I have 2 tables , one stores IDs and another logs for each ID , i would like to get sum of log for each ID and ID number from these 2 tables
A B
------- -------------
ID ID_C LOG
1 1 15
2 1 30
3 4 44
4 2 14
5 3 88
3 10
2 10
for getting sum query is
SELECT SUM(LOG) FROM B WHERE ID_C ='2' ;
notice ID and ID_C are same but name is different in tables
and for getting all ids available query is
SELECT ID FROM A ;
I would like to get the following table result
result
--------------------
ID SUM
1 45
4 44
2 24
3 98
I tried
SELECT SUM(LOG) FROM B WHERE ID_C in (SELECT ID FROM A ) ;
but it result in sum of all IDs
It looks like you just need a join aggregation here:
SELECT a.ID, SUM(b.LOG) AS SUM
FROM A a
INNER JOIN B b
ON b.ID_C = a.ID
GROUP BY a.ID
ORDER BY a.ID;
Note that the inner join will also remove ID values from the A table which no entries whatsoever in the B table, which seems to be the behavior you want.
you should use inner join and GROUP BY:
SELECT A.ID as ID, SUM(LOG) AS SumLOG
FROM A inner join B ON A.ID = B.ID_C
GROUP BY A.ID
if you needed can use where for ID filter.
Related
I have the table 'Table01' which contains the keys that should be mandatory:
id
1
2
3
4
And I also have the table 'Table02' which contains the records to be filtered:
id
customer
weight
1
a
100
2
a
300
3
a
200
4
a
45
1
b
20
2
b
100
3
b
17
1
c
80
4
c
90
2
d
30
3
d
30
4
d
50
So I want to identify which are the mandatory id's that the table 'Table02' does not have, and in turn identify which is the 'customer' of each id's that the table 'Table02' does not have.
The resulting table should look like this:
customer
id
b
4
c
2
c
3
d
1
What I have tried so far is a 'rigth join'.
proc sql;
create table table03 as
select
b.id
from table02 a
right join table01 b
on a.id=b.id
where a.id is null;
run;
But that query is not identifying all the id's that should be mandatory.
I hope someone can help me, thank you very much.
here is one way:
select cl.customerid , a.id
from
Table1 a
cross join
( select customerid
from table2
group by customerid
) cl
where not exists ( select 1 from table2 b
where b.customerid = cl.customerid
and b.id = a.id
)
You can use an EXCEPT between two sub-selects. The first creates a matrix of all possibilities, and the except table is a selection of the extant customers.
Example:
data ids;
do id = 1 to 4; output; end;
run;
data have;
input id customer $ weight;
datalines;
1 a 100
2 a 300
3 a 200
4 a 45
1 b 20
2 b 100
3 b 17
1 c 80
4 c 90
2 d 30
3 d 30
4 d 50
run;
proc sql;
create table want(label='Customers missing some ids') as
select matrix.*
from
(select distinct have.customer, ids.id from have, ids) as matrix
except
(select customer, id from have)
;
quit;
If you are doing it in SQL server. Something like #eshirvana above posted, but also you can use with cte:
;with cte as
(
SELECT t1.id, t2.Customer
FROM Table01 t1
cross join (select distinct customer from Table02)
)
SELECT a.customer, a.id FROM cte a
LEFT JOIN Table02 b
ON a.id=b.id AND a.customer=b.customer
where b.id is null
Given this table structure:
Table A
ID AGE EDUCATION
1 23 3
2 25 6
3 22 5
Table B
ID AGE EDUCATION
1 26 4
2 24 6
3 21 3
I want to find all matches between the two tables where the age is within 2 and the education is within 2. However, I do not want to select any row from TableB more than once. Each row in B should be selected 0 or 1 times and each row in A should be selected one or more times (standard left join).
SELECT *
FROM TableA as A LEFT JOIN TableB as B ON
abs(A.age - B.age) <= 2 AND
abs(A.education - B.education) <= 2
A.ID A.AGE A.EDUCATION B.ID B.AGE B.EDUCATION
1 23 3 3 21 3
2 25 6 1 26 4
2 25 6 2 24 6
3 22 5 2 24 6
3 22 5 3 21 3
As you can see, the last two rows in the output have duplicated B.ID of 2 and 3 when compared to the entire result set. I'd like those rows to return as a single null match with A.ID = 3 since they were both matched to previous A values.
Desired output:
(note that for A.ID = 3, there is no match in B because all rows in B have already been joined to rows in A.)
