awk - print on column-specific conditions, print empty fields for non-match - awk

Question

My large file has date in $1 and 19 columns with numerical values, separated by ";". One or many columns must meet a column-specific smaller-than-condition for printout. I'd like to print them on the same line, beginning with $1 (date) – keeping the original table structure intact, ie, printing empty fields for those which do not meet their specific condition on this particular row. Only print lines with at least 1 match.
Later, I will have to exchange the printout conditions to larger-than and several between-values (<>) which is why I'm interested in a programmatic awk solution as opposed to manipulation of data in a time-consuming spreadsheet application.
My OS is MacOS.
Excerpt from input; changed ";" to "," because the system didn't let me use ";" and added spaces to the delimiter for readability):
1503_12_26 , 100.09 , 33.54 , 75.72 , 9.17 , 96.01 , 29.46 , 71.64 , 5.09 , 98.96 , 32.41 , 74.59 , 8.04 , 28.33 , 70.51 , 95 , 70.63 , 28.45 , 90.92
1503_12_27 , 102.94 , 31.87 , 80.47 , 9.4 , 98.89 , 27.82 , 76.42 , 5.35 , 102.7 , 31.63 , 80.23 , 9.16 , 27.58 , 76.18 , 97.59 , 75.12 , 26.52 , 93.54
1503_12_28 , 107.76 , 32.44 , 87.2 , 11.88 , 103.26 , 27.94 , 82.7 , 7.38 , 106.64 , 31.32 , 86.08 , 10.76 , 26.82 , 81.58 , 100.38 , 79.82 , 25.06 , 95.88
1503_12_29 , 112.87 , 33.57 , 94.21 , 14.91 , 107.58 , 28.28 , 88.92 , 9.62 , 110.66 , 31.36 , 92 , 12.7 , 26.07 , 86.71 , 103.25 , 84.59 , 23.95 , 97.96
1503_12_30 , 117.99 , 34.95 , 101.21 , 18.17 , 111.69 , 28.65 , 94.91 , 11.87 , 114.68 , 31.64 , 97.9 , 14.86 , 25.34 , 91.6 , 106.12 , 89.34 , 23.08 , 99.82
1503_12_31 , 123.07 , 36.51 , 108.12 , 21.56 , 115.63 , 29.07 , 100.68 , 14.12 , 118.66 , 32.1 , 103.71 , 17.15 , 24.66 , 96.27 , 108.95 , 94 , 22.39 , 101.51
1504_01_01 , 128.08 , 38.22 , 114.88 , 25.02 , 119.42 , 29.56 , 106.22 , 16.36 , 122.58 , 32.72 , 109.38 , 19.52 , 24.06 , 100.72 , 111.72 , 98.52 , 21.86 , 103.06
Desired output:
1503-12-26 ; ; 33.54 ; ; 9.17 ; ; ; ; 5.09 ; ; ; ; 8.04 ; ; ; ; ; ;
1503-12-27 ; ; 31.87 ; ; 9.4 ; ; ; ; 5.35 ; ; ; ; 9.16 ; ; ; ; ; ;
1503-12-28 ; ; 32.44 ; ; 11.88 ; ; ; ; 7.38 ; ; ; ; ; ; ; ; ; ;
1503-12-29 ; ; 33.57 ; ; 14.91 ; ; ; ; 9.62 ; ; ; ; ; ; ; ; ; ;
1503-12-30 ; ; 34.95 ; ; 18.17 ; ; ; ; ; ; ; ; ; ; ; ; ; ;
1503-12-31 ; ; ; ; 21.56 ; ; ; ; ; ; ; ; ; ; ; ; ; ;
I started out with a chain of OR || conditions for each column but couldn't think of how to empty the fields that don't match their criteria.
awk -F";" ' $2 < 80 || $3 < 35 || $4 < 60 || $5 < 24 || $6 < 45 || $7 < 24 || $8 < 30 || $9 < 8 || $10 < 60 || $11 < 24 || $12 < 30 || $13 < 10 || $14 < 10 || $15 < 10 || $16 < 24 || $17 < 8 || $18 < 8 || $19 < 8 ' input.txt > output.txt
It just prints all fields of a row if 1 field is a hit.
Then separate awk statements for each column in a bash-file (.sh) and appending them to output.txt. But I get separate lines for each hit, and I also won't know which column had met its condition.
So I added new fields to printout: column header ; condition ; $value.
example:
awk -F";" ' $3 < 35 {print $1 "\;SJMV\;<35\;" $3} ' input.txt >>output.txt
Output:
1503-12-26 ; SJMV ; \<35 ; 33.54
1503-12-26 ; SJM ; \<24 ; 9.17
1503-12-26 ; JM ; \<10 ; 8.04
1503-12-26 ; SJ ; \<8 ; 5.09
Couldn't think of a way to get this back into the table structure, either.
I might have to do some IF, FOR, or WHILE loops within the first attempted chain of OR ||
to empty the non-matching fields. But I don't know how.
This is my first Q here. Appreciate comments re improvement, as well.

Answer 1

Clear the field if its test fails.
Remember to set the output delimiter.
awk -F";" -v OFS=";" '
!( $2 < 80 ) { $2="" }
!( $3 < 35 ) { $3="" }
!( $4 < 60 ) { $4="" }
!( $5 < 24 ) { $5="" }
!( $6 < 45 ) { $6="" }
!( $7 < 24 ) { $7="" }
!( $8 < 30 ) { $8="" }
!( $9 < 8 ) { $9="" }
!( $10 < 60 ) { $10="" }
!( $11 < 24 ) { $11="" }
!( $12 < 30 ) { $12="" }
!( $13 < 10 ) { $13="" }
!( $14 < 10 ) { $14="" }
!( $15 < 10 ) { $15="" }
!( $16 < 24 ) { $16="" }
!( $17 < 8 ) { $17="" }
!( $18 < 8 ) { $18="" }
!( $19 < 8 ) { $19="" }
{ print }
' input.txt > output.txt
To exclude lines where all columns were cleared, you could check if any tests succeeded:
awk -F";" -v OFS=";" '
{
t=0
if ( $2 < 80 ) t=1; else $2=""
if ( $3 < 35 ) t=1; else $3=""
if ( $4 < 60 ) t=1; else $4=""
if ( $5 < 24 ) t=1; else $5=""
if ( $6 < 45 ) t=1; else $6=""
if ( $7 < 24 ) t=1; else $7=""
if ( $8 < 30 ) t=1; else $8=""
if ( $9 < 8 ) t=1; else $9=""
if ( $10 < 60 ) t=1; else $10=""
if ( $11 < 24 ) t=1; else $11=""
if ( $12 < 30 ) t=1; else $12=""
if ( $13 < 10 ) t=1; else $13=""
if ( $14 < 10 ) t=1; else $14=""
if ( $15 < 10 ) t=1; else $15=""
if ( $16 < 24 ) t=1; else $16=""
if ( $17 < 8 ) t=1; else $17=""
if ( $18 < 8 ) t=1; else $18=""
if ( $19 < 8 ) t=1; else $19=""
if (t) print
}
' input.txt > output.txt