Capture date from file name as a parameter then rename the file - vb.net

Question

Not sure if this is possible but each day a file will be sent to a folder: Z:\prod\DataProcessing\temp
The file name will look like this: 20230215_UniqueProductsFile.txt
I am wondering if it is possible to
a) search the folder for the version of the file with a date
b) capture the date to use as a parameter for another process
c) rename the file to UniqueProductsFile.txt overwriting the existing one in the folder from the previous days load
Any help would be appreciated.

Answer 1

a) search the folder for the version of the file with a date b) capture the date to use as a parameter for another process
This is possible using the IO.File.Exists method (documentation) to check if the file exists. For example:
Private Function UniqueProductsFileExistsByDate(directory As String, value As DateTime, ByRef output As String) As Boolean
Dim filename = $"{value:yyyyMMdd}_UniqueProductsFile.txt"
Dim path = IO.Path.Combine(directory, filename)
Dim fileExists = IO.File.Exists(path)
If (fileExists) Then
output = path
End If
Return fileExists
End Function
c) rename the file to UniqueProductsFile.txt
This is possible using IO.File.Move (documentation) where the first argument is the ByRef value set in the UniqueProductsFileExistsByDate method and the second argument is the new name:
Dim directory = IO.Path.Combine("Z:", "prod", "DataProcessing", "temp")
Dim value = DateTime.Today
Dim path As String
If (UniqueProductsFileExistsByDate(directory, value, path)) Then
Dim newPath = IO.Path.Combine(directory, "UniqueProductsFile.txt")
IO.File.Move(path, newPath)
End If