Let's say I have a table like such:
Store productId
Test 1 6524
Test 1 6521
Test 1 6523
Test 2 6234
Test 2 6264
Test 3 6395
I am trying to find a way to check whether the store has the product 6524 and if it does it should remove the entire group (store) from the list so that the result can look like the below.
Expected Outcome:
Test 2
Test 3
I have tried doing a GROUP by followed by HAVING productId <> 6524 but this of course just gets rid of the single row not the entire group.
You can use NOT EXISTS such as
SELECT DISTINCT Store
FROM tab t
WHERE NOT EXISTS ( SELECT 0
FROM tab
WHERE Store = t.Store
AND productId = 6524 )
which filters out the matching values of Store column
select store
from your_table
group by store
having sum(productId=6524)=0;
Related
I have two tables and I need to filter the data by filter id depends on the relation to to filter group id.
For example I have this two tables:
Table 1:
ItemID
FilterID
3
122
3
123
3
4
17
123
Table 2:
FilterID
FilterGroupID
122
5
123
5
4
1
If I search by filter id = 123 than all item id with this filter need to be returned.
If I search two or more different filter id that have different group id I need to get only the item ids that have all filter id and group id.
Desired output:
first input: 123 -> return item id =3 and item id = 17
second input: 123,4 -> return item id = 3 because filter id 123 belong to group id 5 and filter id 4 belong to group id 1 and item id 3 is the only one that has this two filters.
third input: 122,123 -> return item id =3 and item id = 17 because both filter id belong to same group.
I am getting a little lost with this query and I will be glad to get some help.
I’ll try to simplify it: Let’s say we have group filter of size and group filter of color. If I filter by size S or M than I need to get all items with this sizes. If I want to add color like blue than the answer will cut the result by: item with size S or M and Color blue. So filter from different group may cut some results
It seems that you want to get every ItemID which has at least one matching filter from each FilterGroupID within your filter input. So within each group you have or logic, and between groups you have and logic
If you store your input in a table variable or Table-Valued parameter, then you can just use normal relational division techniques.
This then becomes a question of Relational Division With Remainder, with multiple divisors.
There are many ways to slice this cake. Here is one option
Join the filter input to the groups, to get each filter's group ID
Use a combination of DENSE_RANK and MAX to get the total distinct groups (you can't use COUNT(DISTINCT in a window function so we need to hack it)
You can change this step to use a subquery instead of window functions. It may be faster or slower
Join the main table, and filter out any ItemIDs which do not have their total distinct groups the same as the main total
SELECT
t1.ItemID
FROM (
SELECT *,
TotalGroups = MAX(dr) OVER ()
FROM (
SELECT
fi.FilterID,
t2.FilterGroupID,
dr = DENSE_RANK() OVER (ORDER BY t2.FilterGroupID)
FROM #Filters fi
JOIN Table2 t2 ON t2.FilterID = fI.FilterID
) fi
) fi
JOIN Table1 t1 ON t1.FilterID = fi.FilterID
GROUP BY
t1.ItemID
HAVING COUNT(DISTINCT FilterGroupID) = MAX(fi.TotalGroups);
db<>fiddle
How do I not get all the ID's grouped, but instead listed from first to last; with all their respective values in the columns next to them?
Instead of grouping it, it should show ID 1 and its value, ID 2 and its value. EVEN if the values for the ID is the same. I tried removing the GROUP_CONCAT, but then it's only showing one ID per customfield_value?
SELECT GROUP_CONCAT(virtuemart_product_id), customfield_value, COUNT(*) c
FROM jos_virtuemart_product_customfields
WHERE virtuemart_custom_id = 6
GROUP BY customfield_value
HAVING c > 1
It's working currently, but grouping the ID's and spacing them with a comma. Should just display as in a normal table/list format.
Currently it shows like this(as you can see, it's ALL the same ICOS number, but different ID's. I ONLY need to display the values WHERE the ICOS NUMBER is "duplicate"):
ID ICOS Count
1,2,3 775896 3
It should be displaying like this:
ID ICOS Count
1 775896 1
2 775896 1
3 775896 1
All rows where the customfield_value is not unique:
-- Assuming MySQL
SELECT virtuemart_product_id, customfield_value
, COUNT(*) c -- maybe not needed
FROM jos_virtuemart_product_customfields
WHERE virtuemart_custom_id = 6
AND customfield_value IN
( SELECT customfield_value
FROM jos_virtuemart_product_customfields
WHERE virtuemart_custom_id = 6
GROUP BY customfield_value
HAVING COUNT(*) > 1 -- more than one row exists
)
GROUP BY virtuemart_product_id, customfield_value -- maybe not needed
If the virtuemart_product_id is unique you don't need the outer count/group by as it will always be 1.
