELECT *
FROM BB )
I have the following table which contains ID's and UserId's.
ID UserID
1111 11
1111 300
1111 51
1122 11
1122 22
1122 3333
1122 45
I'm trying to count the distinct number of 'IDs' so that I get a total, but I also need to get a total of ID's that have also seen the that particular ID as well... To get the ID's, I've had to perform a subquery within another table to get ID's, I then pass this into the main query... Now I just want the results to be displayed as follows.
So I get a Total No for ID and a Total Number for Users ID - Also would like to add another column to get average as well for each ID
TotalID Total_UserID Average
2 7 3.5
If Possible I would also like to get an average as well, but not sure how to calculate that. So I would need to count all the 'UserID's for an ID add them altogether and then find the AVG. (Any Advice on that caluclation would be appreciated.)
Current Query.
SELECT DISTINCT(a.ID)
,COUNT(b.UserID)
FROM a
INNER JOIN b ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999)
GROUP BY a.ID
Which then Lists all the IDs and COUNT's all the USERID.. I would like a total of both columns. I've tried warpping the query in a
SELECT COUNT(*) FROM (
but this only counts the ID's which is great, but how do I count the USERID column as well
You seem to want this:
SELECT COUNT(DISTINCT a.ID), COUNT(b.UserID),
COUNT(b.UserID) * 1.0 / COUNT(DISTINCT a.ID)
FROM a INNER JOIN
b
ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999);
Note: DISTINCT is not a function. It applies to the whole row, so it is misleading to put an expression in parentheses after it.
Also, the GROUP BY is unnecessary.
The 1.0 is because SQL Server does integer arithmetic and this is a simple way to convert a number to a decimal form.
You can use
SELECT COUNT(DISTINCT a.ID) ...
to count all distinct values
Read details here
I believe you want this:
select TotalID,
Total_UserID,
sum(Total_UserID+TotalID) as Total,
Total_UserID/TotalID as Average
from (
SELECT (DISTINCT a.ID) as TotalID
,COUNT(b.UserID) as Total_UserID
FROM a
INNER JOIN b ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999)
) x
I have a table with column a having not necessarily distinct values and column b having for each value of a a number of distinct values. I want to get a result having each value of a appearing only once and getting the first found value of b for that value of a. How do I do this in sql server 2000?
example table:
a b
1 aa
1 bb
2 zz
3 aa
3 zz
3 bb
4 bb
4 aa
Wanted result:
a b
1 aa
2 zz
3 aa
4 bb
In addition, I must add that the values in column b are all text values. I updated the example to reflect this.
Thanks
;with cte as
(
select *,
row_number() over(partition by a order by a) as rn
from yourtablename
)
select
a,b
from cte
where rn = 1
SQL does not know about ordering by table rows. You need to introduce order in the table structure (usually using an id column). That said, once you have an id column, it's rather easy:
SELECT a, b FROM test WHERE id in (SELECT MIN(id) FROM test GROUP BY a)
There might be a way to do this, using internal SQL Server functions. But this solution is portable and more easily understood by anyone who knows SQL.