I need some SQL to determine if a property exists in multiple counties.
I have a list of distinct property ids and county ids, but I'm not sure how to find if the property exists in more than one county.
TABLE: PROPERTIES
PROPERTYID
COUNTYID
12345
1111
12345
1112
23456
1111
34567
2222
In this example, I need some sql that will only show me property 12345 since it exists in both county 1111 and 1112.
I'm sure there is some easy SQL, but I can't figure it out.
Sample data:
SQL> with properties (propertyid, countryid) as
2 (select 12345, 1111 from dual union all
3 select 12345, 1112 from dual union all
4 select 23456, 1111 from dual union all
5 select 34567, 2222 from dual
6 )
Query:
7 select propertyid
8 from properties
9 group by propertyid
10 having count(distinct countryid) > 1;
PROPERTYID
----------
12345
SQL>
Related
I have an Oracle database application which creates lists of duplicate records for people to review, with users being able to deduplcate, leave or mark the record as being different to each other (legitimate duplicates). I need to report on the number of records in this queue.
The challenge is the legitimate duplicates as these are held on a second table of data and are held as two rows for each pair marked up (a≠b). However as duplicate groups can contain a number of duplicates, and records could be marked up a being a legitimate duplicate more than once I need to somehow remove the records that are marked up as legitimate duplicates from all the other records in a candidate group. Hopefully that is making sense.
So a simplified view of the two tables would be:
Duplicate Candidates
Group Key
Dup-1 123
Dup-1 234
Dup-2 123
Dup-2 345
Dup-2 567
Dup-3 234
Dup-3 567
Dup-4 123
Dup-4 567
Dup-4 235
Legitimate Duplicates:
Group Key
A 123
A 234
B 345
B 456
C 123
C 567
D 123
D 235
The results I would like to return from this example would be:
Duplicate Candidates
Group Key
Dup-2 123
Dup-2 345
Dup-2 567
Dup-3 234
Dup-3 567
Dup-4 567
Dup-4 235
Dup-1 would not be returned as Legitimate Group A has both Keys, Dup-2 would be returned as while both Key 123 and 345 are marked up as legitimate duplicates they are not currently marked as different to each other. Dup-3 again should be returned as the two records are not marked as legitimate duplicates. Finally the row Dup-4 123 should not be returned as it is marked up as legitimate duplicate to both of the other records in the group, but they should be returned as they are not marked a legitimate duplicates of each other.
I really need to carry this out in SQL as I will feed this data into a reporting solution (Business Objects or Tablaux) directly. Is anyone able to give me a nudge in the right direction on this. Unfortunately our software is completely black box so I cannot reverse engineer this from the code that deals with this for users.
Using Exists. Return the Candidate if at least one other member of the group is not in any group of Legitimates where the tested Candidate is a member too.
select *
from Candidates c
where exists (
select 1
from Candidates c2
where c2.Grp = c.Grp and c2.Key <> c.Key
and not exists (
select 1
from Legitimate l
where l.Key = c.Key
and exists (
select 1
from Legitimate l2
where l2.Grp = l.Grp and l2.Key = c2.Key
)
)
)
order by Grp, Key
Generate pairs of duplicate candidates using:
SELECT "GROUP",
PRIOR key AS key1,
key AS key2
FROM duplicate_candidates
WHERE LEVEL = 2
CONNECT BY PRIOR "GROUP" = "GROUP"
AND PRIOR key < key
and pairs of legitimate candidates using:
SELECT MIN(key), MAX(key)
FROM legitimate_duplicates
GROUP BY "GROUP"
Then you can find the duplicate pairs that are not in the legitimate candidate pairs and UNPIVOT the pairs and find the DISTINCT keys. In a single query:
SELECT DISTINCT
