I am generating simple syntactic dependecies trees such as in the following example:
Best layout is "dot" but on the top row things get very crowded. Is there any parameter or other way to avoid node labels overlapping with neighbouring nodes (and ideally edges)?
Maybe some matplotlib parameter to "draw on a very wide canvas"? (sorry totally matplotlib ignorant).
Here is the code I am currently using:
import platform
import matplotlib
import matplotlib.pyplot as plt
import stanza
import networkx as nx
from netgraph import InteractiveGraph
if platform.system() == "Darwin":
matplotlib.use("TkAgg") # MacOSX backend is bugged; use TkAgg
def display_graph(G: nx.DiGraph, title: str):
"""Use netgraph to show the graph"""
nodecolors = nx.get_node_attributes(G, "nodecol")
nodelabels = nx.get_node_attributes(G, "lemma")
nodeshapes = nx.get_node_attributes(G, "nodeshape")
edgelabels = nx.get_edge_attributes(G, "label")
# now plot the graph
plot_instance = InteractiveGraph(
G,
node_layout="dot",
node_labels=nodelabels,
node_color=nodecolors,
node_label_fontdict=dict(size=12),
node_shape=nodeshapes,
node_alpha=0.5, # node transparency
edge_labels=edgelabels,
edge_layout="curved",
arrows=True,
)
plt.suptitle(title, wrap=True)
plt.show()
return
Is there any parameter or other way to avoid node labels overlapping with neighbouring nodes (and ideally edges)?
If you set the parameter node_label_offset to some float, e.g. node_label_offset=0.05, then netgraph will find the position 0.05 away from the node center that is furthest away from all other nodes and edges. However, there is no guarantee that there aren't any label overlaps as the space may simply be too crowded.
Maybe some matplotlib parameter to "draw on a very wide canvas"? (sorry totally matplotlib ignorant).
The width and height of the canvas are controlled by the shape parameter. The default is shape=(1, 1). So shape=(2, 2) would double the size of the canvas.
However, as fontsizes in matplotlib (and hence netgraph) are defined in display units, you would also have to increase the size of the matplotlib figure to decrease the size of the text relative to the whole figure.
fig, ax = plt.subplots(figsize=(2*6.4, 2*4.8)) # default is 6.4, 4.8
plot_instance = InteractiveGraph(G, node_layout='dot', shape=(2, 2), ax=ax, ...)
Further suggestions:
Remove the node edges. node_edge_color=nodecolors or node_edge_width=0..
I would set the node alpha to one, as otherwise the underlying edge becomes visible. Use lighter node colors if needed.
Basically, you want to remove any source of contrast that distract from the text if you want the labels to "pop".
Related
Problem Statement
I'm attempting to add two patches -- a rectangle patch and a text patch -- to the same space within a 3D plot. The ultimate goal is to annotate the rectangle patch with a corresponding value (about 20 rectangles across 4 planes -- see Figure 3). The following code does not get all the way there, but does demonstrate a rendering issue where sometimes the text patch is completely visible and sometimes it isn't -- interestingly, if the string doesn't extend outside the rectangle patch, it never seems to become visible at all. The only difference between Figures 1 and 2 is the rotation of the plot viewer image. I've left the cmap code in the example below because it's a requirement of the project (and just in case it affects the outcome).
Things I've Tried
Reversing the order that the patches are drawn.
Applying zorder values -- I think art3d.pathpatch_2d_to_3d is overriding that.
Creating a patch collection -- I can't seem to find a way to add the rectangle patch and the text patch to the same 3D collection.
Conclusion
I suspect that setting zorder to each patch before adding them to a 3D collection may be the solution, but I can't seem to find a way to get to that outcome. Similar questions suggest this, but I haven't been able to apply their answers to this problem specifically.
Environment
macOS: Big Sur 11.2.3
Python 3.8
Matplotlib 3.3.4
Figure 1
Figure 2
Figure 3
The Code
Generates Figures 1 and 2 (not 3).
