This is my code:
SELECT ROW_NUMBER()OVER(order by date) as rowNo, id, amount
INTO #temptbl
FROM sales
WHERE code = 1000
I'm trying to group this temporary table and sum the amount by its id so the id will be unique.
*The row column is mandatory because it will be used later.
I've tried few ways like this,
SELECT ROW_NUMBER()OVER(order by date) as rowNo, id, amount
INTO #temptbl
FROM sales
WHERE code = 1000
GROUP BY id
and even tried subquey nad nesting but it wont work. I know the solution must be simple its just i cant see it yet. Thank you
You can use SUM with Partition BY like this:
SELECT ROW_NUMBER()OVER(order by date) as rowNo, id,
Sum(amount) over (partition by id) sumAmount
FROM sales
WHERE code = 1000
As you know, since you want the Row number then sum amount will be repeated for same ids
Related
i´m working with a table that looks like this:
Start
https://i.stack.imgur.com/uibc3.png
My desired result would look like this:
Result
https://i.stack.imgur.com/v0sic.png
So i´m triyng to select the max value from two "combined" colums. If the values are the same amount (Part C), the outcome doesn't matter.
I tried to order the table by max value and then using distinct but the result didn't turn out as expected
Could you please offer a solution or some insight to this? Thanks in advance!
Use row_number():
select *
from (
select t.*, row_number() over(partition by part order by amount desc, zone) rn
from mytable t
) t
where rn = 1
For each part, this gives you the row with the highest amount; if there are top ties, column zone is used to break them.
If you want to allow ties, then use rank() instead, like:
rank() over(partition by part order by amount desc) rn
You can achieve this by using SUB Query
DECLARE #T TABLE(
PART VARCHAR(50),
ZONE VARCHAR(10),
Amt INT)
Insert Into #T Values ('PartA','71H',1),('PartA','75H',2),('PartB','98D',1),('PartB','98A',3),('PartC','75H',1),('PartC','52H',1)
SELECT M.PART,MIN(M.Zone) AS ZONE,S.AMOUNT
FROM #T M
INNER JOIN (
SELECT Part,MAX(Amt) as AMOUNT From #T
GROUP BY PART) S ON S.AMOUNT=M.Amt AND S.PART=M.PART
GROUP BY M.PART,S.AMOUNT
ORDER BY M.PART
I need to write a hive query. I am working on a data set that has three columns : Customer ID, Product ID and the Price. I need to write a query which outputs the columns Customer ID and Product ID for the maximum item bought by the customer.
SELECT [customer], [product] FROM table WHERE [price] = (SELECT MAX(t.[price]) AS price
FROM table as t WHERE t.[customer] = [customer])
Could be something like this if you're wanting to find the most expensive item that a customer has purchased? I'm unsure if the syntax is 100% correct but it should give you something to go from. I've added a cheat sheet below for Hive just incase.
Hive Cheat Sheet
Using row_number():
select Customer_ID, Product_ID
from
(select Customer_ID,
Product_ID,
row_number () over ( partition by Customer_ID order by Price desc) rn
from table
where customer_id=given_customer_id --add filter if necessary
)s
where rn=1;
I'm looking for a t-sql script that returns a list, that shows every second value from a grouping from Table1.
For example I have the following data (Table1) and want the desired result-list:
Table1:
Customer Quantity
A 5
A 8 (*)
B 3
B 5 (*)
B 11
C 7
D 4
D 23 (*)
Desired retult-list:
Customer Quantity
A 8
B 5
D 23
I think about doing something something with 'select distinct and left outer join', but I can't get it to work. Possibly I need an row numbering, but can't figure out how to do it. Anyone can help me?
