I am stuck at the following issue writing a SELECT SQL statement and was wondering if anyone can help. I have the following table with ProductID and Status fields:
ProductID
Status
AP56546
AP56546
Shipped
AP56546
AD92402
Delayed
AD92402
AD92402
BE91455
BE91455
SL19423
SL19423
SL19423
SL19423
Expected
How can I populate the Status for all Product with the same ID if even one of them has a status against it? If no Status exists for a certain product, then it can stay null. How can I do this using a SELECT statement? The expected result should be below (ProductID BE91455 is still null because there is no status against any of the rows where it occurs)
ProductID
Status
AP56546
Shipped
AP56546
Shipped
AP56546
Shipped
AD92402
Delayed
AD92402
Delayed
AD92402
Delayed
BE91455
BE91455
SL19423
Expected
SL19423
Expected
SL19423
Expected
SL19423
Expected
Thank you
The following using max partitioned by ProductId should work for you:
select ProductId, Max(Status) over(partition by ProductId) Status
from t;
You can achieve desired results using below query:
Sample Table
CREATE TABLE TableData (
ProductID varchar(10),
Status varchar(10)
)
Sample Data
INSERT INTO TableData (ProductID, Status)
VALUES
('AP56546', ''),
('AP56546', 'Shipped'),
('AP56546', ''),
('AD92402', 'Delayed'),
('AD92402', ''),
('AD92402', ''),
('BE91455', ''),
('BE91455', ''),
('SL19423', ''),
('SL19423', ''),
('SL19423', ''),
('SL19423', 'Expected');
Query
WITH CTE AS (
SELECT ProductID, Status
FROM TableData
WHERE Isnull(Status,'') <> ''
GROUP BY ProductID, Status
)
SELECT TableData.ProductID, COALESCE(CTE.Status, '') AS Status
FROM TableData
LEFT JOIN CTE
ON TableData.ProductID = CTE.ProductID;
Related
I have the following table
I need to get the following output as "SVGFRAMXPOSLSVG" from the 2 columns.
Is it possible to get this appended values from 2 columns
Please try this.
SELECT STUFF((
SELECT '' + DEPART_AIRPORT_CODE + ARRIVE_AIRPORT_CODE
FROM #tblName
FOR XML PATH('')
), 1, 0, '')
For Example:-
Declare #tbl Table(
id INT ,
DEPART_AIRPORT_CODE Varchar(50),
ARRIVE_AIRPORT_CODE Varchar(50),
value varchar(50)
)
INSERT INTO #tbl VALUES(1,'g1','g2',NULL)
INSERT INTO #tbl VALUES(2,'g2','g3',NULL)
INSERT INTO #tbl VALUES(3,'g3','g1',NULL)
SELECT STUFF((
SELECT '' + DEPART_AIRPORT_CODE + ARRIVE_AIRPORT_CODE
FROM #tbl
FOR XML PATH('')
), 1, 0, '')
Summary
Use Analytic functions and listagg to get the job done.
Detail
Create two lists of code_id and code values. Match the code_id values for the same airport codes (passengers depart from the same airport they just arrived at). Using lag and lead to grab values from other rows. NULLs will exist for code_id at the start and end of the itinerary. Default the first NULL to 0, and the last NULL to be the previous code_id plus 1. A list of codes will be produced, with a matching index. Merge the lists together and remove duplicates by using a union. Finally use listagg with no delimiter to aggregate the rows onto a string value.
with codes as
(
select
nvl(lag(t1.id) over (order by t1.id),0) as code_id,
t1.depart_airport_code as code
from table1 t1
union
select
nvl(lead(t1.id) over (order by t1.id)-1,lag(t1.id) over (order by t1.id)+1) as code_id,
t1.arrive_airport_code as code
from table1 t1
)
select
listagg(c.code,'') WITHIN GROUP (ORDER BY c.code_id) as result
from codes c;
Note: This solution does rely on an integer id field being available. Otherwise the analytic functions wouldn't have a column to sort by. If id doesn't exist, then you would need to manufacture one based on another column, such as a timestamp or another identifier that ensures the rows are in the correct order.
