I got a table with the following content:
Order_item
Order-id
item-id
1
45
4
45
4
57
5
68
5
32
6
68
I would like to know how many items are contained in average per order.
I tried that sql query:
select count(item-id), order-id
from order_item
group by order-id
that got me the following result:
Order-id
count
1
1
4
2
5
2
6
1
And now I would divide the 6 items of the count through 4 orders which gets me to my result of average 1,5 items per order.
How would I write a SQL query to get the result 1,5?
Divide count of all rows by distinct IDs and multiply by 1.0 to implicitly cast for numeric division.
select Count(*) / (Count(distinct Order_Id) * 1.0)
from Order_item;
Related
I have a list of transactions where the ID's are repeated and I have the quantity of items being bought. I need to count the number of times that a particular number of items were purchased at once.
Row
ItmNBR
TQTY
1
123
5
2
123
5
3
123
5
3
456
25
4
456
19
I need to produce an out put like this...
ItmNBR
QTY
Occurance
123
5
3
123
19
1
123
25
1
I can get the first two columns of my result but when I attempt to counting over a partition I end up counting getting repeating numbers since I'm only looking up 9 items I just count the number of rows in which the Cnt is the same.
TOT_IVO_ITM_QTY
Count(*) OVER (PARTITION BY QTY) AS CNT
FROM dataset
WHERE YEAR(bus_dt) = 2021
AND ITM_NBR IN (12639,12940,12949,12955,13485,13666,43950,631343,1103731)
AND QTY BETWEEN 5 AND 25
ORDER BY ITM_NBR
,QTY
GROUP BY ITM_NBR, TOT_IVO_ITM_QTY```
I think you just want group by:
select ItmNBR, QTY, count(*)
from t
group by ItmNBR, QTY
order by count(*) desc;
This assumes that you want the count by item and quantity, which seems to be the gist of the question.
Trying an SQL question here. I have a SQLite DB (table):
type_id value
1 26
1 24
2 30
3 5
3 15
I want to achieve the following. For each type_id, I would like to know the number of rows (count) with that type_id and the average value (average) of the group. In the example table I would end up with:
type_id count average
1 2 25
2 1 30
3 2 10
Any ideas? Thanks :)
Just GROUP BY type_id and take the COUNT and AVG:
SELECT type_id, COUNT(*) AS count, AVG(value) AS average
FROM test
GROUP BY type_id
Output:
type_id count average
1 2 25
2 1 30
3 2 10
Demo on dbfiddle
I've spent that last couple of days searching for a way to make a SQL query that searches the database and returns records where the SUM of the same ID's equal or grater then the value provided.
For this I've been using the W3schools database to test it out in the products table.
More so what I've been trying to do:
SELECT * FROM products
WHERE supplierid=? and SUM(price) > 50
in the "where supplier id" would loop through same suppliers and sum of their price higher than 50 in this case return the records.
In this case it would read supplier ID 1 then add the price of all that supplier 18+19+10=47 now 47 < 50 so it will not print those records at the end. Next supplier ID 2 22+21.35=43.35 and again would not print those records until the sum of price is higher than 50 it will print
I'm working with a DB2 database.
SAMPLE data:
ProductID ProductName SupplierID CategoryID Price
1 Chais 1 1 18
2 Chang 1 1 19
3 Aniseed 1 2 10
4 Chef Anton 2 2 22
5 Chef Anton 2 2 21.35
6 Grandma's 3 2 25
7 Uncle Bob 3 7 30
8 Northwoods 3 2 40
9 Mishi 4 6 97
10 Ikura 4 8 31
11 Queso 5 4 21
12 Queso 5 4 38
13 Konbu 6 8 6
14 Tofu 6 7 23.25
How about:
select * from products where supplierid in (
select supplierid
from products
group by supplierid
having sum(price) > 50
);
The subquery finds out all the supplierid values that match your condition. The main (external) query retrieves all rows that match the list of supplierids.
not tested, but I would expect db2 to have analytic functions and CTEs, so perhaps:
with
basedata as (
select t.*
, sum(t.price) over(partition by t.supplierid) sum_price
from products t
)
select *
from basedata
where supplierid = ?
and sum_price > 50
The analytic function aggregates the price information but does not group the resultset, so you get the rows from your initial result, but restricted to those with an aggregated price value > 50.
The difference to a solution with a subquery is, that the use of the analytic function should be more efficient since it has to read the table only once to produce the result.
say I have a table like this
user, count
1 5
2 3
3 20
4 13
5 10
I want to get the total from all the count row, so basically 5+3+20+13+10=51, I want to get the 51
How to do that?
Thanks.
select sum(count) as Total from tablename;
select sum(count) from yourtablename
I have a SQL table with data in the following format:
REF FIRSTMONTH NoMONTHS VALUE
--------------------------------
1 2 1 100
2 4 2 240
3 5 4 200
This shows a quoted value which should be delivered starting on the FIRSTMONTH and split over NoMONTHS
I want to calculate the SUM for each month of the potential deliveries from the quoted values.
As such I need to return the following result from a SQL server query:
MONTH TOTAL
------------
2 100 <- should be all of REF=1
4 120 <- should be half of REF=2
5 170 <- should be half of REF=2 and quarter of REF=3
6 50 <- should be quarter of REF=3
7 50 <- should be quarter of REF=3
8 50 <- should be quarter of REF=3
How can I do this?
You are trying extract data from what should be a many to many relationship.
You need 3 tables. You should be able to write a JOIN or GROUP BY select statement from there. The tables below don't use the same data values as yours, and are merely intended for a structural example.
**Month**
REF Month Value
---------------------
1 2 100
2 3 120
etc.
**MonthGroup**
REF
---
1
2
**MonthsToMonthGroups**
MonthREF MonthGroupREF
------------------
1 1
2 2
2 3
The first part of this query gets a set of numbers between the start and the end of the valid values
The second part takes each month value, and divides it into the monthly amount
Then it is simply a case of grouping each month, and adding up all of the monthly amounts.
select
number as month, sum(amount)
from
(
select number
from master..spt_values
where type='p'
and number between (select min(firstmonth) from yourtable)
and (select max(firstmonth+nomonths-1) from yourtable)
) numbers
inner join
(select
firstmonth,
firstmonth+nomonths-1 as lastmonth,
value / nomonths as amount
from yourtable) monthly
on numbers.number between firstmonth and lastmonth
group by number