I am using matplotlib with tikzplotlib to plot (PGF/TikZ) figures.
I do not want a grid to be plotted, however the grid is always activated in the TeX output.
How can I get around this?
I don't want to edit the .tex
if possible.
Bonus question: Is there also a way to get the legend title?
Example:
import numpy as np
import matplotlib.pyplot as plt
import tikzplotlib as tikz
x = np.arange(0, 5, 1)
y = x
fig, ax = plt.subplots()
ax.plot(x, y, label='asdf')
ax.grid(False)
ax.legend(title='asdf')
ax.set(xlabel='x',
ylabel='y')
plt.show()
tikz.clean_figure()
tikz.save("asdf.tex", figure=fig)
matplotlib plot (without grid)
tikzplotlib plot (grid activated)
I have a pandas series containing numbers ranging between 0 and 100. I want to visualise it in a horizontal bar consisting of 3 main colours.
I have tried using seaborn but all I can get is a heatmap matrix. I have also tried the below code, which is producing what I need but not in the way I need it.
x = my_column.values
y = x
t = x
fig, (ax1, ax2) = plt.subplots(1, 2)
ax1.scatter(x, y, c=t, cmap='brg')
ax2.scatter(x, y, c=t, cmap='brg')
plt.show()
What I'm looking for is something similar to the below figure, how can I achieve that using matplotlib or seaborn?
The purpose of this is not quite clear, however, the following would produce an image like the one shown in the question:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.colors import LinearSegmentedColormap
x = np.linspace(100,0,101)
fig, ax = plt.subplots(figsize=(6,1), constrained_layout=True)
cmap = LinearSegmentedColormap.from_list("", ["limegreen", "gold", "crimson"])
ax.imshow([x], cmap=cmap, aspect="auto",
extent=[x[0]-np.diff(x)[0]/2, x[-1]+np.diff(x)[0]/2,0,1])
ax.tick_params(axis="y", left=False, labelleft=False)
plt.show()
I want to draw a 3D scatter, in which the data is colored by group. Here is the data sample:
aa=pd.DataFrame({'a':[1,2,3,4,5],
'b':[2,3,4,5,6],
'c':[1,3,4,6,9],
'd':[0,0,1,2,3],
'e':['abc','sdf','ert','hgf','nhkm']})
Here, a, b, c are axis x, y, z. e is the text shown in the scatter. I need d to group the data and show different colors.
Here is my code:
fig = plt.figure()
ax = fig.gca(projection='3d')
zdirs = aa.loc[:,'e'].__array__()
xs = aa.loc[:,'a'].__array__()
ys = aa.loc[:,'b'].__array__()
zs = aa.loc[:,'c'].__array__()
colors = aa.loc[:,'d'].__array__()
colors1=np.where(colors==0,'grey',
np.where(colors==1,'yellow',
np.where(colors==2,'green',
np.where(colors==3,'pink','red'))))
for i in range(len(zdirs)): #plot each point + it's index as text above
ax.scatter(xs[i],ys[i],zs[i],color=colors1[i])
ax.text(xs[i],ys[i],zs[i], '%s' % (str(zdirs[i])), size=10, zorder=1, color='k')
ax.set_xlabel('a')
ax.set_ylabel('b')
ax.set_zlabel('c')
plt.show()
But I do not know how to put a legend on the plot. I hope my legend is like:
The colors and the numbers should match and be ordered.
Could anyone help me with how to customize the color bar?
First of all, I've taken the liberty to reduce your code a bit:
I'd suggest to create a ListedColormap to map integer->color, which allows you to pass the color column via c=aa['d'] (note it's c=, not color=!)
