awk to convert scientific notation in file to original integer in csv file - awk

Question

I am trying to use awk to covert all scientific notation to its original integer. The below does execute, but the scientific notation remains in the output.
awk
awk -F, '{
for (i=1;i<=NF;i++) if ($i+0 == $i && $i ~ /e/) $i = sprintf("%.0f", $i)
} 1' f.csv
f.csv
[Header],,
....
....
,,
[Data],,
ID,Number,Test
1,2.07E-11,a
2,2.07E-11,a
desired
[Header],,
....
....
,,
[Data],,
ID,Number,Test
1,207081000000,a
2,207081000000,a

Answer 1

A few issues with the current code and/or description:
trying to match E against e will always fail
input of 2.07E-11 becomes 0.000000000207 (not 207081000000) and with a format of %.0f this would display as 0
even if the input is 2.07E+11 this should convert to 207000000000 and not 207081000000 (ie, where did the 81 come from? or is this a typo?)
output field delimiter has not been defined
why loop through all fields if only the 2nd field is of interest?
Modifying the input file:
$ cat f.csv
[Header],,
....
....
,,
[Data],,
ID,Number,Test
1,2.07E-11,a
2,2.07E+11,a
One awk idea:
awk '
BEGIN { FS=OFS=","}
{ if ($2+0 == $2 && $2 ~ /[eE]/)
$2=sprintf("%.0f",$2)
}
1' f.csv
This generates:
[Header],,
....
....
,,
[Data],,
ID,0,Test
1,0,a
2,207000000000,a
Assuming the input may contain scientific values in different fields we can push our changes into OP's code ...
$ cat f.csv
[Header],,
....
....
,,
[Data],,
ID,Number,Test
1,2.07E-11,a
2,2.07E+11,a
3,skip_this_field,5.6789E+11
Updating OP's awk code:
awk '
BEGIN { FS=OFS=","}
{ for (i=1;i<=NF;i++)
if ($i+0 == $i && $i ~ /[eE]/)
$i=sprintf("%.0f",$i)
}
1' f.csv
This generates:
[Header],,
....
....
,,
[Data],,
ID,Number,Test
1,0,a
2,207000000000,a
3,skip_this_field,567890000000