Beneath is the script I used to make and fill Table1:
CREATE TABLE Table1
(Customer nvarchar(1) NULL,
Quantity int NOT NULL);
INSERT INTO Table1(Customer,Quantity)
VALUES
('A',5),
('A',8),
('B',3),
('B',5),
('B',11),
('C',7),
('D',4),
('D',23);
This can be done quite easily using the row_number window function:
SELECT customer, quantity
FROM (SELECT customer, quantity,
ROW_NUMBER() OVER (PARTITION BY customer
ORDER BY quantity ASC) AS rn
FROM table1) t
WHERE rn = 2
You can use ROW_NUMBER and a CTE:
WITH data AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY Customer ORDER BY Quantity) rn
FROM #Table1
)
SELECT Customer, Quantity
FROM data
WHERE rn = 2
How it works:
Using ROW_NUMBER() will assign a sequential number to each row based on what's specified in OVER (). In OVER i specify to PARTITION the rows on customer, that means each group of data on same customer will be numberered separately. Then ORDER BY Quantity mean it should order the data based on quantity for each customer - so i can get the 2nd row for each customer ordered by quantity.
I have a SQL problem (MS SQL Server 2012), where I only want one result per set, but have different items in some rows, so a group by doesn't work.
Here is the statement:
Select Deliverer, ItemNumber, min(Price)
From MyTable
Group By Deliverer, ItemNumber
So I want the deliverer with the lowest price for one item.
With this query I get the lowest price for each deliverer.
So a result like:
DelA 12345 1,25
DelB 11111 2,31
And not like
DelA 12345 1,25
DelB 12345 1,35
DelB 11111 2,31
DelC 11111 2,35
I know it is probably a stupid question with an easy solution, but I tried for about three hours now and just can't find a solution. Needles to say, I'm not very experienced with SQL.
Just Add an aggregate function to your deliverer field also, as appropriate (Either min or max). From your data, I guess you need min(deliverer) and hence use the below query to get your desired result.
Select mIN(Deliverer), ItemNumber, min(Price)
From MyTable
Group By ItemNumber;
EDIT:
Below query should help you get the deliverer with the lowest price item-wise:
SELECT TABA.ITEMNUMBER, TABA.MINPRICE, TABB.DELIVERER
FROM
(
SELECT ITEMNUMBER, MIN(PRICE) MINPRICE
FROM MYTABLE GROUP BY
ITEMNUMBER
) TABA JOIN
MYTABLE TABB
ON TABA.ITEMNUMBER=TABB.ITEMNUMBER AND
TABA.MINPRICE = TABB.PRICE
You should be able to do this with the RANK() (or DENSE_RANK()) functions, and a bit of partitioning, so something like:
; With rankings as (
SELECT Deliverer,
rankings.ItemNumber,
rankings.Price
RANK() OVER (PARTITION BY ItemNumber ORDER BY Price ASC) AS Ranking
FROM MyTable (Deliverer, ItemNumber, Price)
)
SELECT rankings.Deliverer,
rankings.ItemNumber,
rankings.Price
FROM rankings
WHERE ranking = 1
I want to use the ROW_NUMBER() to get...
To get the max(ROW_NUMBER()) --> Or i guess this would also be the count of all rows
I tried doing:
SELECT max(ROW_NUMBER() OVER(ORDER BY UserId)) FROM Users
but it didn't seem to work...
To get ROW_NUMBER() using a given piece of information, ie. if I have a name and I want to know what row the name came from.
I assume it would be something similar to what I tried for #1
SELECT ROW_NUMBER() OVER(ORDER BY UserId) From Users WHERE UserName='Joe'
but this didn't work either...
Any Ideas?
For the first question, why not just use?
SELECT COUNT(*) FROM myTable
to get the count.
And for the second question, the primary key of the row is what should be used to identify a particular row. Don't try and use the row number for that.
If you returned Row_Number() in your main query,
SELECT ROW_NUMBER() OVER (Order by Id) AS RowNumber, Field1, Field2, Field3
FROM User
Then when you want to go 5 rows back then you can take the current row number and use the following query to determine the row with currentrow -5
SELECT us.Id
FROM (SELECT ROW_NUMBER() OVER (ORDER BY id) AS Row, Id
FROM User ) us
WHERE Row = CurrentRow - 5
Though I agree with others that you could use count() to get the total number of rows, here is how you can use the row_count():
To get the total no of rows:
with temp as (
select row_number() over (order by id) as rownum
from table_name
)
select max(rownum) from temp
To get the row numbers where name is Matt:
with temp as (
select name, row_number() over (order by id) as rownum
from table_name
)
select rownum from temp where name like 'Matt'
You can further use min(rownum) or max(rownum) to get the first or last row for Matt respectively.
