Is there a way to add gitlab variables to the command ?
eg: variables: ARTIFACTORY_ADDRESS: "a.com"
script:
sshpass -p "password" ssh -o "StrictHostKeyChecking=no" user#SERVER 'echo $ARTIFACTORY_ADDRESS'
Currently its not taking the value from the variable and printing $ARTIFACTORY_ADDRESS in the console. I want the value to be printed in the console
Check first if using double-quotes would help enabling variable substitution:
sshpass -p "password" ssh -o "StrictHostKeyChecking=no" user#SERVER \
"echo $ARTIFACTORY_ADDRESS"
^^^ ^^^
Related
I am trying to run the following command in karate using karate.fork
ssh -o ProxyCommand="ssh -W %h:%p -i ~/.ssh/id_rsa root#myjumphost" -i ~/.ssh/id_rsa -o StrictHostKeyChecking=no -o PasswordAuthentication=no root#finaldest echo test
I have broken this up into an array to pass to karate.fork like so:
[
ssh,
-o,
ProxyCommand="ssh -W %h:%p -i ~/.ssh/id_rsa root#myjumphost",
-i,
~/.ssh/id_rsa,
-o,
StrictHostKeyChecking=no,
-o,
PasswordAuthentication=no,
root#finaldest,
echo test
]
Then run the command like so:
* karate.fork(args) where args is the array mentioned above
The command works when I paste it into the terminal and run it manually, however when run with karate.fork I get
zsh:1: no such file or directory: ssh -W finaldest:22 -I ~/.ssh/id_rsa root#myjumphost
kex_exchange_identification: Connection closed by remote host
I have tried adding a few backslashes before the " in the ProxyCommand but no amount of back slashes fixes this issue. I think I am misunderstanding what karate.fork is doing to run the command, is there some internal parsing or manipulating of the given input? I was able to get this command to work when I used useShell: true however this option breaks other tests for me so I would really like to avoid it.
I had to remove the double quotes, seems like they didn't play well with karate.fork and the command still runs without them
[
ssh,
-o,
ProxyCommand=ssh -W %h:%p -i ~/.ssh/id_rsa root#myjumphost,
-i,
~/.ssh/id_rsa,
-o,
StrictHostKeyChecking=no,
-o,
PasswordAuthentication=no,
root#finaldest,
echo test
]
I am passing command line arguments to a shell file i.e assignRole.sh which contains an SQL command which will use these arguments like below
ssh -o StrictHostKeyChecking=no -T $key < /oracle/oracle_user/makhshif/./assignRole.sh name open_mode >> /oracle/oracle_user/dftest.txt
This gives me error and does not accept arguments of name and open_mode and gives error, but if I execute the statement outside of ssh command like:
/oracle/oracle_user/makhshif/./assignRole.sh name open_mode
This runs fine
What is the problem with ssh command and how should I adjust these parameters so these can be accepted for the shell script assignRole.sh
< /oracle/oracle_user/makhshif/./assignRole.sh
This commands sends a content of that file to stdin. So obviously it can't process variables that you haven't send to remote machine. Just preprocess your script or create a script on remote machine and call it with arguments
Though it's even easier to pass variables like this:
ssh -o StrictHostKeyChecking=no -T $key "var1=$var1 var2=$var2" < /oracle/oracle_user/makhshif/./assignRole.sh name open_mode >> /oracle/oracle_user/dftest.txt
For example my function for executing update scripts on all cluster nodes:
# functions:
ssh_exec(){
local DESCR="$1"; shift
local SCRIPT="$1"; shift
local hosts=("$#")
echo =================================================
echo = $DESCR
echo = Going to execute $SCRIPT...
read -a res -p "Enter 'skip' to skip this step or press Enter to execute: "
if [[ $res = "skip" ]]
then
echo Skipping $SCRIPT...
else
echo Executing $SCRIPT...
for host in "${hosts[#]}"
do
local cur=${!host}
echo Executing $SCRIPT on $host - $cur...
sshpass -p "$rootpass" ssh -o "StrictHostKeyChecking no" root#${cur} \
"ns1=$ns1 ns2=$ns2 search=$search zoo1=$zoo1 zoo2=$zoo2 zoo3=$zoo3 node0=$node0 pass=$pass CURIP=$cur CURHOST=$host bash -s" \
<$SCRIPT >log-$SCRIPT-$cur.log 2>&1
echo Done.
done
echo =================================================
fi
}
Then I use it like this:
read -p "Please check that Solr started successfully and Press [Enter] key to continue..."
