I have emojis in my PosgreSQL table:
which I need to remove.
I used a script:
select full_name,
ltrim(rtrim(regexp_replace(full_name, '[^a-zA-Z]', ' ', 'g'))) as Cleansed_Name
from Emoji_Test
It removes the emoji from "Amie Bartly Fashion Blogger" which is good but transforms "Amina Öztürk to "Amina zt rk" which is not good.
What can I do to remove only emojis and keep pertinent name information?
I tested it on a database here and just changed the regex you used.
Query
select firstname, regexp_replace(firstname, '[^A-Za-zÀ-ÖØ-öø-ÿ]', ' ', 'g') from person where firstname ilike '%débora%';
Output
Débora❤️,Débora
Related
I want to select where 2 strings but without taking
underscore
apostrophe
dash..
Hello !
I want to select an option in my SQL database who look like this :
Chef d'équipe aménagement-finitions
With an original tag who look like this
chef-déquipe-aménagement-finitions
Some results in database had a - too
SELECT *
FROM table
WHERE REPLACE(name, '-', ' ') = REPLACE('chef-déquipe-aménagement-finitions', '-', ' ')
didnt work because of missing '
And a double replace didn't work too.
I want the string be able to compare without taking
underscore
apostrophe
dash
and all things like that
is this possible ?
Thanks for your help
Have good day !
Depends on your rdbms, but here's how I would perform in MySQL 8. If using a different version or rdbms, then first determine how to escape the single quote and modify as needed.
with my_data as (
select 'Chef d''équipe aménagement-finitions' as name
)
select name,
lower(replace(replace(name, '\'', ''), ' ', '-')) as name2
from my_data;
name
name2
Chef d'équipe aménagement-finitions
chef-déquipe-aménagement-finitions
Sql-server and Postgres version:
lower(replace(replace(name, '''', ''), ' ', '-')) as name
After posting, this, I re-read and noticed you are also looking to replace other characters. You could either keep layering the replace function, or, look into other functions.
I am using PostgreSQL. Data in the table looks like below there is ''. I would like to remove '' with the empty value.
Query:
select 'Patriots Colony Family Monthly'
Actual Result Screenshot:
Expected result:
Abcd
You can use regex_replace to remove non alphanumeric chars
select regexp_replace(yourColumn, '[^[:alnum:]]', ' ', 'g')
from yourTable;
You can also do like this
select regexp_replace(yourColumn, '[^a-zA-Z0-9]+',' ','g')
from yourTable;
I want to extract the un-matched values in data like in (table1)
name id subject
maria 01 Math computer english
faro 02 Computer stat english
hina 03 Chemistry physics bio
The below query
Select *
from table1
where subject like ‘%english%’ or
subject like ‘%stat%’
returns first two rows that are matched with the criteria.
But I just need to extract the un-matched values from column (subject) like below output
unmatched
math computer
computer
chemistry physics bio
(Because in the first row only math computer values are not matching, in the second row two matches and in third row there are no matches).
can i get that output??
With REPLACE you eliminate all occurrences of the values 'english' and/or 'stat':
SELECT
trim(
replace(replace(replace(subject, 'english', ''), 'stat', ''), ' ', '')
) unmatched
FROM tablename;
The final trim and replace will remove double spaces from the result and spaces from the start and the end.
You have a poor table design. You should be storing lists as separate rows in another table -- a so-called "junction" or "association" table. SQL has a great data type for storing lists. It is called a "table" not a "string".
That said, sometimes we are stuck with other peoples really, really bad choices of data model.
If so, you can use replace() and trim() to get the list you want. I would do:
SELECT trim(replace(replace(' ' || subject || ' ', ' english ', ' '
), ' stat ', ''
), ' ', ' '
) as unmatched
FROM tablename;
This easily generalizes to more values, without worrying about introducing adjacent spaces.
I need to get a list of names as per the following format
"Mr."+first name initial+last name+"."
There is only one table for this
salesperson (f_name, l_name)
What i have been trying is;
SELECT 'Mr.' ||' ' || SUBSTRING(f_name,1,1) || ' ' || l_name ||’.’||
FROM salesperson;
It works without the substring or left, but not if I include them.
Use concat instead of || operator to concatenate strings in MySQL. As you have it, it would be interpreted as logical OR condition, hence you get the error.
SELECT CONCAT('Mr.',' ',SUBSTRING(f_name,1,1),' ',l_name,'.')
FROM salesperson;
Oracle solution
SELECT 'Mr.'||' '||SUBSTR(f_name,1,1)||' '||l_name||'.'
FROM salesperson;
It is better practice anyways to grab the name data in full and then format it in the view part of your application with languages that are more suited to string manipulation. This also makes your code more reusable.
That being said use this
SELECT CONCAT("Mr. ",SUBSTRING( f_name, 1, 1 ) ," ",l_name,".") FROM salesperson
I am writing a small query to extract all last names from a bunch of Author name database. Names on file will contain first and middle name, or just first name.
Ex: John Smith
John T. Smith
So I cannot search purely by just after the first space... But I know for sure that the lastname should be from the END to the first space from the right side of the string. I don't really care about first name.
This is what I currently have...
select [name], LEFT([name], CHARINDEX(' ', [name] + ' ')-1) as firstName,
SUBSTRING([name], charindex(' ', [name]+' ') + 1, LEN([name])) as lastName
from Author
;
I am quite new to sql, any help is highly appreciated!
Thanks in advance!
EDIT: for those who ever come across this need for help, this line helps:
select substr(t.string,instr(t.string,' ',-1)+1) last_word
For Oracle DB try this :
WITH t AS
(SELECT name AS l FROM <your query>
)
SELECT SUBSTR(l,instr(l,' ',-1)+1,LENGTH(l)) FROM t;
SUBSTRING_INDEX() should work in this case.
select name, SUBSTRING_INDEX(name,' ',-1) as lastName from Author;