I have a table in sql.
I need to check if columns A and B are 1 to 1 match (Meaning for each row in A, there is only one value in B)
but if you see below, it is not.
Only Cat A and Cat C have one values in Col B.
So is there a way to identify between 2 columns
A B C
Cat A asd 34
Cat A asd 56
Cat B dfg 67
Cat B ghj 7
Cat C ggh 78
Cat D ertrty 9
Cat D tyutyu 6
Cat D tuuiy 45
SELECT A, COUNT(DISTINCT B)
FROM your_table
GROUP BY A
HAVING COUNT(DISTINCT B) = 1;
Related
This problem is out of my ability range and I can’t get anywhere with it beyond knowing I can probably use LEAD, LAG or maybe a cursor?
Here is a breakdown of the table and question:
row_id is always an IDENTITY(1, 1) column.
The set_id column always starts out in groups of 3s (two 0s for the first set_id, don't worry about why).
The letter column is alphabetic. There are varying counts of duplicates.
Here's the original table:
row_id
set_id
letter
1
0
A
2
0
A
3
1
A
4
1
B
5
1
B
6
2
B
7
2
B
8
2
C
9
3
C
10
3
C
11
3
D
12
4
D
13
4
D
14
4
D
What I need is a code that: if there is a duplicate letter in the next row, then the set_id in the next row should be the same as the previous row (alt_set_id).
If that doesn't make sense, here is the result I want:
row_id
set_id
letter
alt_set_id
1
0
A
0
2
0
A
0
3
1
A
0
4
1
B
1
5
1
B
1
6
2
B
1
7
2
B
1
8
2
C
2
9
3
C
2
10
3
C
2
11
3
D
3
12
4
D
3
13
4
D
3
14
4
D
3
Here's where I am with code so far, I'm not really close but I think I am on the right path:
SELECT
*,
CASE
WHEN letter = [letter in next row]
THEN 'yes'
ELSE 'no'
END AS 'next row a duplicate?',
'tbd' AS alt_row_id
FROM
(SELECT
*,
LEAD(letter) OVER (ORDER BY row_id) AS 'letter in next row'
FROM
sort_test) AS dt
WHERE
row_id = row_id
That query has the below result set, which is something I think I can work with, but it doesn't feel very efficient and I'm not yet getting the result needed in the alt_set_id column:
row_id
set_id
letter
letter in next row
next row a duplicate?
alt_set_id
1
0
A
A
yes
tbd
2
0
A
A
yes
tbd
3
1
A
B
no
tbd
4
1
B
B
yes
tbd
5
1
B
B
yes
tbd
6
2
B
B
yes
tbd
7
2
B
C
no
tbd
8
2
C
C
yes
tbd
9
3
C
C
yes
tbd
10
3
C
D
no
tbd
11
3
D
D
yes
tbd
12
4
D
D
yes
tbd
13
4
D
D
yes
tbd
14
4
D
NULL
no
tbd
Thanks for any help!
Based on your example data, you want the minimum set_id for each letter. If so, use window functions;
select t.*, min(set_id) over (partition by letter) as alt_set_id
from sort_test t;
It would appear if I understand correctly a simple correlated subquery will give you the desired result:
select *, (select Min(set_Id) from t t2 where t2.letter=t.letter) as alt_set_id
from t
See working DB Fiddle
I have following two tables:
A.
A_ID Amount GL_ID
------------------
1 100 10
2 200 11
3 150 10
4 20 10
5 369 12
6 369 11
7 254 12
B.
B_ID Name GL_ID
-----------------
1 A 10
2 B 10
3 C 11
4 D 11
5 E 12
6 F 12
I want to join these tables. They have GL_ID column in common (ID of another table). Table A store transactions along with GL_ID while table B defines document type (A, B, C, D etc.) with reference to GL_ID.
A & B don't have any common column except GL_ID. I want the following result, relevant document type (A, B, C, D etc.) for each transaction in table A.
A.A_ID A.Amount B.Name
-----------------------
1 100 A
2 200 B
3 150 B
4 20 B
5 369 A
6 369 D
7 254 D
But when I apply to join (LEFT, RIGHT, FULL JOIN) keyword, query shows repeated values. But I only want to have relevant Doc Type for each line in table A.
try this.
select distinct A.A_ID, A.Amount, B.Name
from A inner join B on A.GL_ID=B.GL_ID
Hi I was trying to paste multiple files (each with a single column but different number of rows) together. But it did't provide what I was expecting. How to solve that?
paste file1.txt file2.txt paste3.txt ... paste100 > out.txt
input file 1:
A
B
C
input file 2:
D
E
input file 3:
F
G
H
I
J
.......