A.ID A.AGE A.EDUCATION B.ID B.AGE B.EDUCATION
1 23 3 3 21 3
2 25 6 1 26 4
2 25 6 2 24 6
3 22 5 null null null
I can do this with a short program, but I'd like to solve the problem using a SQL query because it is not for me and I will not have the luxury of ever seeing the data or manipulating the environment.
Any ideas? Thanks
As #Joel Coehoorn said earlier, there has to be a mechanism that selects which pairs of (a,b) with the same (b) are filtered out from the output. SQL is not great on allowing you to select ONE row when multiple match, so a pivot query needs to be created, where you filter out the records you don't want. In this case, filtering can be done by reducing all of match IDs of B as a smallest (or largest, it doesn't really matter), using any function that will return one value from a set, it's just min() and max() are most convenient to use. Once you reduced the result to know which (a,b) pairs you care about, then you join against that result, to pull out the rest of the table data.
select a.id a_id, a.age a_age, a.education a_e,
b.id b_id, b.age b_age, b.education b_e
from a left join
(
SELECT
a.id a_id, min(b.id) b_id from a,b where
abs(A.age - B.age) <= 2 AND
abs(A.education - B.education) <= 2
group by a.id
) g on a.id = g.a_id
left join b on b.id = g.b_id;
To my knowledge something like this is not possible with a simple select statement and joins because you need to know what has already been selected in order to eliminate duplicates.
You can however try something a little more like this:
DECLARE #JoinResults TABLE
(A_ID INT, A_Age INT, A_Education INT, B_ID INT, B_Age INT, B_Education INT)
INSERT INTO #JoinResults (A_ID, A_Age, A_Education)
SELECT ID, AGE, EDUCATION
FROM TableA
DECLARE #i INT
SET #i = 1
--Assume that A_ID is incremental and no values missed
WHILE (#i < (SELECT Max(A_ID) FROM #JoinResults
BEGIN
UPDATE #JoinResult
SET B_ID = SQ.ID,
B_Age = SQ.AGE,
B_Education = SQ.Education
FROM (
SELECT ID, AGE, EDUCATION
FROM TableB b
WHERE (
abs((SELECT A_Age FROM #JoinResult WHERE A_Id = #i) - AGE) <=2
AND abs((SELECT A_Education FROM #JoinResult WHERE A_Id = #i) - EDUCATION) <=2
) AND (SELECT B_ID FROM #JoinResults WHERE B_ID = b.id) IS NULL
) AS SQ
SET #i = #i + 1
END
SELECT #JoinResults
NOTE: I do not currently have access to a database so this is untested and I am weary of 2 potential issues with it
I am not sure how the update will react if there are no results
I am unsure if the IS NULL check is correct to eliminate the duplicates.
If these issues do arise let me know and I can help troubleshoot.
In SQL-Server, you can use the CROSS APPLY syntax:
SELECT
a.id, a.age, a.education,
b.id AS b_id, b.age AS b_age, b.education AS b_education
FROM tableB AS b
CROSS APPLY
( SELECT TOP (1) a.*
FROM tableA AS a
WHERE ABS(a.age - b.age) <= 2
AND ABS(a.education - b.education) <= 2
ORDER BY a.id -- your choice here
) AS a ;
Depending on the order you choose in the subquery, different rows from tableA will be selected.
Edit (after your update): But the above query will not show rows from A that have no matching rows in B or even some that have but not been selected.
It could also be done with window functions but Access does not have them. Here is a query that I think will work in Access:
SELECT
a.id, a.age, a.education,
s.id AS s_id, s.age AS b_age, s.education AS b_education
FROM tableB AS a
LEFT JOIN
( SELECT
b.id, b.age, b.education, MIN(a.id) AS a_id
FROM tableB AS b
JOIN tableA AS a
ON ABS(a.age - b.age) <= 2
AND ABS(a.education - b.education) <= 2
GROUP BY b.id, b.age, b.education
) AS s
ON a.id = s.a_id ;
I'm not sure if Access allows such a subquery but if it doesn't, you can define it as a "Query" and then use it in another.
Use SELECT DISTINCT
SELECT DISTINCT A.id, A.age, A.education, B.age, B.education
FROM TableA as A LEFT JOIN TableB as B ON
abs(A.age - B.age) <= 2 AND
abs(A.education - B.education) <= 2
can any one help to solve this issue in SQL SERVER 2008. I want to put seq numbering to the grouped items in the select query result.
select a.grade, a.name, a.age, seqno
from tab A join tab B on A.id = B.id
[group based on Grade column]
The result should show as shown below.