"GROUP",
key
FROM (
SELECT "GROUP",
PRIOR key AS key1,
key AS key2
FROM duplicate_candidates
WHERE LEVEL = 2
AND (PRIOR key, key) NOT IN (SELECT MIN(key), MAX(key)
FROM legitimate_duplicates
GROUP BY "GROUP")
CONNECT BY PRIOR "GROUP" = "GROUP"
AND PRIOR key < key
)
UNPIVOT (key FOR id IN (key1, key2))
Which, for the sample data:
CREATE TABLE duplicate_candidates ("GROUP", Key) AS
SELECT 'Dup-1', 123 FROM DUAL UNION ALL
SELECT 'Dup-1', 234 FROM DUAL UNION ALL
SELECT 'Dup-2', 123 FROM DUAL UNION ALL
SELECT 'Dup-2', 345 FROM DUAL UNION ALL
SELECT 'Dup-2', 567 FROM DUAL UNION ALL
SELECT 'Dup-3', 234 FROM DUAL UNION ALL
SELECT 'Dup-3', 567 FROM DUAL UNION ALL
SELECT 'Dup-4', 123 FROM DUAL UNION ALL
SELECT 'Dup-4', 567 FROM DUAL UNION ALL
SELECT 'Dup-4', 235 FROM DUAL;
CREATE TABLE Legitimate_Duplicates ("GROUP", Key) AS
SELECT 'A', 123 FROM DUAL UNION ALL
SELECT 'A', 234 FROM DUAL UNION ALL
SELECT 'B', 345 FROM DUAL UNION ALL
SELECT 'B', 456 FROM DUAL UNION ALL
SELECT 'C', 123 FROM DUAL UNION ALL
SELECT 'C', 567 FROM DUAL UNION ALL
SELECT 'D', 123 FROM DUAL UNION ALL
SELECT 'D', 235 FROM DUAL;
Note: GROUP is a reserved word and cannot be an unquoted identifier. It would be better to use a different name for the columns but you can use a quoted identifier (but its not best practice).
Outputs:
GROUP
KEY
Dup-2
123
Dup-2
345
Dup-2
567
Dup-3
234
Dup-3
567
Dup-4
235
Dup-4
567
db<>fiddle here
I have a table named "customer" that looks like this:
ID ALPHA BRAVO CHARLIE DATE
-------------------------------------------------
1 111 222 333 02/02/2019
2 333 444 555 11/11/2019
3 666 555 777 12/12/2019
4 777 888 999 05/05/2020
5 100 101 110 12/25/2020
and I need to get the following output:
ID ALPHA BRAVO CHARLIE DATE NEW_COL ROW_NUM
-----------------------------------------------------------------------
1 111 222 333 02/02/2019 333 4
2 333 444 555 11/11/2019 333 3
3 666 555 777 12/12/2019 333 2
4 777 888 999 05/05/2020 333 1
5 100 101 110 12/25/2020 010 1
The ALPHA, BRAVO, and CHARLIE columns represent customer IDs. A given customer can have multiple IDs in the system. Records 1-4 represent IDs belonging to the same customer, let's say John. As per the table, John has 12 IDs, and his latest ID is 999. Record 5 represents another customer, let's say Jane. Jane has three IDs, and her last ID is 110.
The purpose of the ROW_NUM column is to get the last CUSTOMER.CHARLIE value. The idea is to use the first CHARLIE value as the partition. Basically, the goal is to get one parent:many children mapping. In this case, the ID 333 should be tied to 555, 777, and 999.
Here is the DDL/DML:
CREATE TABLE CUSTOMER
(ID NUMBER(20) NOT NULL,
ALPHA NUMBER(20) NOT NULL,
BRAVO NUMBER(20) NOT NULL,
CHARLIE NUMBER(20) NOT NULL,
CREATEDDATE DATE
);
INSERT INTO CUSTOMER
VALUES
(1, 111, 222, 333, to_date('02-FEB-19','DD-MON-RR'));
INSERT INTO CUSTOMER
VALUES
(2, 333, 444, 555, to_date('11-NOV-19','DD-MON-RR'));
INSERT INTO CUSTOMER
VALUES
(3, 666, 555, 777, to_date('12-DEC-19','DD-MON-RR'));
INSERT INTO CUSTOMER
VALUES
(4, 777, 888, 999, to_date('05-MAY-20','DD-MON-RR'));
INSERT INTO CUSTOMER
VALUES
(5, 100, 101, 110, to_date('25-DEC-20','DD-MON-RR'));
COMMIT;
I have tried the following query, but it fails to populate the partition column correctly:
WITH
charlies
AS
(SELECT DISTINCT charlie
FROM customer),
mult_customers
AS
(SELECT c.*, c.charlie AS NEW_COL
FROM customer c
UNION
SELECT c.*,
CASE WHEN c.alpha = e.charlie THEN c.alpha ELSE c.bravo END AS NEW_COL
FROM customer c
JOIN charlies e ON e.charlie = c.alpha OR e.charlie = c.bravo),
ranked
AS
(SELECT mc.*,
ROW_NUMBER ()
OVER (PARTITION BY NEW_COL ORDER BY createddate DESC) AS row_num
FROM mult_customers mc)
SELECT *
FROM ranked
ORDER BY ID;
Thanks for any help provided.