you don't need to use __array__() here, in the code below you can directly use aa['a']
finally, you can add an empty scatter plot for each color in the ListedColormap, and this can then be rendered correctly by ax.legend()
import pandas as pd
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
from matplotlib.colors import ListedColormap
import matplotlib.patches as mpatches
aa=pd.DataFrame({'a':[1,2,3,4,5],
'b':[2,3,4,5,6],
'c':[1,3,4,6,9],
'd':[0,0,1,2,3],
'e':['abc','sdf','ert','hgf','nhkm']})
fig = plt.figure()
ax = fig.gca(projection='3d')
cmap = ListedColormap(['grey', 'yellow', 'green', 'pink','red'])
ax.scatter(aa['a'],aa['b'],aa['c'],c=aa['d'],cmap=cmap)
for x,y,z,label in zip(aa['a'],aa['b'],aa['c'],aa['e']):
ax.text(x,y,z,label,size=10,zorder=1)
# Create a legend through an *empty* scatter plot
[ax.scatter([], [], c=cmap(i), label=str(i)) for i in range(len(aa))]
ax.legend()
ax.set_xlabel('a')
ax.set_ylabel('b')
ax.set_zlabel('c')
plt.show()
I am trying to shorten a colorbar by half. Does anyone know how to do this? I tried cax.get_position() and then cax.set_position(), but this method did not work.
Besides, it seems that axes created by axes_grid1 has the same bbox positions as the original axes. Is this a bug?
PS. I have to use axes_grid1 to create colorbar axes, because I need to use tight_layout() afterwards, and tight_layout() only applies to axes created by axes_grid1 but not ones created by add_axes().
import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid1 import make_axes_locatable
import numpy as np
plt.figure()
ax = plt.gca()
im = ax.imshow(np.arange(100).reshape((10,10)))
divider = make_axes_locatable(ax)
cax = divider.append_axes("right", size="5%", pad=0.05)
bbox1 = ax.get_position()
print(bbox1)
bbox1 = cax.get_position()
print(bbox1)
plt.colorbar(im, cax=cax)
plt.show()
The whole point of the axes_divider is to divide the axes to make space for a new axes. This ensures that all axes have the same surrounding box. And that is the box you see being printed.
Some of the usual ways to create a colorbar, at a certain location in the figue are shown in this question. Here the problem seems to be to be able to call tight_layout. This is achievable with the following two options. (There might be others still.)
A. using gridspec
I'm not too sure about the exact requirements here, but it seems that using a normal grid layout would be more in the direction of what you need here.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec
fig = plt.figure()
gs = gridspec.GridSpec(2, 2, width_ratios=[95,5],)
ax = fig.add_subplot(gs[:, 0])
im = ax.imshow(np.arange(100).reshape((10,10)))
cax = fig.add_subplot(gs[1, 1])
fig.colorbar(im, cax=cax, ax=ax)
plt.tight_layout()
plt.show()
B. Using axes_grid1
If you really need to use axes_grid1, it might become a little bit more complicated.
import matplotlib.pyplot as plt
import matplotlib.axes
from mpl_toolkits.axes_grid1 import make_axes_locatable, Size
import numpy as np
fig, ax = plt.subplots()
im = ax.imshow(np.arange(100).reshape((10,10)))
divider = make_axes_locatable(ax)
pad = 0.03
pad_size = Size.Fraction(pad, Size.AxesY(ax))
xsize = Size.Fraction(0.05, Size.AxesX(ax))
ysize = Size.Fraction(0.5-pad/2., Size.AxesY(ax))
divider.set_horizontal([Size.AxesX(ax), pad_size, xsize])
divider.set_vertical([ysize, pad_size, ysize])
ax.set_axes_locator(divider.new_locator(0, 0, ny1=-1))
cax = matplotlib.axes.Axes(ax.get_figure(),
ax.get_position(original=True))
locator = divider.new_locator(nx=2, ny=0)
cax.set_axes_locator(locator)
fig.add_axes(cax)
fig.colorbar(im, cax=cax)
plt.tight_layout()
plt.show()
I would like to plot the same mpl.pyplot.plot with different axes. My code looks like this:
import matplotlib.pyplot as plt
plt.subplot(211)
plot1 = plt.plot(data)
ax = plt.gca()
plt.axis('equal')
plt.grid()
plt.xlabel('x')
plt.ylabel('y')
:
much more stuff
:
plt.subplot(212)
command_to_plot(last_plot)
ax.set_xlim(a, b)
But unfortunately command_to_plot does not exist. So how can I do this?