SeqNo Grade Name Age
----- ----- ---- ---
1 A abc 23
2 A xyz 7
1 B dfg 34
2 B sxd 23
3 B vvv 56
In the below query, how i can join the second table and using a "join'
SELECT ROW_NUMBER() OVER ( PARTITION BY [a.Grade] ORDER BY [a.Name]) AS 'SeqNo',
[a.Grade], [a.Name], [a.Age]
FROM Employee a WITH (NOLOCK)
ORDER BY [a.Grade],[a.Name]
I have a table like this
Table A:
Id Count
1 4
1 16
1 8
2 10
2 15
3 18
etc
Table B:
1 sample1.file
2 sample2.file
3 sample3.file
TABLE C:
Count fileNumber
16 1234
4 2345
15 3456
18 4567
and so on...
What I want is this
1 sample1.file 1234
2 sample2.file 3456
3 sample3.file 4567
To get the max value from table A I used
Select MAX (Count) from A where Id='1'
This works well but my problem is when combining data with another table.
When I join Table B and Table A, I need to get the MAX for all Ids and in my query I dont know what Id is.
This is my query
SELECT B.*,C.*
JOIN A on A.Id = B.ID
JOIN C on A.id = B.ID
WHERE (SELECT MAX(COUNT)
FROM A
WHERE Id = <what goes here????>)
To summarise, what I want is Values from Table B, FileNumber from Table c (where the count is Max for ID from table A).
UPDATE: COrrecting table C above. Looks like I need Table A.
I think this is the query you're looking for:
select b.*, c.filenumber from b
join (
select id, max(count) as count from a
group by id
) as NewA on b.id = NewA.id
join c on NewA.count = c.count
However, you should take into account that I don't get why for id=1 in tableA you choose the 16 to match against table C (which is the max) and for id=2 in tableA you choose the 10 to match against table C (which is the min). I assumed you meant the max in both cases.
Edit:
I see you've updated tableA data. The query results in this, given the previous data:
+----+---------------+------------+
| ID | FILENAME | FILENUMBER |
+----+---------------+------------+
| 1 | sample1.file | 1234 |
| 2 | sample2.file | 3456 |
| 3 | sample3.file | 4567 |
+----+---------------+------------+
Here is a working example
Using Mosty’s working example (renaming the keyword count to cnt for a column name), this is another approach:
with abc as (
select
a.id,
a.cnt,
rank() over (
partition by a.id
order by cnt desc
) as rk,
b.filename
from a join b on a.id = b.id
)
select
abc.id, abc.filename, c.filenumber
from abc join c
on c.cnt = abc.cnt
where rk = 1;
select
PreMax.ID,
B.FileName,
C2.FileNumber
from
( select C.id, max( C.count ) maxPerID
from TableC C
group by C.ID
order by C.ID ) PreMax
JOIN TableC C2
on PreMax.ID = C2.ID
AND PreMax.maxPerID = C2.Count
JOIN TableB B
on PreMax.ID = B.ID
I have two Tables
Let suppose A and B
Now suppose the structure of table A is Like that
id stock
37 1
40 1
37 1
40 1
37 1
37 1
And B is like that
id stock
37 1
37 1
40 1
Now i want to write a query that give me sum of specific id stock in (table A - Table B) and if that id does not exist in table B then only stock from A.
So i will expect result like that
id stock
40 1
37 2
I thought that left join will be possible option here and i write query like that
SELECT A.id,
SUM(CAST(isNull(A.Stock, 0) as int) - CAST(isNull(B.Stock, 0) as int) )'Stock'
from A
LEFT OUTER JOIN
B
ON A.id = B.id
group by A.id
But Problem is that the above query gives desired records but wrong quantity/Stocklevel as shown below:
id stock
37 0
40 1
How can I resolve Stock Level issue.
I guess you are looking for something like this.
select A.id, A.SumA - coalesce(B.SumB, 0) as stock
from (
select A.id, sum(A.stock) as SumA
from A
group by A.id
) as A
left outer join
(
select B.id, sum(B.stock) as SumB
from B
group by B.id
) as B
on A.id = B.id
Result:
id stock
----------- -----------
37 2
40 1
SE Data
SELECT A.id, A.Stock - isNull(B.stock, 0) as Stock from A
LEFT OUTER JOIN B
ON A.id = B.id
That would be it I think.
PS. you group by something that you did not include in your case scenario. Your expected result is also not understandable to me (it conflicts with your problem description)