I want to find this count but when I execute the query it seems like it is stucked to "waiting for the query to complete" forever...any ideas?
SELECT (
SELECT COUNT(*)
FROM accidents,"Vechicles"
where "Date_of_accident"<'2010-01-01' and "Urban_or_Rural" like 'Urban' and "Age_Band_Of_Driver" like '26 - 35'
) AS count1
Because your query will select every row from the first table that matches your criteria, then for each row it will then select EVERY row from the second table that matches your criteria. This might end up being a huge number of rows that end up selected.
Here's an example:
CREATE TABLE #dumb (id INT);
CREATE TABLE #dumber (id INT);
INSERT INTO #dumb SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3;
INSERT INTO #dumber SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3;
SELECT * FROM #dumb, #dumber;
3 rows in each table, but the query selects 3 * 3 = 9 rows. Now imagine that there's 3 million rows in each table!
I have a query that vertically expands data by using Union condition. Below are the 2 sample tables:
create table #temp1(_row_ord int,CID int,_data varchar(10))
insert #temp1
values
(1,1001,'text1'),
(2,1001,'text2'),
(4,1002,'text1'),
(5,1002,'text2')
create table #temp2(_row_ord int,CID int,_data varchar(10))
insert #temp2
values
(1,1001,'sample1'),
(2,1001,'sample2'),
(4,1002,'sample1'),
(5,1002,'sample2')
--My query
select * from #temp1
union
select * from #temp2 where CID in (select CID from #temp1)
order by _row_ord,CID
drop table #temp1,#temp2
So my current output is:
I want to group the details of every client together for which I am unable to use 'where' clause across Union condition.
My desired output:
Any help?! Order by is also not helping me.
I can imagine you want all of the rows for a CID sorted by _row_ord from the first table before the ones from the second table. And the CID should be the outermost sort criteria.
If that's right, you can select literals from your tables. Let the literal for the first table be less than that of the second table. Then first sort by CID, then that literal and finally by _row_ord.
SELECT cid,
_data
FROM (SELECT 1 s,
_row_ord,
cid,
_data
FROM #temp1
UNION ALL
SELECT 2 s,
_row_ord,
cid,
_data
FROM #temp2) x
ORDER BY cid,
s,
_row_ord;
db<>fiddle
If I correctly understand your need, you need the output to be sorted the way that #temp1 rows appear before #temp2 rows for each cid value.
What you could do is generate additional column ordnum assigning values for each table, just for sorting purposes, and then get rid of it in the outer select statement.
select cid, _data
from (
select 1 as ordnum, *
from #temp1
union all
select 2 as ordnum, *
from #temp2 t2
where exists (
select 1
from #temp1 t1
where t1.cid = t2.cid
)
) q
order by cid, ordnum
I have also rewritten your where condition for an equivalent which should work faster using exists operator.
Live DEMO - click me!
Output
cid _data
1001 text1
1001 text2
1001 sample1
1001 sample2
1002 text1
1002 text2
1002 sample1
1002 sample2
Use With. here is my first try with your sql
create table #temp1(_row_ord int,CID int,_data varchar(10))
insert #temp1
values
(1,1001,'text1'),
(2,1001,'text2'),
(4,1002,'text1'),
(5,1002,'text2')
create table #temp2(_row_ord int,CID int,_data varchar(10))
insert #temp2
values
(1,1001,'sample1'),
(2,1001,'sample2'),
(4,1002,'sample1'),
(5,1002,'sample2');
WITH result( _row_ord, CID,_data) AS
(
--My query
select * from #temp1
union
select * from #temp2 where CID in (select CID from #temp1)
)
select * from tmp order by CID ,_data
drop table #temp1,#temp2
result
_row_ord CID _data
1 1001 sample1
2 1001 sample2
1 1001 text1
2 1001 text2
4 1002 sample1
5 1002 sample2
4 1002 text1
5 1002 text2
Union is placed between two result set blocks and forms a single result set block. If you want a where clause on a particular block you can put it:
select a from a where a = 1
union
select z from z
select a from a
union
select z from z where z = 1
select a from a where a = 1
union
select z from z where z = 1
The first query in a union defines column names in the output. You can wrap an output in brackets, alias it and do a where on the whole lot:
select * from
(
select a as newname from a where a = 1
union
select z from z where z = 2
) o
where o.newname = 3
It is important to note that a.a and z.z will combine into a new column, o.newname. As a result, saying where o.newname will filter on all rows from both a and z (the rows from z are also stacked into the newname column). The outer query knows only about o.newname, it knows nothing of a or z
Side note, the query above produces nothing because we know that only rows where a.a is 1 and z.z is 2 are output by the union as o.newname. This o.newname is then filtered to only output rows that are 3, but no rows are 3
select * from
(
select a as newname from a
union
select z from z
) o
where o.newname = 3
This query will pick up any rows in a or z where a.a is 3 or z.z is 3, thanks to the filtering of the resulting union
I have in my Oracle Responsys Database a table that contains records with amongst other two variables:
status
location_id
I want to count the number of records grouped by status and location_id, and display it as a pivot table.
