how to setup IOServiceAddMatching for different product identifications - objective-c

need to use IOServiceAddMatchingNotification routine for supporing multiple product identifications.
To show the concept, I got part of this code from a site and revised it.Kept it short.
// Set up matching dictionary.
NSMutableDictionary* matchingDictionary;
for (int n = 0; n < numberOfDevices; n++)
{
matchingDictionary = (NSMutableDictionary*)IOServiceMatching(kIOUSBDeviceClassName);
[matchingDictionary setObject:[NSNumber numberWithLong:myVid[n]] forKey:[NSString stringWithUTF8String:kUSBVendorID]];
[matchingDictionary setObject:[NSNumber numberWithLong:myPid[n]] forKey:[NSString stringWithUTF8String:kUSBProductID]];
// Set up a notification callback for device addition on first match.
IOServiceAddMatchingNotification(g_notificationPort, kIOFirstMatchNotification, (CFMutableDictionaryRef)matchingDictionary, deviceAddedCallback, (void*)self, &g_iteratorAdded);
}
I am not sure if it really is correct?. I did not see complains from the xcode and it works.

This requires a nuanced answer - there are three things to note here:
In principle, yes, you need to create distinct matching notifications for each independent match dictionary.
However, it looks like you're expecting only one io_iterator_t to be created and updated with each matching dictionary, as you only have a single variable to store it, g_iteratorAdded. This is not the case. The code shown suffers from a resource leak. Each successful call to IOServiceAddMatchingNotification will create a new iterator, so you will need to retain all of them in an array or so. And then, when you no longer need the notifications (at the latest, when self is dealloc'd, or you'll get callbacks on a freed object!), you need to release all of the iterators.
For matching multiple different USB product IDs but identical vendor IDs, you actually don't need to create multiple match dictionaries and notifications. Instead of kUSBProductID with a single NSNumber/CFNumber, provide a kUSBProductIdsArrayName (aka kUSBHostMatchingPropertyProductIDArray) and specify an array of numbers. (NSArray/CFArray containing a NSNumber/CFNumber for every product ID.)Alternatively, if your product IDs match some hex pattern, you can also use kUSBProductIDMask in conjunction with kUSBProductID: in this case, candidate devices' product IDs will be bitwise masked (&) with the number provided for kUSBProductIDMask before comparing to the kUSBProductID.
If you need to match multiple vendor IDs, you will still need to create a matching notification for each vendor ID, and provide the list of product IDs in the kUSBProductIdsArrayName value for each.
Update: Sample code for array PID match dictionaries
Some rough untested code for dealing with kUSBProductIdsArrayName, assuming your VIDs/PIDs are laid out like this:
static const uint16_t myVid[] = { 0x1234, 0x5555 };
static const size_t numberOfVids = sizeof(myVid) / sizeof(myVid[0]);
static const uint16_t myPid[] = {
// for VID 0x1234
0x1, 0x2, 0x3, 0x1001, 0x1002,
// for VID 0x555
0x100, 0x101,
};
static const unsigned pidsForVid[] = { 5, 2 };
Setting up the matching dictionaries would then look something like this:
unsigned next_pid_index = 0;
for (int n = 0; n < numberOfVids; n++)
{
NSMutableDictionary* matchingDictionary =
(__bridge_transfer NSMutableDictionary*)IOServiceMatching(kIOUSBDeviceClassName);
[matchingDictionary setObject:#(myVid[n]) forKey:#kUSBVendorID];
NSMutableArray* pid_array = [NSMutableArray arrayWithCapacity:pidsForVid[n]];
for (unsigned i = 0; i < pidsForVid[n]; ++i)
{
[pid_array addObject:#(myPid[next_pid_index])];
++next_pid_index;
}
[matchingDictionary setObject:pid_array forKey:#kUSBProductIdsArrayName];
// Set up a notification callback for device addition on first match.