Use row_number() over (order by myorderedidentifier) as id in a subquery or view to achieve this. Don't use rownum. It could give you unpredictable results. Without an ORDER BY clause, there is no guarantee that the same query will return the same results each time.
Output
| RESULT |
|-----------------|
| SVGFRAMXPOSLSVG |
A sample table us like
STATUS INVOICE
=======================
processed 100
reconciled 100
reconciled 200
paid 300
paid 100
paid 200
Output should be
STATUS INVOICE
=======================
processed 100
reconciled 200
paid 300
Logic : If there are multiple statuses against an invoice number , then we should follow the below order to fetch .
Processed > reconciled > paid
Please help me with the SQL query statement for this requirement .
This is a prioritization query. You can handle it using row_number():
select t.*
from (select t.*,
row_number() over (partition by invoice
order by case status when 'Processed' then 1 when 'reconciled' then 2 when 'paid' then 3 else 4 end
) as seqnum
from t
) t
where seqnum = 1;
You need conditional ordering with row_number() :
select top (1) with ties t.*
from table t
order by row_number() over (partition by invoice
order by (case status
when 'Processed'
then 1
when 'reconciled'
then 2
when 'paid'
then 3
else 4
end)
);
Others answers are ok but I'm posting it for the cases there's hundres (or more) of categories because in this case populating a table variable is better than writing lots and lots of CASE statements.
The trick here is to populate a table variable or temp table with your ordering rules and just aggregate by it.
create table dbo.[SAMPLE]
(
[STATUS] varchar(30) not null
,[INVOICE] int not null
)
GO
insert into dbo.[SAMPLE]
values
('processed', 100)
,('reconciled', 100)
,('reconciled', 200)
,('paid', 300)
,('paid', 100)
,('paid', 200)
GO
The below is a partial result showing how it get grouped by your ordering rules
--Processed > reconciled > paid
declare #Ordering as table
(
[STATUS] varchar(30) not null
,[Order] smallint not null
)
insert into #Ordering
values
('processed', 3)
,('reconciled',2)
,('paid',1)
select sp.[INVOICE], max(ord.[Order]) as Precedence
from dbo.[SAMPLE] sp
join #Ordering ord on ord.[STATUS] = sp.[STATUS]
group by sp.[INVOICE]
and below the final query with the expected results
--Processed > reconciled > paid
declare #Ordering as table
(
[STATUS] varchar(30) not null
,[Order] smallint not null
)
insert into #Ordering
values
('processed', 3)
,('reconciled',2)
,('paid',1)
select ord.[STATUS], grouped.INVOICE
from
(
select sp.[INVOICE], max(ord.[Order]) as Precedence
from dbo.[SAMPLE] sp
join #Ordering ord on ord.[STATUS] = sp.[STATUS]
group by sp.[INVOICE]
) as grouped
join #Ordering ord on ord.[Order] = grouped.Precedence
It can be also a interesting solution from performance perspective (acid test required of course).
if you have a status table and the order of status like this
id desc
1 processed
2 reconcilied
3 paid
the better way is joining with this tatble, group by invoice and select max(id)
select i.invoice, max(s.id)
from status s left outer join invoice i
on s.desc = i.status
group by i.invoice
if you havn't this table you can use with to create a virtual table and do this or you can use the case then
https://modern-sql.com/feature/with
https://learn.microsoft.com/it-it/sql/t-sql/language-elements/case-transact-sql?view=sql-server-2017
You can try this.