......
Desired output:
A D F
B E G
C H
I
J
Would this be same if the files have multiple columns with different number of rows?
for example:
file1
A 1
B 2
C 3
file2
D 4
E 5
file3
F 6 %
G 7 &
H 8 #
I 9 #
J 10 ?
output:
A 1 D 4 F 6 %
B 2 E 5 G 7 &
C 3 H 8 #
I 9 #
J 10 ?
Isn't the default behaviour of paste exactly what you ask?
% paste <(echo "a
b
c
d") <(echo "1
2
3") <(echo "10
> 20
> 30
> 40
> 50
> 60")
a 1 10
b 2 20
c 3 30
d 40
50
60
%
Given below is the snapshot of my data
NameAgeIncome Group
Asd 20 A
Asd 20 A
b 19 E
c 21 B
c 21 B
c 21 B
df 21 C
rd 24 D
I want ot include a flag variable where it says 1 to one of the duplicate row and 0 to another. And also 0 to rest of the rows which are not duplicate. Given below is the snapshot of final desired output
NameAgeIncome Group Flag
Asd 20 A 1
Asd 20 A 0
b 19 E 0
c 21 B 1
c 21 B 1
c 21 B 0
df 21 C 0
rd 24 D 0
Can anyone help me how to create this Flag variable in Oracle database
You can do this using analytic functions and case:
select t.*,
(case when row_number() over (partition by name, age, income order by name) = 1
then 0 else 1
end) as GroupFlag
from table t;
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Closed 10 years ago.
i have two files
file1
-------------------------------
1 a t p b
2 b c f a
3 d y u b
2 b c f a
2 u g t c
2 b j h c
file2
--------------------------------
1 a b
2 p c
3 n a
4 4 a
i want combine these 2 files based last columns (column 5 of file1 and column 3 of file2) using awk
result
----------------------------------------------
1 a t p 1 a b
2 b c f 3 n a
2 b c f 4 4 a
3 d y u 1 a b
2 b c f 3 n a
2 b c f 4 4 a
2 u g t 2 p c
2 b j h 2 p c
at the very beginning, I didn't see the duplicated "a" in file2, I thought it would be solved with normal array matching. ... now it works.
an awk onliner:
awk 'NR==FNR{a[$3"_"NR]=$0;next;}{for(x in a){if(x~"^"$5) print $1,$2,$3,$4,a[x];}}' f2.txt f1.txt
test
kent$ head *.txt
==> f1.txt <==
1 a t p b
2 b c f a
3 d y u b
2 b c f a
2 u g t c
2 b j h c
==> f2.txt <==
1 a b
2 p c
3 n a
4 4 a
kent$ awk 'NR==FNR{a[$3"_"NR]=$0;next;}{for(x in a){if(x~"^"$5) print $1,$2,$3,$4,a[x];}}' f2.txt f1.txt
1 a t p 1 a b
2 b c f 3 n a
2 b c f 4 4 a
3 d y u 1 a b
2 b c f 3 n a
2 b c f 4 4 a
2 u g t 2 p c
2 b j h 2 p c
note, the output format was not sexy, but it would be acceptable if pipe it to column -t
Other way assuming files have no headers:
awk '
FNR == NR {
f2[ $NF ] = f2[ $NF ] ? f2[ $NF ] SUBSEP $0 : $0;
next;
}
FNR < NR {
if ( $NF in f2 ) {
split( f2[ $NF ], a, SUBSEP );
len = length( a );
for ( i = 1; i <= len; i++ ) {
$NF = a[ i ];
}
}
printf "%s\n", $0;
}
' file2 file1 | column -t
It yields:
1 a t p 1 a b
2 b c f 3 n a
2 b c f 4 4 a
3 d y u 1 a b
2 b c f 3 n a
2 b c f 4 4 a
2 u g t 2 p c
2 b j h 2 p c
A bit easier in a language that supports arbitrary data structures (list of lists). Here's ruby
# read "file2" and group by the last field
file2 = File .foreach('file2') .map(&:split) .group_by {|fields| fields[-1]}
# process file1
File .foreach('file1') .map(&:split) .each do |fields|
file2[fields[-1]] .each do |fields2|
puts (fields[0..-2] + fields2).join(" ")
end
end
outputs
1 a t p 1 a b
2 b c f 3 n a
2 b c f 4 4 a
3 d y u 1 a b
2 b c f 3 n a
2 b c f 4 4 a
2 u g t 2 p c
2 b j h 2 p c