IOReturn result = IOServiceAddMatchingNotification(
g_notificationPort,
kIOFirstMatchNotification,
(__bridge_retained CFMutableDictionaryRef)matchingDictionary,
deviceAddedCallback,
(__bridge void*)self,
&g_iteratorAdded[n]);
assert(result == kIOReturnSuccess);
}

Related

Parallel Dynamic Programming with CUDA

It is my first attempt to implement recursion with CUDA. The goal is to extract all the combinations from a set of chars "12345" using the power of CUDA to parallelize dynamically the task. Here is my kernel:
__device__ char route[31] = { "_________________________"};
__device__ char init[6] = { "12345" };
__global__ void Recursive(int depth) {
// up to depth 6
if (depth == 5) return;
// newroute = route - idx
int x = depth * 6;
printf("%s\n", route);
int o = 0;
int newlen = 0;
for (int i = 0; i<6; ++i)
{
if (i != threadIdx.x)
{
route[i+x-o] = init[i];
newlen++;
}
else
{
o = 1;
}
}
Recursive<<<1,newlen>>>(depth + 1);
}
__global__ void RecursiveCount() {
Recursive <<<1,5>>>(0);
}
The idea is to exclude 1 item (the item corresponding to the threadIdx) in each different thread. In each recursive call, using the variable depth, it works over a different base (variable x) on the route device variable.
I expect the kernel prompts something like:
2345_____________________
1345_____________________
1245_____________________
1234_____________________
2345_345_________________
2345_245_________________
2345_234_________________
2345_345__45_____________
2345_345__35_____________
2345_345__34_____________
..
2345_245__45_____________
..
But it prompts ...
·_____________
·_____________
·_____________
·_____________
·_____________
·2345
·2345
·2345
·2345
...
What I´m doing wrong?
What I´m doing wrong?
I may not articulate every problem with your code, but these items should get you a lot closer.
I recommend providing a complete example. In my view it is basically required by Stack Overflow, see item 1 here, note use of the word "must". Your example is missing any host code, including the original kernel call. It's only a few extra lines of code, why not include it? Sure, in this case, I can deduce what the call must have been, but why not just include it? Anyway, based on the output you indicated, it seems fairly evident the launch configuration of the host launch would have to be <<<1,1>>>.
This doesn't seem to be logical to me:
I expect the kernel prompts something like:
2345_____________________
The very first thing your kernel does is print out the route variable, before making any changes to it, so I would expect _____________________. However we can "fix" this by moving the printout to the end of the kernel.
You may be confused about what a __device__ variable is. It is a global variable, and there is only one copy of it. Therefore, when you modify it in your kernel code, every thread, in every kernel, is attempting to modify the same global variable, at the same time. That cannot possibly have orderly results, in any thread-parallel environment. I chose to "fix" this by making a local copy for each thread to work on.
You have an off-by-1 error, as well as an extent error in this loop:
for (int i = 0; i<6; ++i)
The off-by-1 error is due to the fact that you are iterating over 6 possible items (that is, i can reach a value of 5) but there are only 5 items in your init variable (the 6th item being a null terminator. The correct indexing starts out over 0-4 (with one of those being skipped). On subsequent iteration depths, its necessary to reduce this indexing extent by 1. Note that I've chosen to fix the first error here by increasing the length of init. There are other ways to fix, of course. My method inserts an extra _ between depths in the result.
You assume that at each iteration depth, the correct choice of items is the same, and in the same order, i.e. init. However this is not the case. At each depth, the choices of items must be selected not from the unchanging init variable, but from the choices passed from previous depth. Therefore we need a local, per-thread copy of init also.
A few other comments about CUDA Dynamic Parallelism (CDP). When passing pointers to data from one kernel scope to a child scope, local space pointers cannot be used. Therefore I allocate for the local copy of route from the heap, so it can be passed to child kernels. init can be deduced from route, so we can use an ordinary local variable for myinit.