This seems to be the exact example that appears here
But when I use the following request :
select * from
(select status,location_id from $a$ )
pivot (count(status)
for location_id in (0,1,2,3,4)
) order by status
The values that appear in the pivot table are just the column names :
output :
status 0 1 2 3 4
-1 0 1 2 3 4
1 0 1 2 3 4
2 0 1 2 3 4
3 0 1 2 3 4
4 0 1 2 3 4
5 0 1 2 3 4
I also gave a try to the following :
select * from
(select status,location_id , count(*) as nbreports
from $a$ group by status,location_id )
pivot (sum(nbreports)
for location in (0,1,2,3,4)
) order by status
but it gives me the same result.
select status,location_id , count(*) as nbreports
from $a$
group by status,location_id
will of course give me the values I want, but displaying them as a column and not as a pivot table
How can I get the pivot table to have in each cell the number of records with the status and location in row and column?
Example data:
CUSTOMER,STATUS,LOCATION_ID
1,-1,1
2,1,1
3,2,1
4,3,0
5,4,2
6,5,3
7,3,4
The table data types :
CUSTOMER Text Field (to 25 chars)
STATUS Text Field (to 25 chars)
LOCATION_ID Number Field
Please check if my understanding for your requirement is correct, you can do vice versa for the location column
create table test(
status varchar2(2),
location number
);
insert into test values('A',1);
insert into test values('A',2);
insert into test values('A',1);
insert into test values('B',1);
insert into test values('B',2);
select * from test;
select status,location,count(*)
from test
group by status,location;
select * from (
select status,location
from test
) pivot(count(*) for (status) in ('A' as STATUS_A,'B' as STATUS_B))
I have a table called tbl which contains all the data I need. I have many columns in this table, but for purposes of this example I will only list the columns necessary to accomplish this task.
Here's how data stored in the tbl (note uID is char(20) and cID is int)*:
uID cID
1 10
1 11
1 12
2 11
We usually query this table like
SELECT * FROM tbl WHERE uID = "1"
So it returns
uID cID
1 10
1 11
1 12
But I also need to return the row where uID is different but cID do match. Or grab the uID of the second row (which is 2) based on cID and do a select statement like this:
SELECT * FROM tbl WHERE uID in ('1','2')
That query will return what I'm looking for
uID cID
1 10
1 11
1 12
2 11
This table contains a lot of rows and I want to be able to do this programatically for every call where cID matches and uID is different.
Any suggestions?
I think this may be what you want:
SELECT *
FROM tbl
WHERE uID = '1'
UNION ALL
SELECT *
FROM tbl
WHERE uID <> '1' AND
EXISTS (select 1 from tbl tbl2 where tbl2.uId = '1' and tbl2.cID = tbl.cID);
or something like this:
SELECT uID, cID
FROM tbl
WHERE uID IN
(
SELECT uID
FROM tbl
INNER JOIN
(
SELECT cID
FROM tbl
GROUP BY cID
HAVING count(*) > 1
) c ON c.cID = tbl.cID
)
I have a unique requirement to select records from one table based on another table only if the second table has at least one record with a certain flag. The query should not return two records for the same ID: example:
Table 1
id name location
4 myname MyLocation
6 hisname HisLocation
7 hername herlocation
The id in this table are unique:
Table two
id details1 details2 closureflg
4 somdetails somedetails Y
4 somdetails somedetails Y
6 somdetails somedetails N
7 somdetails somedetails N
7 somdetails somedetail N
I need to select from the first table one record only as long as the corresponding id has records in Table 2 whose closure flag is N:
I have tried:
select * from table1 where id in(select id from tbale2 where closureflg = 'N');
this returns two records for id 7;
My expected output:
id name location
6 hisname HisLocation
7 hername herlocation.
Please help.
please, try this one
SELECT *
FROM table1 t1
WHERE EXISTS(SELECT * FROM table2 t2 WHERE closureflag = 'N' AND t1.ID = t2.ID);
I would try it with a join
select id, name, location from table1
join table2 on table1.id=table2.id
where table2.closureflg = 'N'
group by id