How can I count the rows of a one2many field and output the current row count ?
This is how it should work.For example:
1 ------column1------------
2 ------column2------------
3 ------column3------------
4 ------Column4------------
etc..
I have made an automated action for this, but it does not work as intended:
The automated action refers to the model of the one2many field and is triggered when a record is created. The following Python code is executed:
for line in record.picking_id.move_line_ids_without_package:
for rec in str(record.x_studio_position):
record['x_studio_position'] = len(record.picking_id.move_line_ids_without_package)
What happens is the following for e.g. 4 columns
4 ------column1------------
4 ------column2------------
4------column3------------
4 ------column4------------
It will write the total number in each row instead of the current column number.
You set the position to the number of lines in the field move_line_ids_without_package, it will be the same for all lines.
You can use enumerate to get the line sequence
Example:
for index, line in enumerate(record.picking_id.move_line_ids_without_package):
line['x_studio_position'] = index + 1
Related
I have a data set in google sheets, for each week of data I have 3 rows. I wish to query the data in every second row to calculate the max value and the last value.
For instance:
ROW
DATA
1
800
2
Text
3
500
4
More text
5
600
6
Blah
7
700
8
Blah
For Max value I have the following which will return 800
MAX(FILTER(QUERY(A1:A,"Select * skipping 2"), QUERY(A1:A,"Select * skipping 2") <> 0))
How do I change it up to return the last value? Which should return 700
try:
=LOOKUP(2^99,FILTER(A:A,A:A<>0))
#rockinfreakshow answer will successfully find the last number.
To filter a range by n amount of rows, you can use:
=FILTER(A:A,MOD(ROW(A:A),n)=1)
Change n with your desired value, and 1 with the number of row you want to get. 1 for the first, 2 for the second, but 0 if you want the nth one. To find MAX, just wrap it in MAX()
To find the last one, even if it's a text or number, you can use SORTN and SEQUENCE:
=SORTN(FILTER(A:A,MOD(ROW(A:A),n)=1,A:A<>""),1,1, SEQUENCE(COUNTA(FILTER(A:A,MOD(ROW(A:A),n)=1,A:A<>""))),0)
It orders the elements in reverse order and only chooses the first one
Remember to change n with the number of rows and =1 with the number of row you want to choose
For example, I have this table in my SQL Server database :
Document
NumberPageMax
First
48
Second
12
Third
4
Fourth
8
Fifth
1
Sixth
3
I need to get a random list of Document for whose the sum of NumberPageMax is equals to 50. If it's not possible to have exactly 50, it's ok to have a little more (first and sixth document for example to have 51).
Do you know if it's possible to do that in SQL and how ?
Thank you !
I have a DataFrame, in which I want to merge certain rows to a single one. It has the following structure (values repeat)
Index Value
1 date:xxxx
2 user:xxxx
3 time:xxxx
4 description:xxx1
5 xxx2
6 xxx3
7 billed:xxxx
...
Now the problem is, that the columns 5 & 6 still belong to the description and were separated just wrong (whole string separated by ","). I want to merge the "description" row (4) with the values afterwards (5,6). In my DF, there can be 1-5 additional entries which have to be merged with the description row, but the structure allows me to work with startswith, because no matter how many rows have to be merged, the end point is always the row which starts with "billed". Due to me being very new to python, I haven´t got any code written for this problem yet.
My thought is the following (if it is even possible):
Look for a row which starts with "description" → Merge all the rows afterwards till reaching the row which starts with "billed", then stop (obviosly we keep the "billed" row) → Do the same to each row starting with "description"
New DF should look like:
Index Value
1 date:xxxx
2 user:xxxx
3 time:xxxx
4 description:xxx1, xxx2, xxx3
5 billed:xxxx
...
df = pd.DataFrame.from_dict({'Value': ('date:xxxx', 'user:xxxx', 'time:xxxx', 'description:xxx', 'xxx2', 'xxx3', 'billed:xxxx')})
records = []
description = description_val = None
for rec in df.to_dict('records'): # type: dict
# if previous description and record startswith previous description value
if description and rec['Value'].startswith(description_val):
description['Value'] += ', ' + rec['Value'] # add record Value into previous description
continue
# record with new description...
if rec['Value'].startswith('description:'):
description = rec
_, description_val = rec['Value'].split(':')
elif rec['Value'].startswith('billed:'):
# billed record - remove description value
description = description_val = None
records.append(rec)
print(pd.DataFrame(records))
# Value
# 0 date:xxxx
# 1 user:xxxx
# 2 time:xxxx
# 3 description:xxx, xxx2, xxx3
# 4 billed:xxxx
Using Pentaho PDI 8.3.
After REST calls with quite complex data structures, I was able to extract data with a row for each data element in a REST result/ E.g:
DataCenterClusterAbstract
1
UK1
Datacenter (auto generated)
Company
29
0
39
15
DATAUPDATEJOB
2016-04-09T21:34:31.18
DataCenterClusterAbstract
2
UK1_Murex
Datacenter (auto generated)
Company
0
0
0
0
DATAUPDATEJOB
2016-04-09T21:34:31.18
DataCenterClusterAbstract
3
UK1_UNIX
Notice that there are 8 data elements that are spread out into separate rows. I would like to condense these 8 data elements into one row each iteration in Pentaho. Is this possible? And assign field names?
Row flattener
Condense 8 data element in columns into one row. Each of these 8 data elements are repeating.
(1) Add row flattener
(2) Assign field names for the rows coming in - so you have 10 data attributes in rows specify a field name for each row.
(3) In table output use space as seperator
So I have a column with this data
1
1
1
2
3
4
5
5
5
how can I do a count if where the value at any given location in the above table is equal to a cell i select? i.e. doing Count([NUMBER]) Where([NUMBER] = Coordinates(0,0)) would return 3, because there are 3 rows where the value is one in the 0 position.
it's basically like in excel where you can do COUNTIF(A:A, 1) and it would give you the total number of rows where the value in A:A is 1. is this possible to do in business objects web intelligence?
Functions in WebI operate on rows, so you have to think about it a little differently.
If your intent is to create a cell outside of the report block and display the count of specific values, you can use Count() with Where():
=Count([NUMBER];All) Where ([NUMBER] = "1")
In a freestanding cell, the above will produce a value of "3" for your sample data.
If you want to put the result in the same block and have it count up the occurrences of values on that row, for example:
NUMBER NUMBER Total
1 3
1 3
1 3
2 1
3 1
4 1
5 3
5 3
5 3
it gets a little more complicated. You have to have at least one other dimension in the query to reference. It can be anything, but you have to be counting something in conjunction with the NUMBER dimension. So, the following would work, assuming there's another dimension in the query named [Duh]:
=Count([NUMBER];All) ForAll([Duh])