You're going to quickly hit some dynamic parallelism (and perhaps memory) limits here if you continue this. I believe the total number of kernel launches for this is 5^5, which is 3125 (I'm doing this quickly, I may be mistaken). CDP has a pending launch limit of 2000 kernels by default. We're not hitting this here according to what I see, but you'll run into that sooner or later if you increase the depth or width of this operation. Furthermore, in-kernel allocations from the device heap are by default limited to 8KB. I don't seem to be hitting that limit, but probably I am, so my design should probably be modified to fix that.
Finally, in-kernel printf output is limited to the size of a particular buffer. If this technique is not already hitting that limit, it will soon if you increase the width or depth.
Here is a worked example, attempting to address the various items above. I'm not claiming it is defect free, but I think the output is closer to your expectations. Note that due to character limits on SO answers, I've truncated/excerpted some of the output.
$ cat t1639.cu
#include <stdio.h>
__device__ char route[31] = { "_________________________"};
__device__ char init[7] = { "12345_" };
__global__ void Recursive(int depth, const char *oroute) {
char *nroute = (char *)malloc(31);
char myinit[7];
if (depth == 0) memcpy(myinit, init, 6);
else memcpy(myinit, oroute+(depth-1)*6, 6);
myinit[6] = 0;
if (nroute == NULL) {printf("oops\n"); return;}
memcpy(nroute, oroute, 30);
nroute[30] = 0;
// up to depth 6
if (depth == 5) return;
// newroute = route - idx
int x = depth * 6;
//printf("%s\n", nroute);
int o = 0;
int newlen = 0;
for (int i = 0; i<(6-depth); ++i)
{
if (i != threadIdx.x)
{
nroute[i+x-o] = myinit[i];
newlen++;
}
else
{
o = 1;
}
}
printf("%s\n", nroute);
Recursive<<<1,newlen>>>(depth + 1, nroute);
}
__global__ void RecursiveCount() {
Recursive <<<1,5>>>(0, route);
}
int main(){
RecursiveCount<<<1,1>>>();
cudaDeviceSynchronize();
}
$ nvcc -o t1639 t1639.cu -rdc=true -lcudadevrt -arch=sm_70
$ cuda-memcheck ./t1639
========= CUDA-MEMCHECK
2345_____________________
1345_____________________
1245_____________________
1235_____________________
1234_____________________
2345__345________________
2345__245________________
2345__235________________
2345__234________________
2345__2345_______________
2345__345___45___________
2345__345___35___________
2345__345___34___________
2345__345___345__________
2345__345___45____5______
2345__345___45____4______
2345__345___45____45_____
2345__345___45____5______
2345__345___45____5_____5
2345__345___45____4______
2345__345___45____4_____4
2345__345___45____45____5
2345__345___45____45____4
2345__345___35____5______
2345__345___35____3______
2345__345___35____35_____
2345__345___35____5______
2345__345___35____5_____5
2345__345___35____3______
2345__345___35____3_____3
2345__345___35____35____5
2345__345___35____35____3
2345__345___34____4______
2345__345___34____3______
2345__345___34____34_____
2345__345___34____4______
2345__345___34____4_____4
2345__345___34____3______
2345__345___34____3_____3
2345__345___34____34____4
2345__345___34____34____3
2345__345___345___45_____
2345__345___345___35_____
2345__345___345___34_____
2345__345___345___45____5
2345__345___345___45____4
2345__345___345___35____5
2345__345___345___35____3
2345__345___345___34____4
2345__345___345___34____3
2345__245___45___________
2345__245___25___________
2345__245___24___________
2345__245___245__________
2345__245___45____5______
2345__245___45____4______
2345__245___45____45_____
2345__245___45____5______
2345__245___45____5_____5
2345__245___45____4______
2345__245___45____4_____4
2345__245___45____45____5
2345__245___45____45____4
2345__245___25____5______
2345__245___25____2______
2345__245___25____25_____
2345__245___25____5______
2345__245___25____5_____5
2345__245___25____2______
2345__245___25____2_____2
2345__245___25____25____5
2345__245___25____25____2
2345__245___24____4______
2345__245___24____2______
2345__245___24____24_____
2345__245___24____4______
2345__245___24____4_____4
2345__245___24____2______
2345__245___24____2_____2
2345__245___24____24____4
2345__245___24____24____2
2345__245___245___45_____
2345__245___245___25_____
2345__245___245___24_____
2345__245___245___45____5
2345__245___245___45____4
2345__245___245___25____5
2345__245___245___25____2
2345__245___245___24____4
2345__245___245___24____2
2345__235___35___________
