How can I put SELECT result set to SELECT column? - sql

Question

I have two tables: Job(ID,Name, etc.) and Address(ID, Job_ID, Name etc). I want to get result like this:
[
{
"Job_ID": 1,
"JobName": "Test",
"Addresses": [
{
"ID": 1,
"Name": "King street"
},
{
"ID": 2,
"Name": "Queen`s street
}
]
}
]
My current query that gets only one address for a job looks like this:
SELECT TOP 100
JO.ID,
JO.Closed as Deleted,
JO.Number as JobNumber,
JO.Name as JobName,
Convert(date, JO.Start_Date) as Start_Date,
JO.Job_Status_ID as Status,
A.ID as Address_ID,
A.Name as Name,
A.Number as Number,
A.Sort_Name as Sort_Name,
A.Address_1 as Address_1,
A.Address_2 as Address_2,
A.ZipCode as ZIP,
A.E_Mail_Address as Email,
A.Web_Site_URL as Web_Site_URL,
A.TAXRATE as Tax_Rate,
A.State
FROM Job JO
INNER JOIN Address A ON A.Job_Id = JO.ID
Is it possible without pivot table(Address_ID, Job_ID)?

Answer 1

You can use FOR JSON to convert you results to JSON. This gives the result you are looking for:
CREATE TABLE #Job (ID INT NOT NULL, Name VARCHAR(50));
INSERT #Job (ID, Name)
VALUES (1, 'Job 1'), (2, 'Job 2');
CREATE TABLE #Address (ID INT NOT NULL, JobID INT NOT NULL, Name VARCHAR(50));
INSERT #Address (ID, JobID, Name)
VALUES (1, 1, 'King street'), (2, 1, 'Queen''s street'), (3, 2, 'Address 3'), (4, 2, 'Address 4');
SELECT JobID = j.ID,
JobName = j.Name,
Addresses = ( SELECT a.ID, a.Name
FROM #Address AS a
WHERE a.JobID = j.ID
FOR JSON AUTO
)
FROM #Job AS j
FOR JSON AUTO;