I am having an issue converting a date column in varchar format to date format in presto-sql. The date_column is in this format : '9/5/2022', '12/23/2022', '%null%' etc.
I have tried the following queries:
SELECT
DATE_PARSE(date_column, '%Y-%m-%d')
FROM table
SELECT
CAST(date_column AS DATE)
FROM table
And there is always this error popping up:
Caused by: io.prestosql.jdbc.$internal.client.FailureInfo$FailureException: Invalid format: "11/30/2022" is malformed at "/30/2022"
The provided format (see the docs) represents year, month, day separated by - while your data is in month, day, year separated by /. Change the format accordingly:
SELECT DATE_PARSE('11/30/2022', '%m/%d/%Y');
Output:
_col0
-------------------------
2022-11-30 00:00:00.000
Note that strings like '%null%' (not just null strings) will be invalid also. If you really have those - you should consider wrapping the parse call into try.
Related
I am trying to extract the month from the the Order_date column by using postgres SQL , and the format is required to come in the name of the month format ;for example, December.
When I applied the extract function , It gave me an error message saying that the date setting has to be changed.
Please advise how to extract the month from the mentioned column ?
The data has been enclosed
SELECT EXTRACT(MONTH FROM order_date::date)
FROm think_sales;
The error message :
[22008] ERROR: date/time field value out of range: "25/06/2021" Hint: Perhaps you need a different "datestyle" setting.
Data :
You may need to define your date format using the to_date function:
select to_char(to_date('25/06/2021', 'dd/mm/yyyy'), 'Month');
Output: June
In your case, you would use:
select to_char(to_date(order_date, 'dd/mm/yyyy'), 'Month');
This work for me:
SELECT EXTRACT(MONTH FROM TIMESTAMP '25/06/2021');
https://www.postgresqltutorial.com/postgresql-date-functions/postgresql-extract/
set date format to dmy (day - month - year )
SET datestyle = dmy;
This answer
Based on the example mentioned here in the Snowflake documentation, why are the date and timestamp values returning different values just by changing the ORDER BY clause? Also, I am trying to convert a string to a date format which is not returning correct results in Snowflake while this works fine in other SQL based Engines. Need help from experts on this.
This query
SELECT '20200710', TO_DATE('20200710');
is returning the following output
20200710 | 1970-08-22
Also tried:
SELECT TO_DATE('20200710', 'YYYY-MM-DD');
and got the error:
Can't parse '20200710' as date with format 'YYYY-MM-DD'
To convert to a date data type, you would use:
SELECT TO_DATE('20200710', 'YYYYMMDD')
I would recommend just keeping the date data type. But if you want a string in the format YYYY-MM-DD:
SELECT TO_CHAR(TO_DATE('20200710', 'YYYYMMDD'), 'YYYY-MM-DD')
I have a date column as dd-mm-yyyy. I would like to convert it to yyyy/mm/dd in bigquery.I have written the following query:
SELECT cast(format(Date, 'yyyy/mm/dd') as string) as Date FROM t1.
The error is : Too many arguments to FORMAT for pattern "23/04/2020"; Expected 1; Got 2.
Can you please assist.
First you need to parse date from dd-mm-yyyy string and then format it as yyyy/mm/dd as in below
FORMAT_DATE('%Y/%m/%d', PARSE_DATE('%d-%m-%Y', day))
You can test, play with above using dummy data as in below example
#standardSQL
WITH `project.dataset.table` AS (
SELECT '15-01-2020' day UNION ALL
SELECT '05-10-2019'
)
SELECT day, FORMAT_DATE('%Y/%m/%d', PARSE_DATE('%d-%m-%Y', day)) AS formated_day
FROM `project.dataset.table`
with output
Row day formated_day
1 15-01-2020 2020/01/15
2 05-10-2019 2019/10/05
You want FORMAT_DATE, not FORMAT.
SELECT FORMAT_DATE("%Y/%m/%d", DATE "2008-12-25");
The reason you're having trouble with FORMAT is that you gave it a format string that doesn't take any parameters. Seeing this, the engine barfs-"I don't need any more parameters to render this string."
NOTE: I am running my query in Qubole's presto and sql command engine.
I am trying to convert my string timestamp to just date but none of the options are working out.
My string timestamp looks like 2017-03-29 10:32:28.0
and I want to have it like 2017-03-29
I have tried following queries to convert this string timestamp to retrieve date
1. select cast(created as date) from table1
Value cannot be cast to date: 2017-05-26 17:23:58.0
2. select cast(from_iso8601_timestamp(created) as date) from table1
Invalid format: "2014-12-19 06:06:36.0" is malformed at " 06:06:36.0"
3. select date(created) from table1
Value cannot be cast to date: 2012-10-24 13:50:00.0
How I can convert this timestamp to date in presto/sql?
As far as explained in the documentation, prestoDB seems to expect timestamps in a format '2001-08-22 03:04:05.321', and dates in a '2001-08-22'.
One solution would be to use a string function to extract the relevant part of the string before converting it. We know that the date part is located before the first space in the string, so.
If you need the date part as a string datatype:
split_part(created, ' ', 1)
If you need the date part as a date datatype:
cast(split_part(created, ' ', 1) as date)
You can try to use one of the following solutions:
SELECT
'2017-03-29 10:32:28.0' AS input_string,
DATE(date_parse('2017-03-29 10:32:28.0', '%Y-%m%-%d %H:%i:%s.%f')) AS solution_1,
DATE(try_cast('2017-03-29 10:32:28.0' as timestamp)) AS solution_2
I have a problem with converting a varchar2 fields into a date format.
I got 2 columns with the datatyp varchar2, one is called qtime the other is called ztime. Both fields contain strings in this format (f.e. 152015 -> would be a timestamp 15:20:15).
For reporting reasons I need to convert this fields into a date format, afterwards I want to substract (qtime-ztime) the fields an convert them into the format [hh] (f.e. after the operation 01:20:00 would be -> 01). Is it possible to to this within Oracle SQL 12c? The biggest problem for me right now is that I don't get those Strings converted into a date format.
select TO_DATE(qtime,'MM/DD/YYYY hh24:mi:ss') just gives me
ORA-01861:"literal does not match format string"
select TO_DATE(qtime,'hh24mmss') gives me a wrong Date
01.03.2018
select TO_TIMESTAMP(qtime,'hh24mmss') gives me a wrong Date
01.03.2018 BUT the correct time with f.e. 15:20:15,0000000
Thank you in advance, any help is appreciated
Note: I only have reading rights on the database Oracle 12c, so I need to to this within Statements
"The Database contains another column with the correct date for each time"
The missing piece of the puzzle! Concatenate the two columns to get something which can be converted to an Oracle DATE:
select to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
Once you have done that you can perform arithmetic of the dates e.g.
select id
, zdatetime - qdatetime as time_diff
from ( select id
, to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
)
If you want the number of hours in the difference you can include this expression in the projection of the outer query:
, extract( hour from (zdatetime - qdatetime) day to second) as hrs_ela
First off, if you are trying to convert a varchar2 into a date without specifying neither day nor month, it will default to the first day of the current month:
If you specify a date value without a date, then the default date is the first day of the current month.
You can read up more here
Also in 2nd and 3rd your example, you are using 'hh24mmss' for specifying hour, minute and second components, but do note that correct format for minutes is 'mi' and not 'mm', which is used for months.
So the solution is to concatenate both date and time component when creating the date as the other answer suggested, tho I would recommend using a single date field as it can store the information you need.