2345__235___25___________
2345__235___23___________
2345__235___235__________
2345__235___35____5______
2345__235___35____3______
2345__235___35____35_____
2345__235___35____5______
2345__235___35____5_____5
2345__235___35____3______
2345__235___35____3_____3
2345__235___35____35____5
2345__235___35____35____3
2345__235___25____5______
2345__235___25____2______
2345__235___25____25_____
2345__235___25____5______
2345__235___25____5_____5
2345__235___25____2______
2345__235___25____2_____2
2345__235___25____25____5
2345__235___25____25____2
2345__235___23____3______
2345__235___23____2______
2345__235___23____23_____
2345__235___23____3______
2345__235___23____3_____3
2345__235___23____2______
2345__235___23____2_____2
2345__235___23____23____3
2345__235___23____23____2
2345__235___235___35_____
2345__235___235___25_____
2345__235___235___23_____
2345__235___235___35____5
2345__235___235___35____3
2345__235___235___25____5
2345__235___235___25____2
2345__235___235___23____3
2345__235___235___23____2
2345__234___34___________
2345__234___24___________
2345__234___23___________
2345__234___234__________
2345__234___34____4______
2345__234___34____3______
2345__234___34____34_____
2345__234___34____4______
2345__234___34____4_____4
2345__234___34____3______
2345__234___34____3_____3
2345__234___34____34____4
2345__234___34____34____3
2345__234___24____4______
2345__234___24____2______
2345__234___24____24_____
2345__234___24____4______
2345__234___24____4_____4
2345__234___24____2______
2345__234___24____2_____2
2345__234___24____24____4
2345__234___24____24____2
2345__234___23____3______
2345__234___23____2______
2345__234___23____23_____
2345__234___23____3______
2345__234___23____3_____3
2345__234___23____2______
2345__234___23____2_____2
2345__234___23____23____3
2345__234___23____23____2
2345__234___234___34_____
2345__234___234___24_____
2345__234___234___23_____
2345__234___234___34____4
2345__234___234___34____3
2345__234___234___24____4
2345__234___234___24____2
2345__234___234___23____3
2345__234___234___23____2
2345__2345__345__________
2345__2345__245__________
2345__2345__235__________
2345__2345__234__________
2345__2345__345___45_____
2345__2345__345___35_____
2345__2345__345___34_____
2345__2345__345___45____5
2345__2345__345___45____4
2345__2345__345___35____5
2345__2345__345___35____3
2345__2345__345___34____4
2345__2345__345___34____3
2345__2345__245___45_____
2345__2345__245___25_____
2345__2345__245___24_____
2345__2345__245___45____5
2345__2345__245___45____4
2345__2345__245___25____5
2345__2345__245___25____2
2345__2345__245___24____4
2345__2345__245___24____2
2345__2345__235___35_____
2345__2345__235___25_____
2345__2345__235___23_____
2345__2345__235___35____5
2345__2345__235___35____3
2345__2345__235___25____5
2345__2345__235___25____2
2345__2345__235___23____3
2345__2345__235___23____2
2345__2345__234___34_____
2345__2345__234___24_____
2345__2345__234___23_____
2345__2345__234___34____4
2345__2345__234___34____3
2345__2345__234___24____4
2345__2345__234___24____2
2345__2345__234___23____3
2345__2345__234___23____2
1345__345________________
1345__145________________
1345__135________________
1345__134________________
1345__1345_______________
1345__345___45___________
1345__345___35___________
1345__345___34___________
1345__345___345__________
1345__345___45____5______
1345__345___45____4______
1345__345___45____45_____
1345__345___45____5______
1345__345___45____5_____5
1345__345___45____4______
1345__345___45____4_____4
1345__345___45____45____5
1345__345___45____45____4
1345__345___35____5______
1345__345___35____3______
1345__345___35____35_____
1345__345___35____5______
1345__345___35____5_____5
1345__345___35____3______
1345__345___35____3_____3
1345__345___35____35____5
1345__345___35____35____3
1345__345___34____4______
1345__345___34____3______
1345__345___34____34_____
1345__345___34____4______
1345__345___34____4_____4
1345__345___34____3______
1345__345___34____3_____3
1345__345___34____34____4
1345__345___34____34____3
1345__345___345___45_____
1345__345___345___35_____
1345__345___345___34_____
1345__345___345___45____5
1345__345___345___45____4
1345__345___345___35____5
1345__345___345___35____3
1345__345___345___34____4
1345__345___345___34____3
1345__145___45___________
1345__145___15___________
1345__145___14___________
1345__145___145__________
1345__145___45____5______
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1345__145___45____4______
