Create a new column based on an existing column in SQL - sql

I have a question in SQL. I have an existing data table like following:
And would like to make the selection into a list. The rule is as following: if an ID selects a product, we will provide it a value 1. Otherwise, the value is 0. For example, ID 1 choose product A and B. So the corresponding is_tap for product A and B is 1, and for C is 0, since there is no selection. The selection here is limited and known. The final table will be something like:
How can I generate this table in SQL? Thanks in advance for your help.

Have derived tables (the subqueries) producing all possible combinations of id and selection.
LEFT JOIN the original table. Use a case expression to return 1 if row exists, otherwise 0.
select t2.id, t3.selection, case when t1.id is not null then 1 else 0 end
from (select distinct id from t1) t2
cross join (select distinct selection from t1) t3
left join t1 on t2.id = t1.id and t3.selection = t1.selection
order by t2.id, t3.selection
Demo at https://dbfiddle.uk/-sS-bvxM

Related

Control on SQL join condition when there are more than one matching row

I have a join with more than one matching row. How can I have more control over the join? In particular, as shown in the example, when there is more than one matching row, I don't want to obtain any result and maintain my input.
In the picture, I am showing the desired result. The row with the green color is correctly obtained because of directing matching and the row with the red color is also correctly not obtained, because there are more than one matching.
Select t2.id, t1.Insurance_num, t1Name, t1.Surname
From Table_1 t1
left join Table_2 t2
on t1.Insurance_num=t2.Insurance_num
I am using Hive, but I guess the answer to this question should be a generic one.
You might try this... I am not sure if it is exactly what you need.
If the coalesce with left-join would be null if no matching Insurance_Num, thus returning 0, or, there is a matching insurance_num, but the count is other than 1, it gets the ELSE condition of the CASE query.
Only if there is a match in the pre-query, and there is one record for that insurance_num does it get the ID from that pre-aggregation query.
select
case when coalesce( PreSum.NumEntries, 0 ) = 1
then cast( PreSum.LowID as varchar )
else 'N.D' end as IDorNot,
t1.Insurance_num,
t1.Name,
t1.Surname
from
table_1 t1
LEFT JOIN
( select
t2.Insurance_Num,
min( t2.id ) as LowID,
count(*) as NumEntries
from
Table_2 t2
group by
t2.Insurance_Num ) PreSum
on t1.insurance_Num = PreSum.Insurance_Num

Join table in oracle database

I have 2 tables that showing data Item master and BOM. I would like to join the tables between Item master as T1 and BOM as T2 and the additional table for table BOM as T3. Item master table containing ITM_CD, ITM_TYP (1,2,3,4) where each ITM_TYP represents a code for the first digit on ITM_CD. The thing that I want is like the picture below
CHILD_CD2 value replace to CHILD_CD1 value. So the data should be like this. What query should I fix ? I am very new using oracle query.
Here is mycode;
SELECT DISTINCT
T1.ITM_CD,
T2.C_ITM_CD AS CHILD_CD1,
T3.C_ITM_CD AS CHILD_CD2
FROM CM_HINMO_ALL T1
INNER JOIN (SELECT P_ITM_CD, C_ITM_CD, BOM_PTN FROM SM_BOM_ALL) T2
ON T1.ITM_CD = T2.P_ITM_CD
LEFT JOIN (SELECT P_ITM_CD, C_ITM_CD, BOM_PTN FROM SM_BOM_ALL) T3
ON T2.C_ITM_CD = t3.P_ITM_CD
WHERE 0=0
AND T2.BOM_PTN IN (1)
AND T1.ITM_TYP IN (1,2)
AND T1.ITM_CD = '110100370'
ORDER BY 2
Just use Case expression to replace the values.
SELECT ITM_CD, CASE WHEN CHILD_CD2 IS NULL THEN CHILD_CD2 ELSE CHILD_CD1 END AS CHILD_CD1
FROM TABLE1
If I understood, you want child_cd2 value should taken precedence over child_cd1 if available. If this assumption is right then we can use coalesce which returns the fist non null expression to achieve the same.
SELECT DISTINCT
T1.ITM_CD,
COALESCE(T3.C_ITM_CD,T2.C_ITM_CD) AS CHILD_CD1
FROM CM_HINMO_ALL T1
INNER JOIN SM_BOM_ALL T2
ON T1.ITM_CD = T2.P_ITM_CD
LEFT JOIN SM_BOM_ALL T3
ON T2.C_ITM_CD = t3.P_ITM_CD
WHERE T2.BOM_PTN IN (1)
AND T1.ITM_TYP IN (1,2)
AND T1.ITM_CD = '110100370'
ORDER BY 2