These were very simple implementations of row_number(). You can use it for more complex grouping. Check out my response on Advanced grouping without using a sub query
If you need to return the table's total row count, you can use an alternative way to the SELECT COUNT(*) statement.
Because SELECT COUNT(*) makes a full table scan to return the row count, it can take very long time for a large table. You can use the sysindexes system table instead in this case. There is a ROWS column that contains the total row count for each table in your database. You can use the following select statement:
SELECT rows FROM sysindexes WHERE id = OBJECT_ID('table_name') AND indid < 2
This will drastically reduce the time your query takes.
You can use this for get first record where has clause
SELECT TOP(1) * , ROW_NUMBER() OVER(ORDER BY UserId) AS rownum
FROM Users
WHERE UserName = 'Joe'
ORDER BY rownum ASC
ROW_NUMBER() returns a unique number for each row starting with 1. You can easily use this by simply writing:
ROW_NUMBER() OVER (ORDER BY 'Column_Name' DESC) as ROW_NUMBER
May not be related to the question here. But I found it could be useful when using ROW_NUMBER -
SELECT *,
ROW_NUMBER() OVER (ORDER BY (SELECT 100)) AS Any_ID
FROM #Any_Table
select
Ml.Hid,
ml.blockid,
row_number() over (partition by ml.blockid order by Ml.Hid desc) as rownumber,
H.HNAME
from MIT_LeadBechmarkHamletwise ML
join [MT.HAMLE] h on ML.Hid=h.HID
SELECT num, UserName FROM
(SELECT UserName, ROW_NUMBER() OVER(ORDER BY UserId) AS num
From Users) AS numbered
WHERE UserName='Joe'
You can use Row_Number for limit query result.
Example:
SELECT * FROM (
select row_number() OVER (order by createtime desc) AS ROWINDEX,*
from TABLENAME ) TB
WHERE TB.ROWINDEX between 0 and 10
--
With above query, I will get PAGE 1 of results from TABLENAME.
If you absolutely want to use ROW_NUMBER for this (instead of count(*)) you can always use:
SELECT TOP 1 ROW_NUMBER() OVER (ORDER BY Id)
FROM USERS
ORDER BY ROW_NUMBER() OVER (ORDER BY Id) DESC
Need to create virtual table by using WITH table AS, which is mention in given Query.
By using this virtual table, you can perform CRUD operation w.r.t row_number.
QUERY:
WITH table AS
-
(SELECT row_number() OVER(ORDER BY UserId) rn, * FROM Users)
-
SELECT * FROM table WHERE UserName='Joe'
-
You can use INSERT, UPDATE or DELETE in last sentence by in spite of SELECT.
SQL Row_Number() function is to sort and assign an order number to data rows in related record set. So it is used to number rows, for example to identify the top 10 rows which have the highest order amount or identify the order of each customer which is the highest amount, etc.
If you want to sort the dataset and number each row by seperating them into categories we use Row_Number() with Partition By clause. For example, sorting orders of each customer within itself where the dataset contains all orders, etc.
SELECT
SalesOrderNumber,
CustomerId,
SubTotal,
ROW_NUMBER() OVER (PARTITION BY CustomerId ORDER BY SubTotal DESC) rn
FROM Sales.SalesOrderHeader
But as I understand you want to calculate the number of rows of grouped by a column. To visualize the requirement, if you want to see the count of all orders of the related customer as a seperate column besides order info, you can use COUNT() aggregation function with Partition By clause
For example,
SELECT
SalesOrderNumber,
CustomerId,
COUNT(*) OVER (PARTITION BY CustomerId) CustomerOrderCount
FROM Sales.SalesOrderHeader
This query:
SELECT ROW_NUMBER() OVER(ORDER BY UserId) From Users WHERE UserName='Joe'
will return all rows where the UserName is 'Joe' UNLESS you have no UserName='Joe'
They will be listed in order of UserID and the row_number field will start with 1 and increment however many rows contain UserName='Joe'
If it does not work for you then your WHERE command has an issue OR there is no UserID in the table. Check spelling for both fields UserID and UserName.