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1345__145___45____45____5
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1345__145___15____5______
1345__145___15____1______
1345__145___15____15_____
1345__145___15____5______
1345__145___15____5_____5
1345__145___15____1______
1345__145___15____1_____1
1345__145___15____15____5
1345__145___15____15____1
1345__145___14____4______
1345__145___14____1______
1345__145___14____14_____
1345__145___14____4______
1345__145___14____4_____4
1345__145___14____1______
1345__145___14____1_____1
1345__145___14____14____4
1345__145___14____14____1
1345__145___145___45_____
1345__145___145___15_____
1345__145___145___14_____
1345__145___145___45____5
1345__145___145___45____4
1345__145___145___15____5
1345__145___145___15____1
1345__145___145___14____4
1345__145___145___14____1
1345__135___35___________
1345__135___15___________
1345__135___13___________
1345__135___135__________
1345__135___35____5______
1345__135___35____3______
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1345__135___35____5______
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1345__135___35____3______
1345__135___35____3_____3
1345__135___35____35____5
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1345__135___15____5______
1345__135___15____1______
1345__135___15____15_____
1345__135___15____5______
1345__135___15____5_____5
1345__135___15____1______
1345__135___15____1_____1
1345__135___15____15____5
1345__135___15____15____1
1345__135___13____3______
1345__135___13____1______
1345__135___13____13_____
1345__135___13____3______
1345__135___13____3_____3
1345__135___13____1______
1345__135___13____1_____1
1345__135___13____13____3
1345__135___13____13____1
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1345__135___135___35____5
1345__135___135___35____3
1345__135___135___15____5
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1345__135___135___13____1
1345__134___34___________
1345__134___14___________
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1345__134___34____4______
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1345__134___34____3______
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1345__134___34____34____4
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1345__134___14____4______
1345__134___14____1______
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1345__134___14____4______
1345__134___14____4_____4
1345__134___14____1______
1345__134___14____1_____1
1345__134___14____14____4
1345__134___14____14____1
1345__134___13____3______
1345__134___13____1______
1345__134___13____13_____
1345__134___13____3______
1345__134___13____3_____3
1345__134___13____1______
1345__134___13____1_____1
1345__134___13____13____3
1345__134___13____13____1
1345__134___134___34_____
1345__134___134___14_____
1345__134___134___13_____
1345__134___134___34____4
1345__134___134___34____3
1345__134___134___14____4
1345__134___134___14____1
1345__134___134___13____3
1345__134___134___13____1
1345__1345__345__________
1345__1345__145__________
1345__1345__135__________
1345__1345__134__________
1345__1345__345___45_____
1345__1345__345___35_____
1345__1345__345___34_____
1345__1345__345___45____5
1345__1345__345___45____4
1345__1345__345___35____5
1345__1345__345___35____3
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1345__1345__345___34____3
1345__1345__145___45_____
1345__1345__145___15_____
1345__1345__145___14_____
1345__1345__145___45____5
1345__1345__145___45____4
1345__1345__145___15____5
1345__1345__145___15____1
1345__1345__145___14____4
1345__1345__145___14____1
1345__1345__135___35_____
1345__1345__135___15_____
1345__1345__135___13_____
1345__1345__135___35____5
1345__1345__135___35____3
1345__1345__135___15____5
1345__1345__135___15____1
1345__1345__135___13____3
1345__1345__135___13____1
1345__1345__134___34_____
1345__1345__134___14_____
1345__1345__134___13_____
1345__1345__134___34____4
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1245__245________________
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1245__245___25____2______
1245__245___25____25_____
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========= ERROR SUMMARY: 0 errors
$
The answer given by Robert Crovella is correct at the 5th point, the mistake was in the using of init in every recursive call, but I want to clarify something that can be useful for other beginners with CUDA.