DECLARE #SampleDate TABLE (STATUS VARCHAR(20), INVOICE INT)
INSERT INTO #SampleDate VALUES
('processed', 100),
('reconciled', 100),
('reconciled', 200),
('paid', 300),
('paid', 100),
('paid', 200)
SELECT STATUS, INVOICE FROM (
SELECT T.*, ROW_NUMBER() OVER(PARTITION BY INVOICE ORDER BY St.ID) AS RN FROM #SampleDate T
INNER JOIN (VALUES (1,'processed'), (2,'reconciled'), (3,'paid')) St(Id, Name) ON T.STATUS = St.Name
) AS X WHERE RN= 1
Result:
STATUS INVOICE
-------------------- -----------
processed 100
reconciled 200
paid 300
WITH TempData As (SELECT MAX(INVOICE) AS INVOICE, [STATUS], CASE WHEN [STATUS] = 'processed' THEN 1 WHEN [STATUS] = 'reconciled' THEN 2 WHEN [STATUS] = 'paid' THEN 3 ELSE 4 END AS SEQ
FROM SAMPLETEST GROUP BY [STATUS])
SELECT [STATUS], INVOICE FROM TempData ORDER BY TempData.SEQ;
I have to write a query which will import some data from table. Table structure is like:
Item_ID
Plant
Price
I have second table with
Item_ID
Plant
Second table is a key, and I have to match rows from first table to get valid price. Seems to be easy, however:
In first table column plant might determinate specific plant, or have value 'ALL'. What I want to do is retrieve price for given plant, if it is set, or get price for value 'ALL' if there is no row for given plant. In other words:
If first.Plant = second.Plant
return price
Else If first.Plant = 'ALL'
return price
Else
return NULL
I can't use simple ON first.Plant = second.Plant OR first.Plant = 'ALL', because there might be two rows: one for given plant and second for rest with value 'ALL'. I need to return only first price in that case. E.g.
Item_ID | Plant | Price
2 | M1 | 10,0
2 | All | 12,0
1 | All | 9,0
In that case for Item_ID = 2 and Plant = M1 the only valid price = 10, but for Item_ID = 2 and Plant = M2 price = 12, and for any Item_ID = 1 price = 9
I hope You understood something after my explanation ;)
Using ROW_Number and a Common Table Expression you can ensure that ROW_NUMBER is partitioned by Item_ID and Plant and ordered such that if there are two rows then 'All' is second. You then simple select the rows with a row number = 1:
Setup
CREATE TABLE #Price
(
Item_ID int,
Plant Varchar(20),
Price Decimal(6,2)
)
CREATE TABLE #Plant
(
Item_ID int,
Plant VARCHAR(20)
)
INSERT INTO #Price
VALUES (2, 'M1', 10.0),
(2, 'All', 12.0),
(1, 'All', 9.0)
INSERT INTO #Plant
VALUES (2, 'M1'),
(2, 'M2'),
(1, 'M1'),
(1, 'M2')
Here's the query for SQL Server >= 2012
;WITH CTE
AS
(
SELECT PL.Item_ID, PL.Plant, PR.PRice, ROW_NUMBER() OVER (PARTITION BY Pl.Item_ID, Pl.Plant ORDER BY IIF(PR.Plant = 'All', 1, 0)) AS RN
FROM #Plant PL
INNER JOIN #Price PR
ON PL.Item_Id = PR.Item_Id AND (PL.Plant = PR.Plant OR PR.Plant = 'ALL')
)
SELECT Item_Id, Plant, Price
FROM CTE
WHERE RN = 1
And here's a version using CASE which will work for all SQL Server >= 2008 R2
;WITH CTE
AS
(
SELECT PL.Item_ID, PL.Plant, PR.PRice, ROW_NUMBER() OVER (PARTITION BY Pl.Item_ID, Pl.Plant ORDER BY CASE WHEN PR.Plant = 'All' Then 1 Else 0 End) AS RN
FROM #Plant PL
INNER JOIN #Price PR
ON PL.Item_Id = PR.Item_Id AND (PL.Plant = PR.Plant OR PR.Plant = 'ALL')
)
SELECT Item_Id, Plant, Price
FROM CTE
WHERE RN = 1
I have been searching for this, but didn't find anything special.
