How can i write this query with gorm? - sql

i want to write this query with gorm
SELECT count(*)
FROM (select distinct on(t1.number) t1.number ,t1.id from "tbl_phone_books" as t1
WHERE (customer_id = 100)) as phone LIMIT 5 OFFSET 0
i wrote this code but it didn't work correctly:
Db.Debug().
Model(models.TblPhoneBook{}).
Select("distinct on(number) number,id).
Where("customer_id = ? , customerId).
Offset(offset).
Limit(5).
Count(&response)

db.Table("tbl_phonebooks").Select("distinct on(number) number, id").Where("customer_id = ?", 100).Group("number, id").Limit(5).Offset(0).Count(&count)

Related

Select random sample of N rows from Oracle SQL query result

I want to reduce the number of rows exported from a query result. I have had no luck adapting the accepted solution posted on this thread.
My query looks as follows:
select
round((to_date('2019-12-31') - date_birth) / 365, 0) as age
from
personal_info a
where
exists
(
select person_id b from credit_info where credit_type = 'C' and a.person_id = b.person_id
)
;
This query returns way more rows than I need, so I was wondering if there's a way to use sample() to select a fixed number of rows (not a percentage) from however many rows result from this query.
You can sample your data by ordering randomly and then fetching first N rows.
DBMS_RANDOM.RANDOM
select round((to_date('2019-12-31') - date_birth) / 365, 0) as age
From personal_info a
where exists ( select person_id b from credit_info where credit_type = 'C' and a.person_id = b.person_id )
Order by DBMS_RANDOM.RANDOM
Fetch first 250 Rows
Edit: for oracle 11g and prior
Select * from (
select round((to_date('2019-12-31') - date_birth) / 365, 0) as age
From personal_info a
where exists ( select person_id b from credit_info where credit_type = 'C' and a.person_id = b.person_id )
Order by DBMS_RANDOM.RANDOM
)
Where rownum< 250
You can use fetch first to return a fixed number of rows. Just add:
fetch first 100 rows
to the end of your query.
If you want these sampled in some fashion, you need to explain what type of sampling you want.
If you are using 12C, you can use the row limiting clause below
select
round((to_date('2019-12-31') - date_birth) / 365, 0) as age
from
personal_info a
where
exists
(
select person_id b from credit_info where credit_type = 'C' and a.person_id = b.person_id
)
FETCH NEXT 5 ROWS ONLY;
Instead of 5, you can use any number you want.

error incorporating a select within a IFNULL in MariaDB

I'm creating a view in MariaDB and i'm having trouble making it work for a couple of fields. Currently this is working:
( SELECT DISTINCT IFNULL(grades.`grade`,'No Grade')
FROM `table` grades
WHERE userinfo.`id` = grades.`id`
AND grades.`Item Name` = 'SOMEINFO'
) 'SOMENAME',
But i need to add a select where the 'No grade' is, in the following form
( SELECT DISTINCT IFNULL( grades.`grade`,
SELECT IF( EXISTS
( SELECT *
FROM `another_table`
WHERE userid = 365
AND courseid = 2
), 'Enrolled', 'Not enrolled'
)
)
FROM `table` grades
WHERE userinfo.`id` = grades.`id`
AND grades.`Item Name` = 'SOMEINFO'
) 'SOMENAME',
i know that
SELECT IF( EXISTS( SELECT *
FROM `another_table`
WHERE userid = 365
AND courseid = 2
),
'Enrolled', 'Not enrolled'
)
is working too, but now the whole thing it's giving me an error, so any suggestions would be greatly appreciated
Thanks
This looks like a subquery:
(SELECT DISTINCT IFNULL(grades.`grade`,
SELECT IF( EXISTS (SELECT *
FROM `another_table`
WHERE userid = 365 AND courseid = 2
), 'Enrolled', 'Not enrolled'
)
)
FROM `table` grades
WHERE userinfo.`id` = grades.`id` AND
grades.`Item Name` = 'SOMEINFO'
) as SOMENAME,
You are using a subquery that returns two columns in a position where a scalar subquery is expected. A scalar subquery returns one column in at most one row.
Unfortunately, there is no easy way to do what you want in MySQL, because of the restrictions on views. I would advise you to rewrite the logic so the exists is handled using a left join in the from clause.