I used this variable because when I tried to launch a child kernel passing a local variable I always got the exception: Error: a pointer to local memory cannot be passed to a launch as an argument.
As I´m C# expert developer I´m not used to using pointers (Ref does the low-level-work for that) so I thought there was no way to do it in CUDA/c programming.
As Robert shows in its code it is possible copying the pointer with memalloc for using it as a referable argument.
Here is a kernel simplified as an example of deep recursion.
__device__ char init[6] = { "12345" };
__global__ void Recursive(int depth, const char* route) {
// up to depth 6
if (depth == 5) return;
//declaration for a referable argument (point 6)
char* newroute = (char*)malloc(6);
memcpy(newroute, route, 5);
int o = 0;
int newlen = 0;
for (int i = 0; i < (6 - depth); ++i)
{
if (i != threadIdx.x)
{
newroute[i - o] = route[i];
newlen++;
}
else
{
o = 1;
}
}
printf("%s\n", newroute);
Recursive <<<1, newlen>>>(depth + 1, newroute);
}
__global__ void RecursiveCount() {
Recursive <<<1, 5>>>(0, init);
}
I don't add the main call because I´m using ManagedCUDA for C# but as Robert says it can be figured-out how the call RecursiveCount is.
About ending arrays of char with /0 ... sorry but I don't know exactly what is the benefit; this code works fine without them.

Three different ways to instantiate Arrays in AssemblyScript

I'm writing a smart contract and want to use Arrays to manipulate data, but looking at the AssemblyScript docs, I'm not sure the best way to proceed.
It seems fine to me to just use:
let testData:string[] = []
but when I consulted the assemblyscript docs, there are three recommended ways to create an Array:
// The Array constructor implicitly sets `.length = 10`, leading to an array of
// ten times `null` not matching the value type `string`. So, this will error:
var arr = new Array<string>(10);
// arr.length == 10 -> ERROR
// To account for this, the .create method has been introduced that initializes
// the backing capacity normally but leaves `.length = 0`. So, this will work:
var arr = Array.create<string>(10);
// arr.length == 0 -> OK
// When pushing to the latter array or subsequently inserting elements into it,
// .length will automatically grow just like one would expect, with the backing
// buffer already properly sized (no resize will occur). So, this is fine:
for (let i = 0; i < 10; ++i) arr[i] = "notnull";
// arr.length == 10 -> OK
When would I want to use one type of instantiation over another? Why wouldn't I just always use the version I presented in the beginning?
Nothing wrong with the array literal approach. It is basically equivalent to
let testData = new Array<string>();
However, sometimes you know what the length of the array should be and in such cases, preallocating the memory using Array.create is more efficient.
UPDATE
With this PR Array.create deprecated and should not be used anymore.