Is it possible to have an SQL query which will act like ALL IN? To better explain, Here is a table structure.
Orders table
OrderItem table (having several columns, but mainly ProductID, OrderID)
ProductGroup table (several columns, but mainly GroupID and ProductID)
I want to write a query which will select all those order which belongs to a specific ProductGroup. So if I have a group named "XYZ" with ID = 10. It has One ProductID in it. Say ProductID01
An order came in with two order items. ProductID01 and ProductID02. To find all orders in the specific Product Group I can use a simple SQL like
SELECT bvc_OrderItem.ProductID, bvc_OrderItem.OrderID
From bvc_OrderItem
INNER JOIN bvc_Product_Group_Product with (nolock) ON bvc_OrderItem.ProductID = bvc_Product_Group_Product.ProductID
WHERE bvc_Product_Group_Product.GroupID = 10
Or I can write using an IN Clause
SELECT bvc_OrderItem.ProductID, bvc_OrderItem.OrderID
From bvc_OrderItem
WHERE ProductID IN (
SELECT ProductID FROM bvc_Product_Group_Product WHERE GroupID=10
)
However, This will return all orders where one or more ProductIDs are part of the product group. I need to return the order row ONLY if ALL of the order items are part of the Product Group
So basically, I need an IN Clause which will considered matched if ALL of the values inside IN Clause matches the rows in bvc_OrderItem.
Or if we are using the Join, then the Join should only succeed if ALL rows on the left have values in the corresponding right table.
If I could write it more simply, I would write it like this
Select ID FROM Table WHERE ID IN (1, 2, 3, 4)
and if the table contains all rows with ids 1,2,3,4; it should return success. If any of these IN values is missing, it should return false and nothing should be selected.
Do you think it is possible? Or there is a workaround to do that?
You can get the list of orders in a variety of ways, such as:
SELECT oi.OrderID
FROM bvc_OrderItem oi JOIN
bvc_Product_Group_Product pgp
ON oi.ProductID = pgp.ProductId AND
pgp.GroupID = 10
GROUP BY oi.OrderID
HAVING COUNT(DISTINCT oi.ProductID) = (SELECT COUNT(*)
FROM bvc_Product_Group_Product
WHERE GroupID = 10
);
Getting the specific products requires an additional join. In most cases, the list of orders is more useful.
The problem with your ALL IN syntax is that it doesn't do what you want. You want to select orders. The syntax:
SELECT bvc_OrderItem.ProductID, bvc_OrderItem.OrderID
From bvc_OrderItem
WHERE ProductID ALL IN (SELECT ProductID
FROM bvc_Product_Group_Product
WHERE GroupID = 10
)
This doesn't specify that you intend for the grouping to be by OrderId, as opposed to some other level.
More fundamentally, though, the SQL language is inspired by relational algebra. The constructs of SELECT, JOIN, WHERE, and GROUP BY directly relate to relational algebra fundamental constructs. The notion of ALL IN -- although sometimes useful -- can be expressed using the more basic building blocks.
You can do it by this tricky statement:
DECLARE #Items TABLE
(
OrderID INT ,
ProductID INT
)
DECLARE #Groups TABLE
(
ProductID INT ,
GroupID INT
)
INSERT INTO #Items
VALUES ( 1, 1 ),
( 1, 2 ),
( 2, 1 ),
( 3, 3 ),
( 3, 4 )
INSERT INTO #Groups
VALUES ( 1, 10 ),
( 2, 10 ),
( 3, 10 ),
( 4, 15 )
SELECT OrderID
FROM #Items i
GROUP BY OrderID
HAVING ( CASE WHEN 10 = ALL ( SELECT gg.GroupID
FROM #Items ii
JOIN #Groups gg ON gg.ProductID = ii.ProductID
WHERE ii.OrderID = i.OrderID ) THEN 1
ELSE 0
END ) = 1
Output:
OrderID
1
2
Also(this is better):
SELECT OrderID
FROM #Items i
JOIN #Groups g ON g.ProductID = i.ProductID
GROUP BY OrderID
HAVING MIN(g.GroupID) = 10
AND MAX(g.GroupID) = 10
How can I combine multiple rows into one row and have a column which contains a comma separate values?