Cross joining tables to see which partners in one table have a report from another table [duplicate]

table1 (id, name)
table2 (id, name)
Query:
SELECT name
FROM table2
-- that are not in table1 already
SELECT t1.name
FROM table1 t1
LEFT JOIN table2 t2 ON t2.name = t1.name
WHERE t2.name IS NULL
Q: What is happening here?
A: Conceptually, we select all rows from table1 and for each row we attempt to find a row in table2 with the same value for the name column. If there is no such row, we just leave the table2 portion of our result empty for that row. Then we constrain our selection by picking only those rows in the result where the matching row does not exist. Finally, We ignore all fields from our result except for the name column (the one we are sure that exists, from table1).
While it may not be the most performant method possible in all cases, it should work in basically every database engine ever that attempts to implement ANSI 92 SQL
You can either do
SELECT name
FROM table2
WHERE name NOT IN
(SELECT name
FROM table1)
or
SELECT name
FROM table2
WHERE NOT EXISTS
(SELECT *
FROM table1
WHERE table1.name = table2.name)
See this question for 3 techniques to accomplish this
I don't have enough rep points to vote up froadie's answer. But I have to disagree with the comments on Kris's answer. The following answer:
SELECT name
FROM table2
WHERE name NOT IN
(SELECT name
FROM table1)
Is FAR more efficient in practice. I don't know why, but I'm running it against 800k+ records and the difference is tremendous with the advantage given to the 2nd answer posted above. Just my $0.02.
SELECT <column_list>
FROM TABLEA a
LEFTJOIN TABLEB b
ON a.Key = b.Key
WHERE b.Key IS NULL;
https://www.cloudways.com/blog/how-to-join-two-tables-mysql/
This is pure set theory which you can achieve with the minus operation.
select id, name from table1
minus
select id, name from table2
Here's what worked best for me.
SELECT *
FROM #T1
EXCEPT
SELECT a.*
FROM #T1 a
JOIN #T2 b ON a.ID = b.ID
This was more than twice as fast as any other method I tried.
Watch out for pitfalls. If the field Name in Table1 contain Nulls you are in for surprises.
Better is:
SELECT name
FROM table2
WHERE name NOT IN
(SELECT ISNULL(name ,'')
FROM table1)
You can use EXCEPT in mssql or MINUS in oracle, they are identical according to :
http://blog.sqlauthority.com/2008/08/07/sql-server-except-clause-in-sql-server-is-similar-to-minus-clause-in-oracle/
That work sharp for me
SELECT *
FROM [dbo].[table1] t1
LEFT JOIN [dbo].[table2] t2 ON t1.[t1_ID] = t2.[t2_ID]
WHERE t2.[t2_ID] IS NULL
You can use following query structure :
SELECT t1.name FROM table1 t1 JOIN table2 t2 ON t2.fk_id != t1.id;
table1 :
id
name
1
Amit
2
Sagar
table2 :
id
fk_id
email
1
1
amit#ma.com
Output:
name
Sagar
All the above queries are incredibly slow on big tables. A change of strategy is needed. Here there is the code I used for a DB of mine, you can transliterate changing the fields and table names.
This is the strategy: you create two implicit temporary tables and make a union of them.
The first temporary table comes from a selection of all the rows of the first original table the fields of which you wanna control that are NOT present in the second original table.
The second implicit temporary table contains all the rows of the two original tables that have a match on identical values of the column/field you wanna control.
The result of the union is a table that has more than one row with the same control field value in case there is a match for that value on the two original tables (one coming from the first select, the second coming from the second select) and just one row with the control column value in case of the value of the first original table not matching any value of the second original table.
You group and count. When the count is 1 there is not match and, finally, you select just the rows with the count equal to 1.
Seems not elegant, but it is orders of magnitude faster than all the above solutions.
IMPORTANT NOTE: enable the INDEX on the columns to be checked.
SELECT name, source, id
FROM
(
SELECT name, "active_ingredients" as source, active_ingredients.id as id
FROM active_ingredients
UNION ALL
SELECT active_ingredients.name as name, "UNII_database" as source, temp_active_ingredients_aliases.id as id
FROM active_ingredients
INNER JOIN temp_active_ingredients_aliases ON temp_active_ingredients_aliases.alias_name = active_ingredients.name
) tbl
GROUP BY name
HAVING count(*) = 1
ORDER BY name
See query:
SELECT * FROM Table1 WHERE
id NOT IN (SELECT
e.id
FROM
Table1 e
INNER JOIN
Table2 s ON e.id = s.id);
Conceptually would be: Fetching the matching records in subquery and then in main query fetching the records which are not in subquery.
First define alias of table like t1 and t2.
After that get record of second table.
After that match that record using where condition:
SELECT name FROM table2 as t2
WHERE NOT EXISTS (SELECT * FROM table1 as t1 WHERE t1.name = t2.name)
I'm going to repost (since I'm not cool enough yet to comment) in the correct answer....in case anyone else thought it needed better explaining.
SELECT temp_table_1.name
FROM original_table_1 temp_table_1
LEFT JOIN original_table_2 temp_table_2 ON temp_table_2.name = temp_table_1.name
WHERE temp_table_2.name IS NULL
And I've seen syntax in FROM needing commas between table names in mySQL but in sqlLite it seemed to prefer the space.
The bottom line is when you use bad variable names it leaves questions. My variables should make more sense. And someone should explain why we need a comma or no comma.
I tried all solutions above but they did not work in my case. The following query worked for me.
SELECT NAME
FROM table_1
WHERE NAME NOT IN
(SELECT a.NAME
FROM table_1 AS a
LEFT JOIN table_2 AS b
ON a.NAME = b.NAME
WHERE any further condition);