OLD ANSWER
let testData:string[] = []
semantically the same as
let testData = new Array<string>()
AssemblyScript doesn't support preallocated sparse arrays (arrays with holes) for reference elements which not explicitly declared as nullable like:
let data = new Array<string>(10);
data[9] = 1; // will be compile error
Instead you could use:
let data = new Array<string | null>(10);
assert(data.length == 10); // ok
assert(data[0] === null); // ok
or Array.create but in this case your length will be zero. Array.create is actually just reserve capacity for backing buffer.
let data = Array.create<string>(10);
assert(data.length == 0); // true
For plain (non-reference) types you could use usual way without care about nullabe or creating array via Array.create:
let data = new Array<i32>(10);
assert(data.length == 10); // ok
assert(data[0] == 0); // ok

For with multiple in

I want to use the basic Objective C stament for (id object in collection) with multiple objects and conditions like this:
for (Origin *origin in [self.fetchedOriginController fetchedObjects] AND Destiny *destiny in [self.fetchedDestinyController fetchedObjects]))
{
NSLog(#"This route starts from %# and ends in %#, origin.name, destiny.name);
}
So the log would be:
This route starts in London and ends in Sidney
This route starts in Madrid and ends in Barcelona
This route starts in Washington and ends in Vienna
(...)
How can this be done?
If you are looking for all combinations just nest:
for (object in collection)
{
for (object2 in collection2)
{
...
}
}
Or are you looking for pairs of objects from two same sized collections? If so create a loop which provides the index:
NSUInteger count = collection.count;
for (NSUInteger ix = 0; ix < count; ix++)
{
id object = collection[ix];
id object2 = collection2[ix];
...
}
If you want to loop over the common pairs of two different sized collections just change the first line to:
NSUInteger count = MIN(collection.count, collection2.count);
If you want something else edit your question to be more explicit.
Something like this would work for what you're trying I think:
for (NSUInteger i = 0; i < collection1.count; i++) {
id object1 = collection1[i];
id object2 = collection2[i];
// continue ...
}
As far as I know, there's no built in syntax to do what you're asking.
This solution makes the assumption that collection1 and collection2 have the same amount of objects, or at least collection2 doesn't exceed collection1 in count. Given your desired syntax, I think you have already planned for this, I just wanted to mention it in case someone else stumbles on this.
What order do you expect this enumeration to happen in? What kind of association between objects from each collection are you looking for?
If you want to take each object from collection and do something with both that object and each object2 in collection2, use nested loops:
for (object in collection) {
for (object2 in collection2) {
// ...
}
}
If you want to go through both collections in order, use two loops.
for (object in collection) { /* ... */ }
for (object2 in collection2) { /* ... */ }
If you expect some sort of mapping between the objects in collection and collection2 (which presumes they have the same count and at least one of them has unique entries), you might look into a data structure that captures that mapping. Then you can iterate across pairs.
NSDictionary *dictionary = [NSDictionary dictionaryWithObjects:collection2 forKeys:collection];
[dictionary enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL *stop){
// ...
}];

C General Protection Fault trying to access object in array

In my program, I store objective-c objects in a c array, like this
va_start(list, o);
retval->objs = malloc(SIZE * count);
retval->objs[0] = (__bridge void *)o;
for (int i = 1; i < count; i++)
{
id o = va_arg(list, id);
retval->objs[i] = (__bridge void *)o;
}
va_end(list);
(count is a number containing how many objects will be added; that value is always correct)
objs is a void ** and is part of retval, which is a pointer to a struct. As of now, SIZE is defined as 100. Increasing and decreasing that had no effect.
As you can see, I bridge o to a void *, as I have to. objs, when all the objects are added, contains 3 objective-c objects. When I try to access a value like this
void *obj = CLArrayObjectAtIndex(_arr, ind);
return (__bridge id)obj;
this is the CLArrayObjectAtIndex() function
void *CLArrayObjectAtIndex(CLArrayType *arr, int ind)
{
void *o = arr->objs[ind];
if (o)
return o;
else
perror("Attempt to access NULL object or index out of bounds."), abort();
}
if the index (ind) is 0, it works. If the index is 1, the program crashes when it returns in main. If the index is 2, the program crashes as soon as I try to access it. If the index is 1, the value returned above is correct, but when the program crashes on return it is nil.
