Here is a example query, I've been trying to find a workaround for this but my knowledge for postgresql at this time is still limited. Thanks in advance.
Sample Query:
select round(3.041,2) as column
Expected Output:
3.03 instead of 3.04
Rounding UP works but I need it to round DOWN as well if the decimal value is <5.
You can round down with some simple decimal counting like
SELECT
3.04 - POWER(10,
(-1 *
CAST(
LENGTH(
SPLIT_PART(
CAST(3.04 AS STRING), '.', 2
)
)
AS INT)
)
)
However, I have no idea why you would do this. Are you sure you aren't trying to use the basic ROUND function and cut off more significant figures?
Related
I'm working on a legacy database and need to parse info from one database to another, parsing it into the new database is easy enough but first I need to create the query to convert and cast the following in the legacy SQL Server database:
WorkedHours(NVARCHAR(10)) is in text format 07:30
I need to convert and cast this as a decimal ie 7.5
I have searched around for the answer to this but can not find anything that has worked, so thought I would put it out there to see if any of you has any ideas.
Edit - What I should of asked is. What is causing an error converting to an int from a character with a value of 0 when trying to trying to convert and cast a time to a decimal?
DATEDIFF(
MINUTE,
0,
CAST('07:30' AS TIME)
)
/
60.0
Works up to '23:59' only
EDIT:
Based on a comment elsewhere, you have some 'bad' values.
This may find them...
SELECT
*
FROM
yourTable
WHERE
TRY_CONVERT(TIME, worked_hours) IS NULL
And as such, this is a safer version of my expression....
DATEDIFF(
MINUTE,
0,
TRY_CONVERT(TIME, worked_hours)
)
/
60.0
(Returns NULL for values that failed to parse.)
There's no reason to pull out the date/time types. Just do some simple string parsing:
cast(left(right('0' + WorkedHours, 5), 2) as int)
+ cast(right(WorkedHours, 2) as int) / 60.00
This won't have any limitations on 24 hours or anything like that. It just assumes that you've got one or two digits before a colon and two digits after.
This should work in SQL Server and an example-string "1101:56" (1101h & 56 minutes) | in general from 0h to >24h:
-- Take all hours before ":" and all Minutes (2 digits) after ":" and convert it to decimal.
select convert(decimal,left('1101:56',CHARINDEX(':','1101:56')-1)) + ( convert(decimal,right('1101:56',2))/60 );
-- with column-placeholder "time_str_from_table"
select convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60 );
If the source table have NULL-Values, than use "ISNULL" with substitution-value "0.0":
-- with column-placeholder "time_str_from_table"
select isnull( ( convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60) ), 0.0);
what would be the Snowflake counterpart of following Teradata SQL?
select CAST( CAST(( 2*-1 )AS FORMAT '9.99') AS CHAR(4))
will give
"2.00"
however in Snowflake,
select CAST(to_char(( 2*-1), 'FM0.00' ) AS CHAR(5));
gives:
"-2.00"
(example was simplified)
How to get rid of the - symbol?
thank you
Probably using ABS() is a good workaround:
select CAST(to_char(( abs(2*-1)), 'FM0.00' ) AS CHAR(5));
https://docs.snowflake.com/en/sql-reference/functions/abs.html
I am trying to convert a varchar to a percentage with a decimal. For example, my report is returning 13590 as a result for a rate, which I would like to have a result of 13.590%. I can't seem to get this to work, any help would be appreciated.
You can use Arithmetic operator inside your query, e.g.
SELECT (report / 100) as rate FROM MyTable;.
If the % is needed, look at the CONCAT function.
Not a very elegant solution, and will drop trailing zeros
SELECT cast(cast(columnA as float) / cast(1000 as float) as varchar(20)) + '%'
I want to convert my decimal SQL query result in percent. Example I have a 0.295333 I want it to be 30% and if I have a 0.090036 I want it to be 9%.
This is what I have so far.
