(Came up with this question in the course of trying to answer this other one)
Consider the following MS-SQL table, called GroupTable:
GroupID
-------
1
2
3
where GroupID is the primary key and is an Identity column.
How do you insert a new row into the table (and hence generate a new ID) without using IDENTITY_INSERT ON?
Note that this:
INSERT INTO GroupTable() Values ()
... won't work.
edit: we're talking SQL 2005 or SQL 2008 here.
This should work:
INSERT INTO GroupTable DEFAULT VALUES
Here you go:
INSERT INTO GroupTable DEFAULT VALUES
It is possible to insert more than one row at a time.
For e.g., to insert 30 rows.
INSERT INTO GroupTable DEFAULT VALUES
GO 30
This will insert 30 rows by incrementing the identity column each time.
Can you try using a Sequence or something similar? Where you select from a Sequence and it will give you the next value in the sequence.
This will work actually--
insert into TABLE default values
Related
I have a set of value which have to be inserted into two tables.Input has say 5 row and I have to insert these 5 rows into table A first.Table A has a identity column.Next i have to insert these 5 rows into table B with an extra column which is the identity from table A.
How this can be done with out using any loops?
Any help will be highly helpful.
INSERT INTO TABLE_A(COL2,COL3)
SELECT COL2,COL3 FROM #TEMP_TAB
set #identityval=##identity
INSERT INTO TABLE_B(COLA,COLB,COLC)
SELECT #identityval,COL2,COL3,COL4 FROM #TEMP_TAB
You cannot insert into multiple tables using a single statment.
What you could do is create an insert trigger on Table A so that after the insert occurs this performs the new insert with the identity of the value inserted into Table A and insert it into Table B.
Here is one solution.
take max of identity column from table TABLE_A
insert new records in table TABLE_A
then insert records on TABLE_B from TABLE_A with Identity greater than last max identity.
Thanks,
Gopal
What you want to do is not possible.
You can get only the value from the last insert using the ##identity variable. This way its possible to add to multiple tables setting the right foreign key without selecting the just inserted row again using a cursor. This approach is not useful when inserting multiple rows at once.
From the documentation:
Use the ##identity global variable to retrieve the last value inserted into an IDENTITY column. The value of ##identity changes each time an insert or select into attempts to insert a row into a table.
Here is a procedure which inserts a single row and you can use the return value to create a reference to the inserted data in another table:
create procedure reset_id as
set identity_insert sales_daily on
insert into sales_daily (syb_identity, stor_id)
values (102, "1349")
select ##identity
select ##identity
execute reset_id
I need to create a table that basically keeps a list of indices only. Therefore I've created a table with just one, auto-incremented column called 'id'. However, I can't seem to implicitly add auto-incremented values to this table.
I know that usually when you have such a column in a table (with more than just this column) you can do:
INSERT INTO TABLE (col1, col2 ...) VALUES (val1, val2 ...)
And if you don't specify the auto-incremented column, it would automatically get a value. However, things like:
INSERT INTO TABLE () VALUES ()
INSERT INTO TABLE
INSERT INTO TABLE ()
etc. all produce an error on my single-columned table. Can anyone offer a solution?
Thanks.
p.s. I'm using Sqlite, in case it matters.
Try this
INSERT INTO dbo.Table DEFAULT VALUES
See this answer:
Previous answer
Try the following:
INSERT INTO YOUR_TABLE(YOUR_ID) VALUES (NULL);
my goal is to select items from a table and append those items into another table located on a remote database on the same server. All columns in both tables match up and are identical. In this case,
I have the tsql:
INSERT INTO db1.dbo.tblitems
SELECT *
FROM db2.dbo.tblitems i2
WHERE i2 = 'import'
i get an error saying:
An explicit value for the identity column in table 'db1.dbo.tblitems' can only be specified when a column list is used and IDENTITY_INSERT is ON.
any ideas why this doesn't work?
thanks in advance
Sounds like there is an identity column in the table. An identity column is a column that is made up of values generated by the database. For example:
create table #TestTable (id int identity, name varchar(50))
insert into #TestTable select 1, 'Will Smith'
This gives the identity column error. You can avoid that in two ways: the first is not to insert the identity column, like:
insert into #TestTable (name) select 'Will Smith'
The second is to use set identity_insert (requires admin privileges):
set identity_insert #TestTable on
insert into #TestTable (id, name) select 1, 'Will Smith'
set identity_insert #TestTable off
In both cases, you have to specify the column list.
I agree with Andomar but a further consideration...
Have you considered the effects of merging these two data sets?
Say I had two identical tables in two databases with this data:
Id Name
1 Bill
2 Bob
3 Bert
Id Name
3 Jenny
4 Joan
5 Jackie
Option 1 of Andomar's would give the girls new IDs. If that ID has been used as a primary key in the table and other tables referenced it as a foreign key then this will break the referential integrity (you will have records pointing to the wrong place).
Option 2 would fall over if there is a unique index on the ID column, which quite likely if it is being used as a key. This is because the two ID values for Bert and Jenny are not unique.
So while Andomar is right in that it will fix the identity insert problem, it doesn't address the issue of why there were identity columns in the first place.
p.s. if this is an issue ask for a solution in a new question.
This might be an issue of permissions. As the server the query is running on cannot determine if the connected user has the permission to insert the data into the destination server/table, it just might not be possible.
how to
compare the values of same table(say for eg: Order table) each and every time the record get inserted ,
if the record with same values get inserted already in same table i should not insert the new record with same values. how to do that exactly in sql server 2008
If exists(select * from Order where key_column=#some_value)
print 'data already exists'
else
Insert into Order(columns) values (#some_value,...)
I'd suggest adding a unique index on the key columns...
ALTER TABLE mytable ADD UNIQUE INDEX myindex (keycolumn1, keycolumn2, ...);
That'd make it impossible to insert a duplicate by accident.
(Came up with this question in the course of trying to answer this other one)
Consider the following MS-SQL table, called GroupTable:
GroupID
-------
1
2
3
where GroupID is the primary key and is an Identity column.
How do you insert a new row into the table (and hence generate a new ID) without using IDENTITY_INSERT ON?
Note that this:
INSERT INTO GroupTable() Values ()
... won't work.
edit: we're talking SQL 2005 or SQL 2008 here.
This should work:
INSERT INTO GroupTable DEFAULT VALUES
Here you go:
INSERT INTO GroupTable DEFAULT VALUES
It is possible to insert more than one row at a time.
For e.g., to insert 30 rows.
INSERT INTO GroupTable DEFAULT VALUES
GO 30
This will insert 30 rows by incrementing the identity column each time.
Can you try using a Sequence or something similar? Where you select from a Sequence and it will give you the next value in the sequence.
This will work actually--
insert into TABLE default values