Select 1st and 2nd Record before record X

SQL Server 2008-12
I have table:
InteractionKey char(18)
dEventTime datetime
SeqNo int
cEventData1
There will be multiple entries per InteractionKey - dEventTime only goes out to the Seconds and SeqNo is incremented if two entries occur on the same second.
What I need to do is select the First and Second record BEFORE the record where
cEventData1 = 'Disconnect'
The final product will give me a count of occurrences grouped by cEventData1.
I am currently using a cursor (will update with cursor source momentarily) I would like to use a CTE - but I really struggle with understanding them...
Any ideas would be appreciated!
Update with Data Sample
INTERACTIONKEY dEventTime SeqNo cEventData1
100186322420130722 2013-07-22 11:50:49.000 1 EnterPassword
100186322420130722 2013-07-22 11:50:49.000 2 CheckPassword
100186322420130722 2013-07-22 11:50:49.000 3 Attendant Disconnect
The result of the query would ideally tell me - : NOTE The Action column here can be simply 'Attendant Disconnect' as Action
cEventData1 Action Count
CheckPassword Attendant Disconnect 1
Here is the query I ended up going with based upon the below answer
SELECT DISTINCT t1.InteractionKey,
DisconnectTime = t1.dEventTime,
PreviousEventTime = t2.dEventTime,
PreviousEvent = t2.cEventData1,
t2.SeqNo
FROM IVRHistory t1
OUTER APPLY
( SELECT TOP 1 t2.dEventTime, t2.SeqNo, t2.cEventData1
FROM IVRHistory t2
WHERE t1.InteractionKey = t2.InteractionKey
AND t1.dEventTime >= t2.dEventTime
AND t1.SeqNo > t2.SeqNo
AND t2.cEventData1 <> 'Attendant Disconnect'
ORDER BY t2.dEventTime DESC, t2.SeqNo DESC
) t2
WHERE t1.cEventData1 = 'Attendant Disconnect'
I would approach this using APPLY:
SELECT t1.InteractionKey,
DisconnectTime = t1.dEventTime,
PreviousEventTime = t2.dEventTime,
PreviousEvent = t2.cEventData1,
t2.SeqNo
FROM T t1
OUTER APPLY
( SELECT TOP 2 t2.dEventTime, t2.SeqNo, t2.cEventData1
FROM T t2
WHERE t1.InteractionKey = t2.InteractionKey
AND t1.dEventTime > t2.dEventTime
ORDER BY t2.dEventTime DESC
) t2
WHERE t1.cEventData1 = 'Disconnect';
This will give you the two records immediately preceeding the disconnect event. If you need more than two records if there are duplicate times you can use TOP 2 WITH TIES.
Without your sample input and output I am guessing a bit, but from what you have said your final aggregate would be:
SELECT t2.cEventData1,
Occurances = COUNT(*)
FROM T t1
OUTER APPLY
( SELECT TOP 2 t2.dEventTime, t2.SeqNo, t2.cEventData1
FROM T t2
WHERE t1.InteractionKey = t2.InteractionKey
AND t1.dEventTime > t2.dEventTime
ORDER BY t2.dEventTime DESC
) t2
WHERE t1.cEventData1 = 'Disconnect'
GROUP BY t2.cEventData1;

how to limit a sql integer query result to <=1

how to limit an integer query result to 1. a return of 2 to be 1, a return 1 to be 1, and a return of 0.5 to be 0.5 because it is <= 1. i don't want to modify the tables, i just want to modify the results.
This is my exact query.
select ((select "V01" from sports where "UID" = '1') * 1.0 ) /
(select "V01" from master where "BALL" = 'REQUIREMENT') ;
I'm using postgres.
To limit, you'd do something like this:
select
case
when yourNumber >= 1 then 1
else yourNumber
end
...
Then you just apply this concept to your query.
As noted by Wiseguy, you could also do:
select LEAST(yourNumber, 1)
, since this is postgresql.
The first solution will work with any ANSI SQL compatible database.
Update
Applied to your query, I think (if I understood what you want correctly) it would be like this:
select LEAST(1,
((select "V01" from sports where "UID" = '1') * 1.0 ) /
(select "V01" from master where "BALL" = 'REQUIREMENT')
);
use the LEAST function , docs: http://www.postgresql.org/docs/8.3/static/functions-conditional.html. Also, check out GREATEST too
SELECT LEAST(1, <your value>)
EDIT replaced GREATEST with LEAST
try this:
select CASE
WHEN ((select V01 from sports where UID = '1') * 1.0 ) /
(select V01 from master where BALL = 'REQUIREMENT') >= 1
THEN 1
ELSE ((select V01 from sports where UID = '1') * 1.0 ) /
(select V01 from master where BALL = 'REQUIREMENT')
END;

Fetch unique combinations of two field values

Probably it has been asked before but I cannot find an answer.
Table Data has two columns:
Source Dest
1 2
1 2
2 1
3 1
I trying to come up with a MS Access 2003 SQL query that will return:
1 2
3 1
But all to no avail. Please help!
UPDATE: exactly, I'm trying to exclude 2,1 because 1,2 already included. I need only unique combinations where sequence doesn't matter.
For Ms Access you can try
SELECT DISTINCT
*
FROM Table1 tM
WHERE NOT EXISTS(SELECT 1 FROM Table1 t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source)
EDIT:
Example with table Data, which is the same...
SELECT DISTINCT
*
FROM Data tM
WHERE NOT EXISTS(SELECT 1 FROM Data t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source)
or (Nice and Access Formatted...)
SELECT DISTINCT *
FROM Data AS tM
WHERE (((Exists (SELECT 1 FROM Data t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source))=False));
your question is asked incorrectly. "unique combinations" are all of your records. but i think you mean one line per each Source. so it is:
SELECT *
FROM tab t1
WHERE t1.Dest IN
(
SELECT TOP 1 DISTINCT t2.Dest
FROM tab t2
WHERE t1.Source = t2.Source
)
SELECT t1.* FROM
(SELECT
LEAST(Source, Dest) AS min_val,
GREATEST(Source, Dest) AS max_val
FROM table_name) AS t1
GROUP BY t1.min_val, t1.max_val
Will return
1, 2
1, 3
in MySQL.
To eliminate duplicates, "select distinct" is easier than "group by":
select distinct source,dest from data;
EDIT: I see now that you're trying to get unique combinations (don't include both 1,2 and 2,1). You can do that like:
select distinct source,dest from data
minus
select dest,source from data where source < dest
The "minus" flips the order around and eliminates cases where you already have a match; the "where source < dest" keeps you from removing both (1,2) and (2,1)
Use this query :
SELECT distinct * from tabval ;