SQL - multiple rows, if one of the rows meets the condition, exclude all

How to exclude multiple rows if one of the rows meets the condition
example table:
id/role_id/code
1/1/112233
1/2/221155
1/3/332233
5/1/323233
5/3/988933
6/1/389349
6/2/112233
6/3/232323
Now I want to find only these id-s, which has role_id=3 and exclude all rows, if one of them contains code=112233
In this example, results should show only this row: 5/3/988933
Gordon showed you how to do it via EXISTS and mentions IN but it can also be done via a left self join as follows:
SELECT t1.*
FROM
Table t1
LEFT JOIN Table t2
ON t1.id = t2.id
AND t2.code = 112233
WHERE
t1.role_id = 3
AND t2.id IS NULL
And while I don't like to use IN because it was mentioned here is how you could do it:
SELECT *
FROM
Table
WHERE
role_id = 3
AND id NOT IN (SELECT ID
FROM
Table
WHERE
code = 112233
and ID IS NOT NULL)
Note I include the line ID IS NOT NULL because if you ever compare something to IN (NULL) you will not get your desired result. In this case an ID field is not likely to ever be null so you can probably remove that statement, I put it in to show the nuance.
If you want the original rows, then use exists or in:
select t.*
from t
where role_id = 3 and
exists (select 1 from t t2 where t2.id = t.id and t2.code = 112233);

How do I Write a SQL Query With a Condition Involving a Second Table?

Table1
...
LogEntryID *PrimaryKey*
Value
ThresholdID - - - Link to the appropriate threshold being applied to this log entry.
...
Table2
...
ThresholdID *PrimaryKey*
Threshold
...
All fields are integers.
The "..." thingies are there to show that these tables hold a lot more imformation than just this. They are set up this way for a reason, and I can't change it at this point.
I need write a SQL statement to select every record from Table1 where the Value field in that particular log record is less than the Threshold field in the linked record of Table2.
I'm newish to SQL, so I know this is a basic question.
If anyone can show me how this SQL statement would be structured, it would be greatly appreciated.
SELECT T1.*
FROM Table1 T1
JOIN Table2 T2 ON T2.ThresholdID = T1.ThresholdID
WHERE T2.Threshold > T1.Value
SELECT t1.*
FROM dbo.Table1 t1 INNER JOIN dbo.Table2 t2 ON t1.ThresholdID = t2.ThresholdID
WHERE t2.Threshold > t1.Value
SELECT * from table1 t1 join table2 t2 on (t1.thresholdId = t2.thresholdId)
where t1.value < t2.threshold;
SELECT t1.LogEntryID, t1.Value, t1.ThresholdID
FROM Table1 t1
INNER JOIN Table2 t2 ON t1.ThresholdID = t2.ThresholdID
WHERE t1.Value < t2.threshold
SELECT * FROM Table1
JOIN Table2
ON table1.ThresholdID = table2.ThresholdID --(assuming table 2 holds the same value to link them together)
WHERE
value < thresholdvalue
A 'JOIN' connects 2 tables based on the 'ON' clause (which can be multipart, using 'AND' and 'OR')
If you have 3 entries in table 2 which share table1's primary key (a one-to-many association) you will receive 3 rows in your result set.
for the tables below, for example:
Table 1:
Key Value
1 Hi
2 Bye
Table 2:
Table1Key 2nd_word
1 You
1 fellow
1 friend
2 now
this query:
SELECT * FROM Table1
JOIN Table2
on table1.key = table2.table1key
gets this result set:
Key Value Table1Key 2nd_word
1 Hi 1 You
1 Hi 1 fellow
1 Hi 1 friend
2 Bye 2 now
Note that JOIN will only return results when there is a match in the 2nd table, it will not return a result if there is no match. You can LEFT JOIN for that (all fields from the second table will be NULL).
JOINs can also be strung together, the result from the previous JOIN is used in place of the original table.