You task is known as connected components. I wrote about 7-8 years ago solution for this and even pl/sql package: http://orasql.org/2017/09/29/connected-components/
This PL/SQL solution is much more effective then pure SQL solutions: http://orasql.org/2014/02/28/straight-sql-vs-sql-and-plsql/
Let me know if you need help with adopting it for your task.
i have 2 database in oracle.
DATABASE TABLE/VIEW NAME
digidb1 CUSTOMER_REFERENCE
digidb2 CUST_REF_VIEW
this query will display all data in the table CUSTOMER_REFERENCE from db digidb1.
select * from CUSTOMER_REFERENCE
cust_id brch_code cust_name description
001 001 COMPANY TEST 1 TEST COMPANY 1
002 002 COMPANY TEST 2 TEST COMPANY 2
003 003 COMPANY TEST 3 TEST COMPANY 3
this query will display all data in the view CUST_REF_VIEW from db digidb2.
select * FROM CUST_REF_VIEW
WINBBN CUSTFULLNAME ISINDIVIDUAL MRGDATE
1234 COMPANY TEST 1 N 12-03-20
4567 COMPANY TEST 4 N 12-03-20
8901 COMPANY TEST 2 N 11-03-20
2345 COMPANY TEST 5 Y 10-03-20
6789 COMPANY TEST 3 N 12-03-20
is it possible to update the table(CUSTOMER_REFERENCE) from database(digidb1) with this data?
i want to update cust_id column in CUSTOMER_REFERENCE from digidb1. the data will come from view CUST_REF_VIEW of digidb2.
the condition for updates are:
CUSTFULLNAME is equal to cust_name
MRGDATE is equal to system date/today (12-03-20)
ISINDIVIDUAL is equal to N.
my expected result is:
cust_id brch_code cust_name description
1234 001 COMPANY TEST 1 TEST COMPANY 1
002 002 COMPANY TEST 2 TEST COMPANY 2
6789 003 COMPANY TEST 3 TEST COMPANY 3
If I understood you correctly, you don't actually want to update anything, but select data from those two views by joining them, using certain conditions. If that's so, then:
SQL> with
2 -- sample data
3 customer_reference (cust_id, brch_code, cust_name, description) as
4 (select '001', '001', 'CT1', 'TC1' from dual union all
5 select '002', '002', 'CT2', 'TC2' from dual union all
6 select '003', '003', 'CT3', 'TC3' from dual
7 ),
8 cust_ref_view (winbbn, custfullname, isindividual, mgrdate) as
9 (select '1234', 'CT1', 'N', date '2020-03-12' from dual union all
10 select '4567', 'CT4', 'N', date '2020-03-12' from dual union all
11 select '8901', 'CT2', 'N', date '2020-03-11' from dual union all
12 select '2345', 'CT5', 'Y', date '2020-03-10' from dual union all
13 select '6789', 'CT3', 'N', date '2020-03-12' from dual
14 )
15 -- query you need
16 select case when v.mgrdate = trunc(sysdate)
17 and v.isindividual = 'N'
18 then v.winbbn
19 else r.cust_id
20 end cust_id,
21 --
22 r.brch_code, r.cust_name, r.description
23 from customer_reference r join cust_ref_view v on v.custfullname = r.cust_name;
CUST BRC CUS DES
---- --- --- ---
1234 001 CT1 TC1
002 002 CT2 TC2
6789 003 CT3 TC3
SQL>
Now, depending on what you really call "database", a database link might to be be involved if those really are different databases, e.g.
from customer_reference r join cust_ref_view#db_link_digidb2 v
----------------
this
If it is just about different users (schemas) within the same database, then you'll need to grant (at least) SELECT privilege from one user to another. It also means that you'd need to precede remote view name with its owner name, e.g.
from customer_reference r join digidb2.cust_ref_view v
--------
this
or - a simpler option - to create a synonym in one schema which will point to view in another schema. In that case, line #23 in query I posted would look exactly the same.
i need to create an oracle select statement that returns acct,name,city,splitcost from table1 and APIcost from table2. table1 splits the 90 into 3 diff. amounts because they are distributed elsewhere. table2 is the API download that only has 1 record of the total 90. if i use inner join the 90 repeats on each row linking by acct. i need the results to look like the second view only show APIcost total 90. once per acct.
hope this makes sense. if i was using sql I'm prob. do a temp table but it has to be done in Oracle which i'm not used too.