Example: Originally my SQLresult would return the following using a simple select script like
select order_no, item_no, item_description
from orders...
order_no item_no item_description
1234 5 toaster
1234 6 hair dryer
Instead I would like to return the results into the below (having the item_description listed in the same order as the item_nos?
order_no item_nos item_descriptions
1234 5, 6 toaster, hair dryer
And could I return results like this?
order_no item_nos_descriptions
1234 5 - toaster, 6 - hair dryer
By the way I'm using SQL 2008...
For SQL Server 2005 and up, here's the way that I usually do it without using Recursive CTE
DECLARE #T TABLE
(
order_no int,
item_no int,
item_description nvarchar(50)
)
INSERT INTO #T VALUES (1234, 5, 'toaster')
INSERT INTO #T VALUES (1234, 6, 'hair dryer')
SELECT order_no,
STUFF(
(
SELECT ', ' + CAST(item_no AS VARCHAR) AS [text()]
FROM #T As MyItem
WHERE MyItem.order_no = MyTable.order_no
FOR XML PATH('')
), 1, 2, '' ) AS item_nos,
STUFF(
(
SELECT ', ' + CAST(item_no AS VARCHAR) AS [text()]
FROM #T As MyItem
WHERE MyItem.order_no = MyTable.order_no
FOR XML PATH('')
), 1, 2, '' ) AS item_descriptions
FROM #T AS MyTable
GROUP BY order_no
This yields:
Result Set (1 item)
order_no | item_nos | item_descriptions |
1234 | 5, 6 | 5, 6
The STUFF removes the last ', ' from the string.
The other way to do this is with recursive CTE, but I think the above will do...
Check out the group_concat function (docs).
select
order_no,
group_concat(item_no ORDER BY item_nos ASC SEPARATOR ', ') as item_nos,
group_concat(item_description ORDER BY item_no ASC SEPARATOR ', ')
as item_descriptions
from orders
group by order_no
will give something like this:
order_no item_nos item_descriptions
1234 5, 6 toaster, hair dryer
For the second form you requested, it would look something like this:
select
order_no,
group_concat( concat(item_no,' - ',item_description
ORDER BY item_no ASC SEPARATOR ', ')
as item_nos_descriptions
from orders
group by order_no
I think you should heed #pst if you can.
That said, most relational databases have a function to do exactly this. In MySQL it's group_concat. In Oracle it's wm_concat. In PostgreSQL it's string_agg. Notice it's rather unstandardized.
To use it, you would do something like this:
SELECT order_no, string_agg(item_description, ',')
FROM orders
INNER JOIN line_items ON line_item.order_id = order.id
GROUP BY order_no;
Note that not all databases have a way to get from CSV back to rows. This is something I know PostgreSQL can do. I would expect Oracle to be able to do it, but haven't checked, and I'm fairly sure that MySQL cannot, but could be mistaken.
Try GROUP_CONCAT if you are using mySQL:
SELECT order_no,
GROUP_CONCAT(item_no ORDER BY item_no ASC SEPARATOR ','),
GROUP_CONCAT(item_description ORDER BY item_no ASC SEPARATOR ',')
FROM Orders
GROUP BY order_no
In this way you can keep the original normalized DB schema and still get the following result:
order_no item_nos item_descriptions
1234 5, 6 toaster, hair dryer
For MySQL you could do this:
SELECT order_no,
GROUP_CONCAT(CONCAT(item_no,' - ',item_description) ORDER BY item_no ASC SEPARATOR ', ')
FROM Orders
GROUP BY order_no