If the index is 1, the EXC_BAD_ACCESS code is 1; if the index is 2, the code is EXC_I386_GPFLT, a general protection fault. I already checked here for an explanation of this exception, although I couldn't find anything helpful. So, does anybody see why this error may be occurring?
when you store obj-c objects in C array don't just bridge cast them since that way arc doesn't know they are still used and releases them. __bridge_retain them so they stay around later, when you free the array __bridge_transfer them to give them back to ARC
also don't define size as 100.. sizeof(id) should work. You only need to store pointers

How to return a C-array from method in Objective-C?

I have a function that returns a variable and I want to know how to return an array the issue is it isn't an NSArray it is just an average C array like this...
-(b2Fixture*) addFixturesToBody:(b2Body*)body forShapeName:(NSString*)shape
{
BodyDef *so = [shapeObjects objectForKey:shape];
assert(so);
FixtureDef *fix = so->fixtures;
int count = -1;
b2Fixture *Fixi[4];
while(fix)
{
count++;
NSLog(#"count = %d",count);
Fixi[count]= body->CreateFixture(&fix->fixture);
if (Fixi[count]!=0) {
NSLog(#"Fixi %d is not 0",count);
}
if (body->CreateFixture(&fix->fixture)!=0) {
NSLog(#"body %d is not 0",count);
}
fix = fix->next;
}
return *Fixi;
}
If you see some variable types you don't know it's because I'm using cocos2d framework to make a game but I'm returning a variable of b2Fixture... This code compiles however only saves the value of the first block of the array "fixi[0]" not the whole array like I want to pass
anyhelp :) thankyou
You can't return a local array. You'll need to do some kind of dynamic allocation or pull a trick like having the array inside a structure.
Here is a link to an in-depth article that should help you out.
In general returning C arrays by value is a bad idea, as arrays can be very large. Objective-C arrays are by-reference types - they are dynamically allocated and a reference, which is small, is what is passed around. You can dynamically allocate C arrays as well, using one of the malloc family for allocation and free for deallocation.
You can pass C structures around by value, and this is common, as in general structures tend to be small (or smallish anyway).
Now in your case you are using a small array, it has just 4 elements. If you consider passing these 4 values around by value is reasonable and a good fit for your design then you can do so simply by embedding the C array in a C structure:
typedef struct
{
b2Fixture *elements[4];
} b2FixtureArray;
...
-(b2FixtureArray) addFixturesToBody:(b2Body*)body forShapeName:(NSString*)shape
{
BodyDef *so = [shapeObjects objectForKey:shape];
assert(so);
FixtureDef *fix = so->fixtures;
int count = -1;
b2FixtureArray Fixi;
while(fix)
{
count++;
NSLog(#"count = %d", count);
Fixi.elements[count]= body->CreateFixture(&fix->fixture);
if (Fixi.elements[count] != 0)
{
NSLog(#"Fixi %d is not 0",count);
}
if (body->CreateFixture(&fix->fixture) != 0)
{
NSLog(#"body %d is not 0", count);
}
fix = fix->next;
}
return Fixi;
}
...
// sample call outline
b2FixtureArray result = [self addFixturesToBody...]
Whether this standard C "trick" for passing arrays by value is appropriate for your case you'll have to decide.
Note: If b2fixture is an Objective-C object make sure you understand the memory management implications of having a C array of objects references depending on the memory management model (MRC, ARC, GC) you are using.
If you need to design function or method that has to return a fixed or limited size array, one possibility is to pass a pointer to the result array to the function or method as a parameter. Then the caller can take care of allocating space, or just use a local or instance variable array. You might want the called function to sanity check that the array parameter isn't NULL before using the array.