There is a column in a string format. Data in that column is a mixture of letters and numbers. I want to pick up rows which contain more than 4 numbers in it.
For example, in the table below, what I'm interested in is row_num 4 as it contains more than 4 numerical values. How can they be selected?
row_num
column_1
1
fje8q934yeufoeha
2
08kfdjaehewaoffe
3
6fdiuewwiaei3eew
4
jfe0293ujfid22fe
We can use a regex replacement here:
SELECT row_num, column_1
FROM yourTable
WHERE LENGTH(REGEXP_REPLACE(column_1, '\D+', '')) > 4;
Related
Am trying to come up with a query where I can return back values where the the distance between the letters could be one or more than one for the chosen letter.
For example:
I have two columns which have letters in Column A and in Column B. I want to return back with rows when column B distance is more than Column A by one or more letters.
It's not clear to me, when you say "greater" if you mean that the distance between any two letters is 2 or 3 (Column B can be alphabetically before or after Column A, by a distance of 2 or 3).. Or if Column B has to be alphabetically after Column A, by a distance of 2 or 3
Because I'm not certain what you're talking about, I present two options. Read the "if" rule and choose the one that applies to your situation, then use the query under it:
If columnA is D and columnB can be any of: A B F G
SELECT * FROM table WHERE ABS(ASCII(columna) - ASCII(columnb)) IN (2,3)
If columnA is D and columnB can be any of: F G
SELECT * FROM table WHERE ASCII(columnb) - ASCII(columna) IN (2,3)
Edit1: Per your later comment, you are now saying that the distance is not just 2 or 3 letters (the first line of your question states "2 or 3") but any number of letters distance equal to or greater than 2:
SELECT * FROM table WHERE ASCII(columnb) - ASCII(columna) >= 2
Overall the technique isn't much different to the above queries and there are many ways to specify what you want:
SELECT * FROM table
WHERE
ASCII(columnb) - ASCII(columna)
BETWEEN <some_number_here> AND <other_number_here>
Ultimately the most important thing is to note the use of ASCII function, which gives us the ascii char code of the first letter in a string:
ASCII('ABCD') => 65
And we can use maths on this to work out if a letter distance from 'A' is more than 1 etc..
Probably also worth noting that ASCII() works on single byte ascii characters. If your data is multibyte (Unicode), you might need to use ORD() instead:
Edit2: Your latest edit to the question revises the limit to "B greater than A by one or more" which is equivalent to >= 1 ..
The question seems not to have a clear spec, please treat the answer as a guide for the general technique:
--for an open ended distance, ascii chars
SELECT * FROM table WHERE ASCII(columnb) - ASCII(columna) >= <some_distance>
--for an open ended distance, unicode
SELECT * FROM table
WHERE ORD(columnb) - ORD(columna) >= <some_distance>
--for a definite range of distances (replace … appropriately)
SELECT * FROM table
WHERE ... BETWEEN <some_distance> AND <some_other_distance>
this will work indeed:
select * from table_name where ascii(col_1)+2=ascii(col_2);
You can use something like this if you need it to be exactly 2 or 3 letters greater
select Column A, ColumnB from table name where ASCII(ColumnB) - ASCII(ColumnA) in (2,3)
If you want all those rows where the the difference is equal more than 2, then use this
select Column A, ColumnB from table name where ASCII(ColumnB) - ASCII(ColumnA) >=2
this is where you can make ascii in action..
select * from SampleTable where (ASCII(sampleTable.ColumnB) - ASCII(ColumnA)) >= 2;
I am using Oracle database.
In my table t_mytable, I have one field myfield and this field has string values like 00101110010.
I need to count the rows which has ""4th digit of myfield value is 1".
For instance,
myfield
-------
00101110010
00111110010
00101101010
00101110010
00111111110
For above data, count should be 2 because 2 rows has fourth bit as 1 (I started from 1 not 0 while determining first digit).
How can I do this in sql?
if myfield is a string you can use substr for extract the fourth char
select count(*)
from t_mytable
where substr(myfield, 4,1) ='1';
I have a set of rows with one column of actual data. The goal is display this data in Matrix format. The numbers of Column will remain same, the number of rows may vary.
For example:
I have 20 records. If I have 5 columns - then the number of rows would be 4
I have 24 records. I have 5 columns the number of rows would be 5, with the 5th col in 5th row would be empty.
I have 18 records. I have 5 columns the number of rows would be 4, with the 4th & 5th col in 4th row would be empty.
I was thinking of generating a column value against each row. This column value would b,e repeated after 5 rows. But I cannot the issue is "A SELECT statement that assigns a value to a variable must not be combined with data-retrieval operations"
Not sure how it can be achieved.
Any advice will be helpful.
Further Addition - I have managed to generate the name value association with column name and value. Example -
Name1 Col01
Name2 Col02
Name3 Col03
Name4 Col01
Name5 Col02
You can use ROW_NUMBER to assign a sequential integer from 0 up. Then group by the result of integer division whilst pivoting on the remainder.
WITH T AS
(
SELECT number,
ROW_NUMBER() OVER (ORDER BY number) -1 AS RN
FROM master..spt_values
)
SELECT MAX(CASE WHEN RN%5 = 0 THEN number END) AS Col1,
MAX(CASE WHEN RN%5 = 1 THEN number END) AS Col2,
MAX(CASE WHEN RN%5 = 2 THEN number END) AS Col3,
MAX(CASE WHEN RN%5 = 3 THEN number END) AS Col4,
MAX(CASE WHEN RN%5 = 4 THEN number END) AS Col5
FROM T
GROUP BY RN/5
ORDER BY RN/5
In general:
SQL is for retrieving data, that is all your X records in one column
Making a nice display of your data is usually the job of the software that queries SQL, e.g. your web/desktop application.
However if you really want to build the display output in SQL you could use a WHILE loop in connection with LIMIT and PIVOT. You would just select the first 5 records, than the next ones until finished.
Here is an example of how to use WHILE: http://msdn.microsoft.com/de-de/library/ms178642.aspx
My table structure is as follows :
id category
1 1&2&3
2 18&2&1
3 11
4 1&11
5 3&1
6 1
My Question: I need a sql query which generates the result set as follows when the user searched category is 1
id category
1 1&2&3
2 18&2&1
4 1&11
5 3&1
6 1
but i am getting all the results not the expected one
I have tried regexp and like operators but no success.
select * from mytable where category like '%1%'
select * from mytable where category regexp '([.]*)(1)(.*)'
I really dont know about regexp I just found it.
so please help me out.
For matching a list item separated by &, use:
SELECT * FROM mytable WHERE '&'||category||'&' LIKE '%&1&%';
this will match entire item (ie, only 1, not 11, ...), whether it is at list beginning, middle or end.
I have a column that has multiple numbers separated by a comma. Example for a row:
`numbers`:
1,2,6,66,4,9
I want to make a query that will select the row only if the number 6 (for example) is in the column numbers.
I cant use LIKE because if there is 66 it'll work too.
You can use like. Concatenate the field separators at the beginning and end of the list and then use like. Here is the SQL Server sytnax:
where ','+numbers+',' like '%,'+'6'+',%'
SQL Server uses + for string concatenation. Other databases use || or the concat() function.
You should change your database to rather have a new table that joins numbers with the row of your current table. So if your row looks like this:
id numbers
1 1,2,6,66,4,9
You would have a new table that joins those values like so
row_id number
1 1
1 2
1 6
1 66
1 4
1 9
Then you can search for the number 6 in the number column and get the row_id