(100 * (sample1/ sample2) ) as 'Percent'
I also tried this one but the problem is result comes with ".00" and I don't know how to remove the decimal.
cast (ROUND(100 * (sample1 / sample2),0) As int ) as 'Percent'
Try with the below script..
cast (100 * Round((sample1 / sample2),2) As int ) as 'Percent'
So as some of the comments pointed out you may need to pay attention to your datatype if one or both of the original columns that you get your decimal from are integer.
One easy way of dealing with that is something like this:
ColA * ColB * 1.0 which will make sure that your integers are treated as decimals
So if you have SQL Server 2012+ you can use Format and not mess with rounding at all. Like this FORMAT(YourDecimal,'#%'), yep that simple.
;WITH cteValues AS (
SELECT 0.295333 as OriginalValue
UNION ALL
SELECT 0.090036 as OriginalValue
)
SELECT
OriginalValue
,FORMAT(OriginalValue,'#%') as PercentFormat
FROm
cteValues
If you are pre 2012 and do not have format an easy way is to round to the 100th then times by 100 and cast as int CAST(ROUND(YourDecimal,2) * 100 AS INT)
;WITH cteValues AS (
SELECT 0.295333 as OriginalValue
UNION ALL
SELECT 0.090036 as OriginalValue
)
SELECT
OriginalValue
,CAST(ROUND(OriginalValue,2) * 100 AS INT) as PercentInt
FROm
cteValues
Because an INT cannot by definition have decimal places, if you are receiving .00 with the method similar to this or the one you have tried, I would ask the following.
Are you combining (multiplying etc.) the value after casting with another column or value that may be decimal, numeric, or float?
Are you looking at the query results in a program outside of SSMS that could be formatting the results automatically, e.g. Excel, Access?
Address your assumptions first.
How does ROUND work? Does it guarantee return values and if so, how? What is the precedence of the two columns? Does Arithmetic operators influence the results and how?
I only know what I do not know, and any doubt is worth an investigation.
THE DIVIDEND OPERATOR
Since ROUND always returns the higher precedence, this is not the problem. It is in fact the divide operator ( / ) that may be transforming your values to an integer.
Always verify the variables are consistently of one datatype or CAST if either unsure or unable to guarantee (such as insufficiently formatted. I.e. DECIMAL(4,2) instead of required DECIMAL(5,3) ).
DECLARE #Sample1 INT
, #Sample2 DECIMAL(4,2);
SET #Sample1 = 50;
SET #Sample2 =83.11;
SELECT ROUND( 100 * #Sample1 / #Sample2 , 0 )
Returns properly 60.
SELECT ROUND( 100 * #Sample2 / #Sample1 , 0)
Incorrectly turns variables into integers before rounding.
The reason is that DIVIDE - MSDN in SQL may return the higher precedence, but any dividend that is an integer returns another integer.
UPDATE
This also explains why the decimal remains after ROUND...it is of higher precedence. You can add another cast to transform the non-INT datatype to the preferred format.
SELECT CAST( ROUND( <expression>, <Length>) AS INT)
Note that in answering your question I learned something myself! :)
Hope this helps.
In database there is column amount which datatype is money. I want to select that row only with two digit after decimal. for this how to write the query?
My query is like this:
SELECT AMOUNT FROM DETAIL_PAGE.
I want to modify this query so that it selects two digits after decimal point.
SELECT AMOUNT - FLOOR(AMOUNT) FROM DETAIL_PAGE
That will get you just the decimal though. I think you want
SELECT FORMAT(AMOUNT, 2) FROM DETAIL_PAGE
Or without commas:
SELECT REPLACE(FORMAT(AMOUNT, 2), ',', '') FROM DETAIL_PAGE
Not sure if this is SQL standard and works elsewhere, but in Oracle you can say
select round(amount,2) from detail_page
-- round(12.345, 2) would return 12.35
or
select trunc(amount,2) from detail_page
-- trunc(12.345, 2) would return 12.34