I have a table that has demographic information about a set of users which looks like this:
User_id Category IsMember
1 College 1
1 Married 0
1 Employed 1
1 Has_Kids 1
2 College 0
2 Married 1
2 Employed 1
3 College 0
3 Employed 0
The result set I want is a table that looks like this:
User_Id|College|Married|Employed|Has_Kids
1 1 0 1 1
2 0 1 1 0
3 0 0 0 0
In other words, the table indicates the presence or absence of a category for each user. Sometimes the user will have a category where the value if false, sometimes the user will have no row for a category, in which case IsMember is assumed to be false.
Also, from time to time additional categories will be added to the data set, and I'm wondering if its possible to do this query without knowing up front all the possible category names, in other words, I won't be able to specify all the column names I want to count in the result. (Note only user 1 has category "has_kids" and user 3 is missing a row for category "married"
(using Postgres)
Thanks.
You can use jsonb funcions.
with titles as (
select jsonb_object_agg(Category, Category) as titles,
jsonb_object_agg(Category, -1) as defaults
from demog
),
the_rows as (
select null::bigint as id, titles as data
from titles
union
select User_id, defaults || jsonb_object_agg(Category, IsMember)
from demog, titles
group by User_id, defaults
)
select id, string_agg(value, '|' order by key)
from (
select id, key, value
from the_rows, jsonb_each_text(data)
) x
group by id
order by id nulls first
You can see a running example in http://rextester.com/QEGT70842
You can replace -1 with 0 for the default value and '|' with ',' for the separator.
You can install tablefunc module and use the crosstab function.
https://www.postgresql.org/docs/9.1/static/tablefunc.html
I found a Postgres function script called colpivot here which does the trick. Ran the script to create the function, then created the table in one statement:
select colpivot ('_pivoted', 'select * from user_categories', array['user_id'],
array ['category'], '#.is_member', null);
I have this sort of structure
ID STATUS
1 FIRSTSTAT
2 FIRSTSTAT
3 FIRSTSTAT
1 SECSTAT
3 SECSTAT
3 THIRDSTAT
3 FOURTHSTAT
3 FIFTHSTAT
I want to get the 3 back because he has all following status (FIRSTSTAT, SECSTAT, THIRDSTAT). Do you have an idea how I could make that?
It should be done by explicitely giving the statuses because other statuses exist so SELECT FROM WHERE = 'THIRDSTAT' is not ok since it should have all three statuses, not only one of them.
So I guess it should be done calculating the SUM or something like that.
I tried the following but of course, it does not work :
SELECT
FROM
WHERE
AND
AND
If the number of different status values is known to always be 3:
select id
from tablename
where status in ('FIRSTSTAT', 'SECSTAT', 'THIRDSTAT')
group by id
having count(distinct status) = 3
this is a sample sql query that i created ms access query. i am trying to get only one row the min(DATE). how ever when i run my query i get multiple lines. any hits? thanks
SELECT tblWarehouseItem.whiItemName,
tblWarehouseItem.whiQty,
tblWarehouseItem.whiPrice,
Min(tblWarehouseItem.whiDateIn) AS MinOfwhiDateIn,
tblWarehouseItem.whiExpiryDate,
tblWarehouseItem.whiwrhID
FROM tblWarehouseItem
GROUP BY tblWarehouseItem.whiDateIn,
tblWarehouseItem.whiItemName,
tblWarehouseItem.whiQty,
tblWarehouseItem.whiPrice,
tblWarehouseItem.whiExpiryDate,
tblWarehouseItem.whiwrhID;
If i have my sql code like that is working as it should:
SELECT MIN(tblWarehouseItem.whiDateIn) FROM tblWarehouseItem;
In the first query, you group by a number of columns. That means the minimum value will be calculated for each group, which in turn means you may have multiple rows. On the other hand, the second query will only get the minimum value for the specified column from all rows, so that there is only one row in the result set.
A simple example is shown below to illustrate the above.
Table:
Key Value
1 1
1 2
2 3
2 4
On Group By Key:
GroupKey MinValue
1 = min(1,2) = 1 -> Row 1
2 = min(3,4) = 3 -> Row 2
On Min (Value)
MinValue
=min(1,2,3,4) = 1 -> Row 1
For a table like above, if you want to select all rows and also show the minimum value from whole table rather than per group, you can do something like this:
select key, (select min(value) from table)
from table
SELECT WI.*
FROM tblWarehouseItem AS WI INNER JOIN (SELECT whiimtID, MIN(tblWarehouseItem.whiDateIn) AS whiDateIn
FROM tblWarehouseItem
GROUP BY whiimtID) AS MinWI ON (WI.whiDateIn = MinWI.whiDateIn) AND (WI.whiimtID = MinWI.whiimtID);