Sort by day, ignoring hours and minutes - sql

Question

I have a little problem for you. I would like to sort by day, but if several with different times are sorted on the day, it separates them. How do I get it out that he only shows all day by day
My date field looks like this
Datum weight
2022-12-09 07:12:49.000 2150
2022-12-09 08:15:49.000 1250
My query
Select FORMAT(Datum, 'dd/MM/yyyy', 'de-DE') as Datum, SUM(weight)
FROM [Produktionsdaten].[dbo].[produktionedelstahl]
WHERE Anlage IN ('Bonak 2')
AND YEAR(Datum)=YEAR(CURRENT_TIMESTAMP)
AND MONTH(Datum)=MONTH(CURRENT_TIMESTAMP)
group BY (Datum)
I want the day to be summarized
Datum weight
12-09-2022 3400

Answer 1

I think you were nearly there - just change the last line
Select FORMAT(Datum, 'dd/MM/yyyy', 'de-DE') as Datum, SUM(weight)
FROM [Produktionsdaten].[dbo].[produktionedelstahl]
WHERE Anlage IN ('Bonak 2')
AND YEAR(Datum)=YEAR(CURRENT_TIMESTAMP)
AND MONTH(Datum)=MONTH(CURRENT_TIMESTAMP)
group BY FORMAT(Datum, 'dd/MM/yyyy', 'de-DE')

Answer 2

could you try to perform the SELECT in this way.
SELECT FORMAT(DATE(Datum), 'dd/MM/yyyy', 'de-DE') AS Datum, SUM(weight)
FROM [Produktionsdaten].[dbo].[produktionedelstahl]
WHERE Anlage IN ('Bonak 2')
AND YEAR(Datum)=YEAR(CURRENT_TIMESTAMP)
AND MONTH(Datum)=MONTH(CURRENT_TIMESTAMP)
GROUP BY DATE(Datum)

Answer 3

You can do it by casting the DATETIME to a DATE and going from there.
SELECT CAST(Datum AS DATE) AS Datum, SUM(Weight) AS Weight
FROM [Produktionsdaten].[dbo].[produktionedelstahl]
GROUP BY CAST(Datum AS DATE)
Here is a very small sample script to demonstrate that this works:
DECLARE #Data TABLE (Datum DATETIME, Weight INT);
INSERT INTO #Data(Datum, Weight) VALUES ('2022-12-09 07:12:49.000', 2150), ('2022-12-09 08:15:49.000', 1250);
SELECT CAST(Datum AS DATE) AS Datum, SUM(Weight) AS Weight
FROM #Data
GROUP BY CAST(Datum AS DATE)
Output:
Datum
Weight
2022-12-09
3400