#Solr configset and collections:
ssh_exec "Solr configset and collections" script06.sh zoo1 zoo2 zoo3
This command executes script06.sh on 3 servers (zoo1,zoo2,zoo3)
As Sayan said, using < redirects the output of running the assignRole.sh script locally, but you want to execute that script on the remote host, with the arguments.
Pass the whole command as the final argument to ssh, in quotes:
ssh -o StrictHostKeyChecking=no -T $key "/oracle/oracle_user/makhshif/./assignRole.sh name open_mode" >> /oracle/oracle_user/dftest.txt
or split into multiple lines for readability:
ssh -o StrictHostKeyChecking=no -T $key \
"/oracle/oracle_user/makhshif/./assignRole.sh name open_mode" \
>> /oracle/oracle_user/dftest.txt
I wanted to change the title of the window using the command as described here over SSH, however I kept get getting the error:
033]sh: Hello: command not found
Connection to host closed.
with the command:
ssh.exe user#host -t 'echo -en "\033];Hello World\007"'
No matter how I try to escape them, it seems to somehow return error. Tried:
ssh.exe user#host -t 'echo -en "\\033];Hello World\\007"'
ssh.exe user#host -t "echo -en \'\\033];Hello World\\007\'"
Any idea how to fix this?
In the following command, the first argument of sh command echo hey is ignored:
$ ssh localhost sh -c 'echo hey; echo ho'
ho
Why?
Your commandline is:
ssh localhost sh -c 'echo hey; echo ho'
ssh starts a shell on localhost and passes it the comandline:
sh -c echo hey; echo ho
The shell on localhost sees two commands. Both run fine.
The problem is that the first command is: sh -c echo hey
The option -c tells sh to execute the next argument. The next argument is echo. The extraneous hey argument is ignored.
To fix your problem, either change your quoting or just don't run the redundant shell:
ssh localhost "sh -c 'echo hey; echo ho'"
ssh localhost 'echo hey; echo ho'
The main confusion is probably that ssh concatenates all the non-option arguments it receives into a single string that it passes to the remote shell to execute.
I'm trying to execute this shell with command line
host="192.168.X.XXX"
user="USERNAME"
pass="MYPASS"
sshpass -p "$pass" scp -o StrictHostKeyChecking=no /home/MYPATH/File.import "$user#$host:/"home/MYPATH/
To copy a file from my local server in to remote server. The remote server is a copy of the remote server but when I try to execute this shell I have this error:
**PERMISSION DENIED, PLEASE TRY AGAIN**
I didn't understand why if I try to execute this command in command line is working.
USERNAME#MYSERVER:~$ sshpass -p 'MYPASS' scp -o StrictHostKeyChecking=no /home/MYPATH/File.import USERNAME#192.168.X.XXX:/home/MYPATH/
Somebody have a solution??
Please use a pipe or the -e option for the password anyway.
export SSHPASS=password
sshpass -e ssh user#remote
Your simple command with -e option:
export SSHPASS=password
sshpass -e scp -o StrictHostKeyChecking=no /home/MYPATH/File.import user#192.168.X.XXX:/home/MYPATH/
Please remove the wrong quotes from your command:
sshpass -p "$pass" scp -o StrictHostKeyChecking=no /home/MYPATH/File.import $user#$host:/home/MYPATH/
You should also be able to remove the quotes around $pass.
Please ensure that you have no special characters in your pass variable or escape them correctly (and no typos anywhere).
For simplicity use a ssh command instead of scp for testing
Use the -v or -vvv option for the scp command to check what scp is trying to do. Also check the secure log or auth.log on the remote server
You have to install "sshpass" command then use the below snippet
export SSHPASS=password
sshpass -e sftp user#hostname << !
cd sftp_path
put filename
bye
!
A gotchya that I encountered was escaping special characters in the password which wasn't necessary when entering it in interactive ssh mode.