No need for a temp table, just build a rank and do a case statement on it to populate the first row with the api_cost. I don't know which row you want, so play with the "order by" clause to get that to do the row you want.
/* Building out your data to a "temp table" */
with table1 as
(select 1111 as acct, 'john' as name, 'hampton' as city, 30 as split_cost, 90 as
api_cost from dual union all
select 1111 as acct, 'john' as name, 'hampton' as city, 40 as split_cost, 90 as
api_cost from dual union all
select 1111 as acct, 'john' as name, 'hampton' as city, 20 as split_cost, 90 as
api_cost from dual union all
select 1111 as acct, 'john' as name, 'hampton' as city, 20 as split_cost, 90 as
api_cost from dual)
/* You need nothing above here, just below */
select acct, name, city, split_cost,
case when rank() over (partition by acct, name, city order by split_cost, rownum) =
1 then api_cost
else null
end as api_cost
from table1; --substitute your table name here
OUTPUT:
ACCT NAME CITY SPLIT_COST API_COST
1111 john hampton 20 90
1111 john hampton 20
1111 john hampton 30
1111 john hampton 40
I have a table abc with following rows:
emp_id_role Group_name Role_name Location_id
12 Insurance Manager Noida
12 Insurance Senior Manager Noida
13 Global Client Services Sw UP
14 Operations Management All Jobs kERALA
and another master table with all the details employee_xyz:
PERSON_ID NAME DOB START_DATE END_DATE SSN
12 DEAN 01-JAN-1990 01-JAN-2017 20-JAN-2017 847474
12 DEAN 01-JAN-1990 21-JAN-2017 03-mar-2018 847474
12 DEAN 01-JAN-1990 04-mar2018 31-DEC-4712 847474
13 SAM 20-JAN-1990 17-JAN-2016 20-JAN-2017 847474
13 SAM 20-JAN-1990 21-JAN-2017 31-DEC-4712 847474
14 JAY 29-dec-1990 21-JAN-2016 31-DEC-4712 847474
I want to fetch the full names from the table employee_xyz for the records in table abc.
When I'm joining these two using the below queries I'm getting more number of rows for an employee than in table abc,
Eg: for employee_id 12 I should get 2 rows as in table abc but I'm getting 9 rows somehow...
Query used is simple :
select * from table_abc abc,
employee_xyz xyz
where xyz.person_id=abc.emp_id_role
and trunc(sysdate) between abc.Start_date and xyz.end_date
and person_id=12;
I suppose you want to select all columns from table_abc with names from employee_xyz.
If your try with select abc.*, xyz.name, you already able to select as two rows since sysdate for person_id= 12 stays in the interval only for third row(start_date:04-mar2018/ end_date:31-DEC-4712) but if you want non-repeating even with more date values stay, you can use distinct : select distinct abc.*, xyz.name as below( where there're two rows in the interval second row's end date converted from '2018-03-03' to '2019-03-03' ) :
with table_abc(emp_id_role, Group_name, Role_name, Location_id) as
(
select 12,'Insurance','Manager','Noida' from dual union all
select 12,'Insurance','Senior Manager','Noida' from dual union all
select 13,'Global Client Services','Sw', 'UP' from dual union all
select 14,'Operations Management','All Jobs','kERALA' from dual
),
employee_xyz(person_id,name, dob, start_date, end_date, ssn) as
(
select 12,'DEAN',date'1990-01-01',date'2017-01-01',date'2017-01-20',847474 from dual union all
select 12,'DEAN',date'1990-01-01',date'2017-01-21',date'2019-03-03',847474 from dual union all
select 12,'DEAN',date'1990-01-01',date'2018-03-04',date'4712-12-31',847474 from dual
)
select distinct abc.*, xyz.name
from table_abc abc join employee_xyz xyz
on xyz.person_id = abc.emp_id_role
where trunc(sysdate) between xyz.Start_date and xyz.end_date
and person_id = 12;
EMP_ID_ROLE GROUP_NAME ROLE_NAME LOCATION_ID NAME
----------- ---------- --------------- ----------- -----
12 Insurance Manager Noida DEAN
12 Insurance Senior Manager Noida DEAN