#! /usr/bin/env python3
# -*- coding: utf-8 -*-
from matplotlib.patches import Rectangle, PathPatch
from matplotlib.text import TextPath
from matplotlib.transforms import Affine2D
import mpl_toolkits.mplot3d.art3d as art3d
import matplotlib.pyplot as plt
from matplotlib.colors import Normalize
plt.style.use('dark_background')
fig = plt.figure()
ax = fig.gca(projection='3d')
cmap = plt.cm.bwr
norm = Normalize(vmin=50, vmax=80)
base_color = cmap(norm(50))
# Draw box
box = Rectangle((25, 25), width=50, height=50, color=cmap(norm(62)), ec='black', alpha=1)
ax.add_patch(box)
art3d.pathpatch_2d_to_3d(box, z=1, zdir="z")
# Draw text
text_path = TextPath((60, 50), "xxxx", size=10)
trans = Affine2D().rotate(0).translate(0, 1)
p1 = PathPatch(trans.transform_path(text_path))
ax.add_patch(p1)
art3d.pathpatch_2d_to_3d(p1, z=1, zdir="z")
ax.set_xlabel('x')
ax.set_xlim(0, 100)
ax.set_xticklabels([])
ax.xaxis.set_pane_color(base_color)
ax.set_ylabel('y')
ax.set_ylim(0, 100)
ax.set_yticklabels([])
ax.yaxis.set_pane_color(base_color)
ax.set_zlabel('z')
ax.set_zlim(1, 4)
ax.set_zticks([1, 2, 3, 4])
ax.zaxis.set_pane_color(base_color)
ax.set_zticklabels([])
plt.show()
This is a well-known problem with matplotlib 3D plotting: objects are drawn in a particular order, and those plotted last appear on "top" of the others, regardless of which should be in front in a "true" 3D plot.
See the FAQ here: https://matplotlib.org/mpl_toolkits/mplot3d/faq.html#my-3d-plot-doesn-t-look-right-at-certain-viewing-angles
My 3D plot doesn’t look right at certain viewing angles
This is probably the most commonly reported issue with mplot3d. The problem is that – from some viewing angles – a 3D object would appear in front of another object, even though it is physically behind it. This can result in plots that do not look “physically correct.”
Unfortunately, while some work is being done to reduce the occurrence of this artifact, it is currently an intractable problem, and can not be fully solved until matplotlib supports 3D graphics rendering at its core.
The problem occurs due to the reduction of 3D data down to 2D + z-order scalar. A single value represents the 3rd dimension for all parts of 3D objects in a collection. Therefore, when the bounding boxes of two collections intersect, it becomes possible for this artifact to occur. Furthermore, the intersection of two 3D objects (such as polygons or patches) can not be rendered properly in matplotlib’s 2D rendering engine.
This problem will likely not be solved until OpenGL support is added to all of the backends (patches are greatly welcomed). Until then, if you need complex 3D scenes, we recommend using MayaVi.
I want to create a bar-plot in python. I want this plot to be beautiful though and I don't like the looks of python's axes.bar() function. Therefore, I have decided to use plt.vlines(). The challenge here is that my x-data is a list that contains strings and not numerical data. When I plot my graph, the spacing between the two columns (in my example column 2 = 0) is pretty big:
Furthermore, I want a grid. However, I would like to have minor grid lines as well. I know how to get all of this if my data was numerical. But since my x-data contains strings, I don't know how to set x_max. Any suggestions?
Internally, the positions of the labels are numbered 0,1,... So setting the x-limits a bit before 0 and after the last, shows them more centered.
Usually, bars are drawn with their 'feet' on the ground, which can be set via plt.ylim(0, ...). Minor ticks can be positioned for example at multiples of 0.2. Setting the length of the ticks to zero lets the position count for the grid, but suppresses the tick mark.
from matplotlib import pyplot as plt
from matplotlib.ticker import MultipleLocator
import numpy as np
labels = ['Test 1', 'Test 2']
values = [1, 0.7]
fig, ax = plt.subplots()
plt.vlines(labels, 0, values, colors='dodgerblue', alpha=.4, lw=7)
plt.xlim(-0.5, len(labels) - 0.5) # add some padding left and right of the bars
plt.ylim(0, 1.1) # bars usually have their 0 at the bottom
ax.xaxis.set_minor_locator(MultipleLocator(.2))
plt.tick_params(axis='x', which='both', length=0) # ticks not shown, but position serves for gridlines
plt.grid(axis='both', which='both', ls=':') # optionally set the linestyle of the grid
plt.show()
Python version: 3.6.4 (Anaconda on Windows)
Seaborn: 0.8.1
Matplotlib: 2.1.2
I'm trying to create a 2D Kernel Density plot using Seaborn but I want each step in the colourmap to have a different alpha value. I had a look at this question to create a matplotlib colourmap with alpha values: Add alpha to an existing matplotlib colormap.
I have a problem in that the lines between contours are visible. The result I get is here:
I thought that I had found the answer when I found this question: Hide contour linestroke on pyplot.contourf to get only fills. I tried the method outlined in the answer (using set_edgecolor("face") but it did not work in this case. That question also seemed to be related to vector graphics formats and I am just writing out a PNG.
Here is my script:
import numpy as np
import seaborn as sns
import matplotlib.colors as cols
import matplotlib.pyplot as plt
def alpha_cmap(cmap):
my_cmap = cmap(np.arange(cmap.N))
# Set a square root alpha.
x = np.linspace(0, 1, cmap.N)
my_cmap[:,-1] = x ** (0.5)
my_cmap = cols.ListedColormap(my_cmap)
return my_cmap
xs = np.random.uniform(size=100)
ys = np.random.uniform(size=100)
kplot = sns.kdeplot(data=xs, data2=ys,
cmap=alpha_cmap(plt.cm.viridis),
shade=True,
shade_lowest=False,
n_levels=30)
plt.savefig("example_plot.png")
Guided by some comments on this question I have tried some other methods that have been successful when this problem has come up. Based on this question (Matplotlib Contourf Plots Unwanted Outlines when Alpha < 1) I have tried altering the plot call to:
sns.kdeplot(data=xs, data2=ys,
cmap=alpha_cmap(plt.cm.viridis),
shade=True,
shade_lowest=False,
n_levels=30,
antialiased=True)
With antialiased=True the lines between contours are replaced by a narrow white line:
I have also tried an approach similar to this question - Pyplot pcolormesh confused when alpha not 1. This approach is based on looping over the PathCollections in kplot.collections and tuning the parameters of the edges so that they become invisible. I have tried adding this code and tweaking the linewidth -
for thing in kplot.collections:
thing.set_edgecolor("face")
thing.set_linewidth(0.01)
fig.canvas.draw()
This results in a mix of white and dark lines - .
I believe that I will not be able to tune the line width to make the lines disappear because of the variable width of the contour bands.
Using both methods (antialiasing + linewidth) makes this version, which looks cool but isn't quite what I want:
I also found this question - Changing Transparency of/Remove Contour Lines in Matplotlib
This one suggests overplotting a second plot with a different number of contour levels on the same axis, like:
kplot = sns.kdeplot(data=xs, data2=ys,
ax=ax,
cmap=alpha_cmap(plt.cm.viridis),
shade=True,
shade_lowest=False,
n_levels=30,
antialiased=True)
kplot = sns.kdeplot(data=xs, data2=ys,
ax=ax,
cmap=alpha_cmap(plt.cm.viridis),
shade=True,
shade_lowest=False,
n_levels=35,
antialiased=True)
This results in:
This is better, and almost works. The problem here is I need variable (and non-linear) alpha throughout the colourmap. The variable banding and lines seem to be a result of the combinations of alpha when contours are plotted over each other. I also still see some clear/white lines in the result.
The following code:
# in ipython notebook, enable inline plotting with:
# %pylab inline --no-import-all
import matplotlib.pyplot as plt
# create some circles
circle1 = plt.Circle((-.5,0), 1, color='r', alpha=.2)
circle2 = plt.Circle(( .5,0), 1, color='b', alpha=.2)
# add them to the plot (bad form to use ;, but saving space)
# and control the display a bit
ax = plt.gca()
ax.add_artist(circle1); ax.add_artist(circle2)
ax.set_xlim(-2, 2); ax.set_ylim(-2, 2)
ax.set_aspect('equal')
# display it
plt.plot()
Produces the following plot:
I would like to specify the colors of the four regions (1) the background (currently white), (2 and 3) each individual event (the non-overlapping areas, currently blue and red), and (4) the intersection event (currently blended to purple). For example, I might color them red, green, blue, yellow -or- I might give them four different, precisely specified grayscale values (the later is more likely). [The colors will be generated based on characteristics of the underlying data.]
I specifically do not want to use alpha blending to "infer" a color in the intersection. I need to explicitly control the colors of all four regions.
I can think of a few strategies to solve this:
Ask mpl to extract the "primitive" patch objects that make up the three distinctly colored graphical regions (and do something similar to operate on the background) and then color them.
Given the circles, manually compute their intersections and color that intersection (somehow). Going point by point seems ugly.
Thanks!
I'm not 100% sure but I think matplotlib does not have the functionality to intersect polygons. But you could use shapely:
import shapely.geometry as sg
import matplotlib.pyplot as plt
import descartes
# create the circles with shapely
a = sg.Point(-.5,0).buffer(1.)
b = sg.Point(0.5,0).buffer(1.)
# compute the 3 parts
left = a.difference(b)
right = b.difference(a)
middle = a.intersection(b)
# use descartes to create the matplotlib patches
ax = plt.gca()
ax.add_patch(descartes.PolygonPatch(left, fc='b', ec='k', alpha=0.2))
ax.add_patch(descartes.PolygonPatch(right, fc='r', ec='k', alpha=0.2))
ax.add_patch(descartes.PolygonPatch(middle, fc='g', ec='k', alpha=0.2))
# control display
ax.set_xlim(-2, 2); ax.set_ylim(-2, 2)
ax.set_aspect('equal')
plt.show()
I am plotting a histogram using
plt.imshow(hist2d, norm = LogNorm(), cmap = gray)
where hist2d is a matrix of histogram values. This works fine except for elements in hist2d that are zero. In particular, I obtain the following image
but would like the white patches to be black.
Thank you!
Here's an alternative method that does not require you to muck with your data by setting a rgb value for bad pixels.
import copy
data = np.arange(25).reshape((5,5))
my_cmap = copy.copy(matplotlib.cm.get_cmap('gray')) # copy the default cmap
my_cmap.set_bad((0,0,0))
plt.imshow(data,
norm=matplotlib.colors.LogNorm(),
interpolation='nearest',
cmap=my_cmap)
The problem is that bins with 0 can not be properly log normalized so they are flagged as 'bad', which are mapped to differently. The default behavior is to not draw anything on those pixels. You can also specify what color to draw pixels that are over or under the limits of the color map (the default is to draw them as the highest/lowest color).
If you're happy with the colour scaling as is, and simply want the 0 values to be black, I'd simply change the input matrix so that the 0s are replaced by the next smallest value:
import matplotlib.pyplot as plt
import matplotlib.cm, matplotlib.colors
import numpy
hist2d = numpy.arange(9).reshape(3,3)
plt.imshow(numpy.maximum(hist2d, sorted(hist2d.flat)[1]),
interpolation='nearest',
norm = matplotlib.colors.LogNorm(),
cmap = matplotlib.cm.gray)
produces
Was this generated with the matplotlib hist2d function?
All you need to do is go through the matrix and set some arbitrary floor value, then make sure to plot this with fixed limits
for f in hist2d:
f += 1e-3
then when you show the figure, all of the whitespace will now be at the floor value, and will show up on the lognormal plot . However, if you are letting hist2d automatically pick the scaling for you, it will want to use the 1e-3 floor value as the minimum. To avoid this, you need to set vmin and vmax values in hist2d
hist2d(x,y,bins=40, norm=LogNorm(